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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 38351. |
Lcm of pi , ( pi )square |
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Answer» Yes it will be π^2?? Confirm ho Pi square |
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| 38352. |
Lcm of under root 3 , under root 6 |
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Answer» √3= √3×1√6=√3×√2Therefore LCM of √3 and √6 = [√3×√3]×√2=3×√2=【3√2】.??? 6 is the ans as:√3*2√3=6And√6*√6=6 |
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| 38353. |
2k =5 (2k+3k) |
| Answer» 2k=5(2k+3k)2k=5(5k)2k=10k5k=0K=0 | |
| 38354. |
Find the square root of 5674 |
| Answer» 75.3 259583 | |
| 38355. |
Solve for x abx\'2+(b\'2-ac)xbc |
| Answer» We have, abx2 + (b2 -ac) x-bc = 0{tex}\\implies{/tex}abx2 + b2 x - acx - bc = 0{tex}\\implies{/tex}bx ( ax+b) - c (ax + b) = 0{tex}\\implies{/tex}(ax + b) (bx - c) = 0Either ax+b = 0 or bx - c = 0{tex}\\implies x = -{b \\over a},\\, {c \\over b}{/tex}Hence, {tex}x = -{b \\over a},\\, {c \\over b}{/tex} are the required solutions. | |
| 38356. |
Can you tell me which book is best for good marks in board - rs agarwal , rd sharma for maths |
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Answer» Rs agarwal is same like rd sharma but you should start with rd sharma Rd sharma is best as it contains ques of all the books including ncert and examplar Rs agarwal gives you the selected and best questions Agar rs agarwal pura lga lo ache marks aaenge R d sharma Rd sharma is the best .....not sure .. ...but it is good |
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| 38357. |
Linear equations for 2x-5y+4=0 and 2x+y-8=0 |
| Answer» Solve it by elimination method | |
| 38358. |
Prove that √5+3 is irrational number |
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| 38359. |
If 8sinA = 4 + cos A find the value of sin A. |
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| 38360. |
6 (ax+by)=3a+2b6 (bx-ay)=3a-2b |
| Answer» Dont know | |
| 38361. |
How to revise maths |
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Answer» During practise mark the questions which seems important to u to revise during exams? To solve the examples repeated by understanding them . |
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| 38362. |
If the HCF(210,355) is empressible in the form of 210 × 5 - 55y , find y |
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Answer» Please give me full answer The value of y=19 |
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| 38363. |
H. C. F. of x and 48 is 3 and their L. C. M. Is 240. Find the value of x |
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Answer» LCM × HCF=PRODUCT OF TWO NUMBERS 240×3=48×X720/48=XX=15 lcm x hcf = product of two numbers 240*3=48*x240*3÷48=x 720÷48=x x=10 15???? |
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| 38364. |
Find cos75 by using the formula cos(A+B)=cosAcosB-SinAsinB |
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| 38365. |
Prove 1+cosA/sinA = sinA/1-cosA |
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| 38366. |
X+1-2x |
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Answer» X=1 X=1 |
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| 38367. |
Find the value of b for which 2x+3 if a factor of 2x^3+9x^2-x-b |
| Answer» X=3/2Put value of x in eq2(3/2)^3+9(3/2)^2-3/2-b=027+81/2-3/2-b=054+81-3-b=0132-b=0-b=-132b=132 | |
| 38368. |
Find qadratic polynomial, the sum and product of whose zeroes are -3 and 2 respectively |
