Find the value of k for which x²+(k-1)x+k²-16 is exactly divisible by (x-3) but not divisible by x+4

Find the value of k for which x²+(k-1)x+k²-16 is exactly divisible b

1.	Find the value of k for which x²+(k-1)x+k²-16 is exactly divisible by (x-3) but not divisible by x+4
Answer» Hahaha For X=33^2+(k+1)x3+k2-16=0K\u200b\u200b\u200b\u200b\u200b\u200b2+3k-4=0(K+4)(k-1)=0 k=-4,1