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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 38401. |
यदि 2x+x-6x-3 के शून्यांक 3 और -3 हो,तो इसके सभी शून्यांक लिखिए |
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| 38402. |
Proove that 3+2 route 5 is an irrational number |
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Answer» Irrational no 3+2√5=P/Q2√5=P/Q-32√5=P-3Q/Q√5=P-3Q/2QSo,it is irrational IrrAtional |
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| 38403. |
2sin^2 30×tan60-3cos^2 60-sec^2 30 |
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| 38404. |
Prove that 1-1 |
| Answer» 0 | |
| 38405. |
2tan30/1+tan*tan45= |
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Answer» 2byroot 3 Hlooooooooo Is anyone online |
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| 38406. |
A quadratic polynomial the sum of whose zeroes is -1 and sum of their reciprocals is 1/6 |
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| 38407. |
Can any one tell me how to plot friction on graph |
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| 38408. |
2ki power9+ 3ki power |
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| 38409. |
Find the value of x and y by cross multiplication methodbx/a + ay/b = a2+b2x+y-2ab |
| Answer» The given pair of equations are:{tex}\\frac{b}{a}x + \\frac{a}{b}y = {a^2} + {b^2} {/tex}So,\xa0{tex}\\frac{b}{a}x + \\frac{a}{b}y -[ {a^2} + {b^2} ] = 0{/tex} ...................(i)And x + y = 2abx + y - 2ab = 0 ....................(ii)Here,{tex}{a_1} = \\frac{b}{a},{b_1} = \\frac{a}{b}{/tex}, c1 = -(a2 + b2)a2 = 1, b2 = 1, c2 = -(2ab)By cross-multiplication method{tex}\\begin{array}{l}\\;\\frac x{{\\displaystyle\\frac ab}\\times-(2ab)\\;-1\\lbrack-(a^2\\;+\\;b^2)\\rbrack}=\\;\\frac y{-(a^2\\;+\\;b^2)\\;-{\\displaystyle\\frac ba}\\lbrack\\;-(2ab)\\rbrack}=\\;\\frac1{{\\displaystyle\\frac ba}-{\\displaystyle\\frac ab}}\\\\\\frac x{\\displaystyle\\frac{-2a^2b}b\\;\\;+(a^2\\;+\\;b^2)}=\\;\\frac y{-(a^2\\;+\\;b^2)\\;+{\\displaystyle\\frac{2ab^2}a}}=\\;\\frac1{\\displaystyle\\frac{b^2\\;-\\;a^2}{ab}\\;}\\\\\\end{array}{/tex}{tex} \\frac{x}{{{\\frac ba - \\frac ab} }} = \\frac{{ - y}}{{ - {b^2} + {a^2}}} = \\frac{1}{{\\frac{{{b^2} - {a^2}}}{{ab}}}} {/tex}{tex} \\frac{x}{{{b^2} - {a^2}}} = \\frac{{ - y}}{{ - {b^2} + {a^2}}} = \\frac{1}{{\\frac{{{b^2} - {a^2}}}{{ab}}}} {/tex}{tex} \\frac{x}{{{b^2} - {a^2}}} = \\frac{1}{{\\frac{{{b^2} - {a^2}}}{{ab}}}} {/tex}{tex}⇒ x = ab{/tex}And, {tex}\\frac{{ - y}}{{ - {b^2} + {a^2}}} = \\frac{1}{{\\frac{{{b^2} - {a^2}}}{{ab}}}} {/tex}{tex}⇒ y = ab{/tex}The solutions of the given pair of equations is x= ab and y = ab . | |
| 38410. |
If x plus 1 upon x is equal to 3 then x sqare plus 1 upon x sqare is equal to |
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Answer» Answer is 5 ×+1÷×=3Square both side(×+1÷×)^2=9×^2+1÷×^2+2=9×^2+1÷×^2=9-2=7 |
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| 38411. |
What is Euclids division lenma |
| Answer» Euclidean division\xa0with remainder is the process of division of two integers, which produces a quotient and a remainder smaller than the divisor. Its main property is that the quotient and remainder exist and are unique, under some conditions. | |
| 38412. |
sin⁴A - cos⁴A = 2sin²A - 1 |
| Answer» We have,L.H.S = sin4A - cos4A{tex}\\Rightarrow{/tex}\xa0L.H.S = (sin2A)2 - (cos2A)2{tex}\\Rightarrow{/tex}\xa0L.H.S = (sin2A + cos2A) (sin2A - cos2A) {tex}\\left[\\because a^2-b^2=\\left(a+b\\right)\\left(a-b\\right)\\right]{/tex}{tex}\\Rightarrow{/tex}\xa0L.H.S = sin2A - cos2 A [\xa0{tex}\\therefore{/tex}\xa0sin2 A + cos2 A = 1]{tex}\\Rightarrow{/tex}\xa0L.H.S = (1 - cos2A)-\xa0cos2 A = 1 - 2cos2 A = 1-2(1-sin2A) = 2sin2A-1 = R.H.S | |
