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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 38451. |
940+35p-------------- =????? 44+p |
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| 38452. |
(a-b)x +(a+b)y =a^-2ab-b^(a+b) (x+y) =a^+b^ |
| Answer» x = a + b{tex}\\therefore{/tex} (a - b)(a + b) + (a + b)y = a2 - b2 - 2aba2 - b2 + (a + b)y = a2 - b2 - 2ab{tex}y = \\frac{{ - 2ab}}{{a + b}}{/tex} | |
| 38453. |
x+y =5 , 2x-3y =4 |
| Answer» x+y=5,2x-3y=4from1 x=5-y putting value of x in 2. 2(5-y)-3y=4. 10-2y-3y=4. 10-5y=4. Y=6/5.putting value of y in2. x+6/5=5. x=25-6/5. X =19/5 | |
| 38454. |
2square root is |
| Answer» 1.414 | |
| 38455. |
Solve by the method of completing the square X2 -6x +3=0 |
| Answer» X-6x/2+3/2=0X-3x+3/2=0X-2(3x)/2+3/2=0X-2(3x)/2+3/2+1-1=0(x-1)²+3/2-1=0(x-1)²+3/2=1(x-1)²=1-3/2(x-1)²=-1/2x-1=root-,+1/2x=1+1/2x=3/2When x-1=-1/2x=-1/2+1x=1/2Answer is x=3/2,1/2 | |
| 38456. |
If alpha and beta are the zeroes of polynomial 3x²+11x-4. Find the value of alpha/beta + beta/alpha |
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| 38457. |
Prove root 2 as irrational |
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Answer» Here it is not possible No |
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| 38458. |
Show that any positive even integer is of the form 6m,6m+2 or 6m+4,where m is some integer |
| Answer» Let p be any positive integerBy division algorithm, p = 6m + r, where 0 {tex} \\leqslant {/tex}r< 6Here r=0,1,2,3,4,5Therefore,values of p are : 6m, 6m + 1, 6m + 2, 6m + 3, 6m + 4, 6m + 5Now 6m+1,6m+3 and 6m+5 are odd numbers because m is a positive integer.Hence 6m, 6m + 2, 6m + 4 are even integers because they are next positive number to the odd numbers 6m-1,6m+1 and 6m+3 respectively\xa0 | |
| 38459. |
Sin60° cos30°+sin30°cos60° |
| Answer» We know Sin (A+B) = SinA CosB + CosA SinBTherefore the above will be Sin (60+30) = Sin 90 = 1 | |
| 38460. |
Find differentiation of sin inverse (a+bcosx/b+acosx) |
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| 38461. |
Any rational isintegera? |
| Answer» No, not every rational number is an integer.\xa0The integers are the positive and negative whole numbers and zero: The rational numbers are numbers that can be represented by a ratio of integers. | |
| 38462. |
Find least positive integer which when multiplies 9÷50 makes it a perfect square. |
| Answer» Sorry didn\'t get | |
| 38463. |
If HCF of 65 and 117 is expressible in the form of 65m-117 then find the value of m |
| Answer» 117 = 13 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa0365 = 13 {tex}\\times{/tex}\xa05HCF (117, 65) = 13LCM(117,65) = 13 {tex}\\times{/tex}\xa05 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa03 = 585Here is given that:{tex}HCF =65m-117{/tex}13 = 65m - 11765m = 130m =\xa0{tex}\\frac { 130 } { 6 5 } ={/tex}2\xa0 | |
| 38464. |
Write all trigonometry identities? |
| Answer» Check revision notes for formulae :\xa0https://mycbseguide.com/cbse-revision-notes.html | |
| 38465. |
Find the remainder when the product of any three consecutive integers is divided by6 |
