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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 42001. |
What is the coordinates of reflection of point (3,5) in x and y-axis? |
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Answer» In X axis : (3,-5)In Y axis : (-3,5) (3,0) and (0,5) |
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| 42002. |
What are the possible values of remainder r, when a positive interger "a" is divided by 3? |
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Answer» Aap sabhi ko cbse ka new practice paper mila school se Please explain How plz explain it Who 0,1,2 |
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| 42003. |
How can I solve probability questions of weeks, leap year, etc easily?? |
| Answer» By practicing them more and more | |
| 42004. |
cot2A+tan2A=47 |
| Answer» | |
| 42005. |
The hcf and lcm of two no. Are 9 and 360 if one no.is 45 find the other no |
| Answer» We know that a x b = H.c.f (a, b) x L.c.m( a,b)a = 45 ,\xa0H.c.f (a, b) = 9 ,L.c.m( a,b) = 360.b = ( 9 x 360) / 45 = 72.∴ Another number is 72 | |
| 42006. |
How to find roots of quadratic equation by using completing square method |
| Answer» ax2 + bx +c=0x2 +bx/a +c/a=0x2 +bx/a=-c/ax2+2(b/2a)x+(b/2a)square=-c/a+(b/2a)square(x+b/2a)square=-c/a+(b/2a)square | |
| 42007. |
The difference of an integer and its reciprocal is 143/12, find the integer |
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Answer» Plz give full solution Integer is 12 12 |
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| 42008. |
Oustion is 7-4n our hame d nikalna h |
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Answer» Your answer is:an=7-4nPutting n=1, 2, 3,.... We get:-a= 7-4(1)=7-4=3a2= 7-4(2)=7-8=-1a3= 7-4(3)= 7-12= -5Thus AP is formed:3, - 1, - 5,.....d=a2-a1d=-1-3=-4Thus, d=-4. Shi se question liko smj nhi aa rha |
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| 42009. |
Cos +tan =p |
| Answer» sec + tan = pSec = p - tansec^2 = (p - tan)^2sec^2 = p^2 + tan^2 - 2ptansec^2 - tan^2 = p^2 - 2ptanp^2 - 2ptan - 1 = 0(p^2 - 1)/2p = tanSec + (p^2 - 1)/2p = pSec = p - (p^2 - 1)/2p = (p^2 + 1 )/2pCos = 2p/(p^2+1)cos^2 = 4p^2/(p^2+1)^2sin^2 = 1 - 4p^2/(p^2+1)^2sin^2 =[ (p^2+1)^2 - 4p^2]/(p^2+1)^2sin^2 = (p^2–1)^2/(p^2+1)^2Sin = (p^2–1)/(p^2+1) | |
| 42010. |
TanA=nTanB , SinA=mSinBThen prove Cos^2A=(m^2-1/n^2-1) |
| Answer» Given,\xa0tan A = n tan B{tex} \\Rightarrow{/tex} tanB = {tex}\\frac{1}{n}{/tex}tan A{tex}\\Rightarrow{/tex}\xa0cotB =\xa0{tex}\\frac { n } { \\tan A }{/tex}..........(1)Also given,\xa0sin A = m sin B{tex}\\Rightarrow{/tex}\xa0sin B =\xa0{tex}\\frac{1}{m}{/tex}sin A{tex}\\Rightarrow{/tex}\xa0cosec B =\xa0{tex}\\frac { m } { \\sin A }{/tex}.....(2)We know that, cosec2B - cot2B = 1, hence from (1) & (2) :-{tex} \\quad \\frac { m ^ { 2 } } { \\sin ^ { 2 } A } - \\frac { n ^ { 2 } } { \\tan ^ { 2 } A } = 1{/tex}{tex}\\Rightarrow \\quad \\frac { m ^ { 2 } } { \\sin ^ { 2 } A } - \\frac { n ^ { 2 } \\cos ^ { 2 } A } { \\sin ^ { 2 } A } = 1{/tex}{tex}\\Rightarrow \\quad \\frac { m ^ { 2 } - n ^ { 2 } \\cos ^ { 2 } A } { \\sin ^ { 2 } A } = 1{/tex}{tex}\\Rightarrow{/tex}\xa0m2 - n2cos2A = sin2A{tex}\\Rightarrow{/tex}\xa0m2 - n2cos2A = 1 - cos2A{tex}\\Rightarrow{/tex}\xa0m2 - 1 = n2cos2A - cos2A{tex}\\Rightarrow{/tex}\xa0m2 - 1 = (n2 - 1) cos2A{tex}\\Rightarrow \\quad \\frac { m ^ { 2 } - 1 } { n ^ { 2 } - 1 } ={/tex}\xa0cos2A | |
| 42011. |
x^2 - 7x -56 = 0 find the value of x |
