If a+b+c=1 and ab+bc+ca=1/3 find a:b:c

1.	If a+b+c=1 and ab+bc+ca=1/3 find a:b:c
Answer» (a+b+c)^2=1^2; = a^2+ b^2+ c^2+ 2ab+ 2bc+ 2ca= 1; = ab + bc + ca = 1- a^2- b^2 -c^2 /2; = 1/3a^2 + b^2 + c^2 = -2/3 + 1 = 1/3ab + bc + ca = a^2 + b^2 + c^2On comparison, a^2 = ab, b^2 = bc, c^2 = acSo a = b, b = c, c = aa : b : c = 1 : 1 : 1

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