| 38413. |
Sin⁴A-cos⁴A=2sin²A-1 |
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| 38414. |
Root x+y=11X+ root y=7Find the value of x and y |
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| 38415. |
Find the factor of the polynomials |
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| 38416. |
HOW SLOW. TRIGNOMETRY. PROBLEMS |
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| 38417. |
given ,a=5,d=3,an=50,find n and sn |
| Answer» Here, a = 5, d = 3, an = 50We know thatan = a + (n – 1)d{tex} \\Rightarrow {/tex}50 = 5 + (n - 1)3{tex} \\Rightarrow {/tex} (n – 1)3 = 50 - 5{tex} \\Rightarrow {/tex}\xa0(n - 1)3 = 45{tex} \\Rightarrow n - 1 = \\frac{{45}}{3}{/tex}{tex} \\Rightarrow {/tex}\xa0n - 1 = 15{tex} \\Rightarrow {/tex}n = 15 + 1{tex} \\Rightarrow {/tex}n = 16Again, we know that{tex}{S_n} = \\frac{n}{2}\\left[ {2a + (n - 1)d} \\right]{/tex}{tex} \\Rightarrow {S_n} = \\frac{{16}}{2}\\left[ {2(5) + (16 - 1)3} \\right]{/tex}{tex} \\Rightarrow {/tex}\xa0Sn = 8[10 +45]{tex} \\Rightarrow {/tex}\xa0Sn = 8(55){tex} \\Rightarrow {/tex}\xa0Sn = 440 | |
| 38418. |
What is the best way to study for exams |
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Answer» Whatever you know go through it nicely Read as much as you can and practice the questions which are difficult and be reviceing them at your familiar period means fresh morning or before going to bed learn by write Revise... Only to sleep |
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| 38419. |
If tan 8/15. Sin tita.... |
| Answer» Sin=8x | |
| 38420. |
2x²-7x=4 |
| Answer» X=4 or -1/2 | |
| 38421. |
Find the quadratic polynomial 2and-6 |
| Answer» (x)ka square + 4x -12 | |
| 38422. |
Skill based questions on the chapter Arithmetic Progression. |
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| 38423. |
TanA/1-cotA - cotA/1-tanA = (secA cosecA+1) |
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| 38424. |
If -3and4are zero of polynamial find numbers of polynomial |
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Answer» Sum of zeros =1Product of zeros=-12And polynomial will beX²-1x+(-12)=X²-1x-12 X²-2x-12 We know that for finding the polynamial from its root has a formula that is x² - ( sum of roots ) x +( product of roots ) According to the question Sum of product will be -3 and the product will be 4 Now , x² - ( -3 ) x+(4) 3x²+4x X(3x+4)3x+4 ,will be the polynamial |
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| 38425. |
Verify that 2 is a zero of the polynomial X3 +4X2 - 3X -18 |
| Answer» Xcube+4xsquare-3x-18Put 2 in place of x8+16-6-1824-24=0 | |
| 38426. |
4x 4 x square + 3 X square + 4 x square |
| Answer» 15 | |
| 38427. |
Result kb nikal tha h 10th walo ka |
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Answer» 30 30th may 28 may ko Rha* |
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| 38428. |
Divide 100 into two parts such that the sum of their reciprocals is 1/24 |
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| 38429. |
Alpha +beta =? |
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Answer» Alpha and Beta are the zeroes of the quadratic poly. ALPHA+BETA=-b/a Alpha and beta are zeroes or roots, their sum is equals to-b÷a or coeficient of x ÷coeficient of x^2 Yes —b/a _b/a -b/c -b/a _ Alpha+Beta = -b/a |
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| 38430. |
Kx+2y-53x-4y-10 find unique solution |
| Answer» 3kx+2y-15 | |
| 38431. |
Express sinA,tanA,andcotA in terms of cosecA |
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| 38432. |
Define HCF of two positive integer. |
