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| 1. |
Find the zeroes of the polynomial x^2+x-a(a+1) |
| Answer» x^2 + x - a(a+1) =0 =>x^2 + (a+1)x - ax - a(a+1) = 0 =>x{x+(a+1)} - a{x+(a+1)} = 0 =>{x+(a+1)}(x-a) = 0 =>x+(a+1) = 0 or x+a = 0. (Since if ab=0 then either a=0 or b=0) =>x = -(a+1) or x = -a ie x = -a -1 or x = -aSo the zeros of the given polynomial are -a -1 or -a.\xa0 | |