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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 41901. |
Is only ncert question ask in 2019 |
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Answer» The q asked all are related to ncert and in ur course but not actually ncert q U can refer to xamidea as it contain enough questions for practice but first complete the NCERT. Noo please don\'t depend only on ncert questions, cbse can ask any questions in boards but yes its answer will be in ncert yeah |
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| 41902. |
Formula of perimeter of circle |
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Answer» 2 pie r 2πr Its 2πr |
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| 41903. |
3 X square + 55 under root x - 10 |
| Answer» What is the question? | |
| 41904. |
Find the solution of equation x=3 and y=-2 |
| Answer» X=3 and y=3Quadratic equation can be written In the form x2+(x+y)x+xySo, X2+(3+2)x+(3)(2) X2+5x+6 | |
| 41905. |
If the zeroes of the polynomial x3-3x2+x+1 are a-b,a and a+b ,find the values of the a and b |
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Answer» {tex}\\begin{array}{l}let\\;\\alpha,\\beta,\\gamma\\;are\\;zeros\\\\hen\\;\\alpha+\\beta+\\gamma=-\\frac{-3}1=3\\\\or\\;a-b+a+a+b=3\\\\3a=3\\;so\\;\\;a=1\\\\\\alpha\\beta\\gamma=-\\frac11=-1\\\\so\\;a(a-b)(a+b)=-1\\\\a(a^2-b^2)=-1\\\\1(1-b^2)=-1\\\\b^2=2\\\\b=\\pm\\sqrt2,a=1\\end{array}{/tex} a=1 and b= root 2 |
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| 41906. |
Define the zero of a polynomial |
| Answer» The polynomial with all the coefficients as zeros is called a zero polynomial. | |
| 41907. |
Sin theta minus cos theta is equal to 1 upon to find one upon sin theta + cos theta |
| Answer» 3.345 | |
| 41908. |
Prove that the altitudes of a triangle are concurrent |
| Answer» Let ABC be any triangle.Let AD ⊥⊥ BC and BE ⊥⊥ toACLet AD and BE intersect at O (origin say)Join CO and extend it to meet AB at F⇒⇒ AOD and BOE are two altotudes of the triangle.We have to prove that COF is the third altitude.⇒⇒ we have to prove that CF is ⊥⊥ to ABLet OA−→−=a→,OB−→−=b→OA→=a→,OB→=b→ and OC−→−=c→OC→=c→We know that AB−→−=b→−a→,BC−→−=c→−b→andAC−→−=c→−a→AB→=b→−a→,BC→=c→−b→andAC→=c→−a→Since AD ⊥⊥ BC and BE ⊥⊥ AC,a→.(c→−b→)=0andb→.(c→−a→)=0a→.(c→−b→)=0andb→.(c→−a→)=0⇒a→.c→=a→.b→⇒a→.c→=a→.b→..........(i) andb→.c→=b→.a→b→.c→=b→.a→..........(ii)But we know that a→.b→=b→.a→a→.b→=b→.a→⇒(i)=(ii)⇒(i)=(ii)⇒a→.c→=b→.c→⇒a→.c→=b→.c→⇒a→.c→−b→.c→=0⇒a→.c→−b→.c→=0⇒(a→−b→).c→=0⇒(a→−b→).c→=0⇒a→−b→is⊥toc→⇒a→−b→is⊥toc→⇒AB−→−⊥toOC−→−⇒AB→⊥toOC→⇒⇒ FOC is altitude of the side AB⇒⇒ All the three altitudes meet at a common point O. | |
| 41909. |
Ifone zero of the quadratic polynomial 4x2 -8kx -9 is negative of the other then find the value of k |
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Answer» K=0 k=0 |
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| 41910. |
2+4+6+.....+x=650.find the value (s) of x. |
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Answer» X=50 and it is the 25th term x=50 |
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| 41911. |
Find the 10th term of an A. P 23,21,19....5 |
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Answer» An=a+(n-1)×dA10=23+(10-1)-2A10=23+9×-2A10=23-18A10=5 5 5 A=23D=-2An = a+(n-1)dA10=23+(10-1)-2 =23+(9)-2 =23-18 =510 th term is 5 5 |
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| 41912. |
The sum of square of two consecutive multiple of 7 is 637 find the multiple |
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Answer» 14,21 No idea |
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| 41913. |
7x+7 -4=0 |
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Answer» 7x+7-4=07x+3=07x=-3X=-3/7 X=-3/7 -3/7 -3/7 |
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| 41914. |
Pythgarous theorem |
| Answer» Study from any reference | |
| 41915. |
If 7cosecA-3cotA=7 prove that 7cotA-3cosecA =3 |
| Answer» Search this question on google. | |
| 41916. |
Given HCF (396,82)=2 find LCM (396,82)=? |
| Answer» HCF×LCM=product of two number2×LCM=396×822×LCM= 30258LCM=30258/2LCM=15129 | |
| 41917. |
Which term of the A.P: 21,18,15,....is -81? Also,is any term 0? |
