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38451.

940+35p-------------- =????? 44+p

Answer»
38452.

(a-b)x +(a+b)y =a^-2ab-b^(a+b) (x+y) =a^+b^

Answer» x = a + b{tex}\\therefore{/tex} (a - b)(a + b) + (a + b)y = a2 - b2 - 2aba2 - b2 + (a + b)y = a2 - b2 - 2ab{tex}y = \\frac{{ - 2ab}}{{a + b}}{/tex}
38453.

x+y =5 , 2x-3y =4

Answer» x+y=5,2x-3y=4from1 x=5-y putting value of x in 2. 2(5-y)-3y=4. 10-2y-3y=4. 10-5y=4. Y=6/5.putting value of y in2. x+6/5=5. x=25-6/5. X =19/5
38454.

2square root is

Answer» 1.414
38455.

Solve by the method of completing the square X2 -6x +3=0

Answer» X-6x/2+3/2=0X-3x+3/2=0X-2(3x)/2+3/2=0X-2(3x)/2+3/2+1-1=0(x-1)²+3/2-1=0(x-1)²+3/2=1(x-1)²=1-3/2(x-1)²=-1/2x-1=root-,+1/2x=1+1/2x=3/2When x-1=-1/2x=-1/2+1x=1/2Answer is x=3/2,1/2
38456.

If alpha and beta are the zeroes of polynomial 3x²+11x-4. Find the value of alpha/beta + beta/alpha

Answer»
38457.

Prove root 2 as irrational

Answer» Here it is not possible
No
38458.

Show that any positive even integer is of the form 6m,6m+2 or 6m+4,where m is some integer

Answer» Let p be any positive integerBy division algorithm, p = 6m + r, where 0 {tex} \\leqslant {/tex}r< 6Here r=0,1,2,3,4,5Therefore,values of p are : 6m, 6m + 1, 6m + 2, 6m + 3, 6m + 4, 6m + 5Now 6m+1,6m+3 and 6m+5 are odd numbers because m is a positive integer.Hence 6m, 6m + 2, 6m + 4 are even integers because they are next positive number to the odd numbers 6m-1,6m+1 and 6m+3 respectively\xa0
38459.

Sin60° cos30°+sin30°cos60°

Answer» We know Sin (A+B) = SinA CosB + CosA SinBTherefore the above will be Sin (60+30) = Sin 90 = 1
38460.

Find differentiation of sin inverse (a+bcosx/b+acosx)

Answer»
38461.

Any rational isintegera?

Answer» No, not every rational number is an integer.\xa0The integers are the positive and negative whole numbers and zero: The rational numbers are numbers that can be represented by a ratio of integers.
38462.

Find least positive integer which when multiplies 9÷50 makes it a perfect square.

Answer» Sorry didn\'t get
38463.

If HCF of 65 and 117 is expressible in the form of 65m-117 then find the value of m

Answer» 117 = 13 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa0365 = 13 {tex}\\times{/tex}\xa05HCF (117, 65) = 13LCM(117,65) = 13 {tex}\\times{/tex}\xa05 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa03 = 585Here is given that:{tex}HCF =65m-117{/tex}13 = 65m - 11765m = 130m =\xa0{tex}\\frac { 130 } { 6 5 } ={/tex}2\xa0
38464.

Write all trigonometry identities?

Answer» Check revision notes for formulae :\xa0https://mycbseguide.com/cbse-revision-notes.html
38465.

Find the remainder when the product of any three consecutive integers is divided by6

Answer» Let three consecutive numbers be x, (x + 1) and (x + 2)Let x = 6q + r 0 {tex}\\leq r < 6{/tex}{tex}\\therefore x = 6 q , 6 q + 1,6 q + 2,6 q + 3,6 q + 4,6 q + 5{/tex}{tex}\\text { product of } x ( x + 1 ) ( x + 2 ) = 6 q ( 6 q + 1 ) ( 6 q + 2 ){/tex}if x = 6q then which is divisible by 6{tex}\\text { if } x = 6 q + 1{/tex}{tex}= ( 6 q + 1 ) ( 6 q + 2 ) ( 6 q + 3 ){/tex}{tex}= 2 ( 3 q + 1 ) .3 ( 2 q + 1 ) ( 6 q + 1 ){/tex}{tex}= 6 ( 3 q + 1 ) \\cdot ( 2 q + 1 ) ( 6 q + 1 ){/tex}which is divisible by 6if x = 6q + 2{tex}= ( 6 q + 2 ) ( 6 q + 3 ) ( 6 q + 4 ){/tex}{tex}= 3 ( 2 q + 1 ) .2 ( 3 q + 1 ) ( 6 q + 4 ){/tex}{tex}= 6 ( 2 q + 1 ) \\cdot ( 3 q + 1 ) ( 6 q + 1 ){/tex}Which is divisible by 6{tex}\\text { if } x = 6 q + 3{/tex}{tex}= ( 6 q + 3 ) ( 6 q + 4 ) ( 6 q + 5 ){/tex}{tex}= 6 ( 2 q + 1 ) ( 3 q + 2 ) ( 6 q + 5 ){/tex}which is divisible by 6{tex}\\text { if } x = 6 q + 4{/tex}{tex}= ( 6 q + 4 ) ( 6 q + 5 ) ( 6 q + 6 ){/tex}{tex}= 6 ( 6 q + 4 ) ( 6 q + 5 ) ( q + 1 ){/tex}which is divisible by 6if x = 6q + 5{tex}= ( 6 q + 5 ) ( 6 q + 6 ) ( 6 q + 7 ){/tex}{tex}= 6 ( 6 q + 5 ) ( q + 1 ) ( 6 q + 7 ){/tex}which is divisible by 6{tex}\\therefore {/tex}\xa0the product of any three natural numbers is divisible by 6.
38466.

