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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 41701. |
1/sec-tan-1/cos=1/cos-1sec+tan |
| Answer» According to the question,L.H.S. =\xa0{tex}\\frac { 1 } { ( \\sec \\theta - \\tan \\theta ) } - \\frac { 1 } { \\cos \\theta }{/tex}{tex}= \\frac { 1 } { ( \\sec \\theta - \\tan \\theta ) } \\times \\frac { ( \\sec \\theta + \\tan \\theta ) } { ( \\sec \\theta + \\tan \\theta ) } - \\sec \\theta{/tex}{tex}= \\frac { ( \\sec \\theta + \\tan \\theta ) } { \\left( \\sec ^ { 2 } \\theta - \\tan ^ { 2 } \\theta \\right) } - \\sec \\theta{/tex}= (sec{tex}\\theta{/tex}\xa0+\xa0tan{tex}\\theta{/tex}) - sec{tex}\\theta{/tex} [{tex}\\therefore{/tex}{tex}sec^2\\theta - tan^2\\theta = 1{/tex}]= tan{tex}\\theta{/tex}.R.H.S. =\xa0{tex}\\frac { 1 } { \\cos \\theta } - \\frac { 1 } { ( \\sec \\theta + \\tan \\theta ) }{/tex}{tex}= \\sec \\theta - \\frac { 1 } { ( \\sec \\theta + \\tan \\theta ) } \\times \\frac { ( \\sec \\theta - \\tan \\theta ) } { ( \\sec \\theta - \\tan \\theta ) }{/tex}= sec{tex}\\theta{/tex} - (sec{tex}\\theta{/tex} - tan{tex}\\theta{/tex})\xa0[{tex}\\therefore{/tex}{tex} sec^2\\theta - tan^2\\theta = 1{/tex}]= tan{tex}\\theta{/tex}.{tex}L.H.S. = R.H.S.{/tex} | |
| 41702. |
Write 70 as praduct of its prime factor |
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| 41703. |
Show that exactly one of the Numbers n,n+2or n+4is divisible by 3 |
| Answer» Let n =3kthen n + 2 = 3k + 2and n + 4 = 3k + 4Case 1: When n=3k ,n is divisible by 3 ............(1)n + 2 = 3k + 2or, n + 2 is not divisible by 3n + 4 = 3k + 4= 3(k + 1) + 1or, n + 4 is not divisible by 3Case 2:When n=3k+1, n is not divisible by 3\xa0n + 2 = (3k + 1) + 2=3k + 3 = 3(k + 1){tex} \\Rightarrow{/tex}\xa0n+ 2 is clearly divisible by 3..........................(2)n + 4 = (3k + 1) + 4= 3k + 5= 3(k + 1) + 2{tex}\\Rightarrow{/tex}\xa0n + 4 is not divisible by 3Case 3:When n=3k+2,n is not divisible by 3\xa0n + 2 = (3k + 2) + 2= 3k + 4(n + 2) is not divisible by 3x + 4 = 3k + 6 = 3(k + 2){tex}\\Rightarrow{/tex}\xa0n + 4 is divisible by 3........................(3)Hence, from (1),(2) and (3) it is clear that\xa0exactly one of the numbers n, n + 2, n + 4, is divisible by 3. | |
| 41704. |
π2 |
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Answer» 44/7 What |
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| 41705. |
If sn=3n2 + n then find a16 |
| Answer» Since , Sn=3n^2+n. .................1 Therefore Sn-1=3(n-1)^2+n-1. Or =3(n^2+1-2n)+n-1. Or =3n^2+3-6n+n-1. Or =3n^2-5n+2 ..............2 We know that ,. An=Sn-Sn-1. Or. =3n^2+n-(3n^2-5n+2) Or. =6n-2. Now,. A16=6(16)-2=96-2={94} Hence, 16th term of this A.P. is 94 | |
| 41706. |
1/2a+b+2x=1/2a+1b+1/2x |
| Answer» {tex}\\frac{1}{2a + b + 2x}{/tex}\xa0=\xa0{tex}\\frac{1}{2a}{/tex}\xa0+\xa0{tex}\\frac{1}{b}{/tex}\xa0+\xa0{tex}\\frac{1}{2x}{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}\\frac{1}{2a + b + 2x}{/tex}\xa0-\xa0{tex}\\frac{1}{2x}{/tex}\xa0=\xa0{tex}\\frac{1}{2a}{/tex}\xa0+\xa0{tex}\\frac{1}{b}{/tex}\xa0{tex}\\Rightarrow{/tex}{tex}\\frac { 2 x - 2 a - b - 2 x } { ( 2 a + b + 2 x ) ( 2 x ) }{/tex}\xa0=\xa0{tex}\\frac{b + 2a}{2a \\times b}{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}\\frac { - ( 2 a + b ) } { ( 2 a + b + 2 x ) 2 x }{/tex}\xa0=\xa0{tex}\\frac{b + 2a}{2ab}{/tex}{tex}\\Rightarrow{/tex}{tex}\\frac { - 1 } { 4 a x + 2 b x + 4 x ^ { 2 } }{/tex}\xa0=\xa0{tex}\\frac{1}{2ab}{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}4x^2 + 2bx + 4ax = -2ab{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}4x^2 + 2bx + 4ax + 2ab = 0{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}2x(2x + b) + 2a(2x + b) = 0{/tex}{tex}\\Rightarrow{/tex}\xa0(2x + b)(2x + 2a) = 0{tex}\\Rightarrow{/tex}\xa0x = -{tex}\\frac{b}{2}{/tex} or x = -a | |
