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Given:⇔ Let the alloys be mixed in the ratio ofX :Y(Assumption)⇔ In 1st alloy, Copper = x/4⇔ In 1st alloy, Tin = 3x/4⇔ In 2nd alloy, Copper = 2y/7⇔ In 2nd alloy, Tin = 5y/7

To find:⇔ Ratio in which 2 alloys must be mixed to get a new alloy with ratio of copper and tin be 3 : 8= ?

Solution:⇔ Now we have,⇒ (x/4 + 2y/7) : (3x/4 + 5y/7) = 3 : 8⇒ (x/4 + 2y/7) / (3x/4+ 5y/7) = 3/8⇒ (7x + 8y/28) / (21x + 20y/28) = 3/8⇒ (7x + 8y) / (21x + 20y) = 3/8⇒ 8 (7x + 8y) = 3 (21x + 20y)⇒ 56x + 64y = 63x + 60y⇒ 64y - 60y = 63x - 56x⇒ 4y = 7x⇒∴x/y = 4/7

⇒ Ratio in which 2 alloys must be mixed to get a new alloy withratioof copper and tin be3 :8=4/7

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H=1mD=70cm= 70/100 = 0.7mr=0.7/2 mArea of tin sheet required = CSA of cylinder + area of base= 2πrh + πr²= 2x22/7x0.7/2 + 22/7x0.7/2x0.7/2= 2.585m²cost of 2.585m² tin sheet = 2.585x300 = Rs. 775.50

total number of books = 201/4 of 20 is 5 that means 15 books are in different languageonly 5 books are written in Hindi language

let the cost of story book be x and text book be 2xSo, x + 2x = 360x = 120cost of textbook= 240So, the cost of 20 textbook= 20×240=4800

Total amount = 63.75 * 7

= 446.25 rupees

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Mean = SUMMATION OF (F*X) / SUMMATION OF F= (6*2 + 10*4 + 14*7 + 18*12 + 24*8 + 28*4 + 30*3) / (2+4+7+12+8+4+3)= 760 / 40= 19

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165=11×151001=11×912552=11×232∴Option 1) is correct as only 3773 is divisible by 11 , same as others.

Ans :- 3×3 = 9

Financial statements present the results of operations and the financial position of the company. Four main statements are commonly prepared by publicly-traded companies: balance sheet, income statement, cash flow statement and statement of changes in equity. .

1+1+1= 3( as X⁰=1)and 4÷(1/4)= 16answer will be 3/16

your answer is wrong

sorry your answer is right

20% price needs to be reduced

It should be reduced by 20% price

3/4

Sum of all angles of triangle is 180°

Let largest angle be A and other two angles are B and C

Let C is smallest angle

According to the given conditionA = B + C...... (1)

C= 1/4 A....... (2)

From eq(1) and eq(2)A = B + 1/4 AB = A - 1/4A = 3/4 A

We know, A + B + C = 180A + 3/4 A + 1/4 A = 1802A = 180A = 90

B = 3/4 A = 3*90/4 = 270/4= 67.5

C = 1/4 A = 90/4 = 22.5

Therefore, angles are 90, 67.5 and 22.5

11 Ruppee is the correct

Let AB = AC = a and AD = b

In a right angled triangle ABC ,

BC²= AB²+ AC²BC²= a²+ a²

BC = a√2

Given AD = b,

we getDB = AB – AD or

DB = a – b

We have to prove that AC + AD = BC or (a + b) = a√2.

By the angle bisector theorem, we get

AD/ DB = AC / BC

b/(a - b) = a/ a√2b/(a - b)

= 1/√2b = (a – b)/ √2b√2

= a – bb(1 + √2) = ab

= a/ (1 + √2)

Rationalizing the denominator with (1 - √2)

b = a(1 - √2) / (1 + √2) × (1 - √2)b

= a(1 - √2)/ (-1)b

= a(√2 - 1)b

= a√2 – ab + a

= a√2or AD + AC = BC

[we know that AC = a, AD = b and BC = a√2]

Hence it is proved.

Q= set of real numbers - set of irrational numbers which gives rational number setrational number will be in the form of p/q

1.37/52.31/63.19/44.23/9

From the diagram attached with this answer,

ABCD is a parallelogram P and Q are the midpoints of sides AB and DC respectively .

Since ABCD is a parallelogram,AB ║ CD and AB = CD

P and Q are the mid points of AB and CD

so, QC = 1/CD =1/AB = PB

ie. QC = PB

Also PB ║ QC and QC = PB then we get, PQ = BC

Therefore PBCQ is also a parallelogram.

A=(3,2)b=(-2,-3)c=(2,3)distance²=(x2-x1)²+(y2-y1)²ab²=(3--2)²+(2--3)² = 25+25ab=√50ac²=(3-2)²+(2-3)² =1+1ac=√2bc²=(2--2)²+(3--3)² = 16+36bc= √52if this triangle is a right angled triangle..bc²=ab²+ac²(Pythagoras theorem52=50+2

so it is a right angled triangle

The largest six digit number is 999999 and smallest sixdigit number is 100000Therefore, total six digit number=999999-100000+1 =899999+1 =900000

For this subtract bothhence9/11-2/11=7/11hence she painted 7/11 more.

9/11-2/11=7/11answer is 7/11

Let LM and BAD intersect at O

as AL = CM and AB = CDtherefore AB-AL=CD-CMBL = DM ___ (i)

consider ∆OMD and ∆OLB• <DOM = <BOL (vertically opposite angles)• <OMD = <OLB (alternate interior angles)• DM = BL (from i)therefore ∆OMD congruent to ∆OLBtherefore OM = OL, OD = OB (CPCT)therefore O bisects LM and BDtherefore LM, BD bisect each other

Let the total wall surface area = x sq. ft

area of wall in sq. ft = 48% of x= 48/100 × x= 48x/100

area painted = 240 sq. ft48x/100 = 240x = 240 × 100 / 48= 500 sq. ft

here 7 is the improper fractionas improper functions are the one having greater numerator and here the fraction is 7/1 so 7>1hope u like my answer

option A is the correct answer

Plz like my answer Plz accepted as best Plz

7. we can write it as 7/1 which is improper fraction because the number in the denominator is lesser than the no. in numerator

option (A) is the right answer of following questions

option a is the right answer of this question

The answer is 7 because 7/1=7

7 as improper fraction. please like as bes

b is the improper fractioni.e 7/8

When afractionhas a numerator that is greater than or equal to the denominator, thefractionis animproper fraction.option a) 7 is the answer of the given question.

8:12:15 is answer of this

2:12:5 This is the correct answer for this question

l:m=2:3m:n=4:5l and m multiple by 4so l:m=8:12and m:n is multiple by 3m:n=12:15

so l:m:n=8:12:15