If x=3 is one root of the quadratic equation x²-2kx-6=0,then find the

1.	If x=3 is one root of the quadratic equation x²-2kx-6=0,then find the value of k.
Answer» x2 - 2kx - 6 = 0x = 3(3)2 - 2k(3) - 6 = 09 - 6k - 6 = 0-6k + 3 = 0-6k = -3k = 3/6k = 1/2 X=3 is a root of the equation.so putting the value of x in equation we get^_^x^2-2kx-6=3^2-2*3k-6=9-6k-6.=>-6k=6-9=>-6k=-3=>k=-3/-6k = 1/2.so the value of k is1/ 2.......hope my answer helped you.

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