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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 38651. |
Find a and b 2x+ab-8 |
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| 38652. |
Find the zeroes of the following polynomial x^2+3/4x+5 |
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Answer» Because, discriminant is <0.. No solutios for this eq. .. |
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| 38653. |
Difference between infinite and infinity |
| Answer» Infinite technically is an adjective. Like this page is white, similarly this series is infinite, but infinity is a noun. It means a certain quantity which is not a fixed number but bigger than any given number. Infinity ∞ is not a number, but an idea that describes something growing without bound. | |
| 38654. |
3x2+11x+6=0 |
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Answer» -12/11 -12/11 |
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| 38655. |
What is probality |
| Answer» The extent to which an event is likely to occurvmeasured by the ratio of favourable cause to the whole number of cause possible. | |
| 38656. |
Solve the following pair of linear equation by the substitution method (1) 9x -10y=12, |
| Answer» 4x+9y=49 | |
| 38657. |
16×16 |
| Answer» 256 | |
| 38658. |
If x=2 and x=3 are roots of the equation 3xsquare-2kx+2m=0 . find the value of k and m |
| Answer» K=15/2m=9 | |
| 38659. |
Find the qurdartic polynomial the sum of zeroes is 0 product is -7 |
| Answer» Sum of zeroes = 0, product of zeroes = -7So the required polynomiais\xa0x^2 -(sum of zeroes)x product of zeroes.ie. x^2 -0x +(-7)ie x^2 -7 | |
| 38660. |
Solve 2x+3y=11and2x-4y=-24and hence find the value of m for which y=mx+3 |
| Answer» m=-1 | |
| 38661. |
separate the number 50 in the sum of which their byaktikram is 1/12 |
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| 38662. |
Find the zeroes of the polynomial x^2+x-a(a+1) |
| Answer» x^2 + x - a(a+1) =0 =>x^2 + (a+1)x - ax - a(a+1) = 0 =>x{x+(a+1)} - a{x+(a+1)} = 0 =>{x+(a+1)}(x-a) = 0 =>x+(a+1) = 0 or x+a = 0. (Since if ab=0 then either a=0 or b=0) =>x = -(a+1) or x = -a ie x = -a -1 or x = -aSo the zeros of the given polynomial are -a -1 or -a.\xa0 | |
| 38663. |
what can I do if I want to recheck my cbse board maths exam of class 10 |
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| 38664. |
Bhai log kis kis ki compartment aai hai maths me |
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Answer» 9th ki to bhut loose marking hui thi iss baar or 10th m krib 1lakh bcho ki compartment aai thi.. 9th m ya 10th m |
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| 38665. |
If the zeros of the polynomial f (x)=2x-15x+3x-30 are in A.P., find them |
| Answer» Let, {tex}α{/tex} = a - d, {tex}β{/tex} = a and {tex}\\gamma {/tex} = a + d be the zeroes of the polynomial.f(x) = 2x3 - 15x2 + 37x - 30{tex}\\alpha + \\beta + \\gamma = - \\left( {\\frac{{ - 15}}{2}} \\right) = \\frac{{15}}{2}{/tex} ....... (i){tex}\\alpha \\beta \\gamma = - \\left( {\\frac{{ - 30}}{2}} \\right) = 15{/tex} ......... (ii)From (i)a - d + a + a + d = {tex}\\frac{{15}}{2}{/tex}\xa0So, 3a = {tex}\\frac{{15}}{2}{/tex}a = {tex}\\frac{{5}}{2}{/tex}and From (ii)a(a - d)(a + d) = 15So, a(a2 - d2) = 15{tex}⇒ \\frac{{5}}{2}{/tex}{tex}\\left[\\left(\\frac52\\right)^2\\;-d^2\\right]{/tex} = 15{tex}⇒ \\frac{25}4\\;-d^2{/tex}= 6{tex}⇒ \\;d^2\\;=\\;\\frac{25}4-6\\;{/tex}{tex}⇒ {d^2} = \\frac{1}{4}{/tex}{tex}⇒ d = \\frac{1}{2}{/tex}Therefore, {tex}\\alpha = \\frac{5}{2} - \\frac{1}{2} = \\frac{4}{2} = 2{/tex}{tex}\\beta = \\frac{5}{2}{/tex}{tex}\\gamma = \\frac{5}{2} + \\frac{1}{2} = 3{/tex}. | |
| 38666. |
for any positive integers prove n cube - n is divisible by 6 |