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Answer» 8th term is 0 An=a+(n-1)d-81=21+(n-1)-3-81-21=(n-1)-3-102=(n-1)-3-102÷-3=n-134=n-134+1=n35=n |
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| 41918. |
Find the distance of the point P(-6,8) from the origin? |
| Answer» As origin is O(0,0) Then distance of OP is OP^2 = (X2-X1)^2+(Y2-y1)^2= (-6-o) ^2 + (8-O)^2= (-6)^2 + (8)^2= 36 + 64=looOP = √Iooop= lo = Ans | |
| 41919. |
All formule of ch 13 |
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Answer» U should check on this app click on ch13 then open cbse revision notes u will get all the formulas of ch13 Use google |
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| 41920. |
2-cosec^2/cosec^2+cot^2=sin-cos/sin+cos |
| Answer» | |
| 41921. |
If p is a prime number then prove that √p is irrational |
| Answer» Let us assume, to the contrary, that √p\xa0isrational.So, we can find coprime integers a and b(b ≠\xa00)such that √p = a/b=>\xa0√p b = a=> pb2\xa0= a2\xa0….(i) [Squaring both the sides]=> a2\xa0is divisible by p=> a is divisible by pSo, we can write a = pc for some integer c.Therefore, a2\xa0= p2c2\xa0….[Squaring both the sides]=>\xa0pb2\xa0= p2c2\xa0….[From (i)]=> b2\xa0= pc2=> b2\xa0is divisible by p=> b is divisible by p=> p divides both a and b.=> a and b have at least p as a common factor.But this contradicts the fact that a and b are coprime.This contradiction arises because we haveassumed that √p is rational.Therefore,\xa0√p is irrational. | |
| 41922. |
Paper 2019 board |
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Answer» In 7 march ? In march |
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| 41923. |
The coordinates of A, B, C and D are (6,3), (-3,5),(4,-2) and (x, 3x) respectively. If ar( |
| Answer» Send full question | |
| 41924. |
Solve the equation by factorisation method [x/(x+1)] + [(x+1)/x]=34/15 |
| Answer» 2x² + 2x +1 = (34x²+34x)/15 2x²+2x+1=2x²+2x + (4x²+4x)/15 (4x²+4x)/15 =1 4x²+4x-15=0 4x²+10x-6x-15=0 (2x-3)(2x+5)=0 x=3/2,x=-5/2 | |
| 41925. |
Find the number of solution of the following pair of linear equation x+2y-8=02x+4y=16 |
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Answer» Infinitely many solutions because a1/a2=b1/b2=c1/c2. Infinitely many solutions |
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| 41926. |
Find the value of a, if the diatance between the pointsA(-3,-14) and B(a,-5) is 9 units. |
| Answer» -3 | |
| 41927. |
Tell me important questions from this subject |
| Answer» Which ???? | |
| 41928. |
A+B BY 2 +Sin A by2 =cos(A+B) by 2 +cos A by 2 |
| Answer» | |
| 41929. |
Cos9theta = sin theta then find the value of tan6 theta |
| Answer» | |
| 41930. |
Frustum cone formulas |
| Answer» Volume= 1/3πh(R^2+r^2+Rr)....... C.s.A=πl(R+r)......T.s.A=πl(R+r)+πR^2+πr^2 | |
| 41931. |
,name |
| Answer» | |
| 41932. |
Where the formula sn=n(n+1)/2 of chapter arithmetic progression use |
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Answer» L = an Sn=n/2(a+l) Sn=n/2(2a+(n-1)d Ye vo formula nhi hai wrong answer sorry..... To find the sum of n terms |
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| 41933. |
If SecA+TanA=p then find the value of CosecA=? |
| Answer» P | |
| 41934. |
5 6 |
| Answer» Question pura likhao | |
| 41935. |
Solve by splitting middle term 36py^2 - 84y+8=0 |
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Answer» Have yu checked the question again, because p hai to solve nhi hoga.......... I think py=π?????? There is p Plz check your question, i think p nhi hona chahiye........ |
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| 41936. |
1/cosecQ-cotQ -1/SinQ=1/SinQ -1/cosecQ+cotQ |
| Answer» | |
| 41937. |
1+1+1=3-1-1-1-1 |
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Answer» Answer is -1 Rakhi is right What type of Question is this? |
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| 41938. |
1add1add1is equal to (3-1-1-1-1)under vinculum |
| Answer» | |
| 41939. |
Summative Assessment_2_2014_2015 set 1 answersheet |
| Answer» ????? | |
| 41940. |
Full mid point theorem |
| Answer» See ncerr | |
| 41941. |
For some a and b ,HCF of 55 and 210 is 210a + 55b ,then find the value of a and b |
