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3cota=4. Find 5sinA+3cosA÷5sinA-3cosA

Answer» Here 3cotaa=4Cota=b/p=4/3(4=b,3=p)Now you find h=5SinA=p/h5sina=5•3/5=33cosa=4/5==12/5Now, 5sina+3cosa ➗ 5sina-3cosa(put the value that we find) 3+12/5 ➗ 3-12/527/5 ➗ 3/5=9 answer
Ans 9


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