This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 63601. |
6. The 4th term of an A P is zero. Prove that the 25th term ot the Al I37. ABC is a triangle. A circle touches sides AB and AC produced and side BC at X, Y and Z respectively.Show, that AX-_ perimeter of AABC. |
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Answer» From the figure u will get thatAX=AYBX=BZCY=CZnowper of triangle ABC =ab+bc+ac=ab+(bz+zc)+ac=ab+bx+ac+cy=ax+ay=2axper of triangle ABC =2axtherefore1/2perimeter of triangle =ax . 7)Tangents from an exterior point to a circle are equal in length.∴ BP = BQ ----- -(i) CP = CR ------(ii) and, AQ = AR ----- (iii)AQ = AR⇒ AB + BQ = AC + CR⇒ AB + BP = AC + CP...(iv) [From eqn (i) and eqn (ii)]Perimeter of ΔABC= AB + BC + AC= AB + (BP + PC) + AC= (AB + BP) + (AC + PC)= 2(AB + BP) [From eqn (iv)]= 2 AQ [From eqn (i)]⇒ AQ = 1/2(Perimeter of ΔABC) |
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| 63602. |
If coordinates of two adjacent vertices of a parallelogram are (3, 2), ,diagonals bisect each other at (2, -5), find coordinates of the other two verticesORunits, find x. |
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| 63603. |
1.Use Euclid's division algorithm to find the HCF of0) 135 and 225(ii)196 and 38220 |
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| 63604. |
1 हा e & हि ५ त तन पल 1) ८. ५:नए e 00 Mo X B L pasdbk ) ex above a ntubrania[Z35p7 Lo loto P एल एपकल, 9६ नि wesls कि | iR damer bo a bot J__u_flflm_u ok ! |
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Answer» If you find this solution helpful, Please like it. |
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| 63605. |
6/A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle。elevation from his eyes to the top of the building increases from 30° to 60° as he walktowards the building. Find the distance he walked towards the building. |
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| 63606. |
V6. A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle ofelevation from his eyes to the top of the building increases from 30° to 60° as he walktowards the building. Find the distance he walked towards the building. |
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| 63607. |
The value of (11S |
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Answer» (11111)(11111) = 123454321 If you find it helpful then please like. thanks |
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| 63608. |
s ug that there is no slack in the string.6. 1.5 m tall boy is standing at some distance from a 30 m tall building. The angelevation from his eyes tohis eyes to the top of the building increases from 30° to 60° as he walkstowards the building. Find the distance he walked towards the building.7. From a noint on |
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Answer» A| | | 30 mt | B----------C 60°----D 30° |1.5 m EAE=height of building (30m)BE= 1.5m boy height in ∆ABCTAN60=AB/BC√3= 28.5/BC√3BC=30BC= 30/√3= 30√3/√3√3=10√3 IN ∆ABD TAN30=AB/BD1/√3= 30/BDBD= 30√3 CD= BD - BC = 30√3 - 10√3 = 20√3 MT = 20×1.732 = 34.64MTHe moves 34.64mt towards building |
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| 63609. |
6. A boy, 1.6 m tall, is 20 m away from a towerand observes the angle of elevation of the topof the tower to be (i) 45째 (ii) 60째. Find theheight of the tower in each case. |
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| 63610. |
A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle ofelevation from his eyes to the top of the building increases from 30° to 60° as he walkstowards the building. Find the distance he walked towards the building. |
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Answer» a a |
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| 63611. |
sm tall girl stands at a distante osen from a land post 8 rasta shadase length 4.5m on the ground, thenfind the height of tempost. |
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Answer» 2.5 is the correct answer of the given question |
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| 63612. |
PRACTICE EXERCISE1. Find the (i) curved surface area and(ii) total surface area of a closed righteylinder, whose height is 7 em and theradius of the base being 3 em. |
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Answer» hit like if you find it useful |
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| 63613. |
Exercise1. Find the sum ofSolve any two5 (-32 |
