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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 41651. |
Is 4x2-8√x +3=0 a quadratic equation |
| Answer» No as the quadatric equation is in the form of ax^2+ bx + c =0 | |
| 41652. |
If sectheta +costheta=cosectheta then find value of p |
| Answer» | |
| 41653. |
X\'2+x+4=8 |
| Answer» (-1plus-minus root 17 )/2 | |
| 41654. |
1/2a+b+2x=1/2a+1/b+1/2x |
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Answer» No Is your ques. is 1/(2a+b+x) in lhs X=-a and -b/2 |
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| 41655. |
2cosQ+2√2=3secQ find Q solve step by step and give ans |
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Answer» ( r MEANS ROOTS..... SO DON\'T GET CONFUSED )2cosQ +2r2 = 3secQ2cosQ + 2r2 = 3/ cosQ2cos^2Q + 2r2cosQ = 3(Multiplying the eq. by r2)2r2cos^2Q + 4cosQ -3r2 = 02r2cos^2Q - 2cosQ + 6cosQ - 3r2 = 0( by factorization we get )cosQ = 1/r2 and cosQ = -3r2/2 (u can find it out and get same result)Since the value of cosQ can\'t be negative Therefore the actual value of cosQ is 1/r2And hence Q is 45° Wait |
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| 41656. |
If a and b are relatively prime,what is their LCM? |
| Answer» LCM=a×b | |
| 41657. |
Pro that tan A+tanB/cotA+cotB=tanA tanB |
| Answer» Tan A+Tan B/1/Tan A+1/Tan B=Tan A+Tan B/ Tan A+Tan B/Tan A*Tan B=Tan A*TanB (as tanA+tanB and tanA + tanB gets cancelled) hence proved. | |
| 41658. |
Prove root 7 is irrational |
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Answer» Let root 7 be a rational numberThen,=√7 = a/b Now by squaring both side= (√7)² = (a/b)²= 7 = a²/b²= 7b² = a². (A²= 7b² from above)Here 7 divides a²Therefore 7 also divides aNow let a= 7c where c is some integerBy squaring both sides= A² = 49c²= 7b² = 49c²= B² = 7c²Here 7 divides b²Therefore 7 also divides bHere a and b both have common factor 7So our contradiction was wrong ,Therefore √7 is irrational First assume it that it is a rational number then your contradiction will be wrong and then you will prove it that it is irrrational and you can see in your book |
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| 41659. |
9sec2A-9tan2A |
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Answer» = 9 (sec²a - tan²a)= 9(1/cos²a - sin²a/cos²a)= 9 ( 1- sin²a / cos²a)= 9 ( cos²a/ cos²a) = 9 ×1= 9 9 |
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| 41660. |
If Sn denotes the sum of first n terms of an AP, prove that S30=3(S20- S10) |
| Answer» S30 = 30/2 ( a+a+29d ) S20 = 20/2 ( a+a+19d )S10 = 10/2 ( a+a+9d )S30=3( S20 - S10 )15 ( 2a + 29d ) = 3[10(2a + 19d) - 5(2a + 9d)] 30a + 435d = 3[ 20a + 190d - 10a - 45d ] = 3[ 10a + 145d ] = 30a +435d | |
| 41661. |
For what value k ,(-4) is a zero of the polynomial x²-x-(2k+2) |
| Answer» Put -4 in the place x you get your answer | |
| 41662. |
In a rhombus of side 10 cm if one of the diagonal is 15 cm find the other diagonal |
| Answer» | |
| 41663. |
Ex 6.4 q-7 |
| Answer» Seee on this app ncert solutions u will get the answer | |
| 41664. |
2x+5x=0 |
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Answer» 2x + 5 x = 07x = 0x = 0/7x = 0 0 |
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| 41665. |
Prove pythagorous theorum |
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Answer» Its given in NCERT please read it It is in the book. |
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| 41666. |
(CosecA-sinA) (secA-cosA)=1/tanA+cotA |
| Answer» Cosec-sin×sec-cos =lhs cosec-1/cosec×sec-l/sec=cosec2 -1/cosec ×sec2-1/sec=cot2/cosec×tan2/sec=cos2/sin2/1/sin×sin/cos2/1/cos=sin×cos RHS=1/sin/cos+cos/sin=sin2+cos2/sin×cos=sin×cos LHS=RHS 2is square | |
| 41667. |
(A+b)hole cube formula |
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Answer» ( a - b)(a^2 + b^2 + ab) ,,,,,,,,or,,, ,,,,,, a^3 + b^3 +3a^2b + 3ab^2,,,,,, (^= power) (a+b)3= a3+ b3+ 3a2b+ 3ab2 |
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| 41668. |
In 5 unit i cant be understand anu thing how it can possible that |
| Answer» Whats ur ques????? Plz write it clearly | |
| 41669. |
polynomial x4+7x3+7x2+px+q is exactly divisible by x2+7x+12, then find the value of p and q |