| Answer» n3\xa0- n = n (n2\xa0- 1) = n (n - 1) (n + 1)\xa0Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2.∴ n = 3p or 3p + 1 or 3p + 2, where p is some integer.If n = 3p, then n is divisible by 3.If n = 3p + 1, then n – 1 = 3p + 1 –1 = 3p is divisible by 3.If n = 3p + 2, then n + 1 = 3p + 2 + 1 = 3p + 3 = 3(p + 1) is divisible by 3.So, we can say that one of the numbers among n, n – 1 and n + 1 is always divisible by 3.⇒ n (n – 1) (n + 1) is divisible by 3.\xa0Similarly, whenever a number is divided by 2, the remainder obtained is 0 or 1.∴ n = 2q or 2q + 1, where q is some integer.If n = 2q, then n is divisible by 2.If n = 2q + 1, then n – 1 = 2q + 1 – 1 = 2q is divisible by 2 and n + 1 = 2q + 1 + 1 = 2q + 2 = 2 (q + 1) is divisible by 2.So, we can say that one of the numbers among n, n – 1 and n + 1 is always divisible by 2.⇒ n (n – 1) (n + 1) is divisible by 2.Since, n (n – 1) (n + 1) is divisible by 2 and 3.∴ n (n-1) (n+1) = n3\xa0- n is divisible by 6.( If a number is divisible by both 2 and 3 , then it is divisible by 6)\xa0\xa0 | |
| 38667. |
30% of 30% of a number is 9 what is that number options 200 300 100 or 18 |
| Answer» 100 | |
| 38668. |
Divide 9x4+x by x+5 |
| Answer» 9×4=3636+x by x+5×+36÷x+5x+5)x+36 (1 x+5 --------------- +31Remainder=31 | |
| 38669. |
What is whole number? |
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Answer» All nature numbers along with 0 are called whole numbers The numbers which start with 0 Start with 0 Whole number is a number which starts from 0 to infinity |
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| 38670. |
formula of Eculid, division lemma |
| Answer» a=bq+r | |
| 38671. |
Anyone of you whose aim to become cbse topper in matric |
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Answer» Ya Yes |
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| 38672. |
When school give 20% in board |
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Answer» Yaa At the last session .. before final exams |
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| 38673. |
Write quadratic formula |
| Answer» Ax2 + bx + c | |
| 38674. |
2018 cbse10th all questions with answers |
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| 38675. |
A=150 d=50 |
| Answer» 150,200,250,300,350,400,450,500................☺ | |
| 38676. |
Parcatical marks will add in comparment exam |
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| 38677. |
3x+(a+1)y=2b-15x-(1-2a) =3b |
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| 38678. |
Sec^thita=x+1/4x ,then prove that sec thiya+tan thita=2x or 1/2x |
| Answer» By the given condition of question\xa0{tex}\\sec \\theta = x + \\frac { 1 } { 4 x }{/tex}{tex}\\therefore \\quad \\tan ^ { 2 } \\theta = \\sec ^ { 2 } \\theta - 1{/tex}{tex}\\Rightarrow \\quad \\tan ^ { 2 } \\theta = \\left( x + \\frac { 1 } { 4 x } \\right) ^ { 2 } - 1 = x ^ { 2 } + \\frac { 1 } { 16 x ^ { 2 } } + \\frac { 1 } { 2 } - 1 = x ^ { 2 } + \\frac { 1 } { 16 x ^ { 2 } } - \\frac { 1 } { 2 } = \\left( x - \\frac { 1 } { 4 x } \\right) ^ { 2 }{/tex}{tex}\\Rightarrow \\quad \\tan \\theta = \\pm \\left( x - \\frac { 1 } { 4 x } \\right){/tex}{tex}\\Rightarrow \\quad \\tan \\theta = \\left( x - \\frac { 1 } { 4 x } \\right) \\text { or, } \\tan \\theta = - \\left( x - \\frac { 1 } { 4 x } \\right){/tex}CASE 1: When\xa0{tex}\\tan \\theta = - \\left( x - \\frac { 1 } { 4 x } \\right) :{/tex}\xa0In this case,{tex}\\sec \\theta + \\tan \\theta = x + \\frac { 1 } { 4 x } + x - \\frac { 1 } { 4 x } = 2 x{/tex}CASE 2: When\xa0{tex}\\theta = - \\left( x - \\frac { 1 } { 4 x } \\right) :{/tex}\xa0In this case,{tex}\\sec \\theta + \\tan \\theta = \\left( x + \\frac { 1 } { 4 x } \\right) - \\left( x - \\frac { 1 } { 4 x } \\right) = \\frac { 2 } { 4 x } = \\frac { 1 } { 2 x }{/tex}Hence,\xa0{tex}\\sec \\theta + \\tan \\theta = 2 x \\text { or } , \\frac { 1 } { 2 x }{/tex} | |
| 38679. |
Write a QP. Whose zeroes are -4/5 and 1/3 |
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| 38680. |
Solve the equation/4x+1/3+ |
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| 38681. |
What is fundamental theorem of arthemics |
| Answer» Every composite number can be expressed in the multiples of its prime factors and this prime factors are unique apart from the order in which they are arranged.This is called the fundamental theorem of arithmetic. | |
| 38682. |
What is the value of 4 sq 67 minus 7 square 23 |
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| 38683. |
