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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 42301. |
2(sin⁶ &+cos⁶&)-3(sin⁴&+cos⁴&)+1=0 |
| Answer» 2(sin6θ + cos6θ) - 3 (sin4θ + cos4θ) + 1\xa0=2[(sin2θ)3 + (cos2θ)3] -3[(sin2θ)2 + (cos2θ)2]+1=2[(sin2θ + cos2θ)3 -3sin2θcos2θ (sin2θ + cos2θ)] -3[(sin2θ + cos2θ)2-2sin2θcos2θ]+1The algebraic identitya3\xa0+ b3\xa0= (a+b)3\xa0- 3ab(a+b) and\xa0a2\xa0+ b2\xa0= (a+b)2\xa0- 2abare used in the above step wherea = sin2θ and b = cos2θ.writing sin2θ + cos2θ = 1, we have\xa0= 2[1-3 sin2θ cos2θ] -3[-2 sin2θcos2θ] + 1= 2-6 sin2θcos2θ -3 + 6 sin2θcos2θ + 1= -3+3=0 | |
| 42302. |
use Euclid\'s algorithms to find HCF of 1190 and 1445 . Express the HCF in the form of 1190m+1445n |
| Answer» 1445 = 1190*1 + 2551190 = 255*4 + 170255 = 170*1 + 85170 = 85*2 + 0So, now the remainder is 0, then HCF is 85Now,85 = 255 - 170(1445 - 1190) - (1190 - 255*4)⇒ 1445 - 1190 - 1190 + 255*4⇒ 1445 - 1190*2 + (1445 - 1190)*4⇒ 1445 - 1190*2 + 1445*4 - 1190*4⇒ 1445*5 - 1190*6⇒ 1190*(- 6) + 1445*51190m + 1445n , where m = - 6 and n = 5 | |
| 42303. |
Find the point on y -axis which is equidistant to (-1,-2)and (0,-4)...please answer .. |
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| 42304. |
Find the value sin60 |
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| 42305. |
Find the value of sin 60 |
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Answer» √3/2 √3/2 √3/2 |
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| 42306. |
213446/35789 |
| Answer» ?5.9640112884? HoPe It HeLpS yOu?? | |
| 42307. |
Solve for x :‐ a÷(x‐a) + b÷(x‐b) = 2 |
| Answer» Solution:Given\xa0First take the LCM of denominators in the left hand side of the given equation.\xa0\xa0\xa0\xa0\xa0\xa0Now let\x92s factorise the quadratic equation in\xa0\xa0\xa0\xa0\xa0\xa0or\xa0 | |
| 42308. |
What is A-A-A criteria for triangles |
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Answer» ⛦Angle Angle Angle criteria⛦Eg-ABC and PQR are two ?\'s If Angle A=Angle PAngleB=Angle QAnd Angle C=AngleR Then the two triangles are similar by AAA criteria. AA (or AAA) or Angle-Angle SimilarityIf any two angles of a triangle are equal to any two angles of another triangle, then the two triangles are similar to each other.From the figure given above, if ∠\xa0A = ∠X\xa0and ∠C = ∠Z\xa0then ΔABC ~ΔXYZ.From the result obtained, we can easily say that,AB/XY = BC/YZ = AC/XZand ∠B = ∠Y |
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| 42309. |
The 4th term of an AP is 0. Prove that its 25th term is triple than its 11th term. |
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| 42310. |
A+B+B+B+80+90=100 solve this question |
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Answer» If uh already knew the answer den y uh asked????? Anyway I liked the answer??? ??? A stand for akad,B stand for bakkad, B stand for bambe, B stands for bo,so the answer is akkad bakkad bambe Bo assi nabbe poore sau Koi janta hai kya ise sabal ka answer ?IDK? ??? |
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| 42311. |
Find the valve of x for which distance between points A (x,7) and B (-2,3) is 4 root 5 |
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| 42312. |
Use euclid division leema 135 and 225 |
| Answer» Given numbers:\xa0135\xa0and\xa0225Here,\xa0225>135.So, we will divide greater number by smaller number.Divide\xa0225\xa0by\xa0135.The quotient is\xa01\xa0and remainder is\xa090.225=135×1+90Divide\xa0135\xa0by\xa090The quotient is\xa01\xa0and remainder is\xa045.135=90×1+45Divide\xa090\xa0by\xa045.The quotient is\xa02\xa0and remainder is\xa00.90=2×45+0Thus, the HCF is\xa045. | |
| 42313. |
What is zero of polynomial |
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Answer» Zero of a polynomial is the value of the variable like x, y, z (anything but not a number) by which the equation would be equal to 0 Zero of a polynomial is the value of the variable like x, y, z (anything but not a number) by which the equation would be equal to 0. Thank You Any value of X by which the whole expression equals to 0 . ? |
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| 42314. |
Prove that the tangents drawn at the end of a diameter of circle are parallel |
| Answer» .Given: A circle with center O And diameter AB Let PQ be the tangent at point A & RS be the tangent at point B To prove: PQ || RS Proof: Since PQ is a tangent at point A OA⟂ PQ (Tangent at any point of circle is perpendicular to the radius through point of contact) angle OAP=90°..(1) Similarly, RS is a tangent at point B OB ⟂ RS (Tangent at any point of circle is perpendicular to the radius through point of contact) angle OBS=90°....(2) From (1) & (2) angle OAP=90°& angle OBS=90°.Therefore angle OAP= angle OBS i.e. angle BAP= angle ABS For lines PQ & RS, and transversal AB angle BAP= angle ABS i.e. both alternate angles are equal So, lines are parallel : PQ II RS .... hope it would be helpful✌? | |