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Answer» Do with -b+-√b^+4ac/2a. 7+-√49+4*56/2-7+√273/2 and -7-√273/2 Answer root me hai x =(7-√273)/2 and x =(7+√273)/2.......? |
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| 42012. |
If one zero of p(x) = 4xsquare-(8ksquare-4k)x-9 is negative of the other find the value of k |
| Answer» Let, the two zeroes of the polynomial f(x) = 4x2 - 8kx - 9 be α and -α.Comparing f(x) = 4x2\xa0- 8kx - 9 with ax2+bx+c we geta = 4; b = -8k and c = -9.Sum of the zeroes = α + (-α) ={tex}-\\frac ba=\\;-\\frac{-8k}4 {/tex}0 = 2kk = 0 | |
| 42013. |
If 4tan =3 Evaluate (4sin-cos+1 ÷4sin +cos-1) |
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Answer» Mera to 24/5 aa rha hai Tan theta = 3/4 =P/BTherefore P=3x B=4x H²=3²+4²=25 H=5Sintheta =3/5 ,. Cos theta = 3/5 (4)(3/5) -4/5 +1 ÷(4)(/5)+4=13/11 The correct answer os 13/11 Tan theth =p/b p=3 b=4 h=5 pit the value of these and answer is 13/11 24/5 is the answer |
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| 42014. |
Can you tell me that where we can apply lcm and hcf in ch1 word problems |
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Answer» No it is applied in few cases only If you see in question the least less minimum apply lcm and if you see the word maximum more high apply hcf |
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| 42015. |
PQ parallel to and PR parallel to CB. Prove that AQ/QD=AR/RB |
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| 42016. |
How to draw figure here to ask questions |
| Answer» Dont know | |
| 42017. |
If common difference of an ap is -4 and seventh term of an ap is 4 find the first term of an ap |
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Answer» A=28 d=-4 a7=4. a+6d=4 a=4-6(-4)a= 4+24=28 28 |
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| 42018. |
A+b formula |
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Answer» https://www.mathexpression.com/basic-algebra-formulas.htmlMath Expression: Basic Algebra Formulas https://www.teachoo.com/6764/932/Algebra-Formulas---(a-b)-3---(a-b)-2--Exponents--Square-Root/category/Introduction/Algebra Formulas - (a+b)^3 , (a+b)^2 , (a+b+c)^3, a^3 - b^3 - Teachoo |
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| 42019. |
513=n%2(108+(n-1)-3) |
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Answer» Ise solve kero answer aa jayega Yes i will tell you ,513=n/2(2×54+(n-1)-3) N = 18,19 Can any one tell why two values of terms are coming? 54, 51, 48,...........First term a = 54Common difference d = 51 - 54 = -3Let n is the number of terms.Given, sum = 513=> (n/2)*{2a + (n - 1)d} = 513=> n{2a + (n - 1)d} = 513*2=> n{2*54 + (n - 1)*(-3)} = 1026=> n{108 - 3n + 3} = 1026=> n{111 - 3n} = 1026=> 111n - 3n2\xa0= 1026=> 3n2\xa0- 111n + 1026 = 0=> n2\xa0- 37n + 342 = 0 {divide by 3}=> (n - 18)*(n - 19) = 0=> n = 18, 19Hence, number of terms is either 18 or 19 |
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| 42020. |
30+(15-f1)÷3=32Find the value of f1 |
| Answer» 9 | |
| 42021. |
the number lies between 100000 and 110000 which is exactly divisible by 8,15,21 |
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Answer» LCM of 8,15,21=840110000/840=130.95hence the greatest no divisible by 840 or divisible by 8,15,21:=840*130=109200\xa0\xa0 100840 |
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| 42022. |
Find weather -150 is a term of A.P 17,12,7,2....? |
