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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 40951. |
If a cos theta +b sin theta =c, then prove that a sin theta -b cos theta =+–√a^2+b^2–c^2 |
| Answer» Given,\xa0acos{tex} \\theta{/tex}\xa0- b sin{tex} \\theta{/tex}\xa0= cSquaring on both sides(a cos{tex} \\theta{/tex}\xa0- b sin{tex} \\theta{/tex})2 = c2By Adding\xa0(a sin{tex} \\theta{/tex}\xa0+ b cos{tex} \\theta{/tex})2\xa0on both sides, we get\xa0(a cos{tex} \\theta{/tex}\xa0- b sin{tex} \\theta{/tex})2 + (a sin{tex} \\theta{/tex}\xa0+ b cos{tex} \\theta{/tex})2\xa0=c2 + (a sin{tex} \\theta{/tex}\xa0+ b cos{tex} \\theta{/tex})2(a2cos2{tex} \\theta{/tex}\xa0+ b2sin2{tex} \\theta{/tex}\xa0- 2ab sin{tex} \\theta{/tex}\xa0cos{tex} \\theta{/tex}) + (a2sin2{tex} \\theta{/tex}\xa0+ b2cos2{tex} \\theta{/tex}\xa0+ 2ab sin{tex} \\theta{/tex}\xa0cos{tex} \\theta{/tex})\xa0=c2 + (a sin{tex} \\theta{/tex}\xa0+ b cos{tex} \\theta{/tex})2a2(cos2{tex} \\theta{/tex}\xa0+ sin2{tex} \\theta{/tex}) + b2(sin2{tex} \\theta{/tex}\xa0+ cos2{tex} \\theta{/tex})=c2 + (a sin{tex} \\theta{/tex}\xa0+ b cos{tex} \\theta{/tex})2a2 + b2\xa0\xa0=\xa0c2 + (a sin{tex} \\theta{/tex}\xa0+ b cos{tex} \\theta{/tex})2{tex} \\Rightarrow{/tex}\xa0(a sin{tex} \\theta{/tex}\xa0+ b cos{tex} \\theta{/tex})2 = a2 + b2 - c2{tex} \\Rightarrow{/tex}\xa0a sin{tex} \\theta{/tex}\xa0+ b cos{tex} \\theta{/tex}\xa0=\xa0{tex} \\pm \\sqrt { a ^ { 2 } + b ^ { 2 } - c ^ { 2 } }{/tex} | |
| 40952. |
Hi anyone\xa0 |
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Answer» I m from uttarakhand May I have ur intro pls Aap kaha se ho Hi Hello |
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| 40953. |
Area of rectangular |
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Answer» L*b Bhai kitna pdhte ho aap! Aapko yeh bhi nahi pta Length × breadth Length×breadth Area of rectangle is length ×breath Lenght × breadth |
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| 40954. |
Find the value of k so that the equation 9 X square + 8 x + 16 is equal to zero has equal roots |
| Answer» Where is k | |
| 40955. |
The sum of two numbers is 16and the sum of there reciprical is1/3 find the numbers |
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Answer» Thanks yogita ji Nice Yogita ji The numbers are 4 and 12 Let one number be x.therefore , another number = 16 - x (because sum of two numbers is 16)also ,1/x + 1/16 - x = 1/3 (Given)\xa0(16 -x +x) / x(16 -x) = 1/3 16*3 = x(16 - x) 48 = 16x - x²or x² - 16x + 48 = 0or x² - 12x - 4x + 48 =0\xa0x(x-12) -4(x-12) =0x-4 = 0 or x-12 =0x=4 or x=12hence one Number is 4 .and another number = 16 - x =16 - 4 = 12 . |
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| 40956. |
I want to know that do u have more model papers of class 10th maths 2018 19 |
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| 40957. |
√x+y=7 and x+√y=11 solve |
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| 40958. |
2+2=5 any one prove that with in one minute |
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Answer» 2+2=52=5-2. .....(1)2=3Then put the value of 2 in equation (1)2+3=5Hence proved ? I serious in study that is a simple question Multiply (2+2)×0=0Mutliply 5×0=00=0Hence proved ?? Yesss...!!I can.. You are not serious in study |
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| 40959. |
Gd morning frnds??????have a nice day????? |
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Answer» Good morning iam feeling sadly Morning guys have a nice day Good morning☀⛅?☀ Good morning have a better day pooja ji Good morning ? |
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| 40960. |
sin(A+B)×sin(A_B)= |
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| 40961. |
sin 105= |
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Answer» I got its answer sin(105) = sin(60+45) = sin60cos45+cos60sin45. =√3÷2 ×1÷√2+1÷2×1÷√2=√3+1÷2√2 answer is √3+1÷2√2 Thanks, but your answer is wrong Sin (105)= (-0.970535283)//// |
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| 40962. |
(secA+tanA) (1-sinA) pls solve this |
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Answer» CosA =cos A/sinA+ sinA/cosA × (1-sinA )=1/sinAcosA × 1- sinA=1- sinA/sinAcosA=1/sinAcosA - sinA/ sinAcosA=cosecAsecA- 1/cosA=cosecAsecA-secA=secA(cosecA - 1) Cos Φ |
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| 40963. |
Give me the 10 board exam time table |
| Answer» 2019 Date SheetDate Day\tSubjectMarch 7, 2019\tThursday MathematicsMarch 13, 2019\tWednesday\tScience Theory Science Without PracticalMarch 19, 2019\tTuesday\tHindi Course A and BMarch 23, 2019\tSaturday\tEnglish Comm., English Lng and LitMarch 27, 2019\tWednesday\tFoundation of IT, Info and Comm TechMarch 29, 2019\tFriday\tSocial Science | |
| 40964. |
Prove root 5 is an irrational no |
