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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 36201. |
Richa have 10$ and Vikash have 100rs who have more money? |
| Answer» Richa have more money, as 10$ =685.95rs | |
| 36202. |
Prove that √2+√3+√5 is a irrational number |
| Answer» root2 is an irrational no.root3 is an irrational no.root5 is an irrational no. We know that sum of two irrational no. is an irrational no.Therefore,root2+root3+root5 is an irrational no. | |
| 36203. |
3x-5y+1=0and 2x+3y=12using cross multiplication method |
| Answer» Search on google | |
| 36204. |
Ria have₹ 23 and Ronak have₹ 100 . Who have more money |
| Answer» Ronak obviously | |
| 36205. |
2/3 *3 |
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Answer» 2/3 x 3=2 (3 will be cancelled) 2/3*3=0.67*3=2.01 |
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| 36206. |
Y=1/2 |
| Answer» | |
| 36207. |
Formula of middle term in arthematic progression? |
| Answer» There is no specific formula for it .We can use median formula | |
| 36208. |
The sum of n,2n,3n terms of an A.P.areS1,S2,S3,respectively. Prove thatS3=3 (S2-S1) |
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Answer» GIVEN :=A1=NA2=2NA3=3NPROOF:=S2-S1 =A2+A1-A1= A2 EQUATION. 1A2 =2NTAKING RHS3(S2-S1) = 3A2.(PROVED. SEE EQUATION. 1) =3(2N) (A2 =2N)=6N. EQUATION OF RHSTAKING LHSS3 =A1+A2+A3=N+2N+3N=6N. EQUATION OF LHSON Comparing equation of LHS and RHSWe can say that LHS = RHSS3=3(S2-S1)HAVE A NICE DAY hsjdhxjsakbsjdkddjhdjz |
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| 36209. |
Find Sn if an=3+2n |
| Answer» Given, an\xa0= 3 + 2na1\xa0= 3 + 2{tex}\\times{/tex}1 = 5a2\xa0= 3 + 2{tex}\\times{/tex}2 = 7a3\xa0= 3 + 2{tex}\\times{/tex}3 = 9Thus the series is 5, 7, 9,......in which a = 5 and d = 7 - 5 = 2{tex}\\therefore \\quad S _ { n } = \\frac { n } { 2 } ( 2 a + ( n - 1 ) d ){/tex}Sn\xa0=\xa0{tex}\\frac n2{/tex}[2(5) + (n - 1)2]Sn\xa0=\xa0{tex}\\frac n2{/tex}[10\xa0+ 2n - 2]Sn\xa0=\xa0{tex}\\frac n2{/tex}[8\xa0+ 2n]Sn\xa0= 4n + n2\xa0 | |
| 36210. |
An AP which Tn equal to Sn |
| Answer» Satyagrah is an idea by which figh for a truth causes against in justic is fought without any voilence | |
| 36211. |
ABC is a triangle in which AB = AC and D is any point on BC prove that AB^2-AD^2=BD×CD |
| Answer» Draw {tex}A E \\perp B C{/tex}In\xa0{tex}\\Delta{/tex}AEB and {tex}\\Delta{/tex}AEC, we haveAB = AC,AE = AE [Common]and, {tex}\\angle{/tex}B = {tex}\\angle{/tex}C [{tex}\\because{/tex}\xa0AB = AC]{tex}\\therefore \\quad \\Delta A E B \\cong \\Delta A E C{/tex}{tex}\\Rightarrow{/tex}\xa0BE = CE [by CPCT]Since {tex}\\Delta{/tex}AED and {tex}\\Delta{/tex}ABE are right triangles right-angled at E.Therefore,{tex}\\Rightarrow{/tex}\xa0AD2 = AE2 + DE2 and AB2 = AE2 + BE2\xa0{tex}\\Rightarrow{/tex}\xa0AB2 -\xa0AD2 = BE2\xa0- DE2{tex}\\Rightarrow{/tex}\xa0AB2 - AD2 = (BE+ DE) (BE - DE){tex}\\Rightarrow{/tex}\xa0AB2 - AD2 = (CE+ DE) (BE - DE) [{tex}\\because{/tex}\xa0BE = CE ]{tex}\\Rightarrow{/tex}\xa0AB2- AD2\xa0= CD·BDHence, AB2 - AD2 = BD·CD | |
| 36212. |
What is BPT Theorm |
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Answer» Theorem:If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points,the other two sides are divided in the same ratio.Ans.Given:ABC is a∆BC||DETo Prove:AD by BD=AE by ECConstruction:Join DC and BE Draw ENperpendicular to AB and DM perpendicular to AE.Proof:BC||DE(given)ar.∆BDE = ar.∆DEC....................eq.1(∆on same base bet.same parallel.)ar.ADE by ar.BDE=1/2×AD×EN by 1/2×BD×ENar.ADE by ar.BDE=AD by BD.............eq.2ar.AED by ar.DEC=1/2×AE×DM by 1/2×EC×DMar.AED by ar.DEC=AE by EC..............eq.3Comparing 2 and 3 using 1ar.ADE by ar.BDE=ar.AED by ar.DECAD by BD=AE by EC(proved){AD by BD+1=AE by EC+1AD+BD by BD= AE+EC by ECAB by BD=AC by ECTaking reciprocalBD by AB= EC by AC1-BD by AB= 1-EC by ACAB-BD by AB= AC-EC by ACAD by AB =AE by AC}corrolary. According to this theorm ,a line is drawn parallel to the one side of a triangle to interset the other two sides in distinct points then the other two sides are divided in same ratio. If in triangle ABC , DE parallel AD then by BPT theorm AD/DB equal AE/EC |
