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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 40851. |
What is. Line sgmnt |
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Answer» A line segment is a piece, or part, of a line in geometry. A line segment is represented by end points on each end of the line segment. A line in geometry is represented by a line with arrows at each end. ... For example, if your end points were A and B, then you would write your line segment AB with a line over the top. Line segment is a line which has 2 end points |
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| 40852. |
The mean of the following distribution is 18 find the frequency f of class 19 to 21 |
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| Answer» | Class interval | Frequency f\t\t\t11-133123613-156148415-1791614417-19131823419-21f2020f21-2352211023-2542496\xa0{tex}\\sum f _ { i } = 40 + f{/tex}\xa0{tex}\\sum f _ { i } x _ { i } = 704 + 20 f{/tex}\tlet the missing frequency is \'f\'.we know that ,\xa0{tex}Mean= \\frac { \\sum f _ { i } x _ { i } } { \\sum f _ { i } }{/tex}{tex}\\Rightarrow 18 = \\frac { 704 + 20 f } { 40 + f }{/tex}{tex}\\Rightarrow 18(40 + f)=704 + 20f{/tex}{tex}\\Rightarrow 720 + 18f =704 + 20f{/tex}\xa0{tex}\\Rightarrow 2f = 16{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0f = 8 | |
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| 40853. |
Csa of frustum |
| Answer» In geometry, a frustum is the portion of a solid (normally a cone or pyramid) that lies between one or two parallel planes cutting it.If we cut a right circular cone by a plane parallel to its base, the portion of the solid between this plane and the base is known as the frustum of a cone.Curved Surface Area (CSA) = pi * l(R + r)wherer = radius of smaller circleR = radius of bigger circlel = slant height of the frustum | |
| 40854. |
find the value of √6+√6+√6+......infinity |
| Answer» Let\xa0{tex}x = \\sqrt { 6 + \\sqrt { 6 + \\sqrt { 6 + \\dots } } }{/tex}\xa0......(i){tex}\\Rightarrow{/tex}\xa0x2 =\xa0{tex}( \\sqrt { 6 + \\sqrt { 6 + \\sqrt { 6 . . } } } ) ^ { 2 }{/tex}\xa0[Squaring both sides]{tex}\\Rightarrow{/tex}\xa0x2 =\xa0{tex}6 + \\sqrt { 6 + \\sqrt { 6 + \\sqrt { 6 + \\ldots } } }{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x^2 = 6 + x{/tex} [From (i)]{tex}\\Rightarrow{/tex}\xa0{tex}x^2 - x - 6 = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}(x - 3) (x + 2) = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}x = 3, x = -2{/tex}{tex}\\therefore{/tex}\xa0x = 3 [{tex}\\because{/tex}\xa0x > 0] | |
| 40855. |
Show that one and only one out of n,n+2,n+4 is divisible by 3, where n is any positive integer. |
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Answer» Harry agar dobara badbad ki to jhumri talliya me gira ke marunga send me your fb id |
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| 40856. |
1- cosA+ sinA/sinA+ cosA-1= 1+ sinA/ cosA. Pls prove this question |
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| 40857. |
Find the distance between two points from origin |
| Answer» under root.x^2 +y^2 | |
| 40858. |
prove 90 degree in trignometric ratios |
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| 40859. |
Derive quadratic formula |
| Answer» Start with\tax^2 + bx + c=0Divide the equation by a\tx^2 + bx/a + c/a = 0Put c/a on other side\tx^2 + bx/a = -c/aAdd (b/2a)2 to both sides\tx^2 + bx/a + (b/2a)^2 = -c/a + (b/2a)^2The left hand side is now in the x2 + 2dx + d2 format, where "d" is "b/2a"So we can re-write it this way:"Complete the Square" (x+b/2a)^2 = -c/a + (b/2a)^2Now x only appears once and we are making progress.Now Solve For "x"Now we just need to rearrange the equation to leave "x" on the left Start with (x+b/2a)^2 = -c/a + (b/2a)^2Square root\t(x+b/2a) = (+-) sqrt(-c/a+(b/2a)^2)Move b/2a to right\tx = -b/2a (+-) sqrt(-c/a+(b/2a)^2)That is actually solved! But let\'s simplify it a bit:Multiply right by 2a/2a\tx = [ -b (+-) sqrt(-(2a)^2 c/a + (2a)^2(b/2a)^2) ] / 2aSimplify:\tx = [ -b (+-) sqrt(-4ac + b^2) ] / 2a | |
