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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 451. |
3. Find the volume of each of the following.Length9 mm(b) 12.5 cm(c)9.6 m(d) 52 cmBreadthHeightVolume6 mm8 cm6 m14 cm7 mm10 cm8 m29 cm |
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Answer» (a)9×7×6=378b)12.5×10×8=1000c)9.6×8×6=460.8d)52×29×14=21112 Thanks |
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| 452. |
39, if x = 2 + 3i then x3-x2 + x + 46 =a)7 b)-7 c)14 d)2 |
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| 453. |
9. In the figure 7.12, a cylindrical 1wrapper of flat tablets is shownThe radius of a tablet is 7 mm andits thickness is 5 mm. How manysuch tablets are wrapped in thewrapper?UFES14 mm10 cm |
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| 454. |
10 A small metallic washer is of 7 mm radius with a hole of 3.5 mm radius. What is the area of thewasher? |
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| 455. |
qualsIf 1, log, (31- + 2), log,(4.3* - 1)(a) log34(c) 1 - log4 3are in A.P. thenx e(b) 1-l0gs 4(d) log4 3 |
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| 456. |
861S8C8109६S9L088919o087.0597एड05६8TlSL1090६ |
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| 457. |
(A) 8(B) 93281(C) 84 |
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Answer» 9 - 3 3/11 * 1 2/9 ÷ 7/9 ÷ 5 1/7 = (9 - 36/11) * (11/9 ÷ 7/9 ÷ 36/7) = (63/11) * (11/7 * 7/36) = (63/11) * (11/36) = 63/36 = 7/4 |
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| 458. |
log4(1/64) |
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Answer» log_4 (64^-1)-log_4 (4^3)-3log _4 (4)-3 will be the answer |
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| 459. |
a) 1/81b) 81c) 243/d) 343A-12--225 दोनोकामान है - |
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| 460. |
1\81+1\91= |
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| 461. |
3|09 | के |
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Answer» 3/10 +4/83+4=7lcm of 10,82×2×2×5407/40 - 3/10 + 4/ 8; 4/ 8 - 3 /10; 1/2 - 3/10 10-6/20; -4/20=-1/5 7/40 is a good answer 3/10 + 4/8 LCM=403×4 + 4×5 12+2032/40 3×4=12 10×8=80 the answer is 92 -1. / 5=======-0.2. |
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| 462. |
शा हि. गा i हि olS dvEe ) zV“L’Hl’jकी पा ० णण्तुआए) 09 पथ ८५६ प४ ,81 पट) ६ 9... 90 500 . 7६ पाई |
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Answer» L.H.S1+tan^2A/1+cot^2A=(1+sin^2A/cos2A)/(1+cos^2A/sin^2A)=((cos^2A+sin^2A)/cos^2A)/(sin^2A+cos^2A)/sin^2A=(1/cos^2A)/(1/sin^2A)=1/cos^2A*sin^2A/1=sin^2A/cos^2A=tan^2A M.H.S(1-tanA/1-cotA)^2=(1+tan^2A-2tanA)/(1+cot^2-2cotA)=(sec^2A-2tanA)/(cosec^2A-2cosA/sinA)=(sec^2A-2*sinA/cos A)/(cosec^2A-2cosA/sinA)=(1/cos^2A-2sinA/cosA)/(1/sin^2A-2cosA/sinA)=[(1-2sinAcosA)/cos^2A]/[(1-2cosAsinA)sin^2A]=(1-2sinAcosA)/cos^2A*sin^2A/(1-2sinAcosA)=sin^2A/cos^2A=tan^2A R.H.S=tan^2A Hence L.H.S=M.H.S=R.H.S |
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| 463. |
o|=09 | ० |
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Answer» 1/6+2/6=1+2/6=3/6=1/2 |
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| 464. |
29 x3 x5565 x 102 x 15314. |
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Answer» 2^9*3^7*5^5/(2*3)^5*(2*5)^2*(3*5)^3= (2)^[9-7]*(3)^[7-6]*(5)^[5-5]= (2)^2*(3)^1*(5)^0= 4*3*1= 12 ans |
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| 465. |
In A4C drtind the aittiesiu12) In the figure, prove that LA + LB + LC + LD + /E t LF-360s.é. |
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Answer» Actually in a equlateral triangle all the sides and angles are equal. One side of an equlateral is 60 degree so when 6 sides are are multiplied by 60 we will get 360 degree . This figure is a compination of 2 triangles because of angle sum property one triangle is equal to 180 degree. So 2 triangle is equals to 360 degrees. In △ACE, By angle Sum property of triangle∠A+∠C+∠E=180° ...(1)Similarly, in △BDF∠B+∠D+∠F=180° ...(2)Adding (1) and (2), we get∠A+∠B+∠C+∠D+∠E+∠F=360° |
