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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 41801. |
Find the roots of the equation :root3xsqare_root2x_root3=0 |
| Answer» (2^1/8)*(3^5/16)*(x^5/8) | |
| 41802. |
If diagonal ac and bd of trapezium abcd with |
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Answer» What is full question Complete your question.... |
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| 41803. |
How to prove Pythagoras theorum |
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Answer» Please prove this theorem?? Its given in ncert.... |
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| 41804. |
Value of sin 45° |
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Answer» 1/root2 I/root2 |
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| 41805. |
if the areas of two similar triangles are equal prove that they are congruent |
| Answer» Let ∆ABC ~∆PQR Area of ∆ABC=area of ∆PQR (AB)²=(PQ)², (BC)²=(QR)²,(AC)² = (PR)² (by theorem 6.3). So, AB=PQ, BC=QR,AC =PR So, ∆ABC is congruent to ∆PQR. (By SSS. Criteria ) | |
| 41806. |
If Mth term of A.P is 1/n and Nth term of same A.P is 1/m then what is the value of S(m+n) th term ? |
| Answer» (m+n)square +m+n/2mn aa rha hai answer...... | |
| 41807. |
The 19th term of an A.P.is equal to 3 times its 6th term. If its 9th term is 19, find the A.P. |
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Answer» a19 =a +18d= 3(a+5d) a+18d=3a+15d 3d=2aa=3/2da+8d=193/2d+8d=193d+16d/2=1919d/2=19d=2a=19-8(2) = 3 3,5,7,9......... 3,5,7,9........ |
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| 41808. |
In a family there are three children .What is the probility of getting one boy? |
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Answer» 7/8 2 boys in a family 1/3 |
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| 41809. |
The sum of n,2n, 3n terms of an A.P are S1,S2, S3 . Prove that S3 = 3(S2-S1) |
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Answer» S1= sum of n terms = n|2{2a+(n-1)d}S2= sum of 2n terms = 2n|2{2a+(2n-1)d}S3= sum of 3n terms= 3n|2{2a+(3n-1)d}Lhs=3(S2-S3)=2n|2 {2a+(2n-1)d} - n|2 {2a+(n-1)d}=3n|2{2a+(3n-1)d}Hence S3=3(S2-S1) \tLet the first term of the A.P. be\xa0a\xa0and the common difference be\xa0d.According the question,We have to prove that S3\xa0= 3 ( S2\xa0– S1).R.H.S = 3 (S2\xa0– S1)\xa0\xa0= S3\xa0= L.H.S⇒ S3\xa0= 3 ( S2\xa0– S1)\t\xa0 |
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| 41810. |
Ab2 =ay2+bc2÷4-bc.xy |
| Answer» | |
| 41811. |
Find the greatest six digit number that is exactly divisible by 18 ,24,36? |
| Answer» First find the LCM of 18 , 24 and 3618 = 2×9 =2×3×324=2×12 = 2×2×6 = 2×2×2×336=2×18 =2×2×9 =2×2×3×3LCM=2×2×2×3×3×3= 8×27= 216We need 6 digit greatest number so multiply it my a number216 × 4629 = 999864 | |
| 41812. |
What is the formula of area of minor segment.? |
| Answer» Area of minor segment = area of sector- area of triangle = thirta/360× ^r(2)-r(2)/2×sinthirta | |
| 41813. |
Value of sin120 |
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Answer» Its root 3 by 2 0 |
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| 41814. |
prove that square root of 2 is irrational? |
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| 41815. |
The 17th term of an AP exceeds its 10th term by 7. Find the common difference |
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Answer» a+16d=a + 9d +7a+16d-a - 9d=77d=7d=1 You too Super fast.....??? d=1 1 |
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| 41816. |
If an=3+5n ,find sn |
| Answer» | |
| 41817. |
If x= -1/2, is a solution of the quadratic equation 3xsquare + 2kx -3=0, find the value of k |
| Answer» Put the value of x in the eqn. and then solve it u will get the answer????????????????????????? | |
| 41818. |
Name the sum of Ap formula |
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Answer» N/2{2a+(n-1)d} The nth term of an AP with first term (a) and common difference (d) an = a+(n-1)dan is also called the genral term of the AP. If there are n terms in the AP, then (an ) represents the last term l N/2[2a+ N/2[2a- |
