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There are 7 total places. 2 is used only twice. Do select any 2 position. So 7c2 Remaining places have 2 possibilities each (1 or 3) So 2^5 TOTAL=7c2 * 2^5=672

1000 is the right answer

thanks

option a is correct as;

The answer is as follows-

[(4÷4)+ 4]×4=20 = (1 + 4)×4= 5×4= 20

a) 100 m below so -100m b) 25 C above so +25 c) 15 C below so -15 d) five number less than 0 -1,-2,-3,-4,-5

Total CP = 25000 + 6000 = 31000 SP = 35000 Profit percentage = (35000-31000)*100/31000 = 4*100/31 = 12.9%

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Total handshakes= 6*5/2= 15

Here n= 6 n-1= 5so total hand shakes= 6*5/2= 15

answer is 15. this is the correct answer

d) 15 is the correct answer

Lenth of rope=169/2m=84.5mCut into 13 equal piecesSo lenght of each rope=84.5/13=6.5m

177 1/3=552/3; 22/3; 552/3× 3/22=552/22=27.5

Here selling price is more than cost price.

Therefore, Profit % = ((SP-CP)/CP) * 100

= ((972-900)/900)*100

= 8%

tysm

profit per cent = (12/72)*100=50/3 is the correct answer 🏆 🏆🏆

50/3 % is the best answer

20

a answer is the correct

Cp of one knife= 10/11

Suppose he bought (11*10) = 110 chocolateCP = 10/11 * 110 = Rs. 100SP = 11/10 * 100 = Rs. 121Gain 21%

Option D

11% is right answer

20%

percent

Thenet domestic product(NDP) equals the grossdomestic product(GDP) minus depreciation on a country's capital goods.Net domestic productaccounts for capital that has been consumed over the year in the form of housing, vehicle, or machinery deterioration.

Net national product refers to gross national product, i.e. the total market value of all final goods and services produced by the factors of production of a country or other polity during a given time period, minus depreciation. Similarly, net domestic product corresponds to gross domestic product minus depreciation.

Let, A be a skew-symmetric square matrix ofn×n, where n is odd, By general properties of determinants,

det(A)=det(A^T)…(i)

However, since A is a skew-symmetric matrix where

aij=−aij(i,j are rows and column numbers ),

∴∴In case of skew-symmetric matrix,

A^T=−ANowdet(−A)=det(A^T)But,det(−A)=(−1)^ndet(A)

where n is no. of rows/columns in a square Matrix.

∴det(A^T)=(−1)^n∵n is odd,(−1)°n=−1∴det(A^T)=−det(A)...iiSubtractingequation(ii)from(i),∴2det(A)=det(A^T)−det(A^T)=0∴det(A)=0

Hence matrix A is singular.... By definition of singular matrix

Hence proved.

Yes. The inverseA−1A−1of invertible symmetric matrix is also symmetric

16(a+b)² -9(a-b)²[4(a+b)]² - [3(a-b)]²

= [4a+4b -3a+3b]× [ 4a+4b+3a-3b]= [a+7b]×[7a+b]

Degree of the polynomial is the highest power on the variables. = Highest power is seen on x, as x^6. Hence the degree is 6.

for a focal length of 11m, object should be placed at a distance less than 11m

...

A+Bis the singular....

a+b is the singular.....

Let, A be a skew-symmetric square matrix of n×n , where n is odd, By general properties of determinants,

det(A)=det(AT)…(i)However, since A is a skew-symmetric matrix where

aij=−aij (i,j are rows and column numbers ),

∴ In case of skew-symmetric matrix,

AT=−ANowdet(−A)=det(AT)But,det(−A)=(−1)ndet(A)where n is no. of rows/columns in a square Matrix.

