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Prove that the length of tangent draw from an external point to a circle are equal

Answer» I {tex}\\triangle{/tex} OPT and {tex}\\triangle{/tex} OQT{tex}\\angle{/tex} OPT={tex}\\angle{/tex}OQT=90OP=OQ=rOT is common\xa0{tex}\\triangle{/tex} OPT and {tex}\\triangle{/tex} OQT{tex}\\begin{array}{l}\\text{Hene ∆OPT≅∆QOT}\\\\\\end{array}{/tex}SO PT=QT\xa0\xa0
Proved in ncert...


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