InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 40801. |
Which of the following is not quadratic equation ? 1).3 X²-5x +9. 2). X³-2x -5=0. |
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Answer» Well done !iiNeha bhat 2 |
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| 40802. |
Matlab Hamadan khan |
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Answer» Fine Kaise he ? |
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| 40803. |
What is sinA =? |
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Answer» tanA×secA 1/cosecA Cos A - 90 Well done prachi ji 1upon cosecA |
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| 40804. |
Last year paper or sample paper solve karne se exam me 90 above aa sakthe hai kya |
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Answer» We are here to study,why are you repeating the question? Rather than trusting on other, use your technique and study. Plzz answer me Why sir question is repeating |
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| 40805. |
(1+tan2A/1+cot2a)=(1-tanA/1-cotA)2=tan2A |
| Answer» The ans is quiet long, but you will get it NCERT maths text book, ch-8,exercise 8.4,Q5,subQ10 | |
| 40806. |
If a+b+c=1 and ab+bc+ca=1/3 find a:b:c |
| Answer» (a+b+c)^2=1^2; = a^2+ b^2+ c^2+ 2ab+ 2bc+ 2ca= 1; = ab + bc + ca = 1- a^2- b^2 -c^2 /2; = 1/3a^2 + b^2 + c^2 = -2/3 + 1 = 1/3ab + bc + ca = a^2 + b^2 + c^2On comparison, a^2 = ab, b^2 = bc, c^2 = acSo a = b, b = c, c = aa : b : c = 1 : 1 : 1 | |
| 40807. |
If the points A(x,y) , B(a,0) and C(0,b) are collinear ,prove that x/a + y/b = 1 |
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Answer» The area of triangle ABC=01/2(x(0-b)+a(b-y) +0(y-0))=00r -bx+ ab-ay +0=0bx +by=abboth side divide by abbx/ab + by/ab = ab/abx/a +y/b=1\xa0\xa0 Subscribe jaroor karna yarr plz Subscribe Royal fun unlimited on YouTube |
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| 40808. |
Miner segment |
| Answer» Subscribe Royal fun unlimited on YouTube | |
| 40809. |
Is anybody online? ?????????? |
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Answer» Hiii ✋✋✋✋ Good morning How sre u my friends???? Hiiiu Yes |
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| 40810. |
Sec0 + tan0 +1 / sec0 + tan0 _1 |
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Answer» Thnx? Rationalise denomenator karo answer aa jayegi .....??? Is ka karna kya hh |
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| 40811. |
If 7 times the 7th term of an AP is equal to 11times the 11th term,then find the 18th term? |
| Answer» Let 1st term of AP be \'a\',Let the common difference be \'d\',So,as per question, 7 x 7th term = 11 x 11th termor, 7 [a+6d] = 11 [a+10d]or, 7a+42d = 11a +110dor, 4a + 68d = 0or, a + 17d = 0 .......(1)Now, 18th term = a+17dor, t18\xa0= 0 (from 1) | |
| 40812. |
Unit test mark 25 subject mathematics |
| Answer» Canel | |
| 40813. |
Prove that n cube - n is divisible by 6 |
| Answer» Let n = 1So 1^3 -1 = 0, which is divisible by 6. Let n = 2So 2^3 - 2 = 6, which is divisible by 6.Let n = 3So 3^3 - 3 = 24, which is divisible by 6.Hence proved | |
| 40814. |
An unbiased die is thrown what is the probability of getting an even number |
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Answer» Lokesh is right 1/2 2 |
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| 40815. |
Hlo guys...... |
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Answer» Would you like to give my answer Hiii any problem hlw. ? Hii...!!! |
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| 40816. |
The diagonals of a trapezium divide each other proportionally. Prove it |
| Answer» Given in the quadrilateral ABCD{tex}\\frac{AO}{BO}=\\frac{CO}{DO}{/tex}or,\xa0{tex}\\frac { A O } { C O } = \\frac { B O } { D O }{/tex} ...(i)Draw\xa0EO {tex}\\parallel{/tex} AB onIn\xa0{tex}\\triangle A B D,{/tex}\xa0EO {tex}\\parallel{/tex} AB (By construction){tex}\\therefore {/tex}\xa0{tex}\\frac { A E } { E D } = \\frac { B O } { D O }{/tex}\xa0(By BPT)...(ii)From (i) and (ii) we get\xa0{tex}\\frac{AO}{CO}=\\frac{AE}{ED}{/tex}Hence by converse of BPT in {tex}\\triangle{/tex}ADC\xa0{tex}EO\\|CD{/tex}But\xa0{tex}EO \\|AB {/tex}So {tex}AB\\|CD {/tex}Therefore ABCD is a trapezium | |
