12.3 ka 8 no

1.	12.3 ka 8 no
Answer» Thanks ? Width of the track = 10 mDistance between two parallel lines = 60 mLength of parallel tracks = 106 mDE = CF = 60 mRadius of inner semicircle, r = OD = O’C= 60/2 m = 30 mRadius of outer semicircle, R = OA = O’B= 30+10 m = 40 mAlso, AB = CD = EF = GH = 106 mDistance around the track along its inner edge = CD+EF+2×(Circumference of inner semicircle)= 106+106+(2×πr) m = 212+(2×22/7×30) m= 212+1320/7 m = 2804/7 mArea of the track = Area of ABCD + Area EFGH + 2 × (area of outer semicircle) – 2 × (area of inner semicircle)= (AB×CD)+(EF×GH)+2×(πr2/2) -2×(πR2/2) m2= (106×10)+(106×10)+2×π/2(r2-R2) m2= 2120+22/7×70×10 m2= 4320 m2

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