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Answer» No - 150 is no a term of this A.P an= a+ (n-1)d-150 = 17 + ( n-1)-5we will solve the eq.- 150 - 17 = ( n-1)-5-167=(n-1)-5167/5=n-1167+5/5=n172/5=n n is in fraction and any term cannot be in fraction hence -150 is not a term of A.PRead more on Brainly.in - https://brainly.in/question/1088917#readmore a=1 7 ,. D = -5 , an =-150Let -150 be the nth terman= a+(n-1) d-150= 17+(n-1) -5-167=(n-1)-5-33.4 =( n-1)-33.4+1 = nn=-32.4 |
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| 42023. |
Prove that the length of tangent draw from an external point to a circle are equal |
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Answer» I {tex}\\triangle{/tex} OPT and {tex}\\triangle{/tex} OQT{tex}\\angle{/tex} OPT={tex}\\angle{/tex}OQT=90OP=OQ=rOT is common\xa0{tex}\\triangle{/tex} OPT and {tex}\\triangle{/tex} OQT{tex}\\begin{array}{l}\\text{Hene ∆OPT≅∆QOT}\\\\\\end{array}{/tex}SO PT=QT\xa0\xa0 Proved in ncert... |
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| 42024. |
Prove that Tan0/1-cot0+cot0/1-tan0=1+sec0×cosec0 |
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| 42025. |
Solve the equation by sustitution method ,x+2y=7and3x-2y=11 |
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Answer» x=9/2 n y= 5/4 Are you ?%sure about your answer chethan X= 9 , y =-1 X=9/2and y=5/4 |
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| 42026. |
Show that tan O+sec O-1/tan O-sec O +1=1+sin O/cos O |
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| 42027. |
If 7 times the 7^th term of an AP is equal to 11 timesits 11^th term then find its 18^th term |
| Answer» 7(a+6d)=11(a+10d)7a+42d=11a+110d7a-11a=110d-42d-4a= 68d a=-17da+17d=0a+(18-1)d=018th term = 0 | |
| 42028. |
Sinx/cotx+cosecx=2+sinx/cotx-cosecx |
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| 42029. |
Prove that 2 root under 3 - 1 is an irrational number |
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Answer» if your Q is 2√3-1 then,Let 2√3-1 be rational number say p/q where q is not equal to zero and p and q are coprime.2√3-1=p/q2√3=p/q+1√3=p+q/2q√3is irrational and p+q/2q is rational.But rational is not equal to irrational. Therefore 2√3-1 is irrational. 2√3-12√2Let 2√2 be rational number say p/q where q is not equal to zero and p&q are coprime.2√2=p/q√2=p/q÷2√2 is irrational and p/q÷2 is rational.But rational is not equal to irrational.Therefore 2√2 is irrational. Let 2√3-1 is rational , let a and b is the positive integer , 2√3-1=a/b , 2√3=a/b+1 , 2√3= a+b/b , √3=a+b/2b , so our assumption was wrong , hence 2√3-1 is irrational |
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| 42030. |
Ysq.-3y+10 |
| Answer» Complete yur question......... | |
| 42031. |
TSA or SA mein kya diffrence hota h |
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Answer» CSA is curved surface area Means walls of room but sometimes take bottom surface This is depend Sometimes on question but TSA is total surface area means adding all curved sides and up and down part Both are same |
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| 42032. |
I have very problems in cordinate geometry plzz help me in videos |
| Answer» I think if you refer to byjus your doubts will be clear,, | |
| 42033. |
a leap year have 53 fridays |
| Answer» 1 year = 365 daysA leap year has 366 daysA year has 52 weeks.Hence there will be 52 Sundays for sure.52 weeks = 52\xa0× 7 = 364 days366 – 364 =2 daysIn a leap year there will be 52 Sundays and 2 days will be left.These 2 days can be:Sunday, MondayMonday, TuesdayTuesday, WednesdayWednesday, ThursdayThursday, FridayFriday, SaturdaySaturday, SundayOf these total 7 outcomes, the favourable outcomes are 2.Hence the probability of getting 53 days = 2/7\xa0 | |
