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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 63651. |
.ASond cys tUtotal surface area. Find the volume of the cylinder. ('22/7)18. A hollow cylinder cal pipe is 210 cm long. Its outer and inner diameter are 10cm and 6cmrespectively. Find the volume of the copper used in making the pipe.d incide surfaces of a ylinders of metal, find the outer and |
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| 63652. |
इन हज SR sनिम्नांकित संख्याओं के पूर्ण वर्ग न होने का कारण लिखिए-(क) 64000 (ख) 89722 (ग 22- " |
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Answer» 1)64000 इस संख्या में जीरो विषम संख्या में है अता यह पूर्ण वर्ग नहीं है 2)89722 इस संख्या में आखिरी अंक दो है जोकि 0 ,1,4 5 6 ,9में से एक नहीं है |
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| 63653. |
1. 3x+237. तो का मान होगा-(क)1 (ख)2 (ग)3 |
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Answer» 3 is the correct answer of the following question of the following question answer is 3 3x+2=73x=5X=5/3 answer 3 is the correct answer 3 is the perfect answer 3x+2=73x=7-23x=5x=5/3 3 is the correct answer of the given question 3x+2=73x=7-23x=5x=5/3 ans. 3x+3=73x=5x=5/3 is correct answer. answer is 3x+2=73x=5x=5/3 the answer to your question is b 3x+2=73x=7-23x=5x=5/3 none of thesex=5/3is correct answer 3x+2=73x=7-23x=5x=5/3 |
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| 63654. |
x2 +7x +10 |
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| 63655. |
x2-7x +12 |
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Answer» x² - 7x + 12x² -3x - 4x + 12x(x -3) -4(x-3)(x-4)(x-3) |
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| 63656. |
x2-7x+12 |
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Answer» x²-7x+12 = x² - 4x - 3x + 12 = x(x - 4) - 3(x - 4) = (x - 3)(x - 4) |
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| 63657. |
The total surface area of Cube and Cuboide are equal. If Cuboide length, breadth& height are 9cm, 6cm & 4cm respectively. Find the side of a Cube. |
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| 63658. |
in a ll gm ABCD, it is given that AB 16 cm and the altitudes corresponding to the sides ABAD are and 8 cm respectively. Find the length of AD6cm8cm |
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| 63659. |
) y-siGive theare thene and whyne passing through (2. 14) How mmone sach linesigh of the equation 3y +7, find the value of a |
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Answer» X = 2 , y = 14 1. x + y = 162. 2 x + y = 18 There are infinite no: of lines passing through (2 , 14) because an equation in two lines have infinite no: of solutions. |
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| 63660. |
Q 14: In the given figure, AB II DC and diagonals AC and BD intersects at O. If OA 3x -1and OB 2x +1, OC 5.x 3 and OD 6x5, find x. |
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| 63661. |
2.Find the HCF of 960 and 432. |
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Answer» 1 2 |
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| 63662. |
Q.5निम्नलिखित के लिए x का मान होगा-3x-77x-337i.- |
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| 63663. |
factorise the following :x²-20x+960=0 |
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Answer» Using quadratic formulax=-b+-√b^2-4acx=20+-√400-3840/2x=20+-√-3440/2as discriminant is less than zero hence no real roots exists |
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| 63664. |
ng quadratic equations for x and give your answer correct to(2013) (i) x2 7x 7.(2018) |
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| 63665. |
cirles are 8cm and 6cm respectively. Find the radiusf(D) 2cmThe radi of twos ofwhich has arhasA) 14cmqual to the sum of the area of the two circles ?(B) 12cm(C) 10cm |
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Answer» Sum of areas of the two circles is π[r1^2+r2^2]Sum=22/7((8)^2+(6)^2)=22/7(64+36)=22/7*100=π100cm^2Hence radius of a circle with sum of areas =πr^2=π100r^2=100r=10cmoption c |
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| 63666. |
7, In the adjoining figure, ABCD is a trapeziumin which CD II AB and its diagonals intersectat O. If AO= (5x-7) cm, OC-(2x + 1) ern,DO = (7x-5) cm and OB = (7x + 1) cm, findthe value of x. |
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| 63667. |
5. Find the HCF of 960 and 432. |
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Answer» prime factorization of 960= 2 × 2 × 2 × 2 × 2 × 2 × 3 × 5the prime factorization of 432=2 × 2 × 2 × 2 × 3 × 3 × 3 Therefore, HCF = 2 × 2 × 2 × 2 × 3=48 |
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| 63668. |
1620羽40%+ 960亟39%-5200啊? 96 |
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Answer» Thanks sir Good night |
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| 63669. |
