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| 63551. |
4th term of an AP is zero.find 25th term |
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Answer» 4th term=a+3d=201025th term=3(3rd term)a+24d=3(a+2d)a+24d=3a+6d18d=2aso a=9d9d+3d=12d=2010so d=167.5a+502.5=2010so a=1507.5 |
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| 63552. |
Find the remainder obtained on dividing p(x)=x^{3}+1 by x + 1. |
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| 63553. |
OME t Ranum will be 5 times as old as he was 8 years ago. How old is Rahim today19. A bag contains 25-palsa and 50-palsa coins whose total value is 30. If the number of25-paisa coins is four times that of 50-paisa coins, find the number of |
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| 63554. |
Show by long division method that x -3 is afactor of 2x⁴+3x³ -26x²-5x+ 6. |
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Answer» if x-3 is a factor of the given polynomialhenceif X=3 is put into equationhence it will give result as zerohence2(3)^4+3(3)^3-26(3)^2-5(3)+6=2*81+81-26*9-15+6=162+81-234-15+6=0 |
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| 63555. |
The 4th term of an A.P. is zero. Prove that the 25th term of the A.P. is three times its 11th term. |
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| 63556. |
The 4th term of an A.P. is zero. Prove that the 25th term of the A.P. is threetimes its 11th term. |
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Answer» Given a4= 0That is (a + 3d) = 0⇒ a = - 3d → (1)nth term of AP is given by an= a + (n – 1)da11= a + 10d = – 3d + 10d = 7d [From (1)]a25= a+ 24d = – 3d + 24d = 21d [From (1)] = 3 x 7dHence a25= 3 x a11 |
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| 63557. |
9. The 4th term of an A.P. is zero. Prove that the 25th term of the A.P. is three times its 11thterm. |
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| 63558. |
Vithout actually calculating the cubes find the value ภf (28), ( 15° + (-13)3 |
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| 63559. |
89. The 4th term of an AP is zero. Prove that the 25th term of the AP is three times its 11th term. |
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| 63560. |
Add. 5x-26x + 17x + 15 y-23 y. |
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| 63561. |
Q.5 Without actually calculating the cubes, Find the value of 453-25-20 |
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| 63562. |
(iv)द्विघात बहुपद 2:£* - 5:< + 2 के शून्यकों का योग है 1A -5 B) 15C) = D) -1© 3 (D)Sum of zeros of the quadratic polynomial2: - 5x+2is:A) -5 B) 15C) = D) -1© 3 (D) |
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| 63563. |
5. Find the remainder obtained on dividing x + x? - 26x + 24by x-6. |
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Answer» answer is 120 Given p(x) =x^3+x^2-26x+24 remainder=x-6now p(6)=(6)^3+(6)^2-26(6)+24= 216+36-156+24=120Thus remainder=120 |
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| 63564. |
1. Which is greater than 4(a) 5,(b) -5(c) -1/2(d) -25. |
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Answer» a) 5 Option is correct 5 is greater than 4, as 5 = 4+1 |
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| 63565. |
36. 28-31x-5x2 |
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| 63566. |
5. 5 Paisa is which part of Re. 1 2(B) 1/50(A) 1/10(C) 1/20 |
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Answer» Re 1 = 100 p So,5 paisa is 5/100 = 1/20 part of Re 1 (C) option is correct |
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| 63567. |
(İ)p(x)=x3-3x2 + 5x-3, . g(x)=x2-2 |
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| 63568. |
If 9th term of an A.P. is zero, prove that its 29th term is double of its 19th |
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| 63569. |
(i) p(x)=x3-3x2 + 5x-3,g(x)=x2-2 |
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Answer» If you like the solution, Please give it a 👍 |
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| 63570. |
: If9th term of an A.P: is zero, prove that its 29th term is double the 19th term. |
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| 63571. |
The 4th term of an AP is zero. Prove that it trigieis |
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| 63572. |
(i)p(x)-x3-3x2 + 5x-3,g(x)-x2-2 |
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Answer» If you like the solution, Please give it a 👍 |
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| 63573. |
14. Without actually calculating the cubes, find the value of each of the following: |
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| 63574. |
(b) 9x2 +24x + 16 |
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Answer» Hit the like button. wrong answer bro how is it possible ❓❓❓❓❓⁉⁉⁉ using property 1=√a+√b+2ab sorry bro its right thanks ok no problemnever mind |
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| 63575. |
EXERCISE 12.2ー(park. in the shape ofaqはadrilateral ABCD. hasC=90P,ABagCD-5m and AD- 8 m. How much area does it occupy? |
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| 63576. |
