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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 41101. |
Which questions are important from statistics chapter |
| Answer» To draw more than type and less than type olive. | |
| 41102. |
What do you mean by arthmatic progression? |
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Answer» AP is a sequence of terms in which the next term is obtained by adding or subtracting a fixed number . Exception-1st term Arithmetic Progression. An arithmetic progression is a sequence of numbers such that the difference of any two successive members is a constant. For example, the sequence 1, 2, 3, 4, ... is an arithmetic progression with common difference 1. |
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| 41103. |
why 1 +sin X = tan X |
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Answer» Ya, plz check ur question Kya , aisa bhi kuch hai......please check yur question ........... Take x = 90degrees1+1=infinity Aisa hota hain kya? |
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| 41104. |
In triangle ABC it is given that DE parllel BC if AD=3 cm DB= 2 cm and DE = 6 cm than BC=? |
| Answer» BC=10 cm | |
| 41105. |
Two tangents are drawn from an external point P to acircle with centre o prove that OA=√3AP |
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Answer» Angle APO =60° Not possible to type diagram based |
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| 41106. |
What is centroid formula ? |
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Answer» x1+ x2+x3 divided by 3 and same as for y Centroid of triangle is equal to x1+x2+x3 upon 3 and y1+y2+y3 upon 3. |
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| 41107. |
If a^2+b^2=c^2Then prove that:(a+b-c)^2=1 |
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| 41108. |
In a quadrilateral |
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| 41109. |
In an Ap the sum of first 10 terms is -150 and sum of its next 10 terms is -550.find the A.P |
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Answer» AP will be 3,-1,-5,-9 Sum of first ten terms = 10/2(a + (10-1)d) = 5(a+9d)=-150 .....1Sum of first twenty terms = 20/2(a + (20-1)d = 10(a + 19d) ....2Sum of first twenty - sum of first 10 = sum of next 10 terms=-550So -150-10a - 19d = -550= -10a -19d= 400Substitute value of a from a in the terms of d and find that A. P. |
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| 41110. |
IF secthita+ tanthita =pThen find the value of cosecthita |
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Answer» Another method:Sec2θ - tan2θ = 1(secθ + tanθ)( secθ - tanθ) = 1p( secθ - tanθ) = 1( secθ - tanθ) = 1/p and, ......-(1)( secθ + tanθ) = p ..... - (2)(1) + (2),secθ = 1/2 (p + 1/p) ,(2) - (1)tanθ = 1/2 (p-1/p)secθ / tanθ = cosecθHence,cosecθ = p +1/p / p-1/p = p2\xa0+1 / p2\xa0-1 |
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| 41111. |
Math new model papers |
| Answer» | |
| 41112. |
What is formula for finding total surface |
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Answer» 2(lb+bh+hl) TSA of cuboid Kiska tsa |
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| 41113. |
2root3divided by5 is irrational |
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Answer» Its irrational No, it\'s irrational Nooooo |
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| 41114. |
2-√3 is an irrational no. Prove that |
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Answer» Please 5 ki jagah 2 rakhna . Baki sabh teekh hai. • Let us assume , to the contrary , that 2 - root 3 is rational.•That is ,we can find coprime a and b (b= not epuals to 0) such that 2- root 3= a/b.• Therefore , 2- a/b= root 3.• Rearranging this equation, we get root 3 = 5-a/b= 5b-a/b.• Since a and b are integers, we get 5-a/b is irrational, and so root 3 is rational.•But this contradicts the fact that root 3 is irrational.• This contradiction has arisen because of our incorrect assumption that 5-root 3 is rational.• So , we concluded that 5-root 3 is irrational.● HENCE PROVED |
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| 41115. |
If R(x,y) is a point on line segment joining the points P(6,-8) and Q(-8,6). Prove that (x+y+2)=0 |
| Answer» since R is the mid point. PR : QR = 1:2m:n=1: 2By section formula R (x,y)=(mx2 +nx1÷m+n,my2+ny1÷m+n) =(1×-8+2×6÷1+2,1×6+2×-8÷1+2) =(-8+12÷3,6-16÷3) =(4÷3,-10÷3)Now,,x=4÷3,y=-10÷3 3x=4 ,3y=-10 =3x+4 eqn.1,=3y+10 eqn.2Comparing eqn.1 and 2 =3x+4=3y+10 =3x-3y+4-10=0 =3x-3y-6=0 =-3(x+y+2)=0 -3 not equal to 0 =x+y+2=0 Hence Proved | |
| 41116. |
Circles all theorem |
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Answer» It will take too much time to type, and I don\'t know how to send pic........ .? Thnx Anushka I mean right Ya, chetna is Wright Consult Google baba ?he can solve your problem?...........actually☺️ bhj toh deti but bhot lamba ho jayega? |