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Answer» My teacher\'s new selfmade formula= x^2-(quita + bita) x + quita × bita. So, x^2-(-3)x+2X^2+3x+2 Let take a polynomial ax² + bx + cThen ,we have sum of zeroes -3 as we know that sum of zeroes = -coefficient of x / coefficient of x²= -b/a= -3/1And product of zeroes = 2= coefficient of constant / coefficient of x²= c/a= 2/1Then we have ,a=1,b=-3,c=2We have polynomial= 1x² - 3x + 2 Ytrrr x^2+3x+2 |
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| 38369. |
How we can represent 2-root 3 on the no.line? |
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| 38370. |
Inan A.P. 19th term is 52 and 38th term is 128 find sumof first 56 term |
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Answer» Answer is 5040,abhi H Ans |
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| 38371. |
What is pass maske |
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| 38372. |
Represent root under 8 on the number line |
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| 38373. |
Prove that the sum of rational and irrational is always irrational. |
| Answer» 3× underroot 8 =3underroot 8 | |
| 38374. |
{234₹_780}power 10 |
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| 38375. |
NCERT math\'s solutions class 10 |
| Answer» Check NCERT Solutions here :\xa0https://mycbseguide.com/ncert-solutions.html | |
| 38376. |
NCERT math\'s solutions |
| Answer» Check NCERT Solutions here :\xa0https://mycbseguide.com/ncert-solutions.html | |
| 38377. |
root 4+3 root 4+3.......=? |
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| 38378. |
What is sin120° |
| Answer» Sin 120°= Sin(180°-120°)=√3/2 | |
| 38379. |
3×4+6÷5_3×5+3= |
| Answer» -4.8 by simple calculation | |
| 38380. |
Sir/mam i have a doubt in lsn real numbers q-2 please solve its urgent |
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| 38381. |
tanA +secA=what |
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| 38382. |
Pt.that _/3 +2_/5 is irrational plz? |
| Answer» To prove this you need to prove that root 3 and root 5 are irrational. You can do this by long Method. Okk now then in last you can say that if irrational get added to rational always an irrational no. Comes And sorry I can\'t write whole answer. But It will be helpful for you. Thanks | |
| 38383. |
integration of sin^2x |
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| 38384. |
When n is a odd integer than show that n square-1 is divided by 8 |
| Answer» We know that 4q + 1,4q+3 odd positive integerIf n=4q+1n^2-1= 16q^2+8+1-1n^2-1=8(2q^2+1)n^2-1 is divisible by 8If n=4q+3n^2-1=16q^2+24q+9-1n^2-1= 8(2q^2+3q+1)n^2-1 is divisible by 8Hence,n^2 -1 is divisible by 8 | |
| 38385. |
Differentiate Between numbers and digits |
| Answer» 0-9 is single so it is called digit .after it 10-infinity it means group of digit is called number.Hope it will helpful | |
| 38386. |
Write the condition for rational number which can have a terminat ing decimal expansion |
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Answer» If the denominator is In the form of multiple of 2 and 5 then it is said to be a terminating decimal. Thank you hope it would be useful for you Sohel shek r u a student of kvs . ok the ans is: the denominator of the rational no. should have the prime factors 2^ m or 5^m or 2^m.5^n . |
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| 38387. |
If alpha and beta are zeros of x2-px+q prove that alpha2/beta2+ beta2/alpha2=p4/q2-4p2/q+2 |