| 41707. |
Simplify (sec + tan) (1- sin) |
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Answer» Correct answer is cos. (1+sin/cos )( 1-sin),,, ,,,,,( 1 )^2 - (sin )^2/cos,,,,,,,, cos^2/cos,,,,,,,, cos (1/ cos+sin/ cos)( 1- sin ) Cos^2 |
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| 41708. |
solve the equation x^2-(√3+1)x+√3=0 by the method of last term = (middle term)^2/ 4 × first term |
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| 41709. |
If in triangle ABC, AD is drawn as median show that AB square +AC square = 2 (AD+ BD) |
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| 41710. |
What is the hcf of 48 and 1232 |
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Answer» 8 answer 48, 1232. Hcf. 8hai For HCF use euclid\'s division Lemma. a = bq + r |
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| 41711. |
What do you mean by mode |
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Answer» The number which appears most often in a set of numbers.\xa0Example: in {6, 3, 9, 6, 6, 5, 9, 3} the Mode is 6 (it occurs most often). The mode of a set of data values is the value that appears most often. |
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| 41712. |
Can anyone there to answer this question1/a+b+x = 1/a+1/b+1/x . Find value of x. |
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Answer» But why do u want to know my full name? What is your full name chetna X = - a and X = -b |
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| 41713. |
Seems important questions in maths |
| Answer» There are so many.....u can find all the questions in this app of each chapter... | |
| 41714. |
Solve the inequality 2x+5/3>5,xeN |
| Answer» ??? Which chapter is this??? | |
| 41715. |
Rajiv walks and cycle at u |
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Answer» Answer me Plzz answer my question 65 |
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| 41716. |
Spare of tsa formula |
| Answer» If you want to know TSA of sphere then it is- 4πr×r | |
| 41717. |
CosA/1-SinA+CosA/1+sinA=2secA |
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| 41718. |
Solve pair of linear equation : (a-b)x+(a+b)y=a2-2ab-b2 and second is:(a+b)(x+y)=a2+b2 |
| Answer» (a - b)x + (a + b)y = a2 - 2ab - b2 ...(1)(a + b)(x + y) = a2 + b2{tex}\\Rightarrow{/tex} (a + b)x + (a + b)y = a2 + b2 ....(2)Subtracting equation (2) from (1), we obtain:(a - b)x - (a + b)x = (a2 - 2ab - b2) - (a2 + b2){tex}\\Rightarrow{/tex} (a - b - a - b)x = -2ab - 2b2{tex}\\Rightarrow{/tex} -2bx = -2b(a + b){tex}\\Rightarrow{/tex} x = a + bSubstituting the value of x in equation (1), we obtain:(a - b) (a + b) + (a + b)y = a2 - 2ab - b2{tex}\\Rightarrow{/tex} a2 - b2 + (a + b)y = a2 - 2ab - b2{tex}\\Rightarrow{/tex} (a + b)y = -2ab{tex}\\Rightarrow y = \\frac{{ - 2ab}}{{a + b}}{/tex} | |
| 41719. |
If 4*x^4-3*x^3-3*x^2+x-7 is divided by 1-2x then what will be the reminder |
| Answer» It might be - 57/8 | |
| 41720. |
1-cosA/1+cosA=sinA+cosA |
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| 41721. |
AD is median of triangle ABC, AB2+AC2=148 & AD=7. Find BC. |
| Answer» BC = 10 units | |
| 41722. |
2+2q+r=5Find value of q and r |
| Answer» 2q+r=3Then value of r=0,1If r=0 ,then value of q=3/2If r=1,then value of q=1 | |