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| 41819. |
A right angle triangle ABC right angled at C prove that tanA=cotB |
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| 41820. |
If the sum of first m term of an AP is 2msquare+3m then what is its second term? |
| Answer» Given:Sm=2m^2+3mTm=Sm-Sm-1Tm=2m^2+3m-2(m-1)^2+3(m-1)Tm=2m^2+3m-2m^2-2+4m+3m-3Tm=10m-5T2=10(2)-5T2=15 | |
| 41821. |
Prove that (sinA + secA) ² +(cosA+cosecA)² =(1+secAcosecA) |
| Answer» Last value after = is also whole square | |
| 41822. |
Please prove thales theoram |
| Answer» It is in the book | |
| 41823. |
In a triangle ABC angel B=45 .Prove that AC^2=AB^2+BC^2-4AREA(triangle ABC). |
| Answer» Construction: Draw AD {tex}\\perp{/tex}\xa0BCProof: In right {tex}\\triangle{/tex}ADC,By using pythagoras theorem, we getAC2 = AD2 + CD2 ...(i)In right {tex}\\triangle{/tex}ADB,By using pythagoras theorem, we getAB2 = AD2 + BD2{tex}\\Rightarrow{/tex}AB2\xa0- BD2 = AD2Putting in (i), we getAC2 = AB2\xa0- BD2 + CD2{tex}\\Rightarrow{/tex}\xa0AC2 = AB2 + CD2\xa0- BD2= AB2+ (CD - BD)(CD + BD) = AB2 + (CD - BD) BC= AB2 + (BC - BD - BD).BC = AB2 + BC2\xa0- 2BC.BD= AB2 + BC2\xa0- 2.AD.BC [ {tex}\\because{/tex}\xa0AD = BD]= AB2 + BC2\xa0- 4ar({tex}\\triangle{/tex}ABC). | |
| 41824. |
Find zeros of polynomials -3;4;7 p(x) |
| Answer» Please complete ur question properly..... | |
| 41825. |
From where paper will come rd or ncert please any can fill my doubt |
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Answer» 80% will be from ncert so practise ncert ? Most of the q are from ncert i.e.about 80%&20%are from outside but it is related to book. Ncert |
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| 41826. |
If the roots of equation (b-c)x*+(c-a)x+(a-b)=0 then prove that 2b=a+c |
| Answer» Given, the\xa0roots of the equation (b - c)x2\xa0+ (c - a)x + (a - b) = 0 are equal.Hence,\xa0{tex}D = 0{/tex}{tex}\\Rightarrow{/tex}{tex}( c - a )^2\xa0-\xa04( b - c )( a - b ) = 0{/tex}{tex}\\Rightarrow{/tex}{tex}c^2 + a^2 + 4b^2 - 2ac - 4ab + 4ac - 4bc\xa0= 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}(c + a - 2b)^2 = 0{/tex}{tex}\\Rightarrow{/tex}{tex}\xa0c + a - 2b = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}2b = a + c{/tex} | |
| 41827. |
Proove that cuberoot 6 is a rational or irrational? |
| Answer» Assume cube root 6 is rational. Then let cube root 6 = a/b ( a & b are co-prime and b not = 0)\xa0Cubing both sides : 6=a^3/b^3\xa0a^3 = 6b^3\xa0a^3 = 2(3b^3)\xa0Therefore, 2 divides a^3 or a^2 * a . By Euclid\'s Lemma if a prime number\xa0divides the product of two integers then it must divide one of the two integers\xa0Since all the terms here are the same we conclude that 2 divides a.\xa0Now there exists an integer k such that a=2k\xa0Substituting 2k in the above equation\xa08k^3 = 6b^3\xa0b^3 = 2{(2k^3) / 3)}\xa0Therefore, 2 divides b^3. Using the same logic as above. 2 divides b.\xa0Hence 2 is common factor of both a & b. But this is a contradiction of the fact that a & b are co-prime. Therefore, the initial assumption is wrong.\xa0cube root 6 is irrational | |
| 41828. |
find the mean and mode for the following |
| Answer» Where is que | |
| 41829. |
1 1 =? |
| Answer» 11 | |
| 41830. |
Find the value of A such that point A lies on line represented by 2x - y = 5. ? |
| Answer» | |
| 41831. |
3.7 multiply 2 divide root 3 |
| Answer» 3,6,9,12,15 | |
| 41832. |
An ox in akolhu is tethered to a rope 3m long How much distance does it cover in 14 round ? |
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Answer» Is 14 diameter D |
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| 41833. |
A quadrilater ABCD is draw to circumscribe a circle |
| Answer» Let ABCD be the quadrilateral circumscribing a circle with centre O.The quadrilateral touches the circle at point P Q R S To prove : AB+ CD= AD+ BCProof: from theorem 10.2 we get the tangents drawn from external point on circle are equalHence, AP=PS .....1BP= BQ.....2CR=CQ........3DR=DS....... 4Adding 1, 2,3 and 4 we getAB+BP+CR+DR=PS+BQ+CQ+D\'SAB+CD=AD+BC Hence proof. | |