| 42315. |
Find the point on the x axis which is equidistant from (7,4) and (8,6) |
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Answer» By using section formula it would be x = 15/2= 7.5. Hlw |
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| 42316. |
what is the common difference of an a.p. in which a 21 -a 7 =84 . |
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Answer» a21 = a + 20da7 = a + 6d ATQ,a21-a7=84a+20d-(a+6d) = 84a - a + 20d - 6d = 8414d = 84d = 84/14d = 6. a21-a7=84(a+(n-1) d) - (a+(n-1)d)=84We know the value of n and a and d is common.Soo..(a+(21-1)d) - (a+(7-1)d)=84(a+20d) - (a+6d)=84a+20d-a-6d=84Sign change because i have open the bracket and a got cancel as opposite sign.20d-6d=8414d=84d=84÷14d=6So 6 is the answer. Your question is not cleared |
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| 42317. |
Maths kyu hota hai |
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Answer» Silai me hai na aaap cos or sin theta nikal thike Maths hamre liye imprtnt isliye h q ki vo agr tumhe contrater bnna h to usmei calculation or formula lagte h or silai karni h to usmei bhi calculation lagti h Kyuki maths ke bina calculations nahi ki ja sakti. |
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| 42318. |
2÷1+2×1+2-2=98-94+4-5-1+001 |
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| 42319. |
Is 2+√3 a monomial? |
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Answer» No nahi hai No |
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| 42320. |
Which is the best reference book can u suggest me for maths? |
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Answer» RD Sharma Just study ncert properly and solve previous year papers That\'s enough ? |
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| 42321. |
The value of cos 0 increasing an 0 Increase |
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Answer» No The value of cos theta decreases as the theta increases. |
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| 42322. |
If α and β are the zeroes of x²+5x+8 then the value of (α+β). |
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Answer» Answer=-5 -5 Answer: The value of α+β is -5.Step-by-step explanation:Since we have given thatLet α and β are the zeroes of the above quadratic equation.As we know the relation between zeroes and the coefficients of quadratic equation in the form of ax²+bx+c=0.Hence, the value of α+β is -5. |
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| 42323. |
Prove that cos a upon 1 + sin a + 1 + sin a upon cos a is equal to 2 sec a |
| Answer» L. H.S Cos a upon 1 + sin a+ 1 + sin a upon Cos a = cos square A + (1 + sin square a ) upon ( 1 + sin a) Cos a = cos square a + 1+ s i n square a 2 sin a upon ( 1 + sin a) + Cos a = sin square a+ cos square a+ 1 + 2 sin a upon ( 1+ sin a ) + Cos a = 1+1 + 2 sin a upon (1 + sin a) Cos a= 2 + 2 sin a upon (1+sin a) Cos a = 2 ( 1+sin a) + cos a = 2 •1 upon Cos a = 2sec a | |
| 42324. |
ABC is an isosceles triangle right angled at c prove that a b square is equal to 2 AC square |
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Answer» Copying all vidya mandir mid term exam questions , ????????? Given ABC is an Isosceles triangle right angled at c prove a b square is equal to 2 AC square proof (AB)² =(AC)² + (BC)² =(AB)²= (AC)²+ (AC)² [BC=AC] = (AB)²= 2(AC)² proved Copying all vidya mandir mid term exam questions , ????????? |
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| 42325. |
Explain why 7 *11 * 13 + 13 and 7 * 6 *5 * 4 *3 * 2 *1 + 5 are composite number |
| Answer» In the first no. 13 is common factor 13(7*11*1+1)In the second one 2 is common factor. 2(7*3*5*2*3*1*1+5)So they are composite numbers | |
| 42326. |
If tan a is equal to COT b prove that a + b is equal to 90 degree |
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| 42327. |
quadratic polynomial formula |
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Answer» Hii vaibhav Singh Parmar here The standard form of a\xa0quadratic equation\xa0is ax2+bx+c=0, where a,b and c are real numbers and a≠0. \'a\' is the coefficient of x2. It is called the\xa0quadratic\xa0coefficient. |
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| 42328. |
A and b are the zero of the quadratic polynomial |
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| 42329. |
If sinA+sin2A=1 find the value of cos12A+3cos10A+3cos8A+cos6A+2cos4A+2cos2A-2 from RD examples |
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| 42330. |
The taxi fare after each km when the fare is Rs 15 for the first km and Rs 8 for each additional km |
| Answer» a=15a+d=15+8=23a+2d=15+2*8=31a+3d=15+2*3=39a+4d=15+4*8=47 | |
| 42331. |
Find the point on x-axis which is equal distance from (2,-5) and (-2,9)? |