26x+24x=12 |
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| 63577. |
5x2-24x-5=0 |
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| 63578. |
17. ABCD is a rectangle formed by the points A (-1, -1), B (-1, 4), C (5, 4)and D (5,-1). Pand S are the mid-points of AB, BC, CD and DA respectively. Find what type of quPORS is.Q.Radrilate |
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| 63579. |
(iii) O is the circumcentre of AABC. Given ZBAC-85° and ZBCA 55then find 20ACadrilateral d RCD the side AR is the diameter of the circle. If |
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| 63580. |
\frac{3^{3} \times 3^{5} \times 2^{3}}{3^{2} \times 6} |
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| 63581. |
xample 15 If A(-5, 7), BC- 4, -5), C(-1, -6) and D(4, 5) are the veadrilateral, find the area of the quadrilateral ABCD |
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| 63582. |
The adjacent angles of a parallelogram are(3x - 10") and (2x + 5°), the value of xis equal to(1) 27(3) 47(4) 43(2) 37 |
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Answer» the awnser is the 3rd option Answer :2)37Explanation: In a parallelogram, opposite angles are equal. Therefore the other two angles are also 3x-10° degrees and 2x+5° degrees. We also know sum of all the angles in any quadrilateral is 360 degrees. Hence, 2(3x-10°) + 2(2x+5°) = 360.6x-20+4x+10=36010x=360+10x=370/10x=37 adjacent angles of parallelogram =180 (3x-10)+(2x+5) =180 3x+2x+5-10 =1805x-5=1805x=180+55x=185x=185/5x=37 The answer is 37 (3x-10)+(2x+5)=1803x-10+2x+5=1803x+2x-10+5=1805x-5=1805x=180+55x=185X=185/5X=37 |
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| 63583. |
Find a quadratic polynomial, the sum and product of whose zeros-5 and 6 respectively |
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| 63584. |
The 8th term of an A.P is zero prove that its 38 term is triple of its 18term |
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| 63585. |
CBSE 2006 C7 The 6th term of an Arithmetic Progression is zero. Prove that its 21st term is triple of its 11th term. |
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Answer» 6th term of AP is a+5d=0a=-5d 21st term=a+20d=-5d+20d=15d11th term=a+10d=-5d+10d=5d 3(5d)=15d3(11th term )=21st term |
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| 63586. |
Apply laws of exponents and simplify\left(\frac{2^{6} \times 3^{4}}{6^{3}}\right)^{2} \times\left(\frac{3^{3} \times 2^{5}}{3 \times 8}\right)^{3} |
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| 63587. |
1. Find the sum 1+3+5++51 (the sum of all odd numbers from 1 to51) without actually adding them. |
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| 63588. |
ty by tria axample 2 Solve 5x -3 <3x +1 when(G)xis an integer,(ii) x is a real number. |
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| 63589. |
1f4 Ă 5x = 500, then the value of xis |
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Answer» I know you don't know |
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| 63590. |
/2//0##8-16 XIS XEO |
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Answer» 10*10+ *100=100*100=10,000 15*15*800=225*800=1,80,000 10×10×100=10;00015×15×800=180,000 |
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| 63591. |
10. A circle touches all the four sides of a quadrilateral ABCD. Prove that AB + CD BC + DA. [2 |
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| 63592. |
Example 13 The centroid of a triangle ABC is at the point (1, 1, 1). If the coordinatesof A and B are (3, -5, 7) and (-1, 7, -6), respectively, find the coordinates of thepoint C. |
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| 63593. |
Show that (-1 + 3 3 1s a real number |
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| 63594. |
thterm 1Striple of its 1 8th term. |
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| 63595. |
63. If (a + i b)-yF, then the value1+i1-i(a2 +b2) is1S |
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Answer» a+ib=√1+i/1-ia+ib=√1+i/1-i*(1+i)/(1-i)a+ib=1+i/√2hence now a-ib=1-i/√2now a^2+b^2=(a-ib)(a+ib)=2/2=1 |
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| 63596. |
1S:1. 3 times (-6) times (-15) divided by 5 is: |
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Answer» 3*-6*-15 ÷ 5 Ans = 54 |
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| 63597. |
If x51 51 is divided by x + 1, theremainder 1S |
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| 63598. |
80. The sumof n terms of the series011+2 1++3 1... isa 1S2) n(n+1) 3) n2+1 |
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| 63599. |
ミ1 9200. Find the width lThe length and breadth of a recuangular piece of land are in the ratio of 5 :3. If the total costaf fencing it at8.24 per metre isて9600, find its length and breadth, |
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Answer» hope that if helped u |
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| 63600. |
The incircle of ÎABC touches the sides BC, CA and AB at D, E and Frespectively. If AB AC, prove that BD- CD. |
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