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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 42401. |
2x+3y=0 what type of eaation |
| Answer» 2x+3y=0 is two variable linear equations. | |
| 42402. |
Coordinate geometry graph |
| Answer» Coordinate geometry deals with graphing (or plotting) and analyzing points, lines, and areas on the\xa0coordinate plane\xa0(coordinate graph). Each\xa0point\xa0on a number line is assigned a number. In the same way, each\xa0point\xa0in a plane is assigned a pair of numbers. | |
| 42403. |
How I can get mathematics practical work |
| Answer» In shop | |
| 42404. |
if sinA=cosA , than tanA is equal to:-(a) 1(b)-3(c)-1(d)2 |
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Answer» 1 1 Ans 1 1 1 |
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| 42405. |
0.2x+0.3y=1.3,0.4x+0.5y=2.3Solve the following pair of liner equation by the substitution method |
| Answer» Answer:x = 2 and y = 3Step-by-step explanation:Given :To Find : solve using substitution methodSolution : -----1\xa0------2Substitute the value of x from 1 in 2So, x = 2 and y = 3 | |
| 42406. |
Solve the following quadratic equation. 6?+1+52?+1= 3,? ≠ −1,−12 |
| Answer» Solve the following quadratic equation. 6/ ?+1 + 5/ 2?+1 = 3,? ≠ −1, −1 2 | |
| 42407. |
sample paper 2010 |
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Answer» Go to chrome and search the question then you will find the sample paper 2010.Hope u r recive the sample paper. Jtjtjtjtjtkt |
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| 42408. |
In the following APs find the missing terms in the boxes 1] -4 , ,. ,. ,. , 6. |
| Answer» -4,-2,0,2,4,6 following APs are missing terms | |
| 42409. |
Prove sina-cosa+1 |
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Answer» SinA-cosA=-1,-(cosA-sinA)=-1,cosA-sinA=1 SinA+CosA=1 |
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| 42410. |
Find the 31 term an AP whose 11th term is 38 and the 16th term is 73? |
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Answer» let first term of Ap is a and common difference is duse formulatn=a+(n-1) dnowt11 = a + (11-1)d = a + 10d = 38same wayt16 = a + 15d =73solve this equation thena= -32 and d= 7now t31 = a+30d= -32 + 210 = 178Hope this ans will be help for y let first term of Ap is a and common difference is duse formulatn=a+(n-1) dnowt11 = a + (11-1)d = a + 10d = 38same wayt16 = a + 15d =73solve this equation thena= -32 and d= 7now t31 = a+30d= -32 + 210 = 178\xa0 |
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| 42411. |
Can basic Students in mathematics take commerce |
| Answer» YESAfter introducing two levels of\xa0mathematics\xa0papers for class 10\xa0students,\xa0CBSE\xa0will now offer applied mathematics as an academic elective at the senior secondary level for those who do not want to take it up for higher studies or won\'t opt for engineering which require a broader understanding of the subject.The elective subject aimed at developing an understanding of basic mathematical and statistical tools and their applications in the field of\xa0commerce\xa0and social science, will be offered as elective for class 11students from 2020 academic session and ultimately for class 12 students from the year after.Students who had taken up basic mathematics in class 10 will be allowed to opt for applied mathematics at senior secondary level."Mathematics is widely used in higher studies — in the field of Economics, Commerce,\xa0Social Sciences\xa0and many others. It has been observed that the existing syllabus of mathematics aligns well with science subjects, but not so much with commerce or social science-based subjects in university education. Keeping this in mind, one more elective course in mathematics syllabus will be offered for senior secondary classes with an aim to provide students relevant experience in mathematics which can be used in the fields other than physical sciences," the\xa0Central Board of Secondary Education\xa0(CBSE) said in an official notification. According to CBSE officials, a course by this name was earlier designed as a skill subject. | |
| 42412. |
√1+sinQ/1-sinQ=√1-sinQ/1+sinQ=2secQ |