| Answer» Factors of x2 + 7x + 12 :x2 + 7x + 12 = 0{tex}\\Rightarrow{/tex}\xa0x2 + 4x + 3x + 12 = 0{tex}\u200b\u200b\\Rightarrow{/tex}\xa0x(x + 4) + 3(x + 4) = 0{tex}\u200b\u200b\\Rightarrow{/tex}(x + 4) (x + 3) = 0{tex}\u200b\u200b\\Rightarrow{/tex}\xa0x = - 4, -3 ...(i)Since p(x) = x4 + 7x3 + 7x2 + px + qIf p(x) is exactly divisible by x2+ 7x + 12, then x = - 4 and x = - 3 are its zeroes. So putting x = - 4 and x = - 3.p(- 4) = (- 4)4 + 7(- 4)3 + 7(- 4)2 + p(- 4) + qbut p(- 4) = 0{tex}\\therefore{/tex}\xa00 = 256 - 448 + 112 - 4p + q0 = - 4p + q - 80{tex}\\Rightarrow{/tex}4p - q = - 80 ...(i)and p(-3) = (-3)4 + 7(-3)3 + 7(-3)2 + p(-3) + qbut p(-3) = 0{tex}\\Rightarrow{/tex}0 = 81-189 + 63 - 3p + q{tex}\\Rightarrow{/tex}0 = -3p + q -45{tex}\\Rightarrow{/tex}3p -q = -45 ..........(ii)On putting the value of p in eq. (i),we get,{tex}4(-35) - q = - 80{/tex}{tex}\\Rightarrow{/tex}{tex}-140 - q = - 80{/tex}{tex}\\Rightarrow\\ {/tex}{tex}-q = 140 - 80{/tex}{tex}\\Rightarrow\\ {/tex}\xa0{tex}-q = 60{/tex}{tex}\\therefore{/tex}\xa0{tex}q = -60{/tex}Hence, p = -35, q = -60 | |
| 41670. |
Formlas all ch |
| Answer» Hows that possible for us to give yu all of them here....refer yur book | |
| 41671. |
Solve for x : 1/x +1/y +1/z = 1/x+y+z |
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Answer» x= -y or x= -z.......... X=-y and -z |
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| 41672. |
tan2A—tan2B=cos2B—cos2A/cosAcosB |
| Answer» | |
| 41673. |
Draw a line parallel to given line |
| Answer» To a line parallel to another line1. Draw two lines perpendicular to given line.2. Cut them with a definite height.3. Join both point and produce it both side.Hence, Given lines are parallel to each other.?? | |
| 41674. |
If sec |
| Answer» Complete your question | |
| 41675. |
Is oswal question book best for board exam |
| Answer» Vry best mango apple | |
| 41676. |
P.g.t. theorem proof |
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Answer» It is P.G.T. theorem not B.P.T.theorem BPT theorum...basic propationality theorum... Ncert me h Ye Pythagoras theorm h Yaa ye to Pythagoras bhi hp skta h I think he want to write BPT theorem Konsi theorem h...P.g.t. ka full form kya h |
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| 41677. |
Using euclid division algorithm find the hcf of 125 and 425 |
| Answer» a = 145b=125Using Euclid division lemma145=125*1+20125=20*6+520=5*4=0So,HCF of 145 or 125 is 5 Hope you found it helpful | |
| 41678. |
Find the area of quadrant whose circumference is 44 cm2 |
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Answer» Circumference= 2πr 44=2πr44=2•22/7•rr=44×7/2×22r=7cmArea of quadrant=1/4πr21/4×22/7×7×7Area=77/2cm2 Let radius be r cmWe are given, Circumference, 2πr = 44 so,\xa0πr = 22 so, 22/7*r = 22 r = 7 cmSo, area of Quadrant = 1/4 *\xa0πr² = 1/4 * 22/7 * 7*7 = 22*7/4 = 154/4 = 38.5 cm²Thank you ?? Circumference=2πr=44cmSo,. r=7cmArea of the quadrant=1/2πr2 =1/2×22/7×7×7 =77/2cm2. |
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| 41679. |
Prove that the lenght of two tangents from an external point to a circle are equal |
| Answer» You can solve this question by construction. Than, congruent them by SAS theoram. By CPCT you would be able to know that the lengths of tangents are equal. | |
| 41680. |
Student observe the following spinner what is the probability of obtaining red colour |
| Answer» | |
| 41681. |
Can (x-2) be the remainder on division of a polynomial p(x) by (2x+3) ? Justify your answer. |
| Answer» No ,\xa0(x - 2) cannot be the remainder on division of a polynomial p(x) by(2x +3)\xa0Because\xa0degree of remainder must be less than degree of\xa0divisor. Here degree of x-2 and 2x-3 is\xa0same that is 1. | |
| 41682. |
A parallelogram has vortices (1,4),(7,11),(k,4)and(1,-3). |
| Answer» Complete your question..... | |
| 41683. |
Sin6A -cos6A |
| Answer» | |
| 41684. |
(X+1) (x+2) (x+3) (x+4)-8=0 |
| Answer» | |
| 41685. |
Find the probability of 12 |
| Answer» check ur question | |
| 41686. |
Write the sum of exponent of prime factors in the prime factorization of 250. |
| Answer» Factorization of 250 =2×5×5×5 ={tex} 2 \\times 5 ^ { 3 }{/tex}Therefore, sum of exponents = 1 + 3 = 4 | |
| 41687. |
196 & 38220 using euclid division |
| Answer» divide 39220 by 196 then divide the devisor with the reminder and repeat this until ur reminder is 0. | |