∴det(AT)=(−1)ndet(A)∵nisodd,(−1)n=−1∴det(AT)=−det(A)…(ii)Subtractingequation(ii)from(i),∴2det(A)=det(AT)−det(AT)=0∴det(A)=0Hence matrix A is singular.... By definition of singular matrix

Hence proved.

option (c) is correct i.e skew symmetric matrix of odd order is singular.

not it's not crrct

what is the rank of a non singular matrix

Therank of a matrixis defined as (a) the maximum number of linearly independent column vectors in thematrixor (b) the maximum number of linearly independent row vectors in thematrix. Both definitions are equivalent. For an r x cmatrix, If r is less than c, then the maximumrankof thematrixis r.

1 is tne correct answer

1is correct answer..........

don't answer this question

A non-singular matrixis a square one whose determinant is not zero. Therankof amatrix[A] is equal to the order of the largestnon-singularsubmatrix of [A]. It follows that anon-singularsquarematrixof n × n has arankof n. Thus, anon-singular matrixis also known as a fullrank matrix.

1. is the right answer

what is the rank of a non singular matrix

Anon-singular matrixis a square one whose determinant isnotzero. Therankof amatrix[A] is equal to the order of the largestnon-singularsubmatrix of [A]. It follows that anon-singularsquarematrixof n × n has arankof n. Thus, anon-singular matrixis also known as a fullrank matrix

Anon-singular matrixis a square one whose determinant is not zero. Therankof amatrix[A] is equal to the order of the largestnon-singularsubmatrix of [A]. It follows that anon-singularsquarematrixof n × n has arankof n. Thus, anon-singular matrixis also known as a fullrank matrix

Fxgjdyt the UK and Ireland destinations only a few days later today to find out what you are looking for the

The above matrix has a zero determinant and is therefore singular. It has no inverse. It has two identical rows. In other words, the rows are not independent. If one row is a multiple of another, then they are not independent, and the determinant is zero. (Equivalently: If one column is a multiple of another, then they are not independent, and the determinant is zero.)

Therankof a matrix is the maximum number of independent rows (or, the maximum number of independent columns). A square matrixAn×nis non-singular only if its rank is equal to n.

the rank of Non-singular matrix is----1

Anon-singular matrixis a square one whose determinant is not zero. Therankof amatrix[A] is equal to the order of the largestnon-singularsubmatrix of [A]. It follows that anon-singularsquarematrixof n × n has arankof n. Thus, anon-singular matrixis also known as a fullrank matrix

det|A| = 6*4-12*2 = 24-24 = 0

so, A is a singular matrix

A square matrix that is not singular, i.e., one that has a matrix inverse. Nonsingular matrices are sometimes also called regular matrices. A square matrix is nonsingular iff its determinant is nonzero

da x bc =dabc

.........

da ×bc=dabc is correct answer

a) circle = 3608 parts are there so each part is 360 /8=45so percentage is (3×45/360)×100=3/8 ×100=37.5%

b) square 360 is the total out of which 4 parts are there 360/4 =90

3parts are filled so 3×90/360= 3/4 *100 %= 75%

37.5 and 75 is the answer to your question

a) 3/8×100 300/8 =37.5 %b) 3/4×100300/4 = 75% Ans.

a) 3/8×100300/8=37.5%b) 3/4×100300/4=75% ans

For the first figure 3/4 th portion is shaded, so it is 75 percent.For the second figure, 1/2 portion is shaded considering 1/4+1/8+1/8.

Area of shaded region = Area of square - Area of two semicircles= 8*8 - (22/7)*4*4= 64 - 176/7= 272/7 sq cm

draw LM as base with length =5.4cm

from point L make angle 115°

from point M make angle 70°

extend the lines of both the angles till the intersect

mark the point of intersection as N

Here is your answer,

According to the question, each side of PQRS must be 42m as PQRS is a square.There are two semi circles on two sides of the square.So, the semi circle's diameter = the side of the square = 42mradius = 42/2 = 21m

as we know the formula forarea of semi circle = Πr²where, Π = 22/7

area = 22/7 × (21)²= 22/7 × 21 × 21= 22 × 3 × 21= 1386m²

so this is the area of bed of one side,total area of beds = 2×1386 = 2772m²

Hence, the total area of beds is 2772m².

Bhai ye 6root2 kaise aaya

please check the updated solution

thank you very much

thank you very much