Solve for x abx\'2+(b\'2-ac)xbc

1.	Solve for x abx\'2+(b\'2-ac)xbc
Answer» We have, abx2 + (b2 -ac) x-bc = 0{tex}\\implies{/tex}abx2 + b2 x - acx - bc = 0{tex}\\implies{/tex}bx ( ax+b) - c (ax + b) = 0{tex}\\implies{/tex}(ax + b) (bx - c) = 0Either ax+b = 0 or bx - c = 0{tex}\\implies x = -{b \\over a},\\, {c \\over b}{/tex}Hence, {tex}x = -{b \\over a},\\, {c \\over b}{/tex} are the required solutions.

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