| Answer» Let three consecutive numbers be x, (x + 1) and (x + 2)Let x = 6q + r 0 {tex}\\leq r < 6{/tex}{tex}\\therefore x = 6 q , 6 q + 1,6 q + 2,6 q + 3,6 q + 4,6 q + 5{/tex}{tex}\\text { product of } x ( x + 1 ) ( x + 2 ) = 6 q ( 6 q + 1 ) ( 6 q + 2 ){/tex}if x = 6q then which is divisible by 6{tex}\\text { if } x = 6 q + 1{/tex}{tex}= ( 6 q + 1 ) ( 6 q + 2 ) ( 6 q + 3 ){/tex}{tex}= 2 ( 3 q + 1 ) .3 ( 2 q + 1 ) ( 6 q + 1 ){/tex}{tex}= 6 ( 3 q + 1 ) \\cdot ( 2 q + 1 ) ( 6 q + 1 ){/tex}which is divisible by 6if x = 6q + 2{tex}= ( 6 q + 2 ) ( 6 q + 3 ) ( 6 q + 4 ){/tex}{tex}= 3 ( 2 q + 1 ) .2 ( 3 q + 1 ) ( 6 q + 4 ){/tex}{tex}= 6 ( 2 q + 1 ) \\cdot ( 3 q + 1 ) ( 6 q + 1 ){/tex}Which is divisible by 6{tex}\\text { if } x = 6 q + 3{/tex}{tex}= ( 6 q + 3 ) ( 6 q + 4 ) ( 6 q + 5 ){/tex}{tex}= 6 ( 2 q + 1 ) ( 3 q + 2 ) ( 6 q + 5 ){/tex}which is divisible by 6{tex}\\text { if } x = 6 q + 4{/tex}{tex}= ( 6 q + 4 ) ( 6 q + 5 ) ( 6 q + 6 ){/tex}{tex}= 6 ( 6 q + 4 ) ( 6 q + 5 ) ( q + 1 ){/tex}which is divisible by 6if x = 6q + 5{tex}= ( 6 q + 5 ) ( 6 q + 6 ) ( 6 q + 7 ){/tex}{tex}= 6 ( 6 q + 5 ) ( q + 1 ) ( 6 q + 7 ){/tex}which is divisible by 6{tex}\\therefore {/tex}\xa0the product of any three natural numbers is divisible by 6. | |
| 38466. |
Solve (x+1)(x+2)(x+3)(x+4)=120 |
| Answer» X4 +24=120X4=120-24X2× x2=【4√6】2X2=4√6X=√4√62√6 | |
| 38467. |
2x+3x-5 |
| Answer» By middle term spliting2×square+(5-2)x-5(2xsquare+5x)(2x-5)Taking x as commonx(2x-5)-1 (2x-5)(x-1)(2x-5) X=1 ,X=2/5 | |
| 38468. |
Prove that root 5 is the irrational no. |
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Answer» It is not easy ok *NCERT book It is given in NCRT |
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| 38469. |
Prove that (2÷x+y)^2+(x-y÷2)^2-1=0 |
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| 38470. |
A+b+c/(a)^-1(b)^-1+(b)^-1(c)^-1+(c)^-1(a)^-1 |
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Answer» 1 =abc prove that |
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| 38471. |
Under root tanA.tanB |
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| 38472. |
a+b+c/(a)-1(b)-1+(b)-1(c)-1+(c)-1(a)-1 |
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| 38473. |
Prove that n=n+1. Where n is any rational number. |
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| 38474. |
What is difference between identities and equations(at least 3 points) |
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| 38475. |
Find the zero of the polynomial x^2+x-p(p+1). |
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| 38476. |
I am information about improvmant exam |
| Answer» I don\'t get ur que | |
| 38477. |
Prove that √7+3by 7 is irrational |
| Answer» Etdsg | |
| 38478. |
Area ke puestion |
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| 38479. |
Two dice are thrown what is the probability of getting an odd number or number less than 2 |
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| 38480. |
Write the properties of rational number with examples |
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| 38481. |
Evaluate4 tan sq.30°+cosec sq.60°-1÷sec sq.45° |
| Answer» Answer is 5/6 you should put the values of trigonometric ratios and then evaluate it then you will get the answer | |
| 38482. |
Solve by elimination:-1/2(x+2y) +5/3(3x-2y) = -3/25/4(x+2y) -3/5(3x-2y) =61/60 |
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Answer» Thank you so much sir for your answer but then also i didnot understand if you can then it will be a great pleasure Let (x+2y) be p and ( 3x- 2y) be q1/2p+5/3q=-3/2Solve it5/4p-3/5q=61/60Solve itWe\'ll get 6p+10q=(-18)............175p-36q=61...........2Multiply eq1 by36 and eq2 by 10 We\'ll get next eq and eliminate them |