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| 41117. |
Find the value of k for which x²+(k-1)x+k²-16 is exactly divisible by (x-3) but not divisible by x+4 |
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Answer» Hahaha For X=33^2+(k+1)x3+k2-16=0K\u200b\u200b\u200b\u200b\u200b\u200b2+3k-4=0(K+4)(k-1)=0 k=-4,1 |
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| 41118. |
Sin^2+cos^2=1 |
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Answer» Batana kya hai Yes.... ? |
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| 41119. |
Find k so that x^+2x+k is the factor of2x |
| Answer» Aisa bhi ho sakta hai please check your question | |
| 41120. |
What is h in statistics? |
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Answer» Height of the data Sorry it is upper limit minus lower limit Class size Just the sums of mean , median and mode which we studied in class 9 ........ And ogive too Difference of upper limit and lower limit |
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| 41121. |
By elimination x+1/2y=2 (1) 3x-y=1 (2)Solve x and y |
| Answer» X=5÷11 and y=4÷11 | |
| 41122. |
Find the area of shaded region in this figure |
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Answer» Where is the figure? Where is the figure Saloni |
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| 41123. |
Is there anything that maths paper will come in 2 sets one easy and One hard? |
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Answer» Yes, but from next year Na Na Na Na |
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| 41124. |
Mais |
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Answer» What\'s your question............ ❓❓ |
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| 41125. |
Find the hcf of 150 and 225 |
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Answer» By Euclid division lemma a=bq+r225=150×1+75150=75×2+0So 75 is the HCF Oh sorry it\'s 75 85 Hcf if 75 10 75 |
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| 41126. |
Find the hcf of 120 and 250 by EDL |
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Answer» EDL means Euclids Division Lemma What is edl HCF 10 10 Bro you can do this by yourself as it is difficult to display it |
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| 41127. |
What is co-prime |
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Answer» When 2 no. Do not have their common factor other then 1 Whose hcf is 1 |
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| 41128. |
Sin54=sec36 |
| Answer» Sin54=sin(90-36)=cos36=1\\sec36 | |
| 41129. |
if tan tita plus sin tita=mtan tita - sin tita=nshow that m sq-n sq=4root mn |
| Answer» L.h.sMsq - Nsq= (tanA+sinA)sq -(tanA-sinA)sq=4tanAsinA.R.h.s4√mn=4√(tanA+sinA)(tanA-sinA)=4√tanAsq - sinAsq=4√sinAsq/cosAsq - sinAsq=4√(sinAsq-sinAsq×cosAsq)/cosA=4sinA/cosA√1-cosAsq=4tanA√sinAsq=4tanAsinA=L.h.s (proved) | |
| 41130. |
What is realnumbers |
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Answer» Collection of rational and irrational number is called real number A real number is a number that can be found on number line |
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| 41131. |
Find the next term of AP : 3,1,-1,-3.... |
| Answer» a= 3Common difference (d) = 1 - 3 = -25th term = -3 +( -2) = -5OrT5\xa0= a +4d= 3 + 4(-2)= 3 + (-8)= -5 | |
| 41132. |
In AP S5+S7 =167 S10= 235Find the AP nth term |
| Answer» What is S.. Here\'s.. | |
| 41133. |
Is ncert is enough for maths |
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Answer» No ncert is not sufficient. It is more important that you understands concepts. Yes it is sufficient for us. But we have to do NCERT textbook twice or thrice with examples. Okk? If u do ncert fully u got only 80% . But it is true u got 80% fully . Another 20 % u got from your brain memory . No |
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| 41134. |
Book R.d.sharma exercise 3.5 Q no 35 |
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| 41135. |
In A.P. , 16th term is p , then find the sum of first 31 terms. |
| Answer» a16 = Pan = a+(n-1)da + 15d = P --------------(1)Sn = n/2[2a+(n-1)d]S31 = (31/2) [2a+30d]= (31/2) × 2 × (a+15d)= 31 × (a+15d)S31 = 31 P | |
| 41136. |
I have a question that.... I forget the tricks of trigonometry table plz remain me the frist tricks |
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Answer» Learn the value of sin theta and cos theta and divide both to get the value of tan theta ...... And rest are reversed like reverse the value of sin theta to get the value of cosec theta and same cos for sec theta and tan for cot theta .... Hope it helps u ?☺ Firstly right 0 1 2 3 4 and then divide them with 4 and after it make their root |