| 41723. |
Which chapters from maths are enough to practise from ncert |
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Answer» Ncert is main for all other subjects as well...Obviously ncert is enough if u practice each n evry question with all the concepts clear... I think, all |
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| 41724. |
Find the sum of first 40 positive integers divisible by 6. |
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Answer» 4920 AP=6,12,................,240n=40,d=6,l=240Sn=n/2(a+l)Sn=40/2(6+240)Sn=20(246)Sn=4920. Ans.......... andFindtheratiooftheareaof 4920...... |
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| 41725. |
In the right ? ABC, angle A =90 and AD perpendicular bc. Then BD➗ DC |
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Answer» Matlab Shayad question adha hai..........?? |
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| 41726. |
X square - 2 x minus 8 |
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Answer» The value of x can be (-2) and 4. x2 - 2x - 8= x2 - 4x + 2x - 8= x(x - 4) + 2 ( x - 4)= ( x + 2) (x - 4) |
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| 41727. |
three cubes each of side 5cm are joined end to end . find the surface area of the resulting solids |
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Answer» 350 cm sq. 350 cm² 350 cm~`|||•√÷÷×∆∆=°¥¢£*"\'\';! 300 cm² 350 use the formula of t.s.a. of cuboid where l=15,b=5,h=5 Maybe 350 cubic cm |
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| 41728. |
sinA - 2sinA×sinA×sinA ÷ 2cosA×cosA×cosA-cosA=tanA. proof |
| Answer» SinA -2Sin 3÷2cos3-cosa=tanH.p | |
| 41729. |
A circle the side bc of a |
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Answer» Complete the question Your welcome ? ???, complete to kro question ko |
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| 41730. |
Tan A+Sin A=m and Tan A -Sin A=nProve that (m square -n square )=4 underroot mn |
| Answer» Is question main pehle Rohan m+n ki value nikalo(2tanA) n then m-n ki (2sinA)Then mn ki value(tan squareA - sin squareA)Then m square- n square ki value nikalo(4 tan A Sin A)... Yeh LHS solve huiFir RHS pe aaoAb yahan par na simply values put kro, humne mn nikala hai upar... Wahi daalo yahan n fir solve krke ans aayega 4sinAtanAJo ki LHS haiyahi ans haiN agar aapko RHS ka na smjh aaye to bata dena vo bhi post kr dungi n btw brackets main valie jo niklegi vo likhi hai | |
| 41731. |
Find the ratio in which the Y axis divides the line segment joining the points (5,-6)and (-1,-4) |
| Answer» Let y-axis divides the line segment joining the points(5, - 6) and (- 1, - 4) in the ratio k: 1and the coordinates of the required point be (0, y).Then, 0 =\xa0{tex}\\frac { 5 \\times ( 1 ) + k \\times ( - 1 ) } { k + 1 }{/tex}{tex}\\Rightarrow{/tex}\xa05 - k = 0{tex}\\Rightarrow{/tex}\xa0k = 5Thus, y-axis divides the line segment joining the points (- 5 , 6) and (- 1, -4) in the ratio 5 : 1. | |
| 41732. |
What is the speed of earth per min |
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| 41733. |
124+8 |
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Answer» 132 what a question i like it .keep it up 132 ???? Itne hard mt pucho dr lgta hai 132 132 it was too hard really? 132 |
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| 41734. |
Is there any changes in this times paper...compared to last year. |
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| 41735. |
Find the eleventh term from the last term of the AP 27, 23, 19,....... -65 |