| 42034. |
Under root 2 is irrational |
| Answer» Given √2 is irrational number.Let √2 = a / b wher a,b are integers b ≠ 0we also suppose that a / b is written in the simplest formNow √2 = a / b⇒ 2 = a2 / b2\xa0⇒ 2b2 = a2∴ 2b2 is divisible by 2⇒ a2 is divisible by 2 ⇒ a is divisible by 2 ∴ let a = 2ca2 = 4c2⇒ 2b2 = 4c2⇒\xa0b2 = 2c2∴ 2c2 is divisible by 2∴ b2 is divisible by 2∴ b is divisible by 2∴a are b are divisible by 2 .this contradicts our supposition that a/b is written in the simplest formHence our supposition is wrong∴ √2 is irrational number. | |
| 42035. |
Prove that √n-1 +√n+1 is an irrational number |
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| 42036. |
Who discovered midpoint theorem? |
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| 42037. |
A number when divided by 61 gives 27 as quotient and 32 as remainder. Find the number |
| Answer» 1679 | |
| 42038. |
How much gain passing marks in 2019 |
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Answer» 99.999999¶¶™✓✓✓✓✓%%%% 26.5 marksfor passing 27 in maths |
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| 42039. |
In triangle ABC, right- angled at ,AB=24cm, BC=7cm. Determine(i) sinA, cosA(ii) sinC, cosC |
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Answer» Hi himanshu singh this is rajalakshmi arumugam how are you Right angled at ???? |
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| 42040. |
State whether 7×11×13+7is composite number or a prime number |
| Answer» You are Abhinandan say yes or no.. it is a composite number because when you simplify it you will get 1008 it has factor=2*2*2*2*3*3*7.so two comes two times as factor so it is a composite number | |
| 42041. |
Find the volume of largest right circular cone that is cut off from cube whose edge is 9cm. |
| Answer» The height of largest cone will be 9 cm and its radius will be 9/2.Therefore volume =π*1/3*9/2*9/2*9 =33*9/14*9 (π= 22/7) = 297*9/14 =2673/14=190.928 cm³ | |
| 42042. |
The sum of the squares of two consecutive odd number is 394 find the number |
| Answer» It will form an equation 2x^2+2x-393=0 | |
| 42043. |
Three vertices of parallelogram taken in order are (1,2) (2,4) and (3,7). Find its fourth vertex |
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Answer» Join it\'s diagonals and then by mid point formula Find its fourth vertex by distance formula I think.....What about u?? |
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| 42044. |
Hindimedium mai kese kare |
| Answer» Bhai isme math hindi medium me nhi hai | |
| 42045. |
Find the common difference if a27th - a7th =84 |
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Answer» D= 4.2 It is 26d+6d... a+26d - a+6d=8426d-6d=8420d=84d=4.2 A27-a7=84A+26d-a+6d=8432d=84D=84/32D=21/8 |
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| 42046. |
Show that positive odd integer 6q+1 or 6q+3 or 6q+5 where q is some integer |
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| 42047. |
If the mean of 25observation is 27and each is decrease by 7what will be the new mean |
| Answer» New mean =20 | |
| 42048. |
In an acute triangle ABC ,if tan(A+B-C)=1and sec(B+C-A)=2,then find A,B,C |
| Answer» C 67.5A45B 57.5 | |
| 42049. |
Proportional theorem proof |
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| 42050. |
I want all question papers solution from 2008 how can i get it |
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