11, A student saves ri on the first day.äš2 on the second day, 3 on the third daand so on. Then, during the month of April, he has savedA. 930 B 480 C. 465 D. 960 |
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| 63670. |
Using Euclid's Algorithm, find the HCF of 2048 and 960. |
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Answer» yes its correct i m just confirming |
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| 63671. |
Concepts of Physi(6-E3) is 16 N andd the friction. If the tension in the string in figurethe acceleration of each block is 0-5 m/s', fincoefficients at the two contacts with theblocks2 kg230μ1Figure 6-E3 |
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| 63672. |
t 2cm4cm10cm2cm8cmCheck Your Knowledge1. Find the area of a square having side 11.5 cm.2. Find the area of a rectangle having length 12. |
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Answer» Areas of the square=side×side =11.5×11.5 =132.25cm2 |
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| 63673. |
Express the following in terr(i) 7x 7 x7x7x 7(ii) axaxaxbxb |
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| 63674. |
20. The speed of the train is 60 km/h. Find the new speed of the train if its speed isa. Increased by 25%b. Decreased by 10% |
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| 63675. |
0 - - 晋Gap = = = = |
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| 63676. |
it 2 zeros of the polynomial f(x)=x^3-4x^2-3x+12 the zero are√3 & -√3 find the third zero.... |
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Answer» okthank you for your answer |
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| 63677. |
Մ ՍԱԱ -5a - 3}}} 8a... 3 - [x - {2g – (5x + y – 3) + 2x} - (x2 – 3gvi7 — 7Y__ (9) |
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Answer» 3-[x-{2y-(5x+y-3+2x2} - (x2-3y) ] |
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| 63678. |
=Initial Knowledge CheckMultiply.6-(-5)Write your answer in simplest form.I Don't KnowSubmitTerms of Use | Privacy |
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Answer» 21.0 is a best answer 💥💥💥 -21 is the right answer 6(-7/2) = -42/2 = -21 -21 the answer is right -21 is correct answer. 21.0 is correct answer |
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| 63679. |
(Ä°) If cose-sine-12sin9, then prove that cose+sine-/2cose |
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Answer» CosA +sinA =√2cosAsquaring⇒(cosA + sin A)² = (√2cosA)²⇒cos²A + sin²A+ 2sinAcosA = 2cos²A⇒1-sin²A+ 1 -cos²A+ 2sinAcosA= 2cos²A⇒2 - 2cos²A =cos²A + sin²A -2sinAcosA⇒2(1 - cos²A)= (cosA - sinA)²⇒cosA - sinA =√[2sin²A]⇒cosA-sinA =√2sinAhence proved |
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| 63680. |
the zero of equation x^2-7x-3 and verify the relationship between zero and coefficients |
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| 63681. |
4. IfcosB + sĂn8-V2 cos θ, then show that(cose-sine)-V2 sine.(C |
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Answer» Let θ= x cos x + sin x =√2 cos x squaring on both side, we get...... cos2x + sin2x + 2cosxsinx = 2cos2x 2sinxcosx = 2cos2x - cos2x - sin2x 2sinxcosx = cos2x - sin2x 2sinxcosx = (cosx+sinx) (cosx - sinx) 2sinxcosx = (root2 cosx) (cosx - sinx) 2sinxcosx/root2 cosx = cosx - sinx √2sinx = cosx - sinx at the 8th line from where root 2x came |
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| 63682. |
12. If Cote7/ then find the value of (1+Sine) (1-Sine)(1+Cose) (1-Cos6) |
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Answer» After multiplicationas we know that(a+b)(a-b)= a^2-b^2so here1-sin^2 theta /1-cos^2 theta=( cos/sin)^2= cot^2 theta= 49/64 As cot theta= cos /sinand 1-sin^2= cos^2 thetaAnswer49/64 |
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| 63683. |
ITI. Answer the following questions :15.In the adjoining figure △ABC & △AMPare two right triangles, right angled atB & M respectively prove that 읽СА-ВСMP |
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Answer» (ii) As, ΔABC ~ ΔAMP (By AA similarity criterion) If two triangles are similar then the corresponding sides are equal, Hence, CA/PA = BC/MP Like my answer if you find it useful! |
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| 63684. |
Govind is 48 yr old. He is twice ascas his son Prem is now. How old wPrem seven years before? |
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Answer» Age of Govind=48yrsAge of Prem=48/2=24Answer =24-7=17 |
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| 63685. |
: ( 6 a + 5 b + 4 c ) ^ { 2 } - ( 6 a - 5 b - 4 c ) ^ { 2 } |
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Answer» (6a+5b+4c)^2 - (6a-5b-4c)^2=[(6a+5b+4c)-(6a-5b-4c)][(6a+5b+4c)+(6a-5b-4c)]=(10b+8c)(12a)=24a(5b+4c) identity used is a^2 - b^2 =(a-b)(a+b) |
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| 63686. |
©If t= ECA, ), (6-2)(3),9 = {(2,-2), (6,0), (2,1)) then34+ 2g : |
