1.

The sum of first n terms of an AP is given by Sn= 2nsq +3n . Find the 16th term of the AP.

Answer» 2n^2+3n S1=2(1)2+3(1)=5S2=2(2)^2+3(2)=14S3=2(3)^2+3(3)=27a1=s1a2=s2-s1 14-5=9a3=s3-s2 27-14=13AP:5,9,13 a=5 ,d=4a16=a+15d 5+16(4)= 69(ANS)


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