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| 36213. |
A man has rs10000 with him... |
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Answer» What to do in question? ?? What to do ??? |
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| 36214. |
Completing square method |
| Answer» StepsStep 1 Divide all terms by a (the coefficient of x2).Step 2 Move the number term (c/a) to the right side of the equation.Step 3 Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation. | |
| 36215. |
Exercise 2.3 in maths class 10th |
| Answer» U can see the solutions of this exercise in this app. | |
| 36216. |
which term of the ap24, 21,18,15...is first negative term |
| Answer» -3 | |
| 36217. |
The sum of p terms of an A.P. is q and the sum of q terms is p. Find the sum of terms (p+q)? |
| Answer» Let a be the first term and d the common difference of the given A.P.{tex}\\therefore S_{p}=\\frac{p}{2}{/tex}\xa0[2a + (p - 1)d] = q\xa0{tex}\\Rightarrow{/tex}\xa02a + (p - 1)d\xa0{tex}=\\frac{2 q}{p}{/tex} ….(i)And\xa0{tex}S_{q}=\\frac{q}{2}{/tex}\xa0[2a + (q - 1)d] = p{tex}\\Rightarrow{/tex}\xa02a + (q - 1)d\xa0{tex}=\\frac{2 p}{q}{/tex}\xa0….(ii)Subtracting eq. (ii) from eq. (i) we get(p - q)d =\xa0{tex}\\frac{2 q}{p}-\\frac{2 p}{q}{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0(p - q)d\xa0{tex}=\\frac{2\\left(q^{2}-p^{2}\\right)}{p q}{/tex}{tex}\\Rightarrow{/tex}\xa0(p - q)d\xa0{tex}=\\frac{-2}{p q}{/tex}(p2\xa0- q2){tex}\\Rightarrow{/tex}\xa0(p - q)d\xa0{tex}=\\frac{-2}{p q}{/tex}\xa0(p + q)(p - q)\xa0{tex}\\Rightarrow d=\\frac{-2}{p q}{/tex}\xa0(p + q)Substituting the value of d in eq. (i) we get2a + (p - 1)\xa0{tex}\\left[\\frac{-2(p+q)}{p q}\\right]=\\frac{2 q}{p}{/tex}{tex}\\Rightarrow 2 a=\\frac{2 q}{p}+\\frac{2(p-1)(p+q)}{p q}{/tex}{tex}\\Rightarrow a=\\frac{q}{p}+\\frac{(p-1)(p+q)}{p q}{/tex}{tex}a=\\frac{q^{2}+p^{2}+p q-p-q}{p q}{/tex}Now\xa0Sp+q\xa0{tex}=\\frac{p+q}{2}{/tex}\xa0[2a + (p + q - 1)d{tex}=\\frac{p+q}{2}\\left[\\frac{2 q^{2}+2 p^{2}+2 p q-2 q-2 q}{p q}+\\frac{(p+q-1)[-2(p+q)}{p q}\\right]{/tex}{tex}=\\frac{p+q}{2}\\left[\\frac{2q^{2} + 2p^{2} + 2pq - 2p - 2q -2p^{2} -2 p q+2 p-2 p q-2 q^{2}+2 q}{p q}\\right]{/tex}{tex}=\\frac{p+q}{2}\\left[\\frac{-2 p q}{p q}\\right]{/tex}\xa0= -(p + q)\xa0hence proved. | |
| 36218. |
Sin2 Q=sin2Q |
| Answer» | |
| 36219. |
7 ones+8 tenth = [ ] tenths |
| Answer» 7 ones + 8 tenth = 7 + 80 = 87\xa0 | |
| 36220. |
All formula of a3 +b3 |
| Answer» a3 + b3 = (a + b) (a2- ab + b2). | |
| 36221. |
Who discovered pai |
| Answer» The Ancient Greek mathematician Archimedes of Syracuse (287-212 BC) is largely considered to be the first to calculate an accurate estimation of the value of pi. | |
| 36222. |
In trigonometry on which question which formula is used |
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Answer» I also wants to know as i face the same problem even I Know all formulas. I also need answer of this question . |
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| 36223. |
Find x :4x-300x-1=0 |
| Answer» x=1/216 | |
| 36224. |
Which metal produce golden flame on burning |
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Answer» Sodium (Na) The metal is Sodium(Na) |
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| 36225. |
(cosec A_sin A) (sec A_cos A) =1/tan A+cot A |