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Answer» 3f+2g={(5a, -1),(5b, -6),(5c, 11)} 3f =[[3a+1+3b-6+3c+9]]= =[3a + 3b + 3C +4]]; 2g =[2a -4 + 2b + 0+ 2C +2] = [2a + 2b + 2C-2];; 3f + 2g =[3a+2a +3b +2b +3c+2c + 2] = [5a + 5b + 5c + 2] the correct ✅answer is, 3f+2g={(5a, -1), (5b, -6), (5c, 11) } |
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| 63687. |
y e4) i)sin 2x = न ans : =+ (1" un ⏠Zet L |
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Answer» thanks |
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| 63688. |
Find the value of the polynomial-4x2 - 5x + 3 at x = 0.un |
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Answer» Simple the answer is 3 Putting x = 0 in the given equation,we get 4*0^2 - 5*0 + 3= 3.Like. |
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| 63689. |
\left. \begin{array} { l } { \text { Simplify } : - \frac { 3 } { 2 } a ( 2 a - 3 b + 4 c ) + \frac { 9 } { 2 } \text { and } \text { fir } } \\ { \text { value for } a = 1 , b = - 1 , \text { and } c = - 2 } \end{array} \right. |
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| 63690. |
at 10% simplevests the moneyo Govind borrows 18,000 at 100interest. He immediately invests theborrowed at 10% compound incompounded half-yearly. How much monedoes Govind gain in one year ? |
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Answer» P=18000rsR=10%T=1 yearS.i. =P *R*T/10018000*10*1/100=1800rsCompounded halfyearlyP =18000 rsT=2 half yearsR=5%A=p[1+r/100]^t=18000[1+5/100]^2=18000[21/20]^2=18000*21*21/400=45*441=19845rsC.i.=19845-18000=1845rsMoney he gained =1845-1800=45rs |
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| 63691. |
in which group does banana plant fir |
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Answer» hrebs |
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| 63692. |
Put these numbers in order from greatest to least.FIR2019Submit |
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Answer» greatest to least; 20(19/25), 20(13/20), 14/25, 9/12 |
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| 63693. |
fir f RTE((a + 1)(a + 2), (a + 2), (a + 2) (a +3),(aéŁ((a + 3) (a + 4), (a + 4)) í |
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Answer» Sorry, we are currently answering only for the questions posted in english! thnx |
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| 63694. |
6. Saima wants to put a lace on the edge of a circular table cover of diameter 1.5 m.Find the length of the lace required and also find its cost if one meter of the lace costs15. (Take π = 3.14) |
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Answer» thanks |
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| 63695. |
of the area of a rhombe3 112 un ² and one of itstisgnols is 14 cm, find firto other diagnol |
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| 63696. |
Find the distance between the following pairs of points:fir(2, 3), (4, 1)1.tha noints (0 o) and (36. 15), Can you now find the |
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| 63697. |
ce cara. CBSE2010-1Mn twice. What is the probability that the same number will come up eitherdie is throwtime? CBSE2010-1MAhinh |
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Answer» No. of outcomes (1,1)(2,2)(3,3)(4,4)(5,5)(6,6)=6 6/6=1 |
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| 63698. |
90. If cosecA + cot A-t, then tan A-215162143 |
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Answer» (cosec A + cot A) x (cosec A - cot A)/(cosec A - cot A) --->11/2 ie (cosec^2 A - cot^2 A) /(cosec A - cot A ) --->11/2 now cosec^2 A - cot^2 A is 1 so 1/(cosecA - cotA) --->11/2 so cosec A - cot A --->2/11 cosec A + cot A ---> 11/2 subtraction gives - 2 cot A --->2/11 -11/2---> -117/22 so cot A ---> 117/44 now tan A ---> 1/cot A ---> 44/117 |
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| 63699. |
If the compound interest on a certain sum of mone3 years at 10% p.a. be *993, what would be the siinterest(a) 3800(b)(d)950.1000 |
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Answer» Let sum of money be P, Time period T = 3, Rate of Interest R = 10%, CI = 993, Amount = A For compound interestA = P(1 + R/100)^TP + CI = P(1 + 10/100)^3P + 993 = P(1.1)^3P + 993 = 1.331P1.331P - P = 993.331P = 993P = 993/.331P = 3000 For simple interestSI = P*R*T/100SI = 3000*10*3/100SI = 900 (c) is correct option |
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| 63700. |
.'. Fraction is-_9kitesh and his friend Jimmy together sold tickets for a charity showor Rs 3800. If Ankitesh sold 13 times as that by Jimmy, how much diach of them sell |
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Answer» Let Jimmy sold the tickets for Rsx.so,Ankitesh sold it for 1 whole 3/8 Times of x =11/8x. ATQx+11/8 x=3800 8x+11x/8=3800 (add by taking lcm) 8x+11x=3800×8 8x+11x=30400 19x=30400 x=30400/19 =1600. therefore Jimmy sold the tickets for Rs 1600and Ankitesh sold the tickets for Rs11/8×1600=Rs2200 |
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