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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 42051. |
Find tenth term from the last of AP: 7,12,17,22........,152 |
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Answer» 107 l-(n-1)d 152-9×5152-45 = 107 107 107 |
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| 42052. |
state the Euclid division algorithm |
| Answer» Let ‘a’ and ‘b’ be any two positive integers. Then there exist unique integers ‘q’ and ‘r’ such that\xa0a = bq + r, 0 ≤ r ≤ b.\xa0\xa0 | |
| 42053. |
Which term of the Ap:121,117,113,....,is its negative terms?[Hint:find n for An |
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Answer» a=121 d=-4An=121+(n-1)(-4)=121+4-4nAn=125-4nIf An=0 then125-4n=0n=125/4=31.25n next to 31 means 32th term is negative It\'s 32 th term 32th term Answer is nothong |
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| 42054. |
Solve for x and y px + qy = p-q and qx -py = p+q |
| Answer» Using elimination method And then value of \'x\' and \'y\' willX=1 and y= -1 | |
| 42055. |
Draw graph of pair of linear equations x + 3y=16 and 2x -3y =12 triangle is formed |
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Answer» Can\'t send image Cant draw here.... |
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| 42056. |
Let the three numbers are x-1, x+3, x-7 are in AP then find the value of x? |
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Answer» No value u waste my time I think question is wrong?????????? No value |
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| 42057. |
Find the 9th term of the AP : 2,6,10,... |
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Answer» a=2, d=4. T9 = a+8d 2 +8×4 2+32 =34 Isi tarah 34.honey ye name kyu badla hai Put a=2,d=4 in the formula a+(n-1)d 34 |
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| 42058. |
Give whatsapp no. For latest cbse sample paper |
| Answer» Why? | |
| 42059. |
If 4/5 ,a and 2 are three consecutive terms of an A.P, then find the value of a |
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Answer» D = a - 4/5 =2- aD = a+a = 2+4/5D = 2a = 10+4/5D = 2a = 14/5 D = a = 14/10Therefore the answer is @4/10 a=7/5.... A=7/5 a = 14/10 |
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| 42060. |
Using euclid division algorithm find whether the pair of numbers 847,2160 are co primes or not. |
| Answer» Q.\xa0Using euclid division algorithm find whether the pair of numbers 847,2160 are co primes or not.Answer:\xa0 | |
| 42061. |
What is euclid division algorithm |
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Answer» Given two positive integers a and b, there exist whole numbers q and r satisfying a=bq+r where r more than or equal to 0 less than b a=bq+rWhere 0 greater than equal to r | |
| 42062. |
L,b are the zeroes of quadratic poly. x2--(k+6) x + 2(2k--1) . Find the value of k if l+b1/2lb |
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| 42063. |
Converse of Pythagoras therom ki statement bata do |
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Answer» Are you honey.if yes then thanks When the sum of square of two sides of a triangle is equal to square of the thitd side then prrove that the angle opposite to the 3rd side is a right angle. |
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| 42064. |
CosecA-SinA = m3, SecA-CosA = n3 Then prove that m4n2+m2n4=1 |
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| 42065. |
Distance from p(2,3)from x axis is |
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Answer» Put distance formula in this question 3 unitsBcoz it is the y-cordinate also called ordinate 3 units |
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| 42066. |
If 9th term of an A.P is 0, show that 29th term is twice its 19th term |
| Answer» Let the first term of an A.P. =\xa0aAnd common difference =\xa0dGiven: 9th\xa0term of an A.P. is 0. Therefore,We have to prove that\xa0Thus,AndFrom equation (2) and (3),Hence proved | |
| 42067. |
Write value of x for which x+2,2x,2x+3 are consecutive term of an ap. |
| Answer» Let us take an A.P of terms a, b, cThe arithmetic mean is b\xa0Here,a= x + 2b= 2xc= 2x + 3On substituting the values in the formula we get :2x=x+2+2x+3/22x=3x+5/24x=3x+5X=5Hence the value of x is 5 | |
| 42068. |
What are the theorams that can be come in exsm of class 10 cbse 2019 |
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Answer» Hey any converse theoram can also come Phythagorus and thales are main important theorems most important (prove that √3 is irrational this type of questions) Pythagoras theorem , bpt, |
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| 42069. |