| 40860. |
Cross multiple exercise 3.6 |
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| 40861. |
Find the value of k, for which one root of the quadratic equation kx²-14x+8 is 2. |
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Answer» K=5 K(2)² - 14(2)+8=04k-28+8=04k-20=04k=20K=5 K=24....... |
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| 40862. |
tan30+tan60-cos90= |
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Answer» 4/√3 4√3/3 2/√3 3/√3 |
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| 40863. |
Find the area of triangle whose base= 25 CM and height=10.8 |
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Answer» 135 cm2 Area of the given Triangle =1/2×base×height =( 1/2×25×10.8 )cm2 =135cm2. Answer |
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| 40864. |
If the area of an equilateral triangle is 36√3 cm2,find its perimeter |
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Answer» Area of equilateral triangal = root3/4 a² Root3/4a² = 36root3Root 3 and root3 will cancel.a²=36x4a²=144a=12Perimeter of equilateral triangle = 3aP=3x12 = 36. 36 cm |
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| 40865. |
What is formula of curved surface area of frustum in chapter 13 |
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Answer» Thanks Abhishek π(R+r)l |
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| 40866. |
Derive the quadratic formula |
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| 40867. |
Koun koun course complete karne ke chakar mein school mein absent rehte ho,..... |
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Answer» To tum meri party ke ho.... Me ? Ham. Chahte hain par sab jaate hain isliye hame bhi jana pad raha hai |
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| 40868. |
Mean mode median formula |
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Answer» It is called as emperical formula..... 3MEDIAN=MODE+2MEAN |
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| 40869. |
all examples of chapter5 |
| Answer» See in NCERT Book | |
| 40870. |
Pure form of quadratic equation |
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Answer» ax2+bx+c=0 ax²+bx+c=0 ax^2+c=0 |
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| 40871. |
a,a+d,a+2d.....land n terms of an AP find (n-1)th term of itin term of |
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| 40872. |
Factorization mein middle term split karte vakt middle mein common factors kaise nikalen. |
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Answer» First and last term ko multiply krke jo aayega uske factor krne h Tum log jo bhi bata rahe ho mujhe ata hai... Magar vo do term choose karne mein hi problem hoti hai samjhe Pehle x ^2 ke cofficient ko aur constant term ko multiply kro. Uske baad X ke cofficient ko factorise karke do numbers choose karo jise ki multiply karne ke baad hame x^2 ke cofficient aur constant term ka product mile aur use add ya subtract karne ke baad hameX ka cofficient mil jae. Example 4x^2 -10x +4 (4×4=16;10 ko split karege to hame 2,8 milega)4x^2-10x+4 = 4x^2 -8x -2x +4. =4x(x-2)-2(x-2)=(4x-2)(x-2)=0 so x=2/4 and 2 Mujhe bhi pata hai but how to choose two middle terms ,middle vale ko kisme splitt karun. First and last term ko multiply kar ke jo aayega |
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| 40873. |
If a diameter of cicle is increased by40% find by how much percentage its area increases |
| Answer» diameter = d=> radius = d/2new diameter = d + 40% of d = d + 2d/5 = 7d/5=> increased radius = 7d/10original area= 22/7 X d2 / 4 = 11d2 / 14increased area = 22/7 X 49d2/100 = 539d2 / 350increase = (539d2 - 297d2)/ 350 = 242d2/ 350= 121d2/ 165\xa0 | |
| 40874. |
Hii.... Friends Good morning |
| Answer» Gd morning...☺☺ | |
| 40875. |
How to find frequency in the given table in formula of median |
