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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 401. |
99. Which of the following solid will have10 faces:(A) Octagonal pyramid(B) Pentagonal prism(C) Pentagonal pyramid(D) Octagonal prism |
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Answer» An octagonal prism has 10 faces 24 edges 16 vertices |
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| 402. |
There is a pentagonalRashida divided it inpentagonal shaped parts as shown in figure, For finding its area Jyothi anddivided it in two different ways. Find the area in both ways and what do youobserve?ST30cmScmRashida's DiagramJyoti Diagram15cm2019-20 |
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| 403. |
Section-AIWrite two functions of bile?2 What |
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Answer» Two important functions of bile are as follows : 1) It assists in the digestion and absorption of fats. 2) It is responsible for the elimination of certain waste products from the body particularly hemoglobin from destroyed red blood cells and excess cholesterol. |
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| 404. |
9. Zero is:(a) an irrational number(c) neither rational nor irrational number(b) a rational number(d) a natural number |
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Answer» b) rational number as p/q form is 0/1 |
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| 405. |
8. write the rational number that is equal to its negativeChoose the correct answe(s) from the given choices9. The product of two irrational numbers isa. A rational number b. An irrational numberc. Neither rational or irrational numbernumberd. A rational or an irrational10. A fractioncan be expressed as a terminating decimal. If qhas no pfactors other thana. 2,5 b. 2,3 c. 2,3,7,5 d.3,5 |
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Answer» 8 . zero , 0 is the rational number that is equal to its negative. 9. option D... example √2 × √2 = √(2×2) =√4 = 2 ( rational) 8. 0 zero is the answer 9. option D ... √2 × √2 = √4 = 2..( rational) 10 A fraction can be expressed as a terminating decimal, if q has no prime factors other than2 or 5 because only 2 and 5 are the coprime to 10. rationalise from of 135/81 is |
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| 406. |
ek aurat 1 hour me 50roti bnati to 3 aurat 1 hour me kitni roti pakayngi |
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Answer» एक औरत एक घण्टे में 50 रोटी बनाती हैतो 3 ओर त=50*3=150रोटी बनाएगी |
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| 407. |
\left( 36 ^ { - 2 } \right) ^ { \frac { 3 } { 4 } } |
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Answer» thanks |
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| 408. |
sqrt(11 %2B 110) |
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Answer» √110+√121=√110+11=√121=11 |
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| 409. |
9+5÷3(36×2) |
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Answer» 9+5/3(36*2)=9+5/3(72) =9+5/216 =9+0.0231 =9.0231 |
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| 410. |
2^(x - 2)*3^(2*x - 6)=36 |
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| 411. |
て89 per kg. Find his profit and the prom perehe selling price of 10 books is equal to the cost price of 12 books. Find the profit percent.150 noer hundred and sells them at348 per dozen. Find his pro |
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Answer» answer is wrong answer is 20 % sorry my mistake! I am extremely sorry! |
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| 412. |
δ0 per kg. rind Ills prom and the p'om4. The selling price of 10 books is equal to the cost price of 12 books. Find the profit percentfinit gallar hure manunes at 3nrhundred and sells them at 248 per dozen. Find his profit or |
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Answer» profit% = |
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| 413. |
What is the purchase price if 25% profit is added with selling price of Rs 600? |
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| 414. |
A man gains 20% by sellingan article for a certain price.If he sells it at double the price,the percentage of profit will be(a) 140(c) 100(e) 120(b) 200(d) 160 |