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Answer» It is very simple question Let us assume that\xa0√5 is a rational number.we know that the rational numbers are in the form of p/q form where p,q are intezers.so,\xa0√5 = p/q p =\xa0√5qwe know that \'p\' is a rational number. so\xa0√5 q must be rational since it equals to pbut it doesnt occurs with\xa0√5 since its not an intezertherefore, p =/=\xa0√5qthis contradicts the fact that\xa0√5 is an irrational numberhence our assumption is wrong and\xa0√5 is an irrational number. |
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| 40965. |
In probability how may red cards nor queen ? |
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Answer» Where is full question 24 20 |
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| 40966. |
Prove that root 3 is an irrational number. Through three way |
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Answer» 2nd way is by long division method.It shows that root3 has non terminating non repeating decimal expension. Let us assume that √3 is a rational numberThat is, we can find integers a and b (≠ 0) such that √3 = (a/b)Suppose a and b have a common factor other than 1, then we can divide by the common factor, and assume that a and b are co-prime.√3b = a⇒\xa03b2 = a2 (Squaring on both sides) → (1)Therefore, a2 is divisible by 3Hence \x91a\x92 is also divisible by 3.So, we can write a = 3c for some integer c.Equation (1) becomes,3b2 = (3c)2⇒\xa03b2 = 9c2∴ b2 = 3c2This means that b2 is divisible by 3, and so b is also divisible by 3.Therefore, a and b have at least 3 as a common factor.But this contradicts the fact that a and b are co-prime.This contradiction has arisen because of our incorrect assumption that √3 is rational.So, we conclude that √3 is irrational. 1 hi way h prove krne ka It has only one way not 3 |
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| 40967. |
If tan 3A = cos(A - 26\') , 3A |
| Answer» Tan (90 -3A) = tan (A-26 ) Tan sa tan cancel (90 -3A) = (A-26 )90+26 =A +3A 116 =4A A =116 /4A=29 This is your answer | |
| 40968. |
Exercise 13.2 question no.5 |
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| 40969. |
X- |
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Answer» Yes please check it Correct your question Vijat ???? What is this |
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| 40970. |
If cot A=7/8 then find:(1+sin A÷ 1+cos A) |
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Answer» (1+8/10.64)÷(1+7/10.63)[ (10.63+8)÷10.63]÷[(10.63+7)÷10.63]18.63÷17.63ANS=1.05 CotA= cosA/sinACosA=7, sinA=81+sinA÷1+cosA1+8÷1+79÷89/8 9/8 (8+113^0•5)÷(7+113^0•5) |
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| 40971. |
hiii patna friends |
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Answer» Hii Rounak....but I am not from Patna. Hi Rishabh Hii ranya Hii raunak Hello ! But not from patna |
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| 40972. |
Show that 2/5√3 is irrational |
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| 40973. |
Who is ajay???????? |
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Answer» Okayz No! Ghaziabad Rishabh Jain are u from delhi What kind of trouble What you mean Riya answer my question after scrolling some questions i am i trouble Ajay....... |
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| 40974. |
Has anyone ever tried to study calculus( maths topic of class 12 ) |
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Answer» Rehi baat class 10 ..... Uska syllabus toh August me hi finish ho gaya !! Ab toh revision bhi 2 baar ho gaya I have tried ..... Bahut dimag khata hai yeh topic par interesting bhi bahut hai !!!! I realy enjoyed studying it Karni toh 12th bhi hai ab nahi toh 2 years baad hi sahi Yha class 10th ki ho nahi rahi ye 12thbki baat karte hai ? Not study too much. First you prepare your own syllabse after that do this. Little No, I can\' t try this |
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| 40975. |
How to solve ex-14.1 questions |
| Answer» Type the que pls | |
| 40976. |
(c-a)^2-4(a-b)(b-c)=0 |
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| 40977. |
Prove that 15 + 6= 21 |
| Answer» Multiplying both sides by 0 0 + 0= 21 *00=0 | |
| 40978. |
Find the value of k if 2 is the solution of polynomial x square minus 2 k x + 5 |
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Answer» If x = 2x2 - 2kx + 5 = 0\xa0(2)2 - 2k(2) + 5 = 04 - 4k + 5 = 0-4k + 9 = 04k = 9k = 9/4 Put 2 as the value of x (2)^2- 2k (2) +5 ( substitution of x )4-4k+5=09-4k=0-4k=-9K= 9/4 -5/4 |
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| 40979. |
Our date sheet has come.....1st exam is Mathmatics ?? |
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Answer» Solve* Aolve ncert Yes Toh upset kyo ho rahi hai aap Toh iss Mai rone ki kya baat ??? |