| Answer» According to Euclid Division Lemma ,HCF of any two positive integer a and b ,with a>b,is obtained as follow :STEP1:a=bq+r,0 | |
| 38433. |
Conjugate of 2 + √5 |
| Answer» 2 -\xa0√5 | |
| 38434. |
Area of sector formula |
| Answer» {tex}\\frac{\\theta}{360}{/tex}X{tex} \\pi{r^2}{/tex} | |
| 38435. |
2+2×2÷2-2 |
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Answer» 2 2 2 2 |
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| 38436. |
Cot- 70 degree = ten 80degree? |
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| 38437. |
Where are the question papers of year 2008,2009 and 2010 of delhi ,outside delhi and foreign |
| Answer» You can check last year papers here :\xa0https://mycbseguide.com/cbse-question-papers.html | |
| 38438. |
If cot theta=12/13 show that 1-cos`2 theta/2-sin theta =3/5 |
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| 38439. |
How many term of ap 72,69,66, make sum of n term 897 |
| Answer» no answer of this question cause (d) is not constant. 69 - 72 = -17 , 66 - 69 = -95 . so, answer 0 . | |
| 38440. |
What is prime no |
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Answer» Those numbers which is diveded by itself called prime no It is divisible by 1 and itself only |
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| 38441. |
When is 10 th result |
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Answer» 30th of may Yet not fixed but may be at last of may or starting of june month |
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| 38442. |
Write the nature of the roots of quadratic equation3x sq.-x+1/3=0 |
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Answer» What will be the answer Find determinant (D) and compare the value of D with Zero if D=0 then it has only one root ,if D is greater than zero than it has many roots and if zero is greater than D then there is no any solutions of the given equation. How to solve these equation? |
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| 38443. |
The roots of the quadratic equation x sq.-5=0 is ______ |
| Answer» -√5 and +√5 | |
| 38444. |
Whagzggtfafffs |
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| 38445. |
A two digit number is four times the sum and three times the product of its digit Find the number |
| Answer» Let the ten\'s digit of the required number be x and its unit\'s digit be y.As per given conditionA two-digit number is four times the sum of its digitsThen, 10x + y = 4(x + y){tex}\\Rightarrow{/tex} 6x - 3y = 0{tex}\\Rightarrow{/tex} 2x - y = 0......... (i)And A two-digit number is twice the product of its digits.Also, 10x + y = 2xy. ....... (ii)Putting y = 2x from (i) in (ii), we get10x\xa0+ 2x = 4x2{tex}\\Rightarrow{/tex} 4x2- 12 x = 0{tex} \\Rightarrow{/tex}\xa04x(x - 3) = 0{tex}\\Rightarrow{/tex} x -\xa03 = 0{tex}\\Rightarrow{/tex} x = 3 [ten\'s digit, x {tex}\\ne{/tex}\xa00]Putting x = 3 in (i), we get y = 6.Thus, ten\'s digit = 3 and unit\'s digit = 6.Hence, the required number is 36. | |
| 38446. |
Chapter 3 exercise 3.3 |
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Answer» It is based on substitution only which question do you want to ask easy it is |
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| 38447. |
Solution of R S aggarwal |
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| 38448. |
maths 1To 3rd lesson CBSE 10th worldproblems |
| Answer» What do you want ask in which | |
| 38449. |
(2,3),(4,1) find distance between pairs |
| Answer» Distance=(x2-x1)+(y2-y1). (-2)²+(1)². 4+1=5so distance ² =5 ,distance is root 5 | |
| 38450. |
Y do we learn maths |
| Answer» If you will not learn maths then you willnot be able to answer simple addition or subtraction. It is used in our daily life | |