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Answer» Here hcf of 55 and 210 is 5 then by euclid division process _210=55×3+45_a 55=45×1+10_b45=10×4+5_c10=5×2+0_dTaking (c) steps as 5=45-10×45=45-(55-45×1)×45=45×5-55×45=(210-55×3)×5-55×45=(210×5)+{55×(-19)}Thus,a=5and b=-19 HCF of 210 & 55210 = 55× 3 + 45 ….....(i)55 = 45 × 1 +10 ….........(ii)45 = 10 ×4 +5 …...........(iii)10 = 5 ×2 + 0hence HCF of 210 & 55 = 5now from (iii), we get45 = 10 ×4 + 5so 5 = 45 – 10×45 = 45 – (55 – 45)×45 = 45 – 55×4 + 45×45 = 45 ×5 – 55×45 = (210 – 55×3) ×5 – 55×45 = 210×5 – 55×15 – 55×45 = 210×5 – 55×195 = 210 x + 55 ywhere x = 5, y = –19\xa0 |
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| 41942. |
what is phythagoras theorem? how can it proved? plz answer this question |
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Answer» P^2=H^2+B^2or H^2=P^2+B^2 OR B^2=P^2+H^2 Take a triangle ABC right angeled at B . Draw BD perpendicular to AC. 1.prove triangle ABC congruent to triangle BDC.2.By CPCT take BC/AC=BD/BC to get BC^2=BD.AC and mark it as 1.3.similarly prove triangle ABC congruent to triangle BDA to get AB/AD=AC/AB to get AB^2=AD.AC mark it as 2.4. Now add 1 and 2 to get AB^2+BC^2=BD.AC + AD.AC =AC (BD+AD) =AC(AC) =AC^2 Hence proved According to pythagoras theorem ,In a right angled triangle the square of hypotenuse is equal to sum of square of its prependicular and base . i.e. h^2=p^2+b^2 |
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| 41943. |
2cosA-2secA |
| Answer» 2 cosA-2/cosA.(2cos²A -2)/cosA.[2(cos²A-1)]/cosA. [2sin²A]/cosA.2sinA*tanA. | |
| 41944. |
Two cubes have their volumes in the ratio 1:27. Find the ratio of their surface areas |
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Answer» let x and y are sides of cubesx3/y3=1/27 so x/y=1/3ratio of SA = 6x2/6y2=x2/y2=(x/y)^2=(1/3)^2=1/9\xa0 1:3 The ratio of their surface area is 1:9 1:3 1:9 |
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| 41945. |
How weather the given question is hcf or lcm |
| Answer» whenever you are required to find a number that is\xa0divisible\xa0by more than one number, you have to find LCM.whenever you are required to find a number that\xa0completely divides\xa0more than one number, you have to find HCF.Coming to illustrative examples\xa0:LCMThree traffic signals change from Red to Green in 10, 15 & 20 seconds respectively. After how much time will all three signals together become Green ?The three traffic signals will change from Red to Green as follows ( in seconds ):First : 10,20,30,40,50,60,70,80 …..Second : 15,30,45,60,75,90 …Third : 20,40,60,80 …It is clear the three signals will flash Green together after 60 seconds. Now , this 60 is completely\xa0divisible\xa0by 10, 15 & 20 and LCM(10, 15 , 20) is 60, hence the problem was of finding LCM.HCFSquare towels has to be cut from a piece of cloth measuring 16m x 20m. What is the minimum number of towels that can be cut so that there is no wastage ?\xa0The towels are square and length is equal to width. Since there should be no wastage, the edge of the towel should exactly divide the length & breadth of the piece of cloth. The dimension of the towel is that highest number which completely divides 16 & 20. So, here we have a case of HCF.HCF(16,20) = 4So, the dimension of towel is 4m x 4mThe minimum number of towels possible is (16 x 20 )/ (4 x 4) = 20. | |
| 41946. |
What is mean my trignometry |
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Answer» Trigonometry measurements of three side of triangle. Trigonometry means three side measurement....... |
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| 41947. |
What in a polynomial |
| Answer» Polynomial is a data base question which has answer in google | |
| 41948. |
Prove the pythagoras theorem and its converse. |
| Answer» See in NCERT page no.145and146 | |
| 41949. |
What type of decimal expansion will 69/60 represent? Why |
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Answer» TerminatingAs prime factors of denominatao is of the form 2^m×5^n Terminating.1.15 ans. |
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| 41950. |
find a and b if the point A(a-1,3) B(2,2a) C(3,b+7) and D(2,1) are vertices of parllelogram |
| Answer» a=2 and b=-5 | |