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| 466. |
-T. lf the LCM of 12 and 42 is 10m + 4, then find the value of m |
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| 467. |
ich direction will you face if you start facing(a) east and make 2 of a revolution clockwise?(b) east and make 1 1 of a revolution clockwie?234(c) west and makeof a revolution anti-clockwise?(d) south and make one full revolution?(Should we specify clockwise or anti-clockwise for this last question? Why not?)you turned through if you stand facing |
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| 468. |
eseWhat is the angle name for half a revolution?What is the angle name for one-fourth revolution?Draw five other situations of one-fourth, half and three-fourth revolution ona clock. |
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| 469. |
\frac { 7 } { 81 } ( 179 - 10 ^ { - 20 } ) \quad ( 2 ) \frac { 7 } { 9 } ( 99 - 10 ^ { - 20 } ) \quad ( 3 ) \frac { 7 } { 81 } ( 179 + 10 ^ { - 20 } ) ( 4 ) \frac { 7 } { 9 } ( 99 + 10 ^ { - 20 } ) |
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| 470. |
esthevalueof(81)Find the value of (81)916 x (81)90.09x(81)"09 |
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| 471. |
(4*1/sqrt(81))*(81^(1/2) %2B 81^(3/2)) |
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| 472. |
10 1ogA1og3 4log3 8log4 81 |
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| 473. |
3, 10, 24, 45,..(A) 63(C) 81(B) 73(D) 94 |
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Answer» option (B) is correct. Full solution send me |
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| 474. |
he quadratic polynomial p(x) with-81 and 3 as productand one of the zeroes respectively is:(a) x2 + 24x-81 (b) 2-24x-81(c) a2 24x + 81 (d) +24x81 |
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Answer» (a) is correct option |
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| 475. |
10, Find the number whose 6 % is 81. |
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| 476. |
5. 132 x 52 - 102 x 62 = ? -(1) 52 (2) 54 (3) 53 (4) 5 |
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Answer» answer (3)h ok bhai 3 he (3) is the correct answer answer is option 3 ok bhai so option 2 5'4 is the correct answer so option (2)5,4 is is the the correct answer point 2 is correct . answers is (c)hope you like it option "b" is right answer the answer is 625 is 5^ show option (2) 5*4 is the correct answer The correct answer is 625 and 5^4 answer is 3 that right answer is option (2) 5 power 4 3 ha bro12356866765765756766767 (3) is the correct answer good luck option 2 is the right answer 625 is the right answer (13^2×5^2)-(10^2×6^2)=65^2-60^2 =5^2 answer 1 wala hai thik the answer of this equation is option no.(2) Option 2. is the correct answer. 2 option is right answer 13sq×5sq-10sq×6sq169×25-100×364225-3600625 13²x5²-10²x6²169x25-100x364225-3600625625=5⁴so 5⁴ is answer 65 power 460 power 465-60=5 answer 3) 5 to the power of 4 second one is write answer iska answer pahala Wala sahi hai 5² 169×25-100×36=4225-3600=625 option 3 is the correct answer 125 ya option no.3 is the right ans option b is right answer 13*13*5*5-10*10*6*6169*25-100*36845-3600-2755 (2) 168*25-100*364225-3600√625=5*5*5*5 it answer is obtion 3 hoga (2).13²×5²-10²×6² = 169×25-100×36 = 4225-3600 =625 =5⁴ This question answered by (B) correct 169*25=4225100*36=36004225-3600=6255*5*5*5=625 13²*5²=65²10²*6²=60²65²-60²A²-B²=(a+b)*(a-b)(65+60)*(65-60)=125*5=625:. 625=5⁴ the answer of this question is 2nd option answer 2 hoga............. 5 the answer 《2》 5 ki power 4 is Wright 5*5*5*5 answer (2) 5⁴ |
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| 477. |
reo. Simplify (81), (81)Âź. |
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Answer» (81)-¼÷(81)¼ =(3)-¹÷3 =(1/3)*(1/3) =1/9 |
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| 478. |
1. किसी कक्षा के सात छात्रों का वजन क्रमश: 48, 52, 40, 53, 60, 54 तथा 49किया है। उन छात्रों का औसत वजन क्या हैं ? |
