InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 41751. |
The sum of first n terms of an AP is given by Sn= 2nsq +3n . Find the 16th term of the AP. |
| Answer» 2n^2+3n S1=2(1)2+3(1)=5S2=2(2)^2+3(2)=14S3=2(3)^2+3(3)=27a1=s1a2=s2-s1 14-5=9a3=s3-s2 27-14=13AP:5,9,13 a=5 ,d=4a16=a+15d 5+16(4)= 69(ANS) | |
| 41752. |
Find the coordinates of the point in y axis which is nearest to the point -2,5 |
| Answer» (0,5) | |
| 41753. |
prove that Sum=n/2(2a+(n-1)d) |
| Answer» Write .. 1st from (a to n term).2nd from (n to a term) And then add both u will get requird answer | |
| 41754. |
WHich is the hardest maths topic? |
|
Answer» "Trigonomertry" i am new here Rishi r u girl or boy?? Ni yrr me fb ni chalati Maths me hard aur bkwas chapter triangles vala lagta he For me coordinate geometry Mariya you was on fb Mazak tha yrr?? The hard chapter of math\'s is trigonometry Triangle Mariya No Puri math??? |
|
| 41755. |
Find the 11 term from the last term of the ap 27,23,19,-------65 |
|
Answer» -25 Common sense is not common in all. Difference is negative , of course it is -65. If it is -65 then answer is -25 It is 65 or -65 |
|
| 41756. |
If cos A = 4/5 then cot A |
|
Answer» 84 ka 4/3 |
|
| 41757. |
Pair of one equation in two variables? What it\'s means.! |
|
Answer» One pair variable meanings in a means is one pair equation in other equation prove the one pair in two variable Linear equations. |
|
| 41758. |
3.1 |
| Answer» | |
| 41759. |
A:p 12 24 36. 120 |
| Answer» 133 | |
| 41760. |
x+y=5 and 2x-3y=4 |
| Answer» | |
| 41761. |
Can you provide me the marking scheme for class 10 mathematics |
|
Answer» chaper1 - 6markschapter2.3.4.5- 20markschapter7- 6markschapter11.10.6- 15markschapter8.9- 12markschapter12.13- 10markschapter14.15- 11marks Available in this app. No |
|
| 41762. |
Prove that, (1+tan theta)(sin theta-cos theta)=(sec theta/cosec² theta)-(cosec theta/sec²theta) |
| Answer» LHS = (1 + tan{tex}\\theta{/tex}\xa0+ cot{tex}\\theta{/tex})(sin{tex}\\theta{/tex}\xa0- cos{tex}\\theta{/tex}){tex}= \\left( 1 + \\frac { \\sin \\theta } { \\cos \\theta } + \\frac { \\cos \\theta } { \\sin \\theta } \\right) ( \\sin \\theta - \\cos \\theta ){/tex}{tex}= \\left( \\frac { \\cos \\theta \\sin \\theta + \\sin ^ { 2 } \\theta + \\cos ^ { 2 } \\theta } { \\cos \\theta \\sin \\theta } \\right) ( \\sin \\theta - \\cos \\theta ){/tex}{tex}= \\frac { ( \\cos \\theta \\sin \\theta + 1 ) } { \\cos \\theta \\sin \\theta } ( \\sin \\theta - \\cos \\theta ){/tex}RHS =\xa0{tex}\\left( \\frac { \\sec \\theta } { \\ cosec ^ { 2 } \\theta } - \\frac { \\cos e c \\theta } { \\sec ^ { 2 } \\theta } \\right) = \\left( \\frac { \\frac { 1 } { \\cos \\theta } } { \\frac { 1 } { \\sin ^ { 2 } \\theta } } - \\frac { \\frac { 1 } { \\sin \\theta } } { \\frac { 1 } { \\cos ^ { 2 } \\theta } } \\right){/tex}{tex}= \\left( \\frac { \\sin ^ { 2 } \\theta } { \\cos \\theta } - \\frac { \\cos ^ { 2 } \\theta } { \\sin \\theta } \\right) = \\frac { \\sin ^ { 3 } \\theta - \\cos ^ { 3 } \\theta } { \\cos \\theta \\sin \\theta }{/tex}{tex}= \\frac { ( \\sin \\theta - \\cos \\theta ) \\left( \\sin ^ { 2 } \\theta + \\cos ^ { 2 } \\theta + \\cos \\theta \\sin \\theta \\right) } { \\cos \\theta \\sin \\theta }{/tex}\xa0[{tex}\\because{/tex} a3\xa0- b3\xa0= (a - b) (a2\xa0+ ab + b2) ]{tex}= \\frac { ( \\sin \\theta - \\cos \\theta ) ( 1 + \\cos \\theta \\sin \\theta ) } { \\cos \\theta \\sin \\theta }{/tex}{tex}\\therefore{/tex}\xa0LHS = RHS | |
