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write the polynomial 2x4-x2+8x in the coefficient from

(c) In point (-5,2), x-coordinate is negative and y-coordinate is positive, so it lies in II quadrant and in point (2, – 5), x- coordinate is positive and y-coordinate is negative, so it lies in IV quadrant.

Angle COD= 180°- 1/2angle C-1/2 angle D=180°-1/2(angle C+D)----------(1)

Angle (A+B+C+D)=360°

AngleC+D= 360° - AngleA- angle B--------------(2)

Substituting (2) in (1)

Angle COD= 180°-1/2(360°- angle A- Angle B)

Angle COD= 180°-180°+1/2 Angle A + 1/2 Angle B= 1/2(Angle A+ Angle B)4.5

Since the respective remainders of 445, 572 and 699 are 4, 5 and 6, we have to find the number which exactly divides (445-4), (572-5) and (696-6).

So, the required number is the HCF of 441, 567 and 693.Firstly, we will find the HCF of 441 and 567.

∴ HCF = 63

Now, we will find the HCF of 63 and 693.

∴ HCF = 63

Hence, the required number is 63.

let 15+17root 3 be a rational no.Then 15 is rational and 15+17root 3 is rational(15+17root 3-15) is also rational because difference of two rationals is rationaltherefore 17root 3 is rationalNOW,17root 3 is rational and 1/17 is rational(17root 3×1/17) is also rational because product of two rationals is rationalit shows that root 3 is rational So,our assumption is wrong Hence,(15+17root3) is irrational

Let√2 be a rational number

Therefore,√2= p/q [ p and q are in their least terms i.e., HCF of (p,q)=1 and q≠ 0

On squaring both sides, we get p²= 2q² ...(1)Clearly, 2 is a factor of 2q²⇒ 2 is a factor of p² [since, 2q²=p²]⇒ 2 is a factor of p

Let p =2 m for all m ( where m is a positive integer)

Squaring both sides, we get p²= 4 m² ...(2)From (1) and (2), we get 2q² = 4m² ⇒ q²= 2m²Clearly, 2 is a factor of 2m²⇒ 2 is a factor of q² [since, q² = 2m²]⇒ 2 is a factor of q

Thus, we see that both p and q have common factor 2 which is a contradiction that H.C.F. of (p,q)= 1

Therefore, Our supposition is wrong

Hence1/√2 is not a rational number i.e., irrational number.

give me ans

.7,.√756,√.765

Use the property of geometric means. Between any 2 numbers a and b, provided ab is not a perfect square, ab−−√ is an irrational number.

In your case, ab=0.7×0.77=0.539. So 0.539−−−−√ is one irrational number.

For the other irrational number, your choices are 0.7×0.539−−−−√−−−−−−−−−−√ or 0.77×0.539−−−−√−−−−−−−−−−−√.

A pair of such irrrational numbers is π and (2)^1/2.

Show proper answer

4 is the correct answer

answer is 4.........

4 is a correct answer

kon sa banana ha questions

similarly you can done half of the problem. first one is easy you will get a contradiction as gcd is not 1 in that.

diagonols = 15 and 24area of rhombus= 1/2 * product of diagonols = 1/2 * 24 *18 = 216 cm square

root2.91911&root2.913133

No. Of trees in each column is xNo. Of trees in row = x + 5Total no. Of trees = 150

Quadratic equationx * (x + 5) = 150x^2 + 5x - 150 = 0x^2 + 15x - 10x - 150 = 0x(x + 15) - 10(x + 15) = 0x = - 15, 10

Value of x can not be - veSo x = 10

Number of trees in column = x = 10Number of trees in row = x + 5 = 10 + 5 = 15

1)53497182)902374153)705349718

1) 53497182) 902374153) 705349718

62,07,009 3,01,75,02019,64,07,100

The total no. of trees are 150.

Let no. of trees in each column be tno. of trees in each row = t + 5Total no. of trees = no. of trees in each row X no. of trees in each column

150 = t ( t+ 5 )150 = t² + 5tt² + 5t - 150 = 0t² + 15t - 10t - 150 = 0t(t + 15) -10(t + 15) = 0(t - 10)(t + 15) = 0t = 10 or -15But t cannot be negative as it is no. of trees.

So, t = 10

Therefore, no. of trees in each row is 10 + 5 = 15and in each column is 10.

Number of trees in row = x + 5Total number of trees = 150x(x + 5) = 150x^2 + 5x - 150 = 0x^2 + 15x - 10x - 150 = 0x(x + 15)-10(x + 15) = 0(x - 10)(x + 15) = 0x = 10, - 15

Number of trees in each row =>x = 10

Number of trees in each column =>x + 5 = 10 + 5 = 15

2 4 6. 2 3 53 5 7. 1 2 45 7 9. 5 6 8

Q. NO. 1blank, 1st row, 1+1=2,1+3=4,1+5=62nd row, 2+1=3,2+3=5,2+5=73rd row 4+1=5,4+3=7,4+5=9Q. No. 21st row, 1+1=2,1+2=3,1+4=52nd row, 0+1=1,0+2=2,0+4=43rd row, 4+1=5,4+2=6,4+4=8

Let the cp be xsp=cp-loss987=x-6/100xx=1050Ramesh purchased it for ₹1050

how the answer comes without simplification.can u explain me

let the number of banana shubham get is 3k and anil be 5k3k + 5k=24k= 3so, the number of banana shubham get is 3k=3×3=9

like here plz ......

the cost of one ticket is c

Then total money spent$13.50 + 9c = $369c = $36 - $13.59c = $22.5c = $2.5

Cost c of one ticket = $2.5

1.1111 is right answer

1.1111 is the correct Answer

1.1111 is the right answer

1.1111 is correct answer

40 unit purchase rs 40 later on 36 unit rs 4040÷36= 1.11per unit price Rs. 1.11

1.1111 is correct answer

1-140-4036-36answer

1.1111 it the correct answer bro

correctansweris 1,111

1.1111 is the correct answer of the following

1.111 is the correct answer to this question

the correct answer is 1,111 of the following question

1.1111 is the answer

hi

1.1111 is the correct answer of this question

1.1111is the correct answee

1111 is the correct answer

Original cost = p

sale discount=35% of p=35/100×p= 0.35p

Cost after discount = p - 0.35p

which is equivalent to

p(1 - 0.35)

0.65p

So, Derrick is wrong

option (D) is correct

Let the apple be denoted as 'x' and mangoes be denoted by 'y'. And the money he carrying be 'm'

Now, man can purchase 16x=10y=m

A/c to the statement, he bought 4x+5y=m-204*(m/16)+5*(m/10)=m-20m/4+m/2=m-208m-6m=160m=80 Rupees

Therefore, for apples 16x=mi.e. x=80/16One apple cost x=5 Rs.

Similarly for mangoes 10y=mi.e. 10y=80Price of 1 mango is y=8 Rs.

And the difference between them is Rs: 3

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octagonal prism has10 faces

i^10= (i⁴)² .i²= -1i^110 = (i⁴)^25×(-1)= -1i^1000= (i⁴)^250= 1

now1 + i^10+ i^110- i^1000=1 + (-1) + (-1) +1=0

0 is the correct answer of the given question

=1+(-1)+(-1)+1=2-2=0 the correct answer is 0

1-1-1+1=0 is the right answer