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| 40876. |
Find The co-ordinates to a point on y- axis which is nearest to the point( -2,5). |
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Answer» Thanks to both of यू It will be (0,5) as we know that in coordinates we first keep x and then y, i.e., (x,y).So the point on y-axis will be (0,x) , here we have supposed the point on y-axis as x.As the nearest point is given (-2,5), so the nearest point will be 5 .Thus the answer is (0,5).\xa0 o,5 is the answer |
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| 40877. |
What is hole number |
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Answer» Numbers from 0 to infinity If you are asking for whole numbers then answer is - numbers from 0 to infinity are called whole no.s O.k All natural numbers together with 0. |
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| 40878. |
tan1 tan11 tan21 tan69 tan79 tan 89 = 1 |
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Answer» Tan (90-1)tan (90-11) tan (90-21) tan69 tan79 tan89=1Cot89 cot79 cot69 tan69 tan79 tan89=1I/ tan89 1/tan79 1/ tan69 tan69 tan 79 tan 89 =1(1/tan=cot)1=1 Solve this problem |
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| 40879. |
If sum of the first 14 terms of an ap is 1050 and its first term is 10, find the 20th term |
| Answer» Here,S14 = 1050n = 14,a = 10Sn = n/2 [2a + (n - 1)d]1050 = 14/2 [20 + 13d]1050 = 140 + 91d910 = 91dd = 10Therefore,a20 = 10 + (20 – 1) × 10 = 200The 20th term is 200. | |
| 40880. |
What is the formula of assumed mean method |
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Answer» X- = [sumition of fi into di ]/ sumiton of fi Mean =a+(submition of fidi /submition of fi) |
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| 40881. |
Which term of AP 2 7 12 17 is 127 |
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Answer» 16th term of AP 2,7,12,17 is 127 64th term 16 |
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| 40882. |
Which term of AP 2,7,12,17....... is 127. |
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Answer» It is 26 term 26th term of AP An=a+(n-1)d127=2+(n-1)5127=2+5n-5127=2-5+5n127=-3+5n127+3=5n130=5n26=n 26th term 26 term |
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| 40883. |
9×4+1-1{28×838÷88-82+929}{(29×8+29÷83-82×8282)} |
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| 40884. |
Sum of n terms of an AP is (3nsquare +2n). Find nth term .Also find 20th term |
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| 40885. |
Find the value of sin18 degree and cos18 degree. Help please.... |
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| 40886. |
Some important question for board exam just like samle paper |
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| 40887. |
Show that 5 - 2 root 3 is an irrational number |
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Answer» here why this contradict that root 3 is an irrational no. firstly we have taken 5-2root 3 as rational so why plz tell Suppose 5-2√3 is a rational no.5-2√3= a/b (for any co prime a and b ,b not equal to 0) -2√3=a/b-5 is also rational-2√3=(a-5b)/b is also rational√3 =(a- 5b)/-2b is also rationalThis contradicts the fact that √3 is an irrational no. So 5-2√3 is an irrational no. Yes Yes |
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| 40888. |
Write whether 2root45 + 3root20 / 2root5 on simplification gives an irrational or a rational number. |
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Answer» 6 root 5+6 is rational 6 root 5+6 ....which is irrational |
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| 40889. |
An integer is chosen between 40 and 80 . What is the probability that is not divisible by 7 |
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Answer» 6/40=3/20 6/40=3/20 |
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| 40890. |