| 41763. |
√8√8√8........... |
| Answer» It is in ap.... | |
| 41764. |
6-5=2 Prove it ??? |
|
Answer» Is it ryt qstn Kese prove hoga? What? |
|
| 41765. |
If sin a= cos a then find the value of 2tan a +cos^2 a |
| Answer» | |
| 41766. |
What is the value of (a+b)³ |
|
Answer» (a+b)whole cube =a cube +3a square b+3ab square + b cube...... (a + b)3= a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)(a – b)3 = a3 – 3a2b + 3ab2 – b3 (a+b)3=a3+b3+3ab(a+b) |
|
| 41767. |
Find the coordinates of point on y-axis which is nearest to the point (-2,5). |
| Answer» 5.-2 | |
| 41768. |
Find the value of cos 30 geometrically |
| Answer» Take an equi. ? And draw an altitude on 1 side you can find the length of side. and altitude of the ? and then find cos 30 from where u had drawn the altitude. | |
| 41769. |
Exercise 6.3 question no. 4 |
|
Answer» QR / QS = QT / PR ( given)Qt / Qr = Pr / Ps (1)<1 = <2 ( given)Pr = Pq (2). ( side opp. To equal < are equal)From 1 and 2 Qt / Qr= Pq / Qs= Pq / Qt = Qs/ Qr (3) In ∆ PQS and TQR we getPq /Qt = Qs / Qr < PQS = In ∆ RPQ and RTS< RPQ = QR/QS=Qt/PR(angle1=angle2 so in triangle PQR PQ=PR becoz sides opposite to equal angles are equal ) So QR/QS=QT/QP So by the converse of bpt theoram PS is parallel to TR Then in triangle PQS and tria.TQR Angle 1 =angle 1( common)Angle QPS=angle QTR ( corresponding angle )SO BY AA~ CRITERIA Triangle PQS~tri.TQR |
|
| 41770. |
From an external point P tangents PA and PB are drawn to a circle with centre O. If |
|
Answer» Complete yur ques first Some one tell me |
|
| 41771. |
Plz sm1 explain #9th Q. Of ex-13.3..(NCERT) plz explain the question... And it\'s solution too. |
|
Answer» Suppose the tank is filled in x hours since water is flowing at the rate of 3km/hr therefore,Lenght of the water column=3xkm=3000x mClearly the water column forms a cylinder of radius r=20/2cm=10cm =1/10m and h=height(length)=3000xmHence vol. Of the water that flows in tank in x hrsπr^2h=( 22/7*1/10*1/10*3000x)cubic mAlso volume of tank=(π*5*5*2). [R=5m and h=2m]Equate the volumes and then you will get your answer that is 1hr 40 min Internal diameter of pipe =20cmInternal radiusof pipe =10cm Water flows at the rate of 3km/h=3000×100cmVolume of water that flow through the pipe in x hours=3000×100×xDimensions of cylindrical tank radius=5×100cm height=2×100cmVolume of pipe=volume of cylindrical tankπ×10×10×3000×100×x=π×500×200X = 5/3 hours = 100 minutes= 1hr 40 minute Diameter of the pipe = 20 cmRadius of the pipe= 10 cmLength of water column = 3km = 3x 1000x 100cmVol. Of water flown in 1hour = π x 100 x 300000 cm3 Tank to be filled=π x 500 x 500 x 200Time required to fill the tank of farmer =Vol. Of tank / Vol. Of water flown= π × 500 × 500 × 200/ π ×100 × 300000 hours5/3 hours = 1/2/3 hours1 hour 40 minutes = 60 + 40 minutes = 100 Please wait a moment Ansr guys.. Be quick.. I need to know it as soon as possible |
