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x + y × 12 + a^ a+25

let the ratio be kso angle y and z are 3k and 7k respectivelythereforey+z = 180°10k = 180°k = 18°angle y = 54°z = 126°x = 126°

(a+b)(a-b)a^2-b^21/4 (x^2-4)

(1x/2 -1)(1x/2 +1) = x^2/4 - 1=0; x^2 = 1+4= 5; x^2 = 5 ;; x = V5

When base same then power will be added. x-1+x+1.2x+1-1x=2.

ower will be added.x-1+x+1

x²/4-1 is the right answer

Using this, cos²x = {1 + cos(2x)}/2cos²(x + π/3) = {1 + cos(2x + 2π/3)}/2 and cos²(x - π/3) = {1 + cos(2x - 2π/3)}/2

ii) Hence, left side of the given one is:

= {1 + cos(2x)}/2 + {1 + cos(2x + 2π/3)}/2 + {1 + cos(2x - 2π/3)}/2

= (3/2) + (1/2)[cos(2x) + cos(2x + 2π/3) + cos(2x - 2π/3)]

= (3/2) + (1/2)[cos(2x) + 2cos(2x)*cos(2π/3)][Since cos(A+B) + cos(A-B) = 2cosA*cosB]

= (3/2) + (1/2)[cos(2x) - cos(2x)] [Since cos(2π/3) = -1/2]

= 3/2 = Right side HENCE PROVED

Thnx but other questions answers

where is d,g,and h

d g h is where

Given that:PT || QR and QT || RSTo Prove:ar(ΔPQR)=ar(ΔQTS)Proof:Since triangle PQR and TQR are on the same base QR and between the parallels PT and QR. Therefore,ar(ΔPQR)=ar(ΔTQR).....(1)Similarly, triangle QTS and TQR are on the same base QT and between the parallels QT and RS. So,ar(ΔQTS)=ar(ΔTQR).....(2)From (1) and (2), we have,ar(ΔPQR)=ar(ΔQTS)Hence Proved.

sum 2/5+ 3/5= 5/5= 1

2/5+3/5=5/5=1 answer.

a) 2/5 + 3/5 = 5/5=1;. 1/9 + 4/9 + 3/9 = 2+4+3/9=. 9/9=1

A can do 1/8 of the work in one day.B can do 1/12 of the work in one day.A and B together can do=1/8+1/12= 5/24 A and B together can do the work in 24/5=4.8hours.

इसका मान 0 होगाBxC एक सदिश देगा जो इन तीनों के लंबवत होगाअतः 90 डिग्री का कोण निर्मित करेगा

11935 is the correct answer

Mean = Summation of yield/ summation of acres= (10+7+5+3+9+6+9)/7= 49/7= 7.

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On subtracting 5 from each number:16 − 5 = 1136 − 5 = 3140 − 5 = 35The required number will be the least common multiple of 11, 31 and 35.L.C.M. of 11, 31 and 35 = 11×31×35 = 11935This is because they do not have any factor in common.So, 11935 is the required number.

this will have a terminating decimal expansion and it will have 6 digits after the decimal point because out of 2 and 5,2 has the highest power which is equal to 6

2gram and 10 gram ratio

A.= 2:10=2/10=1/2 =1:2B=60:200=60/200=3/10=3:10C=12:3=12/3=4/1=4:1

coordinate of a centroid is ((3+4+5)/3 , (4+5+0)/3 ) = (12/3 , 9/3 ) = (4 , 3)

1 and is a=3since i=-1sustitute the value of i in the given equation u will get a.which is =3

Squaring both sides2i=1-a^2+2aicomparing2i=2aia=1

total income =118.25+120.30+116.20=354.75

354.75 is your correct answer

₹354.75 is total income of three days

118.25+120.30+116.20=354.75

total income for three days will be 118.25+120.30+116.20=354.75

354.75 is the right answer

118.25+120.30+116.20=354.75

354.75 is right answer

118.25+120.30+116.20=354.75

118.25+120.30+116.20=354.75 is right answers for this question

add all three 118.25+120.30+116.20=354.75

total for three days will be 118.25+120.30+116.20=354.75 is the right answer

thanks

=5-[(i)^4]^5=5-[1]^5=5-1=4

4 is the correct answer

you have 6 numbered balls - from 1 to 6. You need to select 3 balls such that ball that is numbered '4' is always selected. Additionally, you need to arrange them in bags A B and C.

In essence you are selecting 2 balls from the remaining 5 balls and subsequently, arranging the 3 balls in bags A B and C.Cases:1.) you can place the ball#4 in A , and arrange the remaining 2 balls in B and C - in 5P2 ways OR2.) you can place the ball#4 in B , and arrange the remaining 2 balls in A and C - in 5P2 ways OR3.) you can place the ball#4 in C , and arrange the remaining 2 balls in B and A - in 5P2 ways

so the total cases are 3 x 5P2 i.e. r x (n-1)P(r-1)

In short, select 2 balls out of remaining 5 in 5C2 ways and arrange the 3 balls in 3! ways. Hence, 3! x 5C2 = 3 x 5P2 = r x(n-1)P(r-1)

Area=lxbhence length =area/breadth=120/8=15cmHence perimeter=2(l+b)=2(15+8)=2(23)=46cm

after to the third 38114 L patrol left in the petrol pump

subtracting on your questions value of first day and value in second day

98000 - (5655+15666+38565) 98000 - 5988638114L

After the third day,petrol left is98000-(5655+15666+38565)=98000-59886=38114l

1st . 25percent decrease 2nd. 50 percent increase

the distance covered by the people 1. 398 kilometres

Raja covered distance on first day-485 kmsecond day he covered-398 kmthird day he covered-502 kmtotal distance he covered-485+398+502=1385 km

A.ans=People that travelstandingup inbuses aresusceptible of suffering falls and injuries, particularly elderly people. Safety measures, however, mostly target seatedpassengers. People that travelstandingup inbuses aresusceptible of suffering falls and injuries, particularly elderly people.

a)7 passengers were standing in the bus.b)the value he depicted that he respect elders