| Answer» Change cosec and sec into 1/ sin and 1/ cosin L.H.S. and also solve R.H.S. | |
| 36226. |
Similarity criterion |
| Answer» | |
| 36227. |
Chapter 4 example 15 solve |
| Answer» | |
| 36228. |
if the zeroes of the polynomial 5x2-7x+k are reciprocal of each other then find the value of k |
| Answer» | |
| 36229. |
The HCF of 225 And 870 is |
| Answer» 15 | |
| 36230. |
Lines |
| Answer» | |
| 36231. |
Show that nsquare -1 is divisible by 8 |
| Answer» 8 | |
| 36232. |
Explain to create similar figures ! |
| Answer» | |
| 36233. |
Find 2 constitution no.whose square have sum is 85 |
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Answer» 6 and 7 are the two consecutive no. Which have 85 as their square\'s sum. Approx 6^2+7^2=85 |
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| 36234. |
Ch-4 |
| Answer» Of which subject? | |
| 36235. |
56_78 |
| Answer» _22 | |
| 36236. |
Product of -235 and 38 |
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Answer» -8930 -8930 |
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| 36237. |
If AD =2.5cm BD =3.0 and AE=3.7cm ,find the length of AC |
| Answer» Use BPT theorem | |
| 36238. |
Ex 1.4 |
| Answer» | |
| 36239. |
Exercise 1.4 |
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Answer» maths ncert? Which book |
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| 36240. |
Find the H.C.F. of (x |
| Answer» X,1 | |
| 36241. |
The sum of two no. is 36. Three times one exceeds twice the other by 8.Find them. |
| Answer» | |
| 36242. |
Sum of two number is 48. One is one third of the other, Find them. |
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Answer» Let the value of 2 digits be x and y x+y=48X=1/3y1/3y+y=48Y+3y=484y=48Y=48/4Y=12So x=1/3*12X=4 Let the number be X and Y So x+y =48 Now ,x = 48-y |
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| 36243. |
The sum of number and its reciprocal is 3 1/3 find the number |
| Answer» Let the first number = x,and the second number = 30-x | |
| 36244. |
Prove the completing square method. Clearly. |
| Answer» {tex}x^2 +\xa06x - 16 = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x^2 + 6x = 16{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x^2 + 6x + 9 = 16 + 9{/tex} [Adding on both sides square of coefficient of x, i.e. ({tex}\\frac{6}{2}{/tex})2]{tex}\\Rightarrow{/tex}\xa0{tex}(x + 3)^2 = 25{/tex}{tex}\\Rightarrow{/tex}\xa0x + 3 =\xa0{tex}\\pm{/tex}{tex}\\sqrt{25}{/tex}{tex}\\Rightarrow{/tex}\xa0x + 3 =5 or x + 3 = -5{tex}\\Rightarrow{/tex}\xa0x = 2 or x = -8 | |
| 36245. |
X€ |
| Answer» Hcb | |
| 36246. |
Real |
| Answer» | |
| 36247. |
Find the sum of the 11th term of A.P., whose 6th term is 30. |
| Answer» | |
| 36248. |
Define secant to a circle |
| Answer» A secant of a curve is a line that intersects the curve in at least two (distinct) points. | |
| 36249. |
What are parabolas |
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Answer» A symmetrical open plane curved form by the intersection of a cone with a plane parallel to its side..the path of a projectile under the influence of gravity follows a curve of this shape.. A parabola is a curve where any point is at an equal distance from:a fixed point (the focus ), anda fixed straight line (the directrix ) |
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| 36250. |
The sum of two consecutive odd numbers is 394.find the numbers. |
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Answer» Let that 2 consecutive no be ,x and x +1 X(x+1)= 394Xsquare +x -394 =0by middel term splitting you further solve you will get the answer I think the questio is:the sum of squares of two c........answer:Numbers are 13 and 15 |
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