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| 415. |
A fruit seller sells mangoes at the rate of9 per kg and there by losses 20%. At whatprice per kg, he should have sold then tomake a profit? |
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Answer» SP=9loss=20%so CP=9/0.8=11.25so need to sell more than 11.25 |
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| 416. |
A fruit seller sells mangoes at the rate of9 per kg and there by losses 20%. At whatprice per kg, he should have sold then tomake a profit |
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Answer» SP=9loss=20%so CP=9/0.8=11.25so need to sell more than 11.25 |
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| 417. |
places7. In a magic square ench row, column and dagonal have the same sum. Check whichof the following is a magic square.the following values of a and b. |
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| 418. |
INTEGERS7. In a magic square each row.column and diagonal have the same sum. Check whichof the following is a magic square.1-100-3 1-214-7 |-4-6 |
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Answer» (i)Each row, column, diagonal sum is zero |
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| 419. |
13Sachin Tandulkar batting average is 53.4 in 199 test matches, what should behis score in 200 test match so his average become 54. |
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| 420. |
"magic square", the sum of the numbers in each row, in each column and alongdiagonals is the same. Is this a magic square?11al Elmal-I=4 92 15(Along the first row-+-+-=-11 11 11 1111110cm wide. |
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Answer» second answer is 15/11 and third is also same 15/11 and you will try in magic square every to different side also your ans is 15/11 second answer is 15/11 and third is also same 15/11 and you will try in magic square every to different side also your ans is 15/11 |
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| 421. |
Find:(i) 25% of 200(ii) 1% of 1 hour |
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| 422. |
3. In a "magic square", the sum of the numbers in each row, in each column and alongthe diagonals is the same. Is this a magic square?11= 100/=1 wilt4 9 2 15(Along the first row -+-+==11 11 11 11115-13 |
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| 423. |
Complete the magic square given below: |
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| 424. |
0 , b \neq 0 \quad ( B ) \quad a \neq 0 , b = 0 |
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Answer» વર્ગિય સમીકરણોમાં 0 હોવું જોઈએ નહીં અને b એ ઝેર હોવું જોઈએ નહીં |
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| 425. |
27. यदि a तथा b दो वास्तविक संख्यायें ऐसी हों कि ab = 0, तो(a) a= 0 तथा b = 0(6) 4 = 0 अथवा b = 0 अथवा दोनों में से प्रत्येक 0(c) a= 0 तथा b* 0(d) b = 0 तथा 4# 0(रेलवे परीक्षा, 2006 |
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Answer» right answer is option b the correct answer is option (b) option (b) is the correct answer. a correct answer is (1) |
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| 426. |
If the diagram in fig. shows that graph of thepolynomial f(x) = ax2 + bx + c, then(a) a < 0,<0 and c > 0(b) a < 0, b < 0 and c < 0(c) a < 0, b>0 and c > 0(d) a < 0, b>0 and c < 0AY |
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Answer» SOLUTION : Option (a) is correct : (a) a > 0, b < 0 and c > 0From the figure, the graph of polynomial p(x) is a parabola open upwards, therefore a >0. y = ax²+bx+c cuts Y- axis at P. On Putting x = 0 in y = ax²+bx+c , We get y = c. Hence , the coordinates of P is (0,y) or (0,c).It is clear that P lies on OY. Therefore c > 0. **For any quadratic polynomial ax² + bx + c , the zeros are precisely the x- coordinates of the points where the graph of y = ax² + bx + c intersects the X- axis. **For any quadratic polynomial the graph of the corresponding equation y = ax² + bx + c has one of the two shapes which are known as parabola either open upwards or open downwards. If a > 0 then the shape of parabola is open upwards or a< 0 then the shape of parabola is open downwards. •If the graph intersects the X-axis AT TWO POINTS then a quadratic polynomial HAS TWO DISTINCT ZEROS. D= b² - 4ac > 0. •If the graph intersects or touches the X-axis at EXACTLY ONE POINT then a quadratic polynomial has TWO EQUAL ZEROES (ONE ZERO).D= b² - 4ac = 0. •If the graph is either completely above X-axis or completely below X-axis axis i.e it DOES NOT INTERSECT X-AXIS axis at any point .Then the quadratic polynomial HAS NO ZERO .D= b² - 4ac < 0. HOPE THIS ANSWER WILL HELP YOU… |