|
| 41772. |
Is 63a term of ap -1,4,9,14......8 |
|
Answer» No it is not a term of A.P No 63 is not the term of following Ap No |
|
| 41773. |
The length of a chain used as a boundary of a semicircle park is108cm find the area of the park |
|
Answer» Find out the radius with the help of circumference and eventually use it to find the area . 2551.5 cm square |
|
| 41774. |
Determine the Ap whose third term is 16 and the 7th term exceeds the 5th term by12 |
| Answer» a3=16a+2d=16 eq.1a7 =a5+12a+6d=a+4d+122d=12d=6Put the value of d in eq.1a+2d=16a+2(6)=16a=16-12a=4The A.P. form 4,10,16,,......... | |
| 41775. |
If triangle ABC similar triangle RQP ,Angle A =80°,& angle B=60°,what is the value of angle P |
| Answer» Value of angle P is 40 degree..... | |
| 41776. |
Find Median of -:CLASS FREQUENCY5-10 210-15 1215-20 220-25 425-30 330-35 435-40 3 |
| Answer» | |
| 41777. |
5 years old previous paper |
| Answer» Mycbse guide have previous year question paper | |
| 41778. |
Prove that 3+2 √5 is irrational |
| Answer» Let us assume 3+√5 is a rational numberBut all the rational no. are in the form p/q So we can also write 3+√5 in p/q form and when we divide p/q with any of their common factor we get a/b which are coprime 3+√5 = a/b √5 = a/b-3 √5= a-3b/b But we know a-3b/b is a rational noBut √5 is an irrational number=> Our assumption is wrong. => 3+√5 is an irrational no | |
| 41779. |
2x2= |
|
Answer» 4 4?? 4?? 4? |
|
| 41780. |
If sec theta + tan theta =p. Find the value of sec theta and sin theta |
| Answer» Sin theta= p square - 1/ p square +1...... sec thita= p square +1/2p .......... | |
| 41781. |
If cosecA+cotA=p then prove that cosA=p^2-1/p^2+1 |
| Answer» Given, cosec θ + cot θ = p...(i)We know that, {tex}cosec^2\\theta-cot^2\\theta=1{/tex}{tex}\\Rightarrow (cosec\\theta+cot\\theta)(cosec\\theta-cot\\theta)=1{/tex}{tex}\\Rightarrow p(cosec\\theta-cot\\theta)=1{/tex}{tex}\\Rightarrow cosec\\theta-cot\\theta=\\frac 1p{/tex}\xa0....(ii)Adding i and ii, we get{tex}2cosec\\theta=p+ \\frac 1p{/tex}{tex}cosec\\theta=\\frac{p^2+1}{2p}{/tex}{tex}\\Rightarrow sin\\theta= \\frac{1}{cosec\\theta}=\\frac{2p}{p^2+1}{/tex}We know that,{tex}cos\\theta=\\sqrt{1-sin^2\\theta}=\\sqrt{1- \\frac{4p^2}{(p^2+1)^2}}=\\sqrt{\\frac{p^4+1-2p^2}{(p^2+1)^2}}{/tex}{tex}cos\\theta=\\sqrt{\\frac{(p^2-1)^2}{(p^2+1)^2}}=\\frac{p^2-1}{p^2+1} {/tex} | |
| 41782. |
Tan 26 Cot64 |
| Answer» tan 26° /cot 64° = tan26° / cot(90°- 26°) = tan26° /tan26° = 1 | |
| 41783. |
Prove that rhombus is not a cyclic quadrilateral |
| Answer» In rhombus ABCD{tex}\\angle A=\\angle C{/tex}And angle A and C both are not equal to 90°So sum of opposite angles is not equal to 180°So ABCD is not cyclic. | |
| 41784. |
In which the following rational number can be expressed as a terminating decimal? |