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Answer» (-7,0) Please answer the question ??? E |
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| 42332. |
Please give me class 10 ex14.1 q2 sol using direct method???????? |
| Answer» Say the question | |
| 42333. |
2 +253828+856-3883√8 |
| Answer» Why did Gandhiji withdraw the Non-Cooperation Movement? * | |
| 42334. |
X2-4X-77=0 |
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Answer» Hi x²-4x-77 = 0\xa0x²-11x+7x-77 = 0\xa0(splitting the middle term)x(x-11)+7(x-11) = 0(x+7)(x-11) = 0\xa0x + 7 = 0 and x - 11 = 0x = -7 and x = 11 If ab=13.3cmac=11.9cm and ec=5.1cm find ad |
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| 42335. |
5 year old kid terms exam questions |
| Answer» ( sin 30 t cos 30 ) ‐ ( sin 60 + cos 60 ) | |
| 42336. |
nirmal1234atla |
| Answer» Which type of question is this? | |
| 42337. |
Sin A + cos b = 1 a is 30 degree B is an acute angle find the value of B |
| Answer» 60° | |
| 42338. |
The circumference of a circle exceeds the diameter by16.8cm .Find the circumference of the circle ? |
| Answer» We know that circumference of a circle = 2π r.We know that diameter = 2r.Given circumference of a circle exceeds diameter by 16.8cm.2πr - 2r = 16.82r(π - 1) = 16.82r(22/7 - 1) = 16.82r(22 - 7/7) = 16.82r(15/7) = 16.830r = 16.8 * 730r = 117.6r = 117.6/30r = 3.92 cm.Therefore the radius of the circle = 3.92cm. | |
| 42339. |
(Sin 30°+cos 60°)-(sin 60° + cos 30°) is equal to: |
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Answer» Ok Please tell us full question after is equal to what 0 |
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| 42340. |
all decimal numbers are |
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| 42341. |
r s garwal real number solve all questions |
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Answer» Prove that which of the following number is rational root 6 .q no 2 . (_ root 3) question no 2 .\' 3 .1416 question no 2; 22 / 7 prove it |
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| 42343. |
prove irrational( 3+root 2) |
| Answer» Let 3+√2 is an rational number.. such that3+√2 = a/b ,where a and b are integers and b is not equal to zero ..therefore,3 + √2 = a/b√2 = a/b -3√2 = (3b-a) /btherefore, √2 = (3b - a)/b is rational as a, b and 3 are integers..It means that √2 is rational....But this contradicts the fact that √2 is irrational..So, it concludes that 3+√2 is irrational..hence proved. | |
| 42344. |
55+76+97-47+5 |
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Answer» 55+76+97-47+5=131+102-47=233-47=186 176 233-47= 186 186 |
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| 42345. |
What is secant? |
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Answer» Secant is a line which touches the circle at two points Secant is a line that touces the circle at two points. a line that intersects the curve at a minimum of two distinct points. The word secant comes from the Latin word secare, meaning to cut. In the case of a circle, a secant will intersect the circle at exactly two points. Secant is a line that touces the circle at two points. |
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| 42346. |
Sin 37 degree |
| Answer» 0.6018 | |
| 42347. |
Find the sum of the first 15 multiples of 8( arithmetic progression) |
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Answer» The answer is 960 The first 8 multiples of 8 are8, 16, 24, 32, 40, 48, 56,64These are in an A.P., having first term as 8 and common difference as 8.Therefore,\xa0a\xa0= 8d\xa0= 8S15\xa0= ?Sn\xa0=\xa0n/2\xa0[2a\xa0+ (n\xa0- 1)d]S15\xa0= 15/2\xa0[2(8)\xa0+ (15 - 1)8]=\xa015/2[6 + (14) (8)]=\xa015/2[16 + 112]= 15(128)/2= 15 × 64= 960\xa0 The answer is 960 |
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| 42348. |
Fector64 |
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Answer» 64 =2×2×2×2×2×2 64=2×4×4×2 64 = 2\xa0× 2\xa0× 2\xa0× 2\xa0× 2\xa0× 2 |
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| 42349. |
How many terms are there in the sequence 3,6,9,.....111? |
| Answer» The given sequence is an A.P. with first term\xa0a=3\xa0and common difference\xa0d=3. Let there be n terms in the given sequence. Then,nth\xa0term=111a+(n−1)d=1113+(n−1)×3=111n=37Thus, the given sequence contains 37 terms. | |
| 42350. |
Check whether 6n can end with the digit 0 for any natural number and |
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Answer» If any digit has the last digit 10 that means it divisible by 10.The factor of 10=2×5, So value of 6 n should be divisible by 2 and 5.Both 6 n is divisible by 2 but not divisible by 5.So, it can not end with 0. Yes, 6n can end with 0 . When we put n= 5 ( because n is any natural no.) Therefore 6*5= 30 which ends with 0. Thus, 6n can end with 0 |
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