How many terms are there in the sequence 3,6,9,.....111?

1.	How many terms are there in the sequence 3,6,9,.....111?
Answer» The given sequence is an A.P. with first term\xa0a=3\xa0and common difference\xa0d=3. Let there be n terms in the given sequence. Then,nth\xa0term=111a+(n−1)d=1113+(n−1)×3=111n=37Thus, the given sequence contains 37 terms.

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