| 40817. |
A quadrilateral is drawn to circumscribe a circle.Prove that AB+CD=AD+BC |
| Answer» We know that the tangent segments from an external point to a circle are equal\xa0{tex}\\therefore{/tex} AP = AS ........(1)BP = BQ .......(2)CR = CQ .......(3)DR = DS .......(4)Adding (1), (2), (3) and (4), we get(AP + BP) + (CR + DR) = (AS + BQ + CQ + DS){tex}\\Rightarrow{/tex}\xa0AB + CD = (AS + DS) + (BQ + CQ){tex}\\Rightarrow{/tex}\xa0AB + CD = AD + BC | |
| 40818. |
What is the distance between the points A(sinø-cosø,0) and B(0,sinø+cosø) ? |
| Answer» | |
| 40819. |
Is 1 a prime number? |
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Answer» The first ten primes are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29.It should be noted that 1 is a non-prime number.Conferring to the definition of prime number, which states that a number should have exactly two factors, but number 1 has one and only one factor. Thus 1 is not considered as a Prime number. No |
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| 40820. |
Find first four term if a is 3x+y and d is x-y |
| Answer» 1.4x2.5x-y3.6x-2y4.7x-3y5.8x-4y6.9x-5y7.10x-6y8.11x-7y | |
| 40821. |
SinA=CosB |
| Answer» SinA=Sin(90-B) =A=90-B=A+B=90. | |
| 40822. |
A average student can study all chapters in 2 months |
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Answer» Yes it is true...actually no body is average.....Jo padhi mai ache hote hai bec.vo hamse thoda zyada padh leta hai thats why vo good students hota hai..Aur average apni capacity se padhte hai.. Yes why not ?sach m |
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| 40823. |
Converse of phythagorus theorm |
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Answer» Mujhe bhi Maths and sci but my problem is trignometry Maths bhut paaand h mujhe |
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| 40824. |
Converes of p.b.t |
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| 40825. |
If tan (3x+30)=1 then find value of x |
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Answer» Keeing Tan (3x+10 ) unchanged in left side change 1 as Tan 45degrees and solve it by cancelling Tan from both sides. x=5 x = 5 |
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| 40826. |
Prove that tangents of a circle from a point are equal without congruence method. |
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Answer» Heuduxhdbxhxhxhxuxudhxhxhxhxuxuxhxvxhdhxhxhxhxgxvshdhdhsbshxhsjsnakisjdhdhxhxhxhxhhxhxhdhdhxhxhdhhdhdhuxhhshhdbbehhshshsushdhxhxbxhxudbshdhdhdbshdushshdhdbdhdhehdhdbdudhdbdhhdhdhdhdudhdydhdbdhdhebsh Let the common point of tangents P and the point meet at the circle are A and B. We use congruency for It can be by side opposite to equal angle are equal |
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| 40827. |
What is common difference of AP in which a21 - A7 = 87? |
| Answer» Common difference =87/14 | |
| 40828. |
What are the 5 important chapters in the NCERT book ? |
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Answer» To pass ch no- ap,probability, circle, construction, statistics Okk tq Triangles, trigonometry, ap, statatics, construction Maths Let me know you In which subject bro |
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| 40829. |
tanA=2/3. Find value of cosecA? |
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Answer» tanA=2/3Opposite side/adjacent side=2/3Opposite side = 2xadjacent side=3xHypotenuse^2=(2x)^2+(3x)^2Hypotenuse^2=4x^2+9x^2Hypotenuse=x√13Cosec A =hypotenuse/opposite sideCosec A=x√13/2xCosecA=√13/2 2/13 |
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| 40830. |
Hemisphere formula |
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Answer» Volume=2/3πr3 TSA : 3(22/7) r2 Curved Surface area--2(22/7) r2 |
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| 40831. |
3cota=4. Find 5sinA+3cosA÷5sinA-3cosA |
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Answer» Here 3cotaa=4Cota=b/p=4/3(4=b,3=p)Now you find h=5SinA=p/h5sina=5•3/5=33cosa=4/5==12/5Now, 5sina+3cosa ➗ 5sina-3cosa(put the value that we find) 3+12/5 ➗ 3-12/527/5 ➗ 3/5=9 answer Ans 9 |
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| 40832. |