| Answer» | |
| 42413. |
Sn=m , Sm=n find Sm+n .Chapter 5 AP cbse |
| Answer» Let a is the first term and d is the common difference .(m - n) = -2a(m-n)/2 -(m-n)(m+n)/2+(m-n)d/21 = -2a/2 - (m+n)/2 + d/21 = -1/2 {2a + (m+n-1)d} ---------(1)from equation (1)S_{m+n} = -(m+n) | |
| 42414. |
Draw a line segment of 7.6cm and divides it in the ratio 5:8 measure to two parts |
| Answer» Step 1: Draw segment\xa0AB\xa0of length\xa07.6\xa0cm\xa0using a ruler.Step 2: Draw a ray\xa0AC\xa0having an acute angle with line\xa0AB.Step 3: Mark\xa013\xa0equidistant points on ray\xa0AC,\xa0A1\u200b,A2\u200b,A3\u200b,...,A13\u200bStep 4: Join\xa0A13\u200b\xa0to\xa0BStep 5: Draw\xa0A5\u200bP\xa0parallel to\xa0A13\u200bB.Point\xa0P\xa0divides\xa0AB\xa0in the ratio\xa05:8. Measuring the lengths, we get\xa0AP=2.9\xa0cm\xa0and\xa0PB=4.7\xa0cm. | |
| 42415. |
0.2x +0.3y =1.30.4x +0.5y 2.3 by substitution method |
| Answer» Given :To Find : solve using substitution methodSolution : -----1\xa0------2Substitute the value of x from 1 in 2So, x = 2 and y = 3 | |
| 42416. |
Prove that 1-tan2theta/1+tan2theta=cos2theta-sin2theta |
| Answer» | |
| 42417. |
P(2)/p(0)=p(x)=4X2+2x+5 find the following |
| Answer» | |
| 42418. |
Factorisation of 2965 |
| Answer» 5×593 | |
| 42419. |
How to find mean with respect to di |
| Answer» | |
| 42420. |
12.3 ka 8 no |
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Answer» Thanks ? Width of the track = 10 mDistance between two parallel lines = 60 mLength of parallel tracks = 106 mDE = CF = 60 mRadius of inner semicircle, r = OD = O’C= 60/2 m = 30 mRadius of outer semicircle, R = OA = O’B= 30+10 m = 40 mAlso, AB = CD = EF = GH = 106 mDistance around the track along its inner edge = CD+EF+2×(Circumference of inner semicircle)= 106+106+(2×πr) m = 212+(2×22/7×30) m= 212+1320/7 m = 2804/7 mArea of the track = Area of ABCD + Area EFGH + 2 × (area of outer semicircle) – 2 × (area of inner semicircle)= (AB×CD)+(EF×GH)+2×(πr2/2) -2×(πR2/2) m2= (106×10)+(106×10)+2×π/2(r2-R2) m2= 2120+22/7×70×10 m2= 4320 m2 |
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| 42421. |
I didn\'t understand (ii) |
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Answer» Give me solutiin Ok |
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| 42422. |
The number of polynomials having zeroes as -2 and 5 is |
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Answer» But how More than 3 |
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| 42423. |
In triangle PQR,XY ll QR such that 5PX=2QX. If PY=6cm then find the length of RY |
| Answer» 5PX = 2QXso, PX/QX = 2/5As QR || XY,So, PX/QX = PY/RYThus, 2/5 = 6/RYBy cross multiplication :2RY = 30RY = 15 cm( I hope this is correct ✔️) | |
| 42424. |
Find the value of p if px+3y=12 & 2x-2y=-7 having no solution |
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Answer» P/2= -3/2 (cross multiply)-2p = 2×3-2p = 6P = 6/-2 P = -3 ? P = -3 |
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| 42425. |
Guyzz please tell me short trick of learning all formula in maths |
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Answer» Write and see daily recall Cramming or understanding the concept behind them ..It\'s ur choice :) Yes it is,( Pakistan bhukha Pyasa Hindustan hara bhara) . Pakistan bhukha - p/b,Pyasa Hindustan - p/h, hara bhara - h/b. Then just reverse it for other 3 formula. |
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| 42426. |
Guys plzz tell me if is there any short trick of learning the formula of trigonometry |
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Answer» PbpHhbSct 2+1 Read my answer on Vikash Gautam question. Yup it is Ha |
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| 42427. |
From when is the boards going to start? |
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Answer» March Board exam will be start aftee the end of feb Till this time no time table is released |
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| 42428. |
The zeroes of polynomial P(x)= x^2 + 7x + 10 * |
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Answer» 8 X=-2,X=-5 X=-2 x^2 +7x+10x^2+5x+2x+10x(x+5)+2(x+5)(x+2) (x+5)x+2=0x=-2x+5=0x=-5. X^2+5x+2x+10X(x+5) 2(x+5)(X+2) (X+5)X+5=0X=-5and x+2=0X=-2The zeroes of the polynomial are -5 and -2 |