| Answer» Here\xa0α and β are the zeros of polynomial f(x) = x2 - px + qSo a=1,b=-p,c=qSum of the zeroes α + β={tex}-\\frac ba{/tex}\xa0= pProduct of the zeroes αβ=q\xa0{tex}\\frac{{{\\alpha ^2}}}{{{\\beta ^2}}} + \\frac{{{\\beta ^2}}}{{{\\alpha ^2}}}{/tex}{tex}= \\frac{{{\\alpha ^4} + {\\beta ^4}}}{{{\\alpha ^2}{\\beta ^2}}}{/tex}{tex}=\\frac{\\left(\\mathrm\\alpha^2+\\mathrm\\beta^2\\right)^2-2\\left(\\mathrm{αβ}\\right)^2}{\\left(\\mathrm{αβ}\\right)^2}=\\frac{\\{(\\mathrm\\alpha+\\mathrm\\beta)^2-2\\mathrm{αβ}\\}^2-2\\left(\\mathrm{αβ}\\right)^2}{\\left(\\mathrm{αβ}\\right)^2}{/tex}{tex}=\\frac{(\\mathrm p^2-2\\mathrm q)^2-2\\mathrm q^2}{\\mathrm q^2}=\\frac{\\mathrm p^4+4\\mathrm q^2-4\\mathrm p^2\\mathrm q-2\\mathrm q^2}{\\mathrm q^2}=\\frac{\\mathrm p^4+2\\mathrm q^2-4\\mathrm p^2\\mathrm q}{\\mathrm q^2}{/tex}{tex}=\\frac{\\mathrm p4}{\\mathrm q^2}-\\frac{4\\mathrm p^2\\mathrm q}{\\mathrm q^2}+\\frac{2\\mathrm q^2}{\\mathrm q^2}=\\frac{\\mathrm p4}{\\mathrm q^2}-\\frac{4\\mathrm p^2}{\\mathrm q}+2=\\mathrm{RHS}{/tex}Hence, proved. | |
| 38388. |
If 2 and 1/2 are the zeros of qx2+5x+r,then prove that q=r |
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| 38389. |
Chapter 1 ex 1.3 1question |
| Answer» Suppose root 5 is a rational numberTherefore root 5= p/ , p,q are integers, & q is not equals to 0On reducing-- root 5= a/b , a & b are coprime no.=> b root 5= aSquaring both sides5b^2= a^2 ------------(i)=> b^2 = a^2 /5Since 5 divides a^2Therefore 5 will also divide a (by theorem 1.3) ----(ii)=> a/5= c=> a= 5c=> a^2 = 25c^2=> 5b^2 = 25c^2 (by eq.^n (i))=> b^2= 5c^2=> b^2 /5= c^2Therefore 5 divides b^2 Therefore 5 will also divide b (by theorem 1.3) -----(iii)From eq.^n (ii) & (iii)5 divides a & b bothTherefore 5 is common factor of a & bBut this contradict the fact that a & b are coprimeTherefore this is due to our wrong assumption that root 5 is rational.Therefore we conclude that root 5 is rational. | |
| 38390. |
Largest natural number which have name |
| Answer» Largest natural number does not exist because every natural number has its successor | |
| 38391. |
prove that sin2A+cos2A=1 |
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| 38392. |
x/a+y/b=2ax-by=a2-b2 |
| Answer» {tex}\\frac { x } { a } + \\frac { y } { b } = 2{/tex}{tex}\\frac { b x + a y } { a b } = 2{/tex}{tex}bx + ay = 2ab{/tex}........(i){tex}ax - by = (a^2\xa0- b^2){/tex}...(ii)Multiplying (i) by b and (ii) by a{tex}b^2x + bay = 2ab^2{/tex}.............(iii){tex}a^2x - bay = a(a^2\xa0- b^2){/tex}........(iv)Adding (iii) and (iv),we get{tex}b^2x + a^2x =\xa02ab^2\xa0+ a^3\xa0- ab^2{/tex}{tex}x(b^2\xa0+ a^2) = 2ab^2\xa0+ a^3\xa0- ab^2{/tex}{tex}x(b^2\xa0+ a^2)\xa0=\xa0ab^2\xa0+ a^3{/tex}{tex}x(b^2\xa0+ a^2)\xa0=a(b^2\xa0+ a^2){/tex}{tex}x = \\frac { a \\left( b ^ { 2 } + a ^ { 2 } \\right) } { \\left( b ^ { 2 } + a ^ { 2 } \\right) } = a{/tex}Putting x = a in (i),we get{tex}b \\times a + a y = 2 a b{/tex}{tex}a y = 2 a b - a b \\Rightarrow a y = a b{/tex}\xa0or y = b{tex}\\therefore{/tex}\xa0solution is x = a, y = b | |
| 38393. |
A triangle ABC B=90, A=45 find C. |
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Answer» C=45° C=45 |
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| 38394. |
2÷x-1 3÷y-1 |
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| 38395. |
Find the 20th term from the last term of the AP:3,8,13....,253 |
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| 38396. |
Find the d of the AP 3,1,-1,-3 |
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Answer» -2 -2 |
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| 38397. |
The range of f (x) =cos [x],for- 3.14/2 |
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| 38398. |
In an A.P., prove that tm+n + tm-n = 2tm. |
| Answer» The equation will be tm + n +tm -nPlus n or -n cancel Because of opposite sign Then answer remains 2tm | |
| 38399. |
Find the LCM and HCF of 6 & 20 by prime factorisation method |
| Answer» 6= 2 x 320= 2 x 2 x 5H.C.F=2 L.C.M= 120 | |
| 38400. |
Find the least possible number |
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