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gubcf Huntington junction

thanku .i know the answer i only check it that it's work properly or not

thank u for giving answer .

your answer will be 264m

first part is 18 and second part is 2.

first part 20second part 1620*2+16*5=40+80=120

1st is 18 and 2nd is 2 this is the answer

1st is 18 and 2nd is 2 this is the ans of the ques

i) 18/12=1.5 40/18=2.22so not in proportionii) 5/3=1.676/5=1.3so not in proportioniii) 8/5=1.6 10/8=1 25so not in proportioniv) 12/10=1.2 5/12=0.42so not in proportion

rope A is 40%hence40/100*5=2m

what is your question

i understand the statement but where is your question

length of rope = 40 m

length of one piece of rope = 10/3 m

ER. RAVI KUMAR ROY

number of pieces of rope = 40 /(10/3) = 40*3/10 = 12 pieces ANS...

12 pieces is the correct answer

total length of rope = 500 m

length of rope cut off = 100 m

remaining length of rope = 500 - 100 = 400 m

ER. RAVI KUMAR ROY

length of each piece of rope cut off = 7 m

number of pieces in 400 m = 57

length of rope remaining = 400 - (57 x 7) = 400 - 399 = 1 m. (ANS)

correct answer is one

I don't know please like

Area of field = 60 X 40 = 2400 m²The horse is tied at one corner of field so area horse can graze = ¼ area of circle of radius equal to length rope from which horse is tied Area horse can graze = 22/7 X 14 X 14 = 616 X 14 = 154m²

SP of the chair = Rs 1375Gain% = 10

CPofthechair={100(100+Gain%)×SP}CPofthechair={100(100+Gain%)×SP}

={100(100+10)×1375}=137500110=Rs.1250

hopessss

Length of arc =θ360×2πrθ360×2πr

72360×2×227×r=8872360×2×227×r=88

r=88×7×36072×2×22=70m

length of arc=8360×2x227xr=88; r=88×7×36072×2×22=70m

2x+3x=1255x=125x=125/5=25

Therefore ,Ist part =2x=2*25= 502nd part=3x=3*25= 75

2x+3x=125 5x=125 x=25 hence 50 and 75

Let one part be x and other will be 4x.

according to question. 4x-x =15 =>3x =15 =>x =5

Hence, the number =x+4x =5x =5*5 =25.

y= 112 is correct answer plz like

ans is 2/8 is the according to the question cholres is 47% ams

Given, Speed of express train = x km/hrThen speed of slower train = (x - 12) km/hr

We know, Travel time = Distance/Speed

240/(x-12) - 240/x = 1

LCM: x(x-12)240x - 240x + 2880 = x^2 - 12xx^2 - 12x - 2880 = 0(x + 48)(x - 60) = 0x = -48(reject x>0)orx = 60

Therefore, Speed of the express train= 60 km/hr

please send me in a simple solution

Let the speed of passenger train is x kmp and that of express train is y kmphDistance = 168 km

Time taken by Express train to travel between akola to bhusawal = 168/y hour

Time taken by passenger train to travel between akola to bhusawal = 168/x hour

According to the question Express train taking 1 hour less168/y + 1 = 168/x168x + xy = 168y168x - 168y + xy = 0..........(1)

ATQy = x + 14............(2)Substitute from eq 2168x - 168(x + 14) + x(x + 14) = 0168x - 168x - 2352 + x^2 + 14x = 0x^2 + 14x - 2352 = 0x^2 + 56x - 42x - 2352 = 0x(x + 56) - 42(x + 56) = 0(x + 56)(x - 42) = 0x = - 56, 42

negative value can be discarded.

Thus Speed of passenger train 42 kmph

Speed of express train = 42+14= 56 kmph

tq

ans of the first question is A (-3,2) because you know two coordinates then apply mid point formula and get your answer

let unknown coordinate be (x,y) now x+3/2=0 so x=-3 and -2+y/2=0 and y=2

ans of 2nd question is D

txs bhai