Solve (x+1)(x+2)(x+3)(x+4)=120

Answer» X4 +24=120X4=120-24X2× x2=【4√6】2X2=4√6X=√4√62√6
38467.

2x+3x-5

Answer» By middle term spliting2×square+(5-2)x-5(2xsquare+5x)(2x-5)Taking x as commonx(2x-5)-1 (2x-5)(x-1)(2x-5) X=1 ,X=2/5
38468.

Prove that root 5 is the irrational no.

Answer» It is not easy ok
*NCERT book
It is given in NCRT
38469.

Prove that (2÷x+y)^2+(x-y÷2)^2-1=0

Answer»
38470.

A+b+c/(a)^-1(b)^-1+(b)^-1(c)^-1+(c)^-1(a)^-1

Answer» 1
=abc prove that
38471.

Under root tanA.tanB

Answer»
38472.

a+b+c/(a)-1(b)-1+(b)-1(c)-1+(c)-1(a)-1

Answer»
38473.

Prove that n=n+1. Where n is any rational number.

Answer»
38474.

What is difference between identities and equations(at least 3 points)

Answer»
38475.

Find the zero of the polynomial x^2+x-p(p+1).

Answer»
38476.

I am information about improvmant exam

Answer» I don\'t get ur que
38477.

Prove that √7+3by 7 is irrational

Answer» Etdsg
38478.

Area ke puestion

Answer»
38479.

Two dice are thrown what is the probability of getting an odd number or number less than 2

Answer»
38480.

Write the properties of rational number with examples

Answer»
38481.

Evaluate4 tan sq.30°+cosec sq.60°-1÷sec sq.45°

Answer» Answer is 5/6 you should put the values of trigonometric ratios and then evaluate it then you will get the answer
38482.

Solve by elimination:-1/2(x+2y) +5/3(3x-2y) = -3/25/4(x+2y) -3/5(3x-2y) =61/60

Answer» Thank you so much sir for your answer but then also i didnot understand if you can then it will be a great pleasure
Let (x+2y) be p and ( 3x- 2y) be q1/2p+5/3q=-3/2Solve it5/4p-3/5q=61/60Solve itWe\'ll get 6p+10q=(-18)............175p-36q=61...........2Multiply eq1 by36 and eq2 by 10 We\'ll get next eq and eliminate them
38483.

Solve the equation by elimination method 11x-7y=xy , 9x-4y=6xy

Answer» 11x-7y=xy.............19x-4y=6xy............2 Multiply by 4 eq1 and by 7 eq2We get 44x-28y=4xy........363x-28y=42xy............4Eliminating eq4 and eq3, we get19x=38xyY=2, put value of y in any eq we\'ll get the value ofx.
38484.

X+y=9

Answer»
38485.

1/2(x+2y)+5/3(3x-2y)=-3/2

Answer»
38486.

Write properties of rational no with example

Answer» It can be form in p/q & q is not equal to 0 For example- 2/5
It is terminating and repeating ( nonterminating )
38487.

what is a standard form of quadratic polynomial

Answer» Ax + By + C = 0Where A, B, C are a real no.
38488.

What is the value of Sin135° ?

Answer» sin(135)= sin (90 + 45) // sin(a + b) = sin(a)cos(b) + cos(a)sin(b)= sin(90)cos(45) + cos(90)sin(45)= ( 1 x 1/√2) + (0 x 1/√2)= 1/√2= (√2)/2
38489.

Find a quadratic polynomial whose zeeoes are -3 and 4

Answer» We have, x = 4\xa0and x = -3.Then,x - 4\xa0= 0 and x +\xa03 = 0{tex}\\Rightarrow{/tex}\xa0(x - 4)(x +\xa03) = 0{tex}\\Rightarrow{/tex}\xa0x2\xa0+\xa03x - 4x -\xa012\xa0= 0{tex}\\Rightarrow{/tex} x2\xa0- x -\xa012\xa0= 0This is the required quadratic equation
38490.

What is the name of acid ant release

Answer» Formic acid is released by ant. It is also known as simple carboxylic acid...
ethanoic acid
Formic acid or ethanoic acid
38491.

Find the HCF of 65 and 117 and Express it in the form 65m and 117 m

Answer» 117 = 13 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa0365 = 13 {tex}\\times{/tex}\xa05HCF (117, 65) = 13LCM(117,65) = 13 {tex}\\times{/tex}\xa05 {tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa03 = 585Here is given that:{tex}HCF =65m-117{/tex}{tex}13=65m-117{/tex}{tex}65m=130{/tex}m =\xa0{tex}\\frac { 130 } { 6 5 } ={/tex}2
38492.

Find the latest no. When divisible by 27 and 37 .Give remember 5 and 29 respectively

Answer» I think its answer is 2
38493.

What is definition of lemma

Answer» Lemma is the proven statement which is used to prove other statements.This definition is also present in NCERT.
38494.

What will be the SA 1 syllabus

Answer»
38495.

Find the numbers whose sum is 40 and product 375

Answer» The no. Is 15+25
38496.

Wst is q

Answer» q is To be the Qetient
38497.

Which terms of AP 3,6,9,12...........is 0

Answer»
38498.

3.7 exersie

Answer»
38499.

X+x+x=4x

Answer» If X=4/3
Ya if we add X
38500.

Draw the graph of following polynomials find numbers of zeroes from graph. 1) y=x-2x+1

Answer»