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Answer» 5/2+(-3/4) =5/2-3/4 =5*2-3/4 =10-3/4 =7/4 |
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| 63614. |
. In fig., a circle inscribed in triangle ABC touches its sides AB, BC and AC at points D,E and F respectively. If AB12 cm, BC-8 cm and AC 10 cm, then find the lengths ofAD, BE and CF |
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| 63615. |
जि FentAT 3 kg of wheotiswidh by the cont9 of crhent |
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Answer» Cost of 8kg wheat= ₹72By using unitary method, we will calculate the cost of 1kg wheat= 72÷8= 9Cost of 1kg wheat =₹9Cost of 15kg wheat= 9×15= ₹135 Answer |
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| 63616. |
Exercise1. A sum of 1000 is lent for 1 year at the rate of 7%p.a. Find the interest and the amount. |
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Answer» Interest= PTR/100hereP= 1000R= 17 %time 1 year = 1000*7/100== 70amount = 1070 |
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| 63617. |
EXERCISE 1.Use Euclid's division algorithm to find the HCF(i) 196 and 38220() 135 and 225 |
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Answer» I don't think you are of 1st Grade |
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| 63618. |
008 o1 ofF mid. p; oy PQrye e IR |
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| 63619. |
4. Which term of the AP: 3, s, 13, 1S,.. is 78?cont |
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Answer» a (first term of A.P.) = 3d (common difference) = 8-3 = 5Let the nthterm of A.P. be an.an(nthterm of an A.P.) = 78an= a + ( n - 1 ) d78 = 3 + ( n - 1 ) 578 - 3 = ( n - 1 ) 575 = ( n - 1 ) 575 / 5 = ( n - 1 )n - 1 = 15n = 15 + 1n = 16Therefore 16thterm of the given A.P. is 78. ty |
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| 63620. |
(iv)D 5 cm C2. In the adjoining figure, show that ABCD isa parallelogram.Calculate the area of lgm ABCD卜,A 5 cm B |
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Answer» thanks but it is too long but nice |
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| 63621. |
In the given figure, AB BC, M is mid-point of AB and N is mid-print of BC. Using Euclid'saxioms, prove that AM = NC. |
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Answer» Given : AB = BC .....(1) MB = NB .....(2) ( due to midpoint) So, Eq(1) - Eq(2) AB - MB = BC - NB AM = NC ( proved) Third Axiom: If equals be subtracted from equals, the remainders are equal |
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| 63622. |
2. Construct a parallelogram ABCD in which AB = 4 cm, BC = 5 cm and ZB = 60°. |
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| 63623. |
a boy 2m tall is standing at some distance from a 30 m tall building. the angle of elevation from his eyes of the top of the building increases from 30° to 60°. find the distance he walked towards the building. |
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Answer» tan 60 =30-2/ab root 3 =28/ab ab = 28/root 3 tan 30 = 28/cb 1/root 3 = 28/ ac + 28/rt 3 ac =28 rt 3 - 28/rt 3 ac =84 - 28/rt 3 ac =56/rt 3 32.34m. Am i right no u r wrong sonu😑 Q show me answer |
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| 63624. |
2. In the adjoining figure, show that ABCD isD 5 cm Ca parallelogram.Calculate the area of llgm ABCD.A 5cm B |
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| 63625. |
The angle between two altitudes of a parallelogram through the vertex of an obtuse angle of theparallelogram is 600. Find the angles of the parallelogranm. |
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| 63626. |
The angle between two altitudes of a parallelogram through the vertex of an obtuse angle of thepatallelogram is 60. Find the angles of the parallelogram |
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| 63627. |
Are the following sets equal ?(x : Ď is a letter in the word reap); |
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| 63628. |
51. In the given figure, AD is the bisector of6 cm. andZBAC. If AB 10 cm., ACBC 12 cm., find BD12 cm. |
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Answer» page 2 |
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| 63629. |
Exercise 1Find the rule which gives the number of matchsticks required to make the followingpatterns-(i) A pattern of letter 'H'(ii)Apattern of letter"V |
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Answer» a) 3 matchsticks b) 2 matchsticks wrong answerplease post correct answer |