| Answer» If one number is perfect square and if it is fraction than it should completely divide each other | |
| 41785. |
Last 3year\'s question paper of maths and science of 10class |
| Answer» U will get it in google ?? | |
| 41786. |
Value of cos A= |
|
Answer» √(1- sin^2) Sin(90-A) It is 1/secA Ashish tell the answer |
|
| 41787. |
Is it necessary to take Id card in cbse board exams? |
|
Answer» Yes Yea it is important to have id card But I don\'t have my ID card Ya..... |
|
| 41788. |
(b+C)^2/bc + (C+A)^2/ca +(a+b)^2/ab=3 |
| Answer» Done but answer kaise likhu | |
| 41789. |
A=10,d=10 |
|
Answer» 10,20,30,40........ A=10, D=10 10,20,30,40...... |
|
| 41790. |
Which is the most important and difficult chapter in Maths. Plz reply |
|
Answer» Area related to circle Arithmetic progressions Trigonometry ex 8.4 last 10 questions No, trigonometry and triangles Surface area and volume |
|
| 41791. |
√3 is irrasanal |
|
Answer» Yes it is the irrational Yes it is irrational? |
|
| 41792. |
Square root formoola |
| Answer» | |
| 41793. |
Solve the quadratic equation by factorization method :x+1/x=626/25 |
| Answer» X=25/601 | |
| 41794. |
Solve 23x_29y=98and29 x_23y=110 |
| Answer» 23x\xa0−\xa029y\xa0=\xa098 ....(1)29x\xa0−\xa023y\xa0=\xa0110 ...(2)Adding\xa0(1)\xa0and\xa0(2),\xa0we\xa0get52x\xa0−\xa052y\xa0=\xa020852 (x-y) =208⇒x\xa0−\xa0y\xa0=\xa04 .....(3)Subtracting\xa0(2)\xa0from\xa0(1),\xa0we\xa0get−6x\xa0−\xa06y\xa0=\xa0−12⇒x\xa0+\xa0y\xa0=\xa02 ....(4)adding\xa0(3)\xa0and\xa0(4),\xa0we\xa0get2x\xa0=\xa06⇒x\xa0=\xa03Now,\xa0from\xa0(4),\xa0we\xa0gety\xa0=\xa0−1Hence, x=3 and y= -1. | |
| 41795. |
In triangle ABC it is given that DE || BC . If AD=3 & DB=2 & DE=6 then find BC |
|
Answer» By aaa criteria...triamgle ade~abcAd/ab=de/bc...2/5=6/bc...hence bc=15cm... Given: ABC is a triangle , DE parallel BC and AD= 3 cm, DB=2 cm and DE=6 cm\xa0To find: AEsol: Since DE parallel BC\xa0 angle ADE= angle ABC (corresponding angles)and angle AED = angle ACB ( " )Triangle ADE ≈ triangle ABC ( by AA similarity)therefore , AD/AB=DE/BC=AE/AC (1)From (1)AD/AB=AE/AC2/5=x/182×18=5x36=5xx=36/5x=7.5cm∵ AE = 7.5 cm 9 |
|
| 41796. |
If x=a sec A+ b tan A and y=a tan A+ b sec A, prove that x^2-y^2=a^2-b^2 |
| Answer» X= a secA+b tanAY= a tanA+b secAOn squaring we get the following;X2+Y2= a2 sec2A+b2 tan2A - (a2 tan2A+b2 sec2A)X2+Y2=a2 sec2A+b2 tan2A - a2- tan2A-b2-sec2AX2+Y2= a2-b2 hence proved. | |
| 41797. |
Find the root of the equation 1/x-3 + 1/x-5=1 ,x is not equal to 3/2 ,5 |
| Answer» 1/x-3 +1/x-5=1(x-5)+(x-3)/(x-3)(x-5)=1X-5+x-3=xroot-8x+15Xroot-10x+23(by b root-4ac,-b+-root D)5+root2,5-root2answers | |
| 41798. |
In equilateral triangle ABC ,D is a point on side BC such that BD = 1/3 BC .prove that 9AD^2 =7AB^2. |
| Answer» It is a book sum.search ncert solutions and find answers. | |
| 41799. |
2^2x^2-7x+5=1 evaluate |
| Answer» x = -4 | |
| 41800. |
यदि दो समरूप Tribhuj ke sangat madhiko ka anupat 5:7 ho to inki bhujao ka anupat gat karo |
|
Answer» Ansawr 5:7 ही होगा। क्योंकि sides और median का अनुपात(ratio) similar triangles में same होता है। i can\'t know your question A |
|