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| 427. |
8. If y ax2 bx + c, represents a parabola openingdownward, then which of the following is correct?ible b2a 4a(1) a > 0, b > 0, c > 0 (2kko, bSAc < 0a): 0, b > 0, с < 0 (4) a>0, b>0 cso |
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| 428. |
Distribute 425 amongst 4 men, 5 women and 6 children in such a way that ratio between theamount a man, a woman and a child receives is 9:8:4.Jabalpur, 2004) |
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Answer» suppose common number is kso man receives 9k woman receives 8k and child receives 4know total of 4 men 5 women and 6 child and total 425 rs.so 4*9k+5*8k+6*4k=42599k=425so k=4.3so each man will get 9×4.3=38.7each woman will get 8×4.3=34.4each child will get 4×4.3=17.2 |
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| 429. |
118. If y ax2 + bx + c, represents a parabola openingdownward, then which of the following is correct?2a 4a(1) a>0, b > 0, c > 0 (2eK0, bSAc<0a)< 0, b > 0, c<0 (4) a>0, b > 0, c<0 |
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| 430. |
State,the number of faces,number of vertices and number of edges of:(1) a pentagonal pyramid(2) a hexagonal prism |
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Answer» the hexagonal prism is a prism with hexagonal base. This polyhedron has 8 faces, 18 edges, and 12 vertices. |
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| 431. |
3. An army contingent of 616 members is to march behind an army band of 32 members ina parade. The two groups are to march in the same number of columns. What is themaximum number of columns in which they can march? |
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Answer» Hcf of 616 and 32 is ans 8 columns is the right answer. |
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| 432. |
4 5fa radio is sold for1440, then there is a loss of 10%. For how much moremoney one should sell it to get the profit of 10%?(0)900(4)275 |
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Answer» GivenSP = CP - CP*10/1001440 = CP (1-1/10)1440 = CP (9/10)CP = 1440*10/9 = 1600 For 10% profitSP = CP(1 + 10/100) = 1600(11/10) = 1760 There is no option of this answer 1760 |
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| 433. |
36) List any five hormones of adenohypophysis, with one function eacih. |
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Answer» The anterior pituitary contains five types of endocrine cell, and they are defined by the hormones they secrete:somatotropes(GH);Lactotropes(PRL);gonadotropes(LH and FSH);corticotropes(ACTH) andthyrotropes(TSH). |
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| 434. |
Given that root 2 is an irrational number PT 5+3root2 is an irrational number |
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Answer» let 5+3√2 be rationalthen5+ 3 √2 = p/q3√2 = p/q -5√2 = (p - 5q)/15But LHS is irrational and RHS is rational so a contradiction , therefore 5+3√2 must be irrational |
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| 435. |
. Evaluate:(i);(ii) : 51(ii) ; -38(iii) ;-130(i) i 63(ii) (i 131 +149)(i)(i97 +Evaluate:. Evaluate:(1) (1° +:191. Evaluate: (1)[:29 +now that:5. 1+i? +i4 +16 = 07.;104 + i 109 +i 114 +; 119 = 06. 1+; 10 + 100 - 1000 = 08. 6i54 +5;"7 - 2i" + 61 68 = 7i |
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| 436. |
(1) Show that 4 2 is an irrational number.(2) Prove that 3+ V5 is an irrational number. |
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Answer» 4V2 x 4V2/ 4V2= (4V2)^2/4V2= =16×2/4V2= =32/4V2 HEYA!!--------- -----------------------------------------------------------------------------------------------------〰Given that :- 4√2 〰To prove :- 4√2 is an irrational number . ⚫We shall prove this by the method of Contraction . so let us assume that 4√2 is a Rational Number . 4√2 = r √2 = r/4 Now, we know √2 is an irrational number. So RHS { r/4 } cannot be rational . As then the equation will be false . So our Assumption is Wrong . Hence , 4√2 is an irrational number....⚫⚫ |