If area of rectangle is 100m^2 and its perimeter is 130m find the length and breadth of rectangle |
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| 38684. |
For any positive integer n,show that n3-3 is divisible by 6 |
| Answer» n3\xa0- n = n (n2\xa0- 1) = n (n - 1) (n + 1)\xa0Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2.∴ n = 3p or 3p + 1 or 3p + 2, where p is some integer.If n = 3p, then n is divisible by 3.If n = 3p + 1, then n – 1 = 3p + 1 –1 = 3p is divisible by 3.If n = 3p + 2, then n + 1 = 3p + 2 + 1 = 3p + 3 = 3(p + 1) is divisible by 3.So, we can say that one of the numbers among n, n – 1 and n + 1 is always divisible by 3.⇒ n (n – 1) (n + 1) is divisible by 3.Similarly, whenever a number is divided by 2, the remainder obtained is 0 or 1.∴ n = 2q or 2q + 1, where q is some integer.If n = 2q, then n is divisible by 2.If n = 2q + 1, then n – 1 = 2q + 1 – 1 = 2q is divisible by 2 and n + 1 = 2q + 1 + 1 = 2q + 2 = 2 (q + 1) is divisible by 2.So, we can say that one of the numbers among n, n – 1 and n + 1 is always divisible by 2.⇒ n (n – 1) (n + 1) is divisible by 2.Since, n (n – 1) (n + 1) is divisible by 2 and 3.∴ n (n-1) (n+1) = n3\xa0- n is divisible by 6.( If a number is divisible by both 2 and 3 , then it is divisible by 6)\xa0\xa0 | |
| 38685. |
Prove 3^1/2 is rational |
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Answer» Prakhar 3to the power1/2 question hai But.... Tumne3×1/2 kia rational no. can be written in the form of p/q. it 3/2 also written in the form of p/q. so it is a rational..I hope you like it... |
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| 38686. |
For any integer n, prove that n³-n is divisible by 6. |
| Answer» yaaa | |
| 38687. |
Find the greatest 6 digits number exactly divisible by 24, 15,and 36. |
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Answer» 360000 LC M of 24,15,36 |
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| 38688. |
If a+b=3 and AB=2 then find asquare+bsquare ,and asquare - bsquare... |
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Answer» A = 2. & B = 1 Solve this b=1or2 thenu find a and a^2+b^2&a^2-b^2 |
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| 38689. |
tan theta *cos theta |
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Answer» SIN THETA Tan theta=sin/cosSin/cos×cos=sintheta Sin theta |
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| 38690. |
4x+2x=0 |
| Answer» x=0 | |
| 38691. |
Factories x^2+4√2x+6 |
| Answer» x^2+3√2x+√2x+6x(x+3√2)+√2(x+3√2)(x+√2) (x+3√2) | |
| 38692. |
If sn=6n-5n^2,than find the 20th term pls give the solution |
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| 38693. |
(a+b) x+ay-(a+b) = 0ax+(a+b) y-ab=o |
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| 38694. |
2x^2+x-528 Solve by factorisation |
| Answer» By factorization . Values of x are = -33/2 and 32 . GOT it Miss Tara jain | |
| 38695. |
0.4x + 0.3y =1.70.7x -0.2y =0.8Solve the following system of equation |
| Answer» O.4x+0.3y=1.7 4/10x+ 3/10y=17/104x+3y/10=17/104x+3y=17 -----(1)Similarly 7x-2y=8-----(2)4x=17-3y X=17-3y/4---(3)Puting (3) in (2)7 (17-3y/4)-2y =8119-21y/4 -2y=8Taking lcm119-21y-8y=8×4-29y=36-119-29y=-83Y=3 7x-2 (3)=87x=8+6X=14/2X=2,y=3 | |
| 38696. |
A quadratic polynomial whose zeroes are -3 and 4 |
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Answer» Formula for making polynomial=x²-(a+B)x+aB.puting values. x²-(-3+4)x+(-3)(4)=0. x²-1x-12=0, it\'s the answer. here sum of the roots, S=-3+4=1Product of the roots P =(-3)(4)=-12We know that x2\xa0+ (sum of the roots)x + product of roots =0x2\xa0+ x- 12=0 x2 - x - 12 It is the correct answer. X2 |
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| 38697. |
3 root 5 minus 2 root 3 |
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| 38698. |
Factorise x-1/x=3 |
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| 38699. |
1+tanA+secA×1+cotA_cosecA |
| Answer» 2 | |
| 38700. |
2÷7×7-8 |
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Answer» minus 6 16.5 |
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