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| 63630. |
аQ.7.If each of the vowels in the word AMERICANchanged to next letter in the English alphabet thenwhich of the following will be the sixth letter fromthe Right end?(1) F(2) X (3) R(5) Q.15.Ifas(4) Plo |
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Answer» F is the correct answer for this question |
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| 63631. |
1) Describe the following sets in Roster formi){x/ x is a letter of the word MARRIAGE) |
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Answer» {M,A,R,I,G,E} is the required set |
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| 63632. |
In tiq ABCD L a T and P n mid contA AB,BD and ap ane |
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| 63633. |
A 150cm tall boy stands at a distance of 8m from a lamp post and cast a shadow of 2m. Find the height of the lamp post |
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| 63634. |
52522 दि कट न e .४ 2y pamsier (24 ajeeie 2gu a)’ “ane e |
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| 63635. |
हमला 2 रपट. o e Mflw\\«j aneProposdvn |
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Answer» 28 × 36 = 1008 24 × 48 = 1152 1008 not equal to 1152vThey are not in proportion. |
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| 63636. |
A 5 cm Bparallelogram ABCD, it is beingthat AB 10 cm and the altitudesponding to the sides AB and AD are Mcm and BM 8 cm, respectively.D. |
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| 63637. |
0. The angle between two altitudes of a parallelogram through the vertexof an obtuse angle of the parallelogram is 60°. Find the angles of theparallelogram. |
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| 63638. |
The angle between two altitudes of a parallelogram drawn from vertex of an obtuse angle of parallelogram is 60 degree. Find all the angles of this parallelogram. |
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| 63639. |
X2-7x+12=0 |
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Answer» x*x - 7x + 12 = 0 x*x - 4x - 3x + 12 = 0 x(x-4)-3(x-4) = 0 (x-4)(x-3) = 0 x = 3,4 If you find this answer helpful then like it. |
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| 63640. |
(i) x2-7x+2 |
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| 63641. |
iii) x2 + 7x-6-0( |
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| 63642. |
3%x2+7x+3-0 |
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Answer» hit like if you find it useful |
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| 63643. |
flag post stands on the top of a building. From a point on the ground, the angles ofof the top and bottom of a flag post are 609 and 45 respectively. If the heightof the flag post is 10 m, find the height of the building. |
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| 63644. |
7, ABE ane ints on the same side of AB sach tha |
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| 63645. |
igh Order Thinking Skills (HOTS)41 and 42 are complementary angles. Z223 are supplementary angles. If 21 45o, fnthe measure of 23and |
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| 63646. |
2. In a parallelogram ABCD, it is beinggiven that AB 10 cm and the altitudescorresponding to the sides AB and AD Mare DL = 6 cm and BM = 8 cm,respectively. Find AD |
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| 63647. |
11. In the adjoining figure PQRS is a kite.Q 120°Find the values of x and y50° |
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| 63648. |
l and BM are the heights on sides AB and AD respectively oflelogram ABCD (Fig 11.24). If the area of the parallelogram1470cm, AB-35 cm and AD = 49 cm, find the length ofBM |
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| 63649. |
2 cubes sach af sotume 64 aom are joined end to end. Find the surfacubond |
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Answer» Like if it is useful thanks thanks |
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| 63650. |
Find the zeros of the following qbetween the zeros and the coef1. x2+7x +123. x2 + 3x-105. 5x2 -4-8x [CBSE 2008]7. 2x2-11x + 15 |
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Answer» 1)x^2 + 7x + 12 = 0 x^2 + 4x + 3x + 12 = 0 x(x + 4) + 3(x + 4) = 0 (x + 3)(x + 4) = 0 x = - 3, - 4 2) x^2 + 3x - 10 = 0 x^2 + 5x - 2x - 10 = 0 x(x + 5) - 2(x + 5) = 0 (x - 2)(x +5) = 0 x = 2, - 5 |
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