| 41834. |
62-36= |
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Answer» 62 - 36 = 26 26 is answer 26 26 |
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| 41835. |
25+25 |
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Answer» 50 The following link for Dr Khan academy in this message and it\'s attachment file and send to me so that you can do that but to kaam nahi hai to khula the best way is Essex junction CO and the second time around to khula the best way is Essex junction CO and the second time around to khula the best way is Essex junction CO and the second time around to khula the best way is Essex junction CO and the second time around to your email find you a call to kaam nahi hai to khula the best of my resume and topic and I am e the eee the first to comment hello my dear I hope to see if I could Answer is 50 59 50 |
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| 41836. |
Write the discriminate of the equation 3x square -7x-2=o |
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Answer» Sorry mistakena=3,b=-7, c=-2discriminate=b2-4ac=(-7)2-4x(3)(-2)=49+25=73 here a=3,b=-7,c=2discriminate={tex}b^2-4ac{/tex}=(-7)(-7)-4x3x2=49-24=25 73 |
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| 41837. |
Find the point on the y axis which is equidistant from the points (-5, -2) and (3,2) |
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Answer» 0,2 (0,-2) |
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| 41838. |
Fi xi kese निकले ge mean formula se |
| Answer» fi will be given and for xi add upper and lower limit and then divide it by 2. | |
| 41839. |
F (x) =x3+11x-6 |
| Answer» F(x) = x3+11x-60=3x+11x-66=14xX = 6/14x = 3/7 | |
| 41840. |
3+33-45+√5 |
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Answer» You can find value of root 5 by yourself. √5-9 |
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| 41841. |
Imperical formula |
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Answer» yes this is correct 3 median-2mean=mode |
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| 41842. |
Number 7×11×13+7 is a prime or not? |
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Answer» It is not a prime number But it is composite no It is a composite number No it is not a prime number. |
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| 41843. |
Ch 14 |
| Answer» Which question ?????? | |
| 41844. |
If the pth term of an A.P be q and qth term be p, prove that the (p+q)th term is zero |
| Answer» | |
| 41845. |
In a family three children what is the probability of getting at least one boy |
| Answer» Let e be probability of getting at least one boy. Favourable outcomes=3 Total outcomes=3 P(e)=3/3=1 | |
| 41846. |
Board question jyada konse paper se aata hai? Arihant ya osswal? |
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Answer» Oswal Question khin se bhi aye, just make everything clear, specially fundamental...... Questions toh kahi se bhi aa skta hain. Thank u so much...and R.D.Sharma ka v questions aata hai kya? Maths ka? Arihant.....according to new edition |
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| 41847. |
Cos 6square theta - sin 6square theta= what... Evaluate |
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| 41848. |
How can i study trignometry for main exam |
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Answer» solve the complete ncert book with examples with peacful mind and practise it by maximum time it is possible for u..................as the facts says that practise makes a man perfect. Just go through simpler questions first then try NCERT questions Study of trigonometry is easy with regular practice of ncert and ncert exemplar book question is sufficient. Solve many numericals |
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| 41849. |
If x=a sec theta + b tan theta and y = a tan theta + b sec theta, prove that x^2-y^2=a^2-b^2 |
| Answer» At first u squaring both sides of both equation then subtract it u will get your answer | |
| 41850. |
Sin theta into cos theta upon cos theta into sin theta |
| Answer» = 1. | |