2cosQ+2√2=3secQ find Q solve step by step and give ans

1.	2cosQ+2√2=3secQ find Q solve step by step and give ans
Answer» ( r MEANS ROOTS..... SO DON\'T GET CONFUSED )2cosQ +2r2 = 3secQ2cosQ + 2r2 = 3/ cosQ2cos^2Q + 2r2cosQ = 3(Multiplying the eq. by r2)2r2cos^2Q + 4cosQ -3r2 = 02r2cos^2Q - 2cosQ + 6cosQ - 3r2 = 0( by factorization we get )cosQ = 1/r2 and cosQ = -3r2/2 (u can find it out and get same result)Since the value of cosQ can\'t be negative Therefore the actual value of cosQ is 1/r2And hence Q is 45° Wait

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