| 41688. |
Check weather (5,-2)(6,4)and(7,-2)are vertices of isosceles triangle |
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Answer» Let the points (5, - 2), (6, 4), and (7, - 2) are representing the vertices A, B, and C of the given triangle respectively.AB = {tex}\\;\\sqrt{{(5-6)}^2+\\;(-2-4)^2}\\;=\\;\\sqrt{(-1)^2\\;+\\;(-6)^2}\\;=\\;\\sqrt{1\\;+36\\;}\\;=\\sqrt{37}{/tex}BC = {tex}\\;\\sqrt{{(6-7)}^2+\\;(4\\;-\\;(-2))^2}\\;=\\;\\sqrt{(-1)^2\\;+\\;(6)^2}\\;=\\;\\sqrt{1\\;+36\\;}\\;=\\sqrt{37}{/tex}CA = {tex}\\;\\sqrt{{(5-7)}^2+\\;(-2)\\;-\\;(-2))^2}\\;=\\;\\sqrt{(-2)^2\\;+\\;(0)^2}\\;=\\;\\sqrt{4\\;}\\;=2{/tex}Therefore, AB = BCAs two sides are equal in length, therefore, ABC is an isosceles triangle. Ya, they are verticies of an isosceles triangle....., its ncert question, yu can check the solution in this app.......... |
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| 41689. |
if α and β are the zeroes of the polynomial x^2 + 7x + 12 then find the value of α+β+2αβ |
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Answer» Since alpha and beta are zeros of the following polynomial therefore alpha + beta + 2 alpha beta is equals to alpha + beta whole square replacing alpha + beta by minus b Upon a now we have given the value of b and a we will put in this and we get answer 49 17 -7+2×12=17 Sorry 17 1.Identify a,b,c values from given quadratic equation 2.find sum of zeros and product of zeros 3.Substitute in the given expression Then we will get answer as 14 |
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| 41690. |
How we finf cf in more than ogive graph? |
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Answer» Both..... Yup, she\'s right....... By substracting the frequencies..... You can find cf in more than ogive graph by 1. Take the total of frequency.2.Write the total frequency in the first cf coloumn for ex. (100 is ur frequency total then 100 will become the first term of cf).3. Then start subtracting ur frequency as same as u do adding while finding simple cf. For ex.(ur first term of cf is 100 and ur first term of frequency is 8 .then subtact 100 -8 gives u ur second term of cf i.e., 92).4. Then continue this process. |
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| 41691. |
State and prove the phythagorus theoream |
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Answer» Plz prefer rs agarwall Please learn NCERT TextBook of mathematics STATEMENT :- In a triangle if the square of a side is equal to the sum of the squares of other two side then the angle opposite to the first side is a right angle..,.......bt i don\'t know how to post a pic here...... Statement In a right triangle the square of any two sides is equal to square of third side |
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| 41692. |
Root 3 |
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Answer» 1.73 Complete ur ques |
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| 41693. |
Prove that: Cosec^2theta /cosec theta-1 - cosec^2 theta+1 |
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Answer» there is no = sign in it so what should we need to prove Mnz there is any mstake in typing? |
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| 41694. |
Solve any equation by completing square method |
| Answer» Konsa | |
| 41695. |
If 3n2+5n then find n term |
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Answer» 6n-3 How the answer is 8 ? ? Explain it 8 |
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| 41696. |
Explain euclid division lemma |
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| 41697. |
Photo grease theorm |
| Answer» | |
| 41698. |
If tanA=1/√5 then what is the value of cosec^2a-sec^2 / cosec^2a+sec^2a |
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Answer» How you had solve?? 4sin^2 (3-√5)/2 |
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| 41699. |
Important question 4 no. in book |
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| 41700. |
All formule of ch quadratic equation |
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Answer» U see your maths ncert book cgapter 2 me alg se hi h Quadratic formula --. -b + √b²-4ac/2a. b square - 4ac |
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