Exercise 6.3 question no. 4

1.	Exercise 6.3 question no. 4
Answer» QR / QS = QT / PR ( given)Qt / Qr = Pr / Ps (1)<1 = <2 ( given)Pr = Pq (2). ( side opp. To equal < are equal)From 1 and 2 Qt / Qr= Pq / Qs= Pq / Qt = Qs/ Qr (3) In ∆ PQS and TQR we getPq /Qt = Qs / Qr < PQS = In ∆ RPQ and RTS< RPQ = QR/QS=Qt/PR(angle1=angle2 so in triangle PQR PQ=PR becoz sides opposite to equal angles are equal ) So QR/QS=QT/QP So by the converse of bpt theoram PS is parallel to TR Then in triangle PQS and tria.TQR Angle 1 =angle 1( common)Angle QPS=angle QTR ( corresponding angle )SO BY AA~ CRITERIA Triangle PQS~tri.TQR

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