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Answer» yes it is correct answer average weight of class =total sum weight of class /total number of student = 48+52+40+53+60+54+49/7 sorry I has posted it's answer incomplete =353/7=50.85 Total weight=48+52+40+53+60+54+49=356Average wt=356/7=50.85kg |
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| 479. |
2522 32 42 ,52 62+........ 00, then find the value ofklf-=12-5+52-53 + 54-55a5 52 53 54 55 |
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| 480. |
3.Thetimetaken,inseconds,tosolve a problem by each of 25 pupilsis as follows16, 20, 26, 27, 28, 30, 33, 37, 38, 40, 42, 43, 46, 46, 46, 48, 49, 50, 53, 58, 59, 60, 64,52, 20(a) Construct a frequency distribution for these data, using a class interval of 10seconds.(b) Draw a histogram to represent the frequency distribution.1 freauency polygon to represent the |
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| 481. |
Find the mean weight of 15 students the following weightsare 41, 39, 48, 52, 46, 62, 54, 40, 46, 52, 48,40, 42, 52, 55 |
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| 482. |
What is a neutralisation reaction! GIOL L,. Give two important uses of washing soda and baking soda |
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Answer» Two important uses of washing soda are:→ It is used in glass, soap, and paper industries.→ It is used to remove permanent hardness of water. Two important uses of baking soda are:→ It is used as baking powder. Baking powder is a mixture of baking soda and a mild acid known as tartaric acid. When it is heated or mixed in water, it releases CO2 that makes bread or cake fluffy.→ It is used in soda-acid fire extinguishers. |
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| 483. |
'ठ्ब o s - itM.i- - /) : RlA-Tam Smo-Gm02 रह [+ 8t 0 |
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Answer» We hav 2 prove 1+sin+cos |
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| 484. |
2. चांद shatam का मान जारी गए । |
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Answer» SinA=15/17 and cosB=12/13Using, sin²A+cos²A=1 we get,cos²A=1-sin²A=1-225/289=(289-225)/289=64/289cosA=8/17 (neglecting the neggative sign since A,B are positive acute angles)sin²B=1-cos²B=1-144/169=(169-144)/169=25/169sinB=5/13(neglecting the neggative sign since A,B are positive acute angles)sin(A+B)=sinAcosB+cosAsinB=15/17×12/13+8/17×5/13=180/221+40/221=220/221cos(A-B)=cosAcosB-sinAsinB=8/17×12/13-15/17×5/13=96/221-75/221=21/221tanA=sinA/cosA=(15/17)/(8/17)=15/8 andtanB=sinB/cosB=(5/13)/(12/13)=5/12 tan(A+B)=(tanA+tanB)/(1-tanAtanB)=(15/8+5/12)/(1-15/8×5/12)=[(45+10)/24]/[(96-75)/96]=(55/24)/(21/96)= 55/24×96/21=210/21=10 15/8 is the correct answer 15/8 is correct answer |
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| 485. |
जि ध =% + Nबे 571 Tam B Sed कर,ड |
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Answer» Use the identity : sec²A - tan²A = 1=> sec²A - 1 = tan²A=> (x + 1/4x)² - 1 = tan²A => tan²A = x² + 1/(16x²) + 1/2 - 1=> tan²A = x² + 1/(16x²) - 1/2=> tan²A = [x - 1/(4x) ]² => tan A = ± [ x - 1/(4x) ] => sec A + tan A = x + 1/(4x) ± [ x - 1/(4x) ] => sec A + tan A = x + 1/(4x) + x - 1/(4x) ==> 2x. . . . . . . . . . . . . . .OR=> sec A + tan A = x + 1/(4x) - x + 1/(4x) ==> 1/2x |
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| 486. |
82IftamA = 15thancalculateseeA. |
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Answer» seca =17/8 is the best answer 17/8 is answer please like sec A= 1/8 is correct answer. |
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| 487. |
If isim - Cas A, find, 2 Tam." At sim A |
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| 488. |
2.In each of the following examplcs find the co-ordinates of point A which dividessegment PQ in the ratio a: b.(1) P(-3, 7), Q(1,-4), a: b = 2 : 1(2) P(-2,-5), Q(4, 3), a : b = 3 : 4(3) P(2, 6), Q(-4, 1), a: b = 1 : 2 |