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| 42429. |
(x+2)^=2x(x^-1) |
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Answer» Use the identity and solve 0..????=!!!!«/":@/25*"#(@\'[email\xa0protected]$ |
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| 42430. |
What is cos 75°+sin 15° |
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Answer» Bhai calculation send kro plz √3/2 |
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| 42431. |
5 tan² A - 5 sec² A + 1 is equal to |
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Answer» -4 -4 -4 4 |
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| 42432. |
Which term of the AP 84, 80, 76..... will be the first negative term. |
| Answer» Given\xa0A.P:\xa084,80,76,72,...First\xa0term\xa0(a)\xa0=\xa084,We have to find when the first negative term appear in the\xa0A.P.Therefore,First negative term appear at 23 rd term in A.P | |
| 42433. |
For what value of k the pair of linear equations kx - 4y = 3 and 6x - 12y = 9 are consistent . |
| Answer» 3 | |
| 42434. |
A straight Highway |
| Answer» | |
| 42435. |
Root 7 is irrational |
| Answer» Yogita Ingle\xa01\xa0year, 7\xa0months agolet us assume that √7 be rational.then it must in the form of p / q [q ≠ 0] [p and q are co-prime]√7 = p / q=> √7 x q = psquaring on both sides=> 7q2= p2 ------ (1)p2\xa0is divisible by 7p is divisible by 7p = 7c [c is a positive integer] [squaring on both sides ]p2\xa0= 49 c2\xa0--------- (2)Subsitute p2\xa0in equ (1) we get7q2\xa0= 49 c2q2\xa0= 7c2=> q is divisible by 7thus q and p have a common factor 7.there is a contradictionas our assumsion p & q are co prime but it has a common factor.So that √7 is an irrational. | |
| 42436. |
If tan theta=cot theta,then the value of sec theta:(i) 2(ii) √2(iii) 1 |
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Answer» 2 nd root 2 (ii) root 2 (ii)root 2 is correct |
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| 42437. |
If the vertices of ABC are A(5. -1), B(-3, -2) and C-1. 8), find the length of median through A. |
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| 42438. |
If tan A = root2-1, then show that sinA. CosA=root2/4 |
| Answer» Tan A = √2 - 1Tan A = p / b { p: perpendicular , b:base}h : hypotenuse(√ 2 - 1 ) / 1 = p / bp= √2 - 1 , b = 1By pythagoras theorem ,p² + b² = h²(√2 - 1 )² + (1)² = h²2 + 1 - 2√2 + 1 = h ²h² = [4 - 2√2 ]Sin A = p / h , Cos A = b / hSin A Cos A = ( p * b ) / h²=> (√ 2 - 1 ) / ( 4 - 2 √2)Rationalize Denomonator ,=> ( √ 2 - 1 ) * ( 4 + 2 √2 ) / ( 4 - 2 √2 )(4 + 2 √2)=> (4 √2 + 4 - 4 - 2√2 ) / ( 16 - 8 )=> 2 √2 / 8=> √2 / 4Hence Proved | |
| 42439. |
Formula of Surface area and Volume |
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Answer» NamePerimeterTotal Surface AreaCurved Surface Area/Lateral Surface AreaVolumeFigureSquare4aa2—-—-Rectangle2(w+h)w.h—-—-Parallelogram2(a+b)b.h—-—-Trapezoida+b+c+d1/2(a+b).h—-—-Circle2\xa0π rπ\xa0r2—-—-Ellipse2π√(a2\xa0+ b2)/2 π a.b—-—-Trianglea+b+c1/2 * b * h—-—-Cuboid4(l+b+h)2(lb+bh+hl)2h(l+b)l * b * hCube6a\xa06a24a2a3Cylinder—-2 π\xa0r(r+h)2πrhπ\xa0r2\xa0hCone—-π\xa0r(r+l)π\xa0r l1/3π r2\xa0hSphere—-4\xa0π r24π r24/3π r3Hemisphere—-3\xa0π r22\xa0π r22/3π r3\xa0 @Deep Arshnoor For all 3d shapes For which 3d shape?? |
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| 42440. |
If cot teetha=7/8;evaluate:1(1+sin teetha) (1-sin teeha) /(1+cos teetha (1-cos teetha) |
| Answer» Step-by-step explanation:We know that\xa0We are given that\xa0On comparingBase = 7Perpendicular = 8To find hypotenuse we will use Pythagoras theoremNow we are supposed to find\xa0Substitute the valuesHence\xa0 | |
| 42441. |
1+ cos theta / sin2 theta equals 1/1- cos theta, by using identities |
| Answer» | |
| 42442. |
p(x)=x+3 then p(x)+p(-x) is equal to |
| Answer» Answer:The value of p(-x)+p(x) is 6.Step-by-step explanation:The given function is .... (1)Substitute x=-x, it the given function. ..... (2)Now add the equations (1) and (2).Combined like terms.Therefore the value of p(-x)+p(x) is 6. | |
| 42443. |
12+23 |