prove that, n^2 -1 is divisible by 8 for positive odd integer n |
| Answer» It is possible when n =4q+1or 4q+3 | |
| 42070. |
Find the centre of a circle if the end points of a diameter are P (-5,7) and Q (3,-11) |
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Answer» (-1,-2) The correct answer is -1,-2 as x=-5+3/2=-1…....…...Y=7-11/2.=-2...(-1,-2) (4,-9) |
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| 42071. |
Find the value of x in given figure |
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Answer» Figure?????? Where is the fig....??? |
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| 42072. |
Find a quadratic polynomial whose zeros are - 4 and 1 respectively |
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Answer» X²-(-4+1)x+-4×1 putting then u gt ans First find their sum and product and put them in formula for quadratic equation |
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| 42073. |
WRite whether 2√45+3√20÷2√5 on simplification gives an irrational or a rational number |
| Answer» Rational (i.e. 6) | |
| 42074. |
Find the value of y for which the distance between the points p (2, - 3 )and q(10,y)is 10 units |
| Answer» Given that\xa0distance between the points P (2, -3) and Q (10, y) is 10\xa0Therefore using distance formula√(2 -10)2 + (-3-y)2 = 10√ (-8)2 + ( 3 + y)2 = 10squaring on both side64 + (y +3)2 = 100(y + 3)2 = 36y + 3 = ± 6y+3=6or y+3= -6Therefore, y=3 or y= -9 | |
| 42075. |
5-9 |
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Answer» Why are u asking such type of question......... - 4 answer ..... So easy .... |
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| 42076. |
Prove that Sec^2 Θ + Cot^2 (90-Θ)= 2Cosec^2(90-Θ) -1 |
| Answer» Sec square theta = cosec(90-theta)Tan square theta = sec square theta -1Cot square(90-theta)=tan square theta In Sab ko equation me put Karna prove go jayega | |
| 42077. |
What is the perimeter of qudrant? |
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Answer» 2radius + (π . radius/2) 2radius +(pie×radius/8) |
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| 42078. |
If the nth term of an AP is( 3n+2) then find the sum of nth term of an AP |
| Answer» n/2(3n+7)..... | |
| 42079. |
Find the value of x when AD=xcm,DB=(x-2),AE=(x+2),EC=(3x-19) cm |
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Answer» Mera bhi ans nhi as RHA.Question me much garbar h. Isme EC ki value 3x-19 hai ya x-1 hai..... Answer |
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| 42080. |
In cbse board which chapter is very important in math and science |
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Answer» All chapters from maths $ science are imp Sabhi chapters important h....... Har chapters me se kuch n kuch to aayega hi.... M Algebric parts are important in maths.In science ,balanced equations are important in chemistry,numericals are important in physics and functions of each part are important in biologg. Right All |
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| 42081. |
the HCF of 45 and 105 in 15. find their LCM. |
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Answer» 315 HCF ×LCM=45×10515×LCM=45×105Lcm=45×105/15LCm=315 315 |
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| 42082. |
solve x: 1÷(a+b+c)=1÷a+1÷b+1÷x, [a,b,x is not equal to0, x is not equal to-(a+b)] |
| Answer» 1/(a+b+x) - 1/x = 1/a + 1/b => -(a+b)/x(a+b+x) = (a+b)/ab. Cancel (a+b) from both sides & cross multiply=> -ab = x(x+a+b) => x^2+(a+b)x+ab = 0=> (x+a)(x+b) = 0x = -a or -b Ans | |
| 42083. |
Coordinates of a point lying at x axis |
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Answer» (X,0) are (x,y) coordinates (X,0) (X,0) X,0 |
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| 42084. |
What is a line segment |
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Answer» Aapne google se dekh ke bataya maine jo padha hai wo bataya dono me bahot difference hai A line segment is a part of line that is bounded by two distinct end points is called a line segment In geometry, a line segment is a part of a line that is bounded by two distinct end points, and contains every point on the line between its endpoints. |
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| 42085. |
show that any positive odd integer is of the form 4q+1 or 4q+3 |
| Answer» Its too long to type........., check it in google, or aisa hi question ncert me bhi hai, check it...... | |
| 42086. |
Which sample papers are the best between mtg and apc for 2019 examination class 10 |
| Answer» I think apko previous year questions solve krne chahiye.........? | |
| 42087. |
