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we know a radius makes 90° angle on any chord and bisects it.so,radii=> 26/ 2 => 13 cm ( H )base=> 24/ 2 => 12 cm ( B )p= ?

H² = B² + P²13² = 12² + P²169 = 144 + P²P²= 169 - 144P² = 25P=√ 25P= 5cm

The distance of chord from the centre is 5cm.

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let the no. is x andx+5 x²+(x+5)²=73

let first number=x other number=x+5

according to question,(x²)+(x+5)²=73x²+x²+25+10x=732x²+10x+25-73=02x²+10x-48=0dividing by 2,x²+5x-24=0x²+8x-3x-24=0x(x+8)-3(x+8)=0(x+8)(x-3)=0x-3=0x=3first number=3other number=3+5=8 ans.

Given thatDE//BC,AD/DB =3/5 and AC=5.6 cmSince ABC is a triangle.AB=AD+DB=3+5=8 cmAC=5.6 cmSo using Thales theorem,AB/DB=AC/AE8/3=5.6/AEAE=5.6×3/8= 0•7×3=2.1 cm

Given chords AB=12 cm, CD =16 cm and AB||CDDraw OP⊥ AB. Let it intersect CD at Q and AB at P∴ AP = PB = 6 cm and CQ = DQ = 8 cm [Since perpendicular draw from the centre of the chord bisects the chord]Let OD = OB = rIn right ΔOQD, r^2 = x^2 + 8^2 [By Pythagoras theorem]r^2 = x^2 + 64 → (1)

In right ΔOPB, r^2 = (x + 2)^2 + 6^2 [By Pythagoras theorem]Þ r^2 = x^2 + 4x + 4 + 36 = x^2 + 4x + 40 → (2)

From (1) and (2) we getx^2 + 64 = x^2 + 4x + 40⇒ 4x = 24∴ x = 6

therefore radius of circle is 6cm.Put x = 3 in (1), we getr2 = 32 + 36 = 9 + 36 = 45∴ r = √45 = 3√5 cm

A, b, c ... in AP.

∴ 2b = a + c .......... (1)

∴ To Prove : 1/(√b + √c), 1/(√c + √a), 1/(√a + √b) ... in AP

⇒ To Prove : [ 1/(√c+√a) ] - [ 1/(√b+√c) ] = [ 1/(√a+√b) ] - [ 1/(√c+√a) ]

⇒ To Prove : [ (√b-√a) / (√b+√c) ] = [ (√c-√b) / (√a+√b) ]

⇒ To Prove : (√b-√a)·(√b+√a) = (√c-√b)·(√c+√b)

⇒ To Prove : b - a = c - b

⇒ To Prove : 2b = a + c, which is True ... from (1)

Hence, the result.

Perimeter of the figure= sum of two sides of triangle+ sum of three sides of the square=(7+7)+(7+7+7)=35 cm

Perimeter will be 2*(perimeter of a semicircle)+perimeter of rectanglehence radius of semicircle is 4.2m(8.4/2)Now the length, =21-(4.2+4.2)=12.6mhence breadth is 8.4mnow perimeter=2*(πr)+(2(l+b))=2*22/7*4.2+2(12.6+8.4)2*22*0.6+2*21=68.4mArea=2*(area of semicircle)+area of rectanglehencearea=2*(πr^2/2)+(l*b)=2*22/7*4.2*4.2+(12.6*8.4)=110.88+105.84=216.72m^2

sorry ur answer is wrong its answer is 161.28msq,51.6m

other methods of doing this

20150+49960+330+82

27=29+731=50+499=90+963=60+382=80+2

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When dice is rolled then total number of outcomes = 6

As dice contain numbers from 1 to 6. Hence its not possible to get number greater than 6.

Therefore,Probability of getting natural number greater than 6= 0/6 = 0

(c) is correct option

4.35×3

2).d=2r3) I) 8 cmii)4.5 cmiii)13 cmIV)15 cmv)12 cm4)I. 4 cmii. 7 cmiii. 8.5 cm

2)d=2r3) ¡)8cm¡¡)4.5cm¡¡¡)13cmlV) 15cm4)¡.4cm¡¡)7cm¡¡¡)8.5cm

Area = product of diagonals/2 = (6 * 9)/2 = 27 cm^2

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The human chromosome with the highest and least number of genes in. them are respectively: a. Chromosome 21 andY.

1) 480/2=240/2=120/2=60/2= 30/2=15/3=5;

2|480|1202|240| 602|120| 303| 60 | 155| 20| 5 | 4 | 1HCF = 2×2×2×3×5 = 120

120 the correct answer of the given question

120 is the right answer of the following

480/2=240/2=120/2=60/2=30/2=15/3=5reqd is H.C.F=2.2.2.2.2.3ans

Thank you very much

not right answer eska answer 320/3,13/2 hai 😊

6 1/2 is written as 13/26 1/2 =(6×2+1)/2=13/2

eska answer snd me plss

area of trapezium=area of rectangle+ area of triangle= (8)(3) +1/2(8)(3)=24+12=36cm^2

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Area of trapezium= 1/2 × sum of parallel sides× height.= 1/2 × ( AB + CD ) × AD= 1/2 × ( 13 + 7 ) × 8 = 1/2 × 20 × 8 = 10 × 8= 80 cm²

Area = 0.5*height*sum of parallel sides= 0.5*8*(7+13)= 0.5*8*20= 8*10= 80 sq cm

184+4=188. 327+2=329find hcf329=188*1+141188=141*1+47141=47*3+0HCF=47hence highest no is 47

1 is the correct answer of this question

x=1 is the correct answer

x=1is correct and best answer 👍 👍👍 👍

(X+2)/3-(X-1)/2=1[(2X+4)-(3X-3)]/6=12X+4-3X+3=1*6-X+7=6-X=6-7-X=-1X=1

2 is the correct answer

For the above solution the lines are inconsistent hence no solution exists.