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Answer» 35 35 answer Kesa class 10th mai aaya? 147*+258 |
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| 42444. |
What is mean by equally likely outcomes |
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Answer» ExampleEach numeral on a die is equally likely to occur when the die is tossed.\xa0Sample space of throwing a die: { 1, 2, 3, 4, 5, 6 }\xa0\xa0\xa0\xa0From this we can make conclusions such as the following:\tGetting a 3 on the toss of a die and getting a 5 on the toss of a die are equally likely events, since the probabilities of each event are equal.\tGetting an even number on the toss of a die and getting an odd number on the toss of a die are equally likely events, since the probabilities of each event are equal.\tGetting a 1, 2 or 3 on the toss of a die and getting a 4, 5 or 6 on the toss of a die are equally likely events, since the probabilities of each event are equal. The chances of both the events occuring is equal. |
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| 42445. |
Show that the product of 3 consecutive numbers are divisible by 6. |
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Answer» Thank you!! ✌?? Let three consecutive positive integers be, n, n + 1 and n + 2.\xa0When a number is divided by 3, the remainder obtained is either 0 or 1 or 2. ∴ n = 3p or 3p + 1 or 3p + 2, where p is some integer.If n = 3p, then n is divisible by 3.\xa0If n = 3p + 1,\xa0⇒\xa0n + 2 = 3p + 1 + 2 = 3p + 3 = 3(p + 1) is divisible by 3.\xa0If n = 3p + 2,\xa0⇒\xa0n + 1 = 3p + 2 + 1 = 3p + 3 = 3(p + 1) is divisible by 3.\xa0So, we can say that one of the numbers among n, n + 1 and n + 2 is always divisible by 3. ⇒ n (n + 1) (n + 2) is divisible by 3.\xa0Similarly, when a number is divided 2, the remainder obtained is 0 or 1.\xa0∴ n = 2q or 2q + 1, where q is some integer.\xa0If n = 2q\xa0⇒\xa0n and n + 2 = 2q + 2 = 2(q + 1) are divisible by 2.\xa0If n = 2q + 1\xa0⇒\xa0n + 1 = 2q + 1 + 1 = 2q + 2 = 2 (q + 1) is divisible by 2.\xa0So, we can say that one of the numbers among n, n + 1 and n + 2 is always divisible by 2.\xa0⇒ n (n + 1) (n + 2) is divisible by 2.\xa0Hence n (n + 1) (n + 2) is divisible by 2 and 3.∴ n (n + 1) (n + 2) is divisible by 6.\xa0 |
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| 42446. |
Find the circumference of a circle whose area is 301.84sqcm |
| Answer» Ar.= πr2=301.84sqcm r2=301.84×7÷22=96.04r=√96.04=9.8cmr=9.8circumference=2πr=2×22÷7×9.8=44×1.4=61.6 cm | |
| 42447. |
Can I get 10 case study based questions in triangles chapter |
| Answer» 1. In ΔLMN, ∟L = 50°and ∟N= 60°. If ΔLMN is similar to ΔPQR, then find ∟Q. (AI CBSE 2009)2. If areas of two similar triangles are in the ratio 25:64, write the ratio of their corresponding sides. (AI CBSE 2009)3. D, E and F are mid points of sides BC, AC and AB respectively of triangle ABC. Find ar(ΔDEF)/ar(ΔABC). ( AI CBSE 2008)4. If one diagonal of a trapezium divides the other diagonal in the ratio 1:2. Prove that one of the parallel sides is double the other. (CBSE 2010)5. ABC is a right triangle, right angled at A, and D is the mid-point of AB. Prove that BC2\xa0= CD2\xa0+ 3BD2. (AI CBSE 2009 C)6. If the diagonals of a quadrilateral divide each other proportionally, prove that it is a trapezium. (CBSE 2008)7. Triangle ABC is right angled at B and D is the mid-point of BC. Prove that:- AC2\xa0= 4AD2\xa0. 3AB2.(AI CBSE 2008 C)8. E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ΔABC is similar to ΔCFB. (AI CBSE 2008) | |
| 42448. |
Case study practice questions |
| Answer» Search it on Google ? | |
| 42449. |
Hsisa |
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Answer» Ok Don\'t post personal information, mobile numbers and other details.Don\'t use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.Ask specific question which are clear and concise.\xa0 |
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| 42450. |
Cgy |
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Answer» What do you mean by power shaing ಹಾಯ್ ಮಚ್ಚ,ಲೋ ಗುಲ್ಡು ಏನ್ ಕಳ್ಸಿದ್ಯೋ ನಿಂಗೆ ಅರ್ಥ ಆಗ್ಬೇಕು ಕಣಲೇ????? |
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