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Answer» a11=-13 galt bataya hai mai ko keh ri hu wese kro...sahi aaega...11 mt rkhna 11={l-(11-1)-4 } now solve it urself -65 ko first term let krke nikalo...aa jaega..oosswl kesample paper 1 me h ye ??? -13 Nth term= {l-(n-1)d} Use l-(n-1) Easy he |
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| 41736. |
Mode of the data is 67 .find x in frequency |
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Answer» Give full information Where is the frequency ?? |
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| 41737. |
Marking scheme of maths of 10 |
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| 41738. |
Q is that from ncert tb of maths pg.no.202 example 6. |
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| 41739. |
How to calculate mean data |
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Answer» Yes I know I\'ve given formula for mean below Yup that for median and also that was wrong there -cf and you have written+cf The method given by geetanjali is for calculating median Summation of fixi/summation of fi Oh I\'m sorry it was for median Any one my friend online For calculating mean there is three forms to calculate mean- step division method and assumed mean method and direct method Go for step deviation metho. I hope u understand L+ {n/2+cf}/f×h |
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| 41740. |
Show that numbers 8n can never end with digit 0 for any natural number n |
| Answer» 8n=(2*3)n where both are doesn\'t devive by 5.if it ends with 0 must devide with 5 | |
| 41741. |
How many syllabus come from ncert.or any other |
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| 41742. |
How to find out the ratios in coordinate geometry if points are given |
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Answer» Let the be K:1 and solve the question Assume m and n in section formula k and 1 respectively......then you will find the vale of k that will be the ratio.........suppose you get ans 1/2 then ratio is 1:2 ......i hope it helps you Use section formula |
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| 41743. |
Find the eleventh term from the last term of the AP:27, 23, 19, ..., –65. |
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Answer» Yaa right answer is -25 a=-65 d=4 a+(n-1)d-65+(11-1)4-65+40-25 -25 -21 24 244 |
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| 41744. |
Draw diagram about both boy and girl are on opposite side of the kite |
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| 41745. |
Cot2A(secA-1)/1+sin2A=sec2A(1-sinA/1+secA) |
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| 41746. |
If the mean of the first \'n\' natural numbers is 5n/9 then what is the value of n? |
| Answer» n=9 | |
| 41747. |
Find the quadratic equation whose roots are 3 and -3 |
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Answer» x2-9 x2-9 |
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| 41748. |
(x+1)^2=2(x-3 |
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| 41749. |
Sin=12/20find the value 8(cosecsquare +cotsquare) |
| Answer» 36.4444 | |
| 41750. |
Aloha guysany new song suggestion??please give\xa0 |
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Answer» ok??? Kisi ke dewana nhi...only except miself.... tum kis k dewne ho What #lovely? Yess coca cola is?? hlo amrit LIsten coca cola song...? Illegal weapon( yr mast song h) songs??? Konse singer ka |
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