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| 437. |
result isWhen a rational number is divided bThe rational number will be:B. 5D. |
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Answer» -2 /9 is the best answer option A is correct answer. 2/9 is the best answer |
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| 438. |
Evaluate : 14% of 600 + 6% of 347-28% of 450 |
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| 439. |
14% of 600+ 6 \% \text { of } 347 - 28 \% \text { of } 450 |
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| 440. |
3. The cost of 347 radios is * 1664212. What is the cost of one radio? |
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Answer» GivenCost of 347radios is Rs 1664212Cost of one radio=1664212/347=Rs4796 347 radios=1664212 rs1radio=1664212/347=4796 rs cost of one radio=₹4796 |
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| 441. |
Write in decimals.(a) 6 mmcm |
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Answer» 6mm = 0.60 cm............ I think is the correct answer 6 mm = 6 × 1 mm = 6 × 1/10 cm = 6/10 cm = 0.6 cm 0.06cm is the answer .6 is the correct answer 0.6 cm. please like me iska write answers 0.6 cm hoga the right answer is 0.6cm |
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| 442. |
14% of 600 + 6 \% \text { of } 347 - 28 \% \text { of } 450 |
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| 443. |
16 cm 7 mm from 20 cm |
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Answer» 20 cm - 16.7 cm = 3.3 cm |
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| 444. |
s=-49*t^2 %2B 294*t |
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| 445. |
\sqrt { \log _ { 2 } x ^ { 4 } } + 4 \log _ { 4 } \sqrt { \frac { 2 } { x } } = 2 |
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| 446. |
19. Two tuning forks A and B produce 5 beats per sec. If fork A is inresonance with a closed organ pipe of length 20 cm and B is inresonance with an open pipe of length 40-5 cm, then calculate theirfrequencies, |
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Answer» assume that the air column in resonance with fork A is closed at one end and open at one end. Then the second column that is in resonance with fork B is open at both ends. Further we take that the resonance frequencies in question are the fundamental frequencies and not hormonics. Let velocity of sound be = c. Frequency of fork A = f1frequency of fork B = f2 beats = | f1 - f2 | = 4 Hz f1 = resonance frequency of closed Air column 15 cm λ / 4 = 15 cm => λ = 60 cm => f1 = c / 60 Hz f2 = resonance frequency of open air column 30.5 cm λ / 2 = 30.5 cm => λ = 61 cm => f2 = c / 61 Hz f1 - f2 = c * [1/60 - 1/61] = c / 3660 = 4 Hz => c = 14, 640 m/s => f1 = 244 Hz and f2 = 240 Hz |
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| 447. |
मा गज. Ve = [जल द न टुखपरVB FT I |
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Answer» L.H.S1+tan^2A/1+cot^2A=(1+sin^2A/cos2A)/(1+cos^2A/sin^2A)=((cos^2A+sin^2A)/cos^2A)/(sin^2A+cos^2A)/sin^2A=(1/cos^2A)/(1/sin^2A)=1/cos^2A*sin^2A/1=sin^2A/cos^2A=tan^2A M.H.S(1-tanA/1-cotA)^2=(1+tan^2A-2tanA)/(1+cot^2-2cotA)=(sec^2A-2tanA)/(cosec^2A-2cosA/sinA)=(sec^2A-2*sinA/cos A)/(cosec^2A-2cosA/sinA)=(1/cos^2A-2sinA/cosA)/(1/sin^2A-2cosA/sinA)=[(1-2sinAcosA)/cos^2A]/[(1-2cosAsinA)sin^2A]=(1-2sinAcosA)/cos^2A*sin^2A/(1-2sinAcosA)=sin^2A/cos^2A=tan^2A R.H.S=tan^2A Hence L.H.S=M.H.S=R.H.S |
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| 448. |
Find the value of\log \left(\frac{225}{32}\right)-\log \left(\frac{25}{81}\right)+\log \left(\frac{64}{729}\right) |
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Answer» log225-log32-log25+log81+log64-log729 = log25 + log9 - log32 - log25 + 2log9 + log32 + log2 - 6log3 = 3log9 + log2 - 3log9 = log2 |
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| 449. |
हा न द+ (08०) |
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Answer» the answer is -16 of above question -18 is the correct answer |
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| 450. |
19 mm into lem |
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Answer» 1 km = 9/1000000 =0.0000009 is the right answee 1 km = 9/1000000=0.0000009 is the correct answer |
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