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| 489. |
Solve.Rosy was 146.8 cm tall on her last birthday. She has grown 5.2 cm. How tamis she now?of wheat |
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Answer» 146.8+5.2=152 cmnow rosy is 152 cm tall rosy is 146.8 cm tall on her last birthday . it means that we have to add both numbers height on last birthday and present height146.8+5.2=152 cm tall 152 cm is the correct answer of the given question 152 cm tall is the right answer when we add 146.8+5.2=152.so now rosy is 152 tall 2044.8 cm is the answer 146.8 + 5.2 = 152.0 rosy is 146.8 cm tall on her last birthday. it means that we have to add both number height on last birthday and present height 146.8+5.2=152cm tall is correct answer |
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| 490. |
Example H:Write any five rational numbers betv3010 and ()=olution: 3so1029 28 2710, 10, 10,………、 10We can take any five of these.ExerciseRepresent these numbers on the number line寸2 5 -9 on the number li13' 13' 13RepresentWrite five rational numbers which are sma |
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| 491. |
EXEList five rational numbers between:G) -1 and 0 (i) -2 and-1Write four more rational numbers i-3-6 -9-12 191.2. |
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Answer» 135973424qtagyzyzyzzuz 1) i) -0.2,-0.4,-0.6,-0.8,-0.9 ii) -1.2,-1.4,-1.6,-1.8,-1.92) -3,-6,-9,-12,-15,-18,-21,-24 |
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| 492. |
EXERCISE 9.11.List five rational numbers between:4 ,-2_and_ach of the following patterns:4 8 '12(i)-1 and 0(ii)-2 and-I,(iii)(iv) - and-2.Write four more rational numbers in e-3 -6 -9-125 10 15' 20 |
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| 493. |
(i)andWrite five rational numbers greafl) Find ten rational numbers betweenandDISCUSS |
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| 494. |
EXERCISE 9.11.List five rational numbers between:(i)-1 and 0(İİ)-2 and-1.-4-2_and_(iii)(iv)--and-2. Write four more rational numbers in each of the following patterns:-3 6-9-125、10 , 15, 20、..234 812 |
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| 495. |
QJdutPIAr- 12,P[B)- 1/4. Findt'sven that A and B are mutual exclusive.Q10.HP(ĐP(B)- 1/4. Find P(An B) given that A and B are mutually exclusive |
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| 496. |
\left(a^{\frac{1}{2}} \cdot b^{\frac{1}{3}}\right)^{\frac{1}{4}} \cdot\left(a^{\frac{1}{3}} \cdot b^{\frac{1}{4}}\right)^{\frac{1}{2}} \cdot\left(a^{\frac{1}{4}} \cdot b^{\frac{1}{2}}\right)^{\frac{1}{3}} |
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| 497. |
If $3 A+4 B T=\left( \begin{array}{rrr}{7} & {-10} & {17} \\ {0} & {6} & {31}\end{array}\right)$ and $2 B-3 A^{T}=\left( \begin{array}{cc}{-1} & {18} \\ {4} & {-6} \\ {-5} & {-7}\end{array}\right)$ then $B=$1) $\left( \begin{array}{rr}{1} & {3} \\ {-1} & {0} \\ {-2} & {-4}\end{array}\right) \quad$ 2) $\left( \begin{array}{ll}{1} & {3} \\ {1} & {0} \\ {2} & {4}\end{array}\right)$3) $\left( \begin{array}{rr}{1-3} \\ {-1} & {0} \\ {2} & {4}\end{array}\right) \quad 4 ) \left( \begin{array}{rr}{-1} & {-3} \\ {1} & {0} \\ {2} & {4}\end{array}\right)$ |
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| 498. |
7.if a/b1 /3, b/c = 2, c/d-1/2, d /e = 3 and e/f-1/4 then the value of abc/def is :a. 3/8c. 3/4b. 27/8d. 27/4 |
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| 499. |
4. Subtract.a)c) 21.3e) 6-1b) -14 2d) 9-216 321 7f) |
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Answer» a) 8/7 - 1/2 = (8×2-7)/2×7 = 9/14 b) 5 3/5 - 1 1/4 = 28/5 - 5/4 = (28×4-5×5)/5×4 = 87/20 c) 2 1/3 - 3/7 = 7/3 - 3/7 = (7×7-3×3)/(3×7) = 40/21 d) 9 4/5 - 2 3/5 = 49/5 - 13/5 = 36/5 e) 6 4/3 - 1 1/2 = 22/3 - 3/2 = (22×2-3×3)/6 = 35/6 f) 16/21 - 3/7 = (16-9)/21 = 7/21 = 1/3 If you find this answer helpful then like it. So much time |
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| 500. |
कम३०' करारूतीन गो ८Fनये ? |
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