Prove that parallelogram circumscribing a circle is rombus. |
| Answer» Given ABCD is a parallelogram in which all the sides touch a given circleTo prove:- ABCD is a rhombusProof:-{tex}\\because{/tex}\xa0ABCD is a parallelogram{tex}\\therefore{/tex}\xa0AB = DC and AD = BCAgain AP, AQ are tangents to the circle from the point A{tex}\\therefore{/tex}\xa0AP = AQSimilarly, BR = BQCR = CSDP = DS{tex}\\therefore{/tex}(AP + DP) + (BR + CR) = AQ + DS + BQ + CS = (AQ + BQ) + (CS + DS){tex}\\Rightarrow{/tex}\xa0AD + BC = AB + DC{tex}\\Rightarrow{/tex}\xa0BC + BC = AB + AB [{tex}\\because{/tex} AB = DC, AD = BC]{tex}\\Rightarrow{/tex}\xa02BC = 2AB{tex}\\Rightarrow{/tex}\xa0BC = ABHence, parallelogram ABCD is a rhombus | |
| 40833. |
What is the formula of finding of area of a regular hexagon inscribed in a circle? |
| Answer» {tex}\\begin{array}{l}Area\\;=\\frac{3\\sqrt3}2\\;r^2\\\\r\\;is\\;radius\\;of\\;circle\\end{array}{/tex} | |
| 40834. |
Sample paper 2018-19 que 4 |
| Answer» a1= 2×1+1=3. a3= 2×3+1= 7. S= n/2 ( a + l) n=3 S3= 3/2 (3 +7) =15 so S3= 15. I hope it\'s clear now if not then check this app in the section of sample paper u find the sample paper and it\'s solution too.? | |
| 40835. |
The length of a tangent from a external point p on a circle with center o is always less then op |
| Answer» | |
| 40836. |
5x+6=0 |
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Answer» x= -6/5 5x+6=0 5x=-6x=-6/5 |
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| 40837. |
What is meaning (143).. |
| Answer» | |
| 40838. |
Use euclids division algorithm to find the HEF of 135& 225 |
| Answer» Iu leaen first theorem and after u will use. Ur answet | |
| 40839. |
ex 151 question |
| Answer» no solution | |
| 40840. |
What is the full form of maths. |
| Answer» M- meri A- aatma T- tumheH- hameshaS-satayegi??? | |
| 40841. |
x=h+a cosy=k+a sin |
| Answer» HaIncomplete or incorrect answer yaar | |
| 40842. |
Find the length of the sides of the rombus whose diagonals mrasure 16 cm and 12 cm respectively |
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Answer» 10cm by pythagorus triplet 10 cm |
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| 40843. |
How to think of two numbers while splitting the middle term in factorisation? |
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Answer» By making the factors of product of coefficient of a and c. Ya its also my doubt........ |
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| 40844. |
My basic are not clear can you help me? |
| Answer» Of which chapter | |
| 40845. |
Show that there are infinitely many positive primes |
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Answer» No Its clear Proofs that there are infinitely many primes. Well over 2000 years ago Euclid proved that there were infinitely many primes.Well over 2000 years ago Euclid proved that there were infinitely many primes. Since then dozens of proofs have been devised and below we present links to several of these. (Note that [Ribenboim95] gives eleven!) My favorite is Kummer\'s variation of Euclid\'s proof. Abhii tkkk jitna bhi questions pucha ek ka bhi answer nii mila Please koi jaldi bta doo |
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| 40846. |
Has cbse uploaded datesheet for 2018-19 class 10th board |
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Answer» Naah❌ ? no No ? I think no! Ya at the last and first weak of dec and jan No |
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| 40847. |
Has maths cbse sample paper launched |
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Answer» Yup bro Yes |
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| 40848. |
Simplify ;sin3Q+cos3Q/sinQ+cosQ |
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Answer» Power Plz tell me this 3 no. Is power or digit |
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| 40849. |
Kiska personal phone hai? |
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Answer» I also have I also have a personal one Ya mera bhi Ya Mera bhi personal ha You\'re lucky....... Mera toh hai yeah |
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| 40850. |
11/5x-4 - (10/4-5x)Find x |
| Answer» | |