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| 41137. |
9m,9m+1 |
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Answer» I think you want to know real numbers What to do with this? Plz post the complete question atleast |
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| 41138. |
sin60cos30=tan60 |
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Answer» After all what is the question and surelySin60×cos30=√3/2×1/2=√3/4 not equal to\xa0tan60 or √3 Noo this question is right sin 60 = √3/2cos 30 = √3/2tan 60 = √3Sin60 ×cos 30 = √3/2 × √3/2 = 3/4tan 60 = √3Note : Check question Tan60=√3.....sin 60=√3/2....cos60=1/2...put these values..... √3/2*1/2.........L,.H. S... There remaining only... √3/1. Or u write √3......but we have also rhs =√3....so lhs=rhs |
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| 41139. |
Show that exactly one of the numbers n,n+1,n+4 is divisible by 3 |
| Answer» We applied Euclid Division algorithm on n and 3. a = bq +r on putting a = n and b = 3 n = 3q +r , 0 | |
| 41140. |
Use euclids division algorithm to find the HCF of 135 and 225 |
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Answer» 45 is the HCF Since 225 > 135, we apply the division lemma to 225 and 135 to obtain225 = 135 × 1 + 90Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain135 = 90 × 1 + 45We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain90 = 2 × 45 + 0Since the remainder is zero, the process stops.Since the divisor at this stage is 45,Therefore, the HCF of 135 and 225 is 45. I recommend to see this app carefully . |
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| 41141. |
The sum of a number and its positive sq root is 6÷25 .find the number |
| Answer» Plz answer | |
| 41142. |
What is the probability that a leap year selected at random will contaib 53 thursdays |
| Answer» 2/7 | |
| 41143. |
Find the value of x square-x(x-5)when x =-2 |
| Answer» (-2)(-2)-(-2)(-2-5)= 4-14= -10 | |
| 41144. |
the point P divide the join of 2, 1 and -3, 6 in the ratio 2:3 does p lie on the line x - 5y+ 15=0. |
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Answer» X=0and y=3 Yes |
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| 41145. |
(a-b)x+(a+b)y=2a square-2b square(a+b)(x+y)=4ab |
| Answer» The given system of equations are:(a - b)x + (a + b)y = 2a2 - 2b2So, (a - b)x + (a + b)y - 2a2 - 2b2 = 0\xa0(a - b)x + (a + b)y - 2(a2 - b2) = 0 ........(i)And (a + b)(x + y) = 4abSo, (a +b)x + (a + b)y - 4ab = 0 ..........(ii)The given system of equation is in the form ofa1x + b1y - c1 = 0and a2x + b2y - c2 = 0Compare (i) and (ii) , we geta1 = a - b, b1 = a + b, c1 = -2(a2 + b2)a2 = a + b, b2 = a + b, c2 = -4abBy cross-multiplication method{tex}\\frac{x}{{2(a + b)({a^2} - {b^2} + 2ab)}}{/tex}\xa0{tex} = \\frac{{ - y}}{{2(a - b)({a^2} + {b^2})}}{/tex}\xa0{tex} = \\frac{1}{{ - 2b(a + b)}}{/tex}Now, {tex}\\frac{x}{{2(a + b)({a^2} - {b^2} + 2ab)}} = \\frac{1}{{ - 2b(a + b)}}{/tex}\xa0{tex}{/tex}{tex}⇒ x = \\frac{{2ab - {a^2} + {b^2}}}{b}{/tex}And, {tex}\\frac{{ - y}}{{2(a - b)({a^2} + {b^2})}} = \\frac{1}{{ - 2b(a + b)}} {/tex}\xa0{tex}⇒ y = \\frac{{(a - b)({a^2} - {b^2})}}{{b(a + b)}}{/tex}The solution of the system of equations are\xa0{tex}\\frac{{2ab - {a^2} + {b^2}}}{b}{/tex}\xa0and {tex}\\frac{{(a - b)({a^2} - {b^2})}}{{b(a + b)}}{/tex}\xa0respectively. | |
| 41146. |
Yogita can u answer it .1. Find the median in an arranged series of an even number of in terms. |
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Answer» Mid term is nth term and (n+1)th term\xa0=>nth term is 2n and (n+1)th term is 2(n+1)median = (2n+2(n+1))/2=2n+1 1 Find the value ofCot18/ tan72 |
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| 41147. |
3a2 |
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Answer» Plz complete ur question ... 3×a×a=3a2 |
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| 41148. |
What is composit numbet |
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Answer» A no which is divisible by the numbers other than 1 or itself is composite no. No. Having more than two factors |
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| 41149. |
Formula of frustum of cone |
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Answer» 1/3 πh(r1×r2+r1r2) Volume puch rehe ho frustum ka |
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| 41150. |
A spere of an siutable radius is melted to form cube whate will be sides of cube formed |
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Answer» If the radius of sphere is \'r\' then the sides of cube will be r(4/3π)^1/3 Question thik se likhye, i can\'t understand. |
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