If 10 to the power 2y = 25then find 10 to the power -y |
| Answer» 10 to the power 2y=2510 to the power y= under root 2510 to the power y =510 to the power -y= 1/10to the power y10 to the power -y = 1/10 y= 1/5ans.(10 to the power y=5) | |
| 42088. |
In ? ABC, angle C = 3angle B = 2 ( angle A + angle B). Find the angles. |
| Answer» Let the {tex}\\angle{/tex} B=x then {tex}\\angle{/tex}C=3x3x=2({tex}\\angle{/tex}A+x)3x=2{tex}\\angle{/tex}A+2xx=2 {tex}\\angle{/tex}A , {tex}\\angle{/tex}A=x/2{tex}\\angle{/tex}A+{tex}\\angle{/tex}B+{tex}\\angle{/tex}C=180x/2+x+3x=1809x/2=180,x=40so {tex}\\angle{/tex}A=20,{tex}\\angle{/tex}B=40 ,{tex}\\angle{/tex}C=120 | |
| 42089. |
In a ∆ABC write tan A+B÷2in terms of angle C |
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Answer» But how can u show answer Cot (C/2) |
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| 42090. |
In triangle ABC AD is the median then show that AB^2+AC^=2(AD^2+BD^2) |
| Answer» \xa0it is clearly shown that ABC is a triangle, in which AD is a median on BC.\xa0construction :- draw a line AM perpendicular to BC.\xa0we have to prove : AB² + AC² = 2(AD² + BD²)\xa0proof :- case 1 :- when , it means AD is perpendicular on BC and both angles are right angle e.g., 90°\xa0then, from ∆ADB,\xa0according to Pythagoras theorem,\xa0AB² = AD² + BD² ..... (1)from ∆ADC ,according to Pythagoras theorem,\xa0AC² = AD² + DC² ...... (2)\xa0AD is median.\xa0so, BD = DC .......(3)from equations (1) , (2) and (3),\xa0AB² + AC² = AD² + AD² + BD² + BD²\xa0AB² + AC² = 2(AD² + BD²) [hence proved ]case 2 :- when\xa0Let us consider that, ADB is an obtuse angle.\xa0from ∆ABM,\xa0from Pythagoras theorem,\xa0AB² = AM² + BM²\xa0AB² = AM² + (BD + DM)²\xa0AB² = AM² + BD² + DM² + 2BD.DM ......(1)from ∆ACM,\xa0according to Pythagoras theorem,\xa0AC² = AM² + CM²\xa0AC² = AM² + (DC - DM)²\xa0AC² = AM² + DC² + DM² - 2DC.DM ......(2)from equations (1) and (2),\xa0AB² + AC² = 2AM² + BD² + DC² + 2DM² + 2BD.DM - 2DC.DM\xa0AB² + AC² = 2(AM² + DM²) + BD² + DC² + 2(BD.DM - DC.DM) ...........(3)a/c to question, AD is median on BC.so, BD = DC .....(4)and from ADM,\xa0according to Pythagoras theorem,\xa0AD² = AM² + DM² ........(5)putting equation (4) and equation (5) in equation (3),\xa0AB² + AC² = 2AD² + 2BD² + 2(BD.DM - BD.DM)AB² + AC² = 2(AD² + BD²) [hence proved].\xa0 | |
| 42091. |
Ncert book of class 10 ex 12.3 question no 8 ka solution koi bata do |
| Answer» To find the difference between the tracks, we have to find the perimeter of the inner and outer track.for the inner trackwe have,2 semicircle, that is a whole circle + the length of the track2×π×r +2×1052×π×35m +2× 105220+210430mfor outer track,2 semicircle=1 circle with diameter (r+14m)=circle with radius 42circumference of circle+ 2×1052×π×42+2×105264+210474mdifference =474-430 =44mthe difference between the outer track and the inner track is 44mRead more on Brainly.in - https://brainly.in/question/2196483#readmore | |
| 42092. |
In the figure ,angle BED=angle BDE and E is the mid point of BC prove that AF/CF =AD/BE |
| Answer» Q.In the figure,\xa0∠BED =\xa0∠BDE and E is the mid-point of BC. Prove that AF / CF = AD / BEConstruction : Draw CG ||\xa0FDBy adding 1 on both sides, | |
| 42093. |
If tan a + cot a= 7. find tan square a +cot square a ?? |
| Answer» 47 | |
| 42094. |
Exercise-1.4 |
| Answer» What | |
| 42095. |
Can i ask one more questions |
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Answer» See at the top Ask now Ok It is a question releted to your mind test. Yes |
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| 42096. |
A+B=90 and tanA=3/4 then find the value of cot B |
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Answer» A + B = 90°B = 90° - A cot B = cot ( 90° - A )Cot B = tan A= 3/4 Yaar koi plz detail ma ans dai do plz Puja can u give me this Ans in detail 3/4....... |
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| 42097. |
Sec70 sin20-cos20 cosec70 |
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Answer» Answer is : 0 0.... |
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| 42098. |
prove pythagoras theorem using similar triangle |
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Answer» See on maths ncert textbook pg 145....or see utub vdos of subject teacher or ganit guru.... Chek in ncert.... |
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| 42099. |
In an Ap Pth Qth and Rth terms are respectively a, b, c. Prove that p(b-c)+q(c-a) +r(a-b) =0. |
| Answer» Ap=a=a+[p-1]d by using Aq=b=a+[q-1]d An=a+[n-1]dAr=c=a+[r-1]da=a+pd-d -1b=a+qd-d -2c=a+rd-d -3Substituting 1 2 3 in p[b-c]+q[c-a]+r | |
| 42100. |
If the p th term of an ap is 1 |
| Answer» | |