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| 38483. |
Solve the equation by elimination method 11x-7y=xy , 9x-4y=6xy |
| Answer» 11x-7y=xy.............19x-4y=6xy............2 Multiply by 4 eq1 and by 7 eq2We get 44x-28y=4xy........363x-28y=42xy............4Eliminating eq4 and eq3, we get19x=38xyY=2, put value of y in any eq we\'ll get the value ofx. | |
| 38484. |
X+y=9 |
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| 38485. |
1/2(x+2y)+5/3(3x-2y)=-3/2 |
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| 38486. |
Write properties of rational no with example |
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Answer» It can be form in p/q & q is not equal to 0 For example- 2/5 It is terminating and repeating ( nonterminating ) |
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| 38487. |
what is a standard form of quadratic polynomial |
| Answer» Ax + By + C = 0Where A, B, C are a real no. | |
| 38488. |
What is the value of Sin135° ? |
| Answer» sin(135)= sin (90 + 45) // sin(a + b) = sin(a)cos(b) + cos(a)sin(b)= sin(90)cos(45) + cos(90)sin(45)= ( 1 x 1/√2) + (0 x 1/√2)= 1/√2= (√2)/2 | |
| 38489. |
Find a quadratic polynomial whose zeeoes are -3 and 4 |
| Answer» We have, x = 4\xa0and x = -3.Then,x - 4\xa0= 0 and x +\xa03 = 0{tex}\\Rightarrow{/tex}\xa0(x - 4)(x +\xa03) = 0{tex}\\Rightarrow{/tex}\xa0x2\xa0+\xa03x - 4x -\xa012\xa0= 0{tex}\\Rightarrow{/tex} x2\xa0- x -\xa012\xa0= 0This is the required quadratic equation | |
| 38490. |
What is the name of acid ant release |
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Answer» Formic acid is released by ant. It is also known as simple carboxylic acid... ethanoic acid Formic acid or ethanoic acid |
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| 38491. |
Find the HCF of 65 and 117 and Express it in the form 65m and 117 m |
| Answer» 117 = 13 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa0365 = 13 {tex}\\times{/tex}\xa05HCF (117, 65) = 13LCM(117,65) = 13 {tex}\\times{/tex}\xa05 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa03 = 585Here is given that:{tex}HCF =65m-117{/tex}{tex}13=65m-117{/tex}{tex}65m=130{/tex}m =\xa0{tex}\\frac { 130 } { 6 5 } ={/tex}2 | |
| 38492. |
Find the latest no. When divisible by 27 and 37 .Give remember 5 and 29 respectively |
| Answer» I think its answer is 2 | |
| 38493. |
What is definition of lemma |
| Answer» Lemma is the proven statement which is used to prove other statements.This definition is also present in NCERT. | |
| 38494. |
What will be the SA 1 syllabus |
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| 38495. |
Find the numbers whose sum is 40 and product 375 |
| Answer» The no. Is 15+25 | |
| 38496. |
Wst is q |
| Answer» q is To be the Qetient | |
| 38497. |
Which terms of AP 3,6,9,12...........is 0 |
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| 38498. |
3.7 exersie |
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| 38499. |
X+x+x=4x |
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Answer» If X=4/3 Ya if we add X |
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| 38500. |
Draw the graph of following polynomials find numbers of zeroes from graph. 1) y=x-2x+1 |
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