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| 40980. |
tano+seco-1/tano-seco+1=1+sino/coso |
| Answer» Replace (seco^2-tano^2) in the place of 1 in tano+seco-1 | |
| 40981. |
Find the nth term when the AP is 3,8,1 3,....... |
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Answer» Yes it is in AP... The nth term will be 5n-2n=a+(n-1)dn=3+(n-1)5n=3+5n-5n=5n-2 Therefore the nth term for the given AP is 5n-2 It is in AP(3,8,13,....) The given series is not in AP. |
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| 40982. |
I wish all my bro and sis HAPPY CHRISTAM I hope all gets good marks in their exams Thanku |
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Answer» S2u N tnks Same to you Miss Yadav Same to u Kiran Same to you and thanks kiran jiiii Thanks and same to you Kiran ji ?? Same to you Same to u sis☺?☺ |
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| 40983. |
all friends study in good |
| Answer» my study good | |
| 40984. |
find three value of a |
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Answer» Complete your question Complete yur question |
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| 40985. |
Pre Board of all subjects |
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Answer» Muskan what is this Please jaldi pado new year se pelly |
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| 40986. |
Cbse board me maths ka tyari kis book se acha hoga batao sir/friend |
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Answer» Oswal sample question paper Ncert book se . For more practoce buy ncert exemplar.After completing both of them , do some sample paper of arihant (i prefer , this one )Or any other RD Sharma |
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| 40987. |
Proove |
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Answer» What proove What What |
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| 40988. |
What is the ratio of the totalsurface area of a solid hemisphere to the square of radius |
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Answer» Is it crct 3pay:1 |
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| 40989. |
Difference between inscribe and circumscribe |
| Answer» Inscribe matlab kisi figure ke ander dusra figure | |
| 40990. |
A plus B whole cube |
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Answer» (a+b)(a square + b square + 2ab) A³ + B³ +3A²B + 3AB² |
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| 40991. |
5^(x+1)+5^(2-x)=5^3+1 |
| Answer» Given,5(x+1) + 5(2\xa0- x) = 53 +1{tex}\\Rightarrow{/tex}\xa05x.5 + 52.5-x = 125 + 1{tex}\\Rightarrow{/tex}\xa05x.5 + {tex}\\frac { 25 } { 5 ^ { x } }{/tex}\xa0= 126Let\xa0{tex}y =5^x{/tex}{tex}\\Rightarrow{/tex}\xa05y +\xa0{tex}\\frac { 25 } { y }{/tex}\xa0= 126{tex}\\Rightarrow5y^2+25=126y{/tex}{tex}\\Rightarrow{/tex}\xa05y2\xa0- 126y + 25 = 0Factorise the equation,{tex}\\Rightarrow{/tex}\xa05y2\xa0- 125y - y + 25 = 0{tex}\\Rightarrow{/tex}\xa05y(y - 25) -1 (y - 25) = 0\xa0{tex}\\Rightarrow{/tex}(y - 25) (5y - 1) = 0{tex}\\Rightarrow{/tex}\xa0y - 25 = 0 or 5y - 1 = 0{tex}\\Rightarrow{/tex}\xa0y = 25 or y = 1/5Now,\xa0{tex}\\Rightarrow{/tex}\xa05x\xa0= 25 or 5x\xa0= 1/5{tex}\\Rightarrow{/tex}\xa05x\xa0= 52 or 5x\xa0= 5-1\xa0{tex}\\Rightarrow{/tex}\xa0x = 2 or x = -1. | |
| 40992. |
No anyone is online ok GOOD NIGHT ALL OF YOU MY DEAR FRIENDS |
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Answer» Hey bro itni padhai mat karo Hey tomarrow is my exam of science i m on. Preparing.Till bio revision is not even started....huh???? |
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| 40993. |
Solve√(3+2√2) |
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| 40994. |
Sin theta by 1 + cos theta + 1 + cos theta by sin theta is equal to 2 cosec theta...prove |
| Answer» Question phle sahi se likho | |
| 40995. |
If sinA-cosA=0, then find cos^4A+sin^4A |
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| 40996. |
MCQ questions for periodic test |
| Answer» Hmne tou de diya | |
| 40997. |
Good morning everyone ??????????????? |
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Answer» Hii Ricky Hey Riya Noooo ?? Good morning bae? |
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| 40998. |
Has anyone buyed cbse sample papers.... Please let me know if anyone has buyed... |
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Answer» Surbhi jain can u please send me those sample papers Sample paper kis k liye Yes l had bought all subjects sample papers |
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| 40999. |
Can u plz ans...i shd lev by 7.20 now |
| Answer» Matlab | |
| 41000. |
P(x) equal to x 3 - 3 x square + 5 x minus 3 x is equal to x square - 2 |
| Answer» Please complete your question........ | |