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Dividing by 7 so3*7/7 and 4*7/721/7 and 28/7nowsix number21/7,22/7,23/7,24/7,25/7,26/7,27/7

We can write 3 and 4 as 3/1 and 4/1 .Then we should multiply both numerator and denominator by 7 then we get -3/1×7\7 = 21/7 and4/1×7/7 = 28/7 .So , six rational number between them are 21/7,22/7,23/7,24/7,25/7,28/7

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For that we will multiply by 10/10so10/40and 20/20 to 1/2so20/40now 11/40,12/40,13/40,14/40will be 4 rational numbers

31/50,16/25,33/50,17/25,7/10,18/25,37/50,19/25,39/50

To find rational number between 5/6 and 3/4 both should have same denominator

Take LCM of 6 and 4

Hence,5/6 = 5*2/12 = 10/123/4 = 3*3/12 = 9/12

Now, Multiply and divide each rational number by 2

Therefore,Rational number between 20/24 and 18/24 is 19/24

the terms would be8/27, (8/27)r, (8/27)r^2, (8/27)r^3, (8/27)r^4, (8/27)r^5, (8/27)r^6 , -81/6

(8/27)r / (8/27) = (-81/16) / ((8/27)r^5)

r^7 = (-81/16)(27/8)r^7 = (-3)^7 / 2^7r = -3/2

Now terms are (8/27)*(-3/2) = - 4/9(8/27)*(9/4)= 2/3(8/27)*(-27/8) = - 1(8/27)*(81/16) = 3/2(8/27)*(-243/32) = - 9/4(8/27)*(728/64) = 27/8

thanks

multiple 5 with 10 and it will give u the answer of this question.to simple sum is this

To find three rational numbers between - 1/2 and 1/4

Multiply and divide first rational number by 4 and second number by 2

Therefore,-1/2 = - 4/81/4 = 2/8

Now,Three rational numbers between - 4/8 and 2/8 are - 3/8, - 2/8, - 1/8

what is the question .I can't able to understand.

-2/3 = -6/9 = 6/-9 is the right answer

-6/9=6/-9 is the right answers

-6/9=6/-9 is the right answers

what is the ques we are able to understand

three rational number between 3 and 3.5 are3.1 =31/103.2 =32/10=16/53.3 =33/103.4 =34/10= 17/5

First term = 3 Last term = 19 3 arithmetic terms need to insert difference = (19-3)/4 = 16/4 = 4 3 , 7 , 11 , 15 , 19 3 arithmetic terms = 7,11,15

A watt is a joule per second.A watt-second is a joule.A kilowatt-second is 1000 * jouleA kilowatt-hour is 60*60* 1000 * jouleA kilowatt-hour is 3 600 000 joules.

Given selling price of buffaloes SP = Rs 20000 each

Gain on one buffalo = 5%SP = CP1( 1 + 5/100)CP1 = 20000*(20/21)CP1 = 19047.62 Loss on second buffalo = 10%SP = CP2( 1 - 10/100)CP2 = 20000*11/10CP2 = 22000

Total selling Price = 40000

Total cost price = CP1 + CP2= 19047.62 + 22000= 41047.62

Since total cost price < total selling priceOverall loss= Rs 41047.62– Rs 40000 = Rs 1047.62

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First see,area of the ring =π (42² - 21²) = 4158 cm²now, we have to remove some parts,that part = (sector formed by bigger circle) -( sector formed by smaller circle) =π (42)²×60°/360 -π(21)²×60°/360° =(π/6)×(42² -21²) = 693 cm²so the required area = 4158 - 693 = 3465 cm²

why33*21

Because area of unshaded region is 33×21 = 693

thank you bhai

60 degree is the right answer

15 was the right answer

If it's a

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1)2*2*32)3*3*23)2*2*2*2*34)7*2*2*26)17*2*2*27)7*2*3*2*38)7*2*3*2*59)7*7*13

Given : In ΔABC, P, Q and R are the mid points of sides BC, CA and AB respectively. AD ⊥ BC.

To prove : P, Q, R and D are concyclic.

Proof :

In ΔABC, R and Q are mid points of AB and CA respectively.

∴ RQ || BC (Mid point theorem)

Similarly, PQ || AB and PR || CA

In quadrilateral BPQR,

BP || RQ and PQ || BR (RQ || BC and PQ || AB)

∴ Quadrilateral BPQR is a parallelogram.

Similarly, quadrilateral ARPQ is a parallelogram.

∴ ∠A = ∠RPQ (Opposite sides of parallelogram are equal)

PR || AC and PC is the transversal,

∴ ∠BPR = ∠C (Corresponding angles)

∠DPQ = ∠DPR + ∠RPQ = ∠A + ∠C ...(1)

RQ || BC and BR is the transversal,

∴ ∠ARO = ∠B (Corresponding angles) ...(2)

In ΔABD, R is the mid point of AB and OR || BD.

∴ O is the mid point of AD (Converse of mid point theorem)

⇒ OA = OD

In ΔAOR and ΔDOR,

OA = OD (Proved)

∠AOR = ∠DOR (90°) {∠ROD = ∠ODP (Alternate angles) & ∠AOR = ∠ROD = 90° (linear pair)}

OR = OR (Common)

∴ ΔAOR congruence ΔDOR (SAS congruence criterion)

⇒ ∠ARO = ∠DRO (CPCT)

⇒ ∠DRO = ∠B (Using (2))

In quadrilateral PRQD,

∠DRO + ∠DPQ = ∠B + ( ∠A + ∠C) = ∠A + ∠B + ∠C (Using (1))

⇒ ∠DRO + ∠DPQ = 180° ( ∠A + ∠B + ∠C = 180°)

Hence, quadrilateral PRQD is a cyclic quadrilateral.

Thus, the points P, Q, R and D are concyclic.

Total distance travelled = 160 + 630 + 646.96 = 1436.96m

yes it is correct answer is 56