InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 40701. |
What is term |
| Answer» A term in mathematics is defined as a number, variable or number-variable combination in an algebraic expression or equation. Terms are separated from each other by a plus, minus or equal sign. | |
| 40702. |
Which is the hardest question till now |
| Answer» Finding the hardest question. | |
| 40703. |
In more than ogive graph commutative frequency here or not.... And how to calculate |
| Answer» | |
| 40704. |
In triangle |
| Answer» What are you try to say, bro???????☡ | |
| 40705. |
Prove that if x and y are odd positive integers, then x2 + y2 is even but not divisible by 4 |
| Answer» Hiii??? | |
| 40706. |
slove sec70 sin20-cos20 cosec70 |
| Answer» Sec70sin20 - cos20cosec70Cosec(90-20)sin20 - cos20sec(90-20)Cosec20sin20 - cos20sec201 - 10 | |
| 40707. |
Find the root of quadratic equation under root of 3x^2+6=9 |
| Answer» 3x^2=9-63x^2=3x^2=3/3x=√1x=1 or x=-1 | |
| 40708. |
tanx=sin95×cos45+sin30 |
| Answer» Please answer me | |
| 40709. |
Prove that 7minus root5 is an irriational no. |
| Answer» Let 7-√5 be rational in the form of a/b Then prove it | |
| 40710. |
2x-2y=10 |
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Answer» Sorry x-y=5☺️ X-y=5 x-y=5 X+ y=5 |
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| 40711. |
Cbse 2018 question paper |
| Answer» Check Question Papers here :\xa0https://mycbseguide.com/cbse-question-papers.html | |
| 40712. |
A pole of 6m casts shadow of2√3 find the anle of sun elevation |
| Answer» angle of sun elevation= 60degree or we can say tan 60 | |
| 40713. |
Class 10 maths paper 2014 |
| Answer» Check Question Papers here :\xa0https://mycbseguide.com/cbse-question-papers.html | |
| 40714. |
Maths ka paper kesa ata he |
| Answer» Not too hard but some questions need fundamental cleared and well practice otherwise all is easy to attain | |
| 40715. |
Tan x=Sin95×cos45+ sin30 |
| Answer» Please answer me | |
| 40716. |
If Sn,the sum of first n terms of an ap is given by Sn=5n²+3n, then find its nth term |
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Answer» An= Sn - Sn-1, S1= 5×1 +3×1 = 5+3=8 S1 is the sum of only first term .....i.e S1=aTherefore when n=1, S1=5(1^2)+3×1=8.....Therefore a=S1=8Again, n=2, ..... S2=5(2^2)+3×2=26....a+a2=S2.. or 8+a2=26...... therefore a2=18Now d=a2-a=18-8=10.....Hence nth term=a+(n-1)d = 8+(n-1)10 = 8+10n-10 = 10n-2 |
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| 40717. |
Some known scientists name\'s |
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Answer» Albert einstein,stephen hawking Isaac Newton Ohm .MendelCharles DarwinLamarck Karl landstiener |
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| 40718. |
If a costheta -bsintheta=c than prove that asintheta-bcostheta=√a2+b2-c2 |
| Answer» | |
| 40719. |
Some general questions from the all 15 chapters |
| Answer» Check notes here :\xa0https://mycbseguide.com/course/cbse-class-10-mathematics/1202/ | |
| 40720. |
Some general questions from all the 15 chapters |
| Answer» Check notes here :\xa0https://mycbseguide.com/course/cbse-class-10-mathematics/1202/ | |
| 40721. |
10£ |
| Answer» 908.67 (indian rupees) | |
| 40722. |
Empirical formula....... |
| Answer» | |
| 40723. |
Tan^A =cos^B-sin^B then prove tan^B=cos^A-sin^B |
| Answer» | |
| 40724. |
I want all the formula of class 10 maths |
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Answer» Pls help tomorrow morning is my paper Flip over the pages and note it down separately. All chapter He said na..... Alll chapters Which chapter formula you need Which formulas you want |
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| 40725. |
For any positive integer n, prove that n^3-n is divisible by 6 |
| Answer» Tanu ke lena | |
| 40726. |
Prove the BAT theorem |
| Answer» I think u want to said about BPT theorem | |
| 40727. |
the sum of three numbers in AP is 3 and their product is -35. find thenumbers |
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Answer» -5,1,7 -2,1,4 -3,1,7 |
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| 40728. |
Exercise 10.3 question number 9 |
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Answer» Oo sry typing mistake it\'s 10.2 Ryt prachi mtlb kuch bhy puchlo Chapter 10 ( circle) hai jisme ex-10 .3 nhi h. |
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| 40729. |
Do we have two types of mathematics paper this tym or next tym? |
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Answer» Ae per as my high level paper for those people who choose maths as there main subject Yes next time because we are prepared for higher level maths that is a plus point our result will have more value that last year result and upcoming year result ? Nxt time because there is no new about that |
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| 40730. |
How to find the collinear points of triangls ( co ordinate geometry) |
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Answer» If the area of triangle is zero then we can prove that three points are collinear We can use the triangle formula in this and then equate it to zero. Cu=403.2g, zn=416g approx.? By using formula √(x²-x¹)²+(y²-y¹)² u have to take like AB,BC,CA and if AB+BC=CA then it will be collinear |
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| 40731. |
Solve 3/5+4/3 |
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Answer» 29/15 29/15 29/15 29/15 |
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| 40732. |
Is the chap perimeter and ar if plane fig. is coming in bord exam |
| Answer» | |