If x=p secA +q tan A and y=p tan A +q sec A then prove that x2-y2 =p2-q2 |
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| 40891. |
What is the invention of srinivasa ramanujan |
| Answer» Srinivasa Ramanujan (1887-1920) was an Indian mathematician who made great and original contributions to many mathematical fields, including complex analysis, number theory, infinite series, and continued fractions. He was "discovered" by G. H. Hardy and J. E.Srinivasa Ramanujan, (born December 22, 1887, Erode, India—died April 26, 1920, Kumbakonam), Indian mathematician whose contributions to the theory of numbers include pioneering discoveries of the properties of the partition function. | |
| 40892. |
How i learn trigonometry formulas and table |
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Answer» Just revise this line for formulas....some people have curly black hair to produce beauty Write down in the paper all the trigonometry formula and in free time you read,learn and write down in paper You can learn trigometric formula by practicing ques of trigo. |
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| 40893. |
96;72H.C.F |
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Answer» 24 \tFind the prime factorization of 72\t72 = 2 × 2 × 2 × 3 × 3\tFind the prime factorization of 96\t96 = 2 × 2 × 2 × 2 × 2 × 3\tTo find the H.C.F multiply all the prime factors common to both numbers:\tTherefore, H.C.F = 2 × 2 × 2 × 3\tH.C.F = 24 |
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| 40894. |
Find the sum AP 2 ,7 ,12...........to 10 terms |
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Answer» 245 Sum of 10 terms = 10/2(2*2+9*5)Now , 5*45= 245 that if sum of 10 terms of an a.p |
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| 40895. |
Ncert exercise 9.1 question no.3 class 10 |
| Answer» Question is not solve in this | |
| 40896. |
If two vertices of a equilateral triangle are (3,0);(6,0). Find third vertex. |
| Answer» Let ABC be the equilateral triangle such that,A = (3,0), B=(6,0) and C=(x,y)Distance between:{tex}\\sqrt {( x_{2}-x_{1})^2+(y_{2} -y_{1})^{2} }{/tex}we know that,AB=BC=ACBy distance formula we get,AB=BC=AC=3unitsAC=BC{tex}\\sqrt{(3-x)^2+y^2}=\\sqrt{(6-x)^2+y^2}{/tex}{tex}9+x^2-6 x+y^2=36+x^2-12 x+y^2{/tex}{tex}6 x=27{/tex}{tex}x=27 / 6=9 / 2{/tex}BC = 3 units{tex}\\sqrt{(6-\\frac{27}{6})^2+y^2}=3{/tex}{tex}(\\frac{(36-27)}{6})^2+y^2=9{/tex}{tex}(\\frac{9}{6})^2+y^2=9{/tex}{tex}(\\frac{3}{2})^2+y^2=9{/tex}{tex}\\frac{9}{4}+y^2=9{/tex}{tex}9+4 y^2=36{/tex}{tex}4 y^2=27{/tex}{tex}y^2=\\frac{27}{4}{/tex}{tex}y=\\sqrt{(\\frac{27}{4})}{/tex}{tex}y=3 \\sqrt{\\frac{3}{2}}{/tex}{tex}(x, y)=(9 / 2,3 \\sqrt{\\frac{3}{2}}){/tex}Hence third vertex of equilateral triangle = C =\xa0{tex}(9 / 2,3 \\sqrt{\\frac{3}{2}}){/tex} | |
| 40897. |
Is there any app which can solve maths problems from any chapter??? |
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Answer» Nope. I need for any type of question. I alredy tried photo math. Yes, brainly or photomath Photomath |
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| 40898. |
Lcm of 70,84 |
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Answer» 420 Find the prime factorization of 7070 = 2 × 5 × 7Find the prime factorization of 8484 = 2 × 2 × 3 × 7Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the lcm:LCM = 2 × 2 × 3 × 5 × 7 = 420 420 |
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| 40899. |
Express sec 50°+cot 78° in terms of t ratios of angle between 0° and 45° |
| Answer» so, sec50+ cot78= sec(90-40) + cot (90-12) = cosec40 + tan12 | |
| 40900. |
Triangle ABC is an isosceles triangle right angled at C. Prove that AB square = 2AC square .. |
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Answer» In triangle ABC, AC=CB because it is a isosceles triangle.By pythagoras theoremABsquare=ACsquare +CBsquareABsquare=2ACsquare {Ab=Ac} Please answer me yesterday was my test. |
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