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Plz sm1 explain #9th Q. Of ex-13.3..(NCERT) plz explain the question... And it\'s solution too. |
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Answer» Suppose the tank is filled in x hours since water is flowing at the rate of 3km/hr therefore,Lenght of the water column=3xkm=3000x mClearly the water column forms a cylinder of radius r=20/2cm=10cm =1/10m and h=height(length)=3000xmHence vol. Of the water that flows in tank in x hrsπr^2h=( 22/7*1/10*1/10*3000x)cubic mAlso volume of tank=(π*5*5*2). [R=5m and h=2m]Equate the volumes and then you will get your answer that is 1hr 40 min Internal diameter of pipe =20cmInternal radiusof pipe =10cm Water flows at the rate of 3km/h=3000×100cmVolume of water that flow through the pipe in x hours=3000×100×xDimensions of cylindrical tank radius=5×100cm height=2×100cmVolume of pipe=volume of cylindrical tankπ×10×10×3000×100×x=π×500×200X = 5/3 hours = 100 minutes= 1hr 40 minute Diameter of the pipe = 20 cmRadius of the pipe= 10 cmLength of water column = 3km = 3x 1000x 100cmVol. Of water flown in 1hour = π x 100 x 300000 cm3 Tank to be filled=π x 500 x 500 x 200Time required to fill the tank of farmer =Vol. Of tank / Vol. Of water flown= π × 500 × 500 × 200/ π ×100 × 300000 hours5/3 hours = 1/2/3 hours1 hour 40 minutes = 60 + 40 minutes = 100 Please wait a moment Ansr guys.. Be quick.. I need to know it as soon as possible |
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