| 40733. |
saction formula |
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Answer» X=M1X2+M2X1/M1+M2 ,Y=M1Y2+M2Y1/M1+M2 thanks X= mx2 +nx1/m+n. Y=my2 +my1/m+n |
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| 40734. |
The diameter of a wheel is 1.54 meters.how far it will travel in 200 Revolution |
| Answer» Circumference of the wheel = 2 × 22/7 ×1.54/2 m = 4.84 mSo for 500 revolution it will travel = 200 × 4.84 m=968 m | |
| 40735. |
What are whole numbers |
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Answer» Whole no. are those no. which starts from zero like 0,1,2,3,4,.... Counting no.s together with 0 are known as whole numbers. All numbers from are called whole numbers |
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| 40736. |
What are natural numbers |
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Answer» Those numbers which are starts from one like 1,2,3,4... 1,2,3,4,5,.............. Don\'t know |
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| 40737. |
Volume of two spheres in the ratio 64:125 find the ratio of there surface areas |
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Answer» Ratio of volumes of two spheres = V1/V2 = 64 /125Volume of sphere = (4/3)πr³V1/V2 = 64/125(4/3)πR1³ / (4/3)πR2³ = 64/125R1³ / R2³ = 64/125(R1/R2)³ = 64/125(R1/R2)= ³√64/125R1/R2 = ⅘Surface area of sphere: 4πr²S1/S2 = 4πR1² / 4πR2²S1/S2= R1² / R2²S1/S2 = (R1/R2)²S1/S2 = (⅘)²S1/S2 = 16/25S1 : S2 = 16 : 25Hence, the ratio of their Surface areas = 16 : 25.\xa0 16:25 16:25 |
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| 40738. |
In fig. ∆odc~∆oba, angle boc= 125 and angle cdo =70. Find angle doc , dco and oab... |
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Answer» Angle doc is of 55,angle dco is also of 55 and angle oab is also of 55 Where is figure?? |
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| 40739. |
A linear equations 2x+4y=10 and 3x+6y=12 |
| Answer» A1/A2=B1/B2 NOT EQUAL TO C1/C2,in this case the pair of linear equation is inconsistent and lines are parrallel so it has no solution | |
| 40740. |
If we prepare only from ncert ...then how much we can score in board exam |
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Answer» Remaining 10% will cover by our school means school will give the marks Now CBSE has issued that if we will prepare from NCERT we can get 90%...seriously You can easily cover 80% above but when you can read each chapter properly Bhagwan bharose h kya 20% And rest 20%??? 80% but only when you prepare very properly. |
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| 40741. |
If p(x,y) lies between the line joining the point A(a,0) and B(0,b) then show that x/a+y/b=1? |
| Answer» If a point (X,Y) lies on a line joining the points A (x1,y1) and B (x2,y2) the equation of the line is given by{tex}\\frac{y-y_{1}}{x-x_{1}}=\\frac{y_{2}-y_{1}}{x_{2}-x_{1}}{/tex}Point P(x,y) lies on the line joining the points A (a,0) and B (0,b). So{tex}\\frac{y-0}{x-a}=\\frac{b-0}{0-a}{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{y}{x-a}=-\\frac{b}{a}{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}a y=-b(x-a){/tex}{tex}\\Rightarrow{/tex}\xa0{tex}a y=-b x+a b{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}a y+b x=a b{/tex}divide both side by ab{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{a y}{a b}+\\frac{b x}{a b}=\\frac{a b}{a b}{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{y}{b}+\\frac{x}{a}{/tex}= 1 (proved) | |
| 40742. |
If x=3 is one root of the quadratic equation x²-2kx-6=0,then find the value of k. |
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Answer» x2 - 2kx - 6 = 0x = 3(3)2 - 2k(3) - 6 = 09 - 6k - 6 = 0-6k + 3 = 0-6k = -3k = 3/6k = 1/2 X=3 is a root of the equation.so putting the value of x in equation we get^_^x^2-2kx-6=3^2-2*3k-6=9-6k-6.=>-6k=6-9=>-6k=-3=>k=-3/-6k = 1/2.so the value of k is1/ 2.......hope my answer helped you. |
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| 40743. |
Area of sector = ? |
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Answer» Thrita/360°÷π×r×r Theta/360°×π×r×r π*¤/360*r² Thita /360×pie×radius×radius |
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| 40744. |
Theside qr of square pqrs is produced to t.prove that pt^2 =rt^2 +2qr×qt |
| Answer» | |
| 40745. |
In figure it ad 6cm, db 9cm |
| Answer» | |
| 40746. |
1+tansquaretheata+1+1/tansqaretheata=1/sinsqaretheata-sinrestofour |
| Answer» 1+tan2A+1+1/tan2A=1/sin2A-sinBhai aage ka question kya hai, smaz nhi aa rha | |
| 40747. |
polinomial |
| Answer» | |
| 40748. |
Proof √5 is an irrational number |
| Answer» let root 5 be rational then it must in the form of p/q [q is not equal to 0][p and q are co-prime] root 5=p/q => root 5 * q = p squaring on both sides => 5*q*q = p*p ------> 1 p*p is divisible by 5 p is divisible by 5 p = 5c [c is a positive integer] [squaring on both sides ] p*p = 25c*c --------- > 2 sub p*p in 1 5*q*q = 25*c*c q*q = 5*c*c => q is divisble by 5 thus q and p have a common factor 5 there is a contradiction as our assumsion p &q are co prime but it has a common factor so √5 is an irrational | |
| 40749. |
A area of equletrel |
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Answer» √3/4(a)square (3/4)a^2 |
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| 40750. |
If angle is 30 degree how to find area minor corresponding sector |
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Answer» area of sector = \xa0\xa0=θ / 360 x area of circle= θ /360 x pi x r2 likh nahi sakta es pa nahi to bauth halka h |
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