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(1) 8u + 6u = 14 u (b) is correct option

(2) 5a + 6a + 7a = 18a (b) is correct option

(3) (2a + 3b) + (4a + 5b) = 6a + 8b (a) is correct option

(4) 12u - 9u = 3u (c) is correct option

the correct answer is b

what is the value of (7a+2b)(a+4b)

6a - a = 35 5a = 35 a = 7

6a - a = 355a = 35a = 35/5a = 7

thank you so much for my homework help

2a-2a^2-4 is the correct answer of the given question

498+183=681=680 (rounded to nearest tens)

228+523=751=750

614+254=868=870

Let the consecutive numbers be n, n+1, n+2

Their product would be n3+3n2+2n

Here it has been stated that n is a natural number. SO the value fo n could be anything from 1 to infinite.

let us test few values of n starting with 1, 2 and 3

n= 1 so n3+3n2+2n = 6 which is divisible by 6,

n= 2 so n3+3n2+2n = 24 which is also divisible by 6 and so on.

SO we may say that the the product of any 3 consecutive natural numbers is divisible by 6.

Thnx

6200 m. thanks for reading

I am doing my test please let me know the answer of my question

how come to scolor ship

wrong

17000 =1200+5000, ans=5000

wrong

The answer to this is 6201

Distance of the flight above the sea

level = 5000m

Distance of the submarine below the

Sea level = -1200m

Vertical distance between flight and

Submarine = | 5000 | + | - 1200 |

= 5000 + 1200

= 6200 m

the answer is 6200 because 5000+1200

नीचे प्रश्न के चित्र को दर्शाया गया है । प्रश्न से, PQ = 24cm , PR = 7cm तथा O वृत्त का केंद्र है।यहां दर्शाये गए चित्र से हम पाते हैं कि QR वृत्त के केंद्र से होकर गुजर रही है अतः , QR अवश्य वृत्त का व्यास है ।

हम यह जानते हैं कि वृत्त का व्यास , वृत्त को दो अर्धवृत्त में बाँटती है और अर्धवृत्त में बना हुआ कोण एक समकोण होता है।अतः ∆PQR एक समकोण त्रिभुज है जिसका angle RPQ= 90°है ।

अब, पायथागोरस प्रमेय से, PR² + PQ² = QR² 7² + 24² = QR² QR² = 49 + 576 = 625 QR = 25cm =

अब, छायांकित भाग का क्षेत्रफल = अर्धवृत्त का क्षेत्रफल - समकोण त्रिभुज का क्षेत्रफल

= 1/2 πr² - 1/2 × PQ × PR

= 1/2 × 22/7 × 25/2 × 25/2 - 1/2 × 24 × 7

= 245.3125 - 84

= 161.3125 cm²

24+a^2(b+3)+8b8(3+b)+a^2(b+3)(b+3)(8+a^2)

(5a+8b)-(6a-4b)=-a+12b

(5a+8b)-(6a4b)=a+12b

7x= x+786x= 78X= 78/6= 39/3= 13

answer is very helpful....

Let number be x8x+3x=14311x=143X=143/11=13Numbers=8*11=88And,3*11=33

33 is the correct answer of this problem

Let numbers are 5x and 6x (5x-8)/ (6x-8) = (4/5) => 5(5x-8)= 4(6x-8) => 25x-40 = 24x-32 => 25x-24x= 40-32 => x= 8 Two numbers are 5x 8= 40 and 6x8 = 48

let the quantity of alcohol and water b 4x and 3x litres respectively.after 5 litres added....water=3x +104x/3x+10=4/520x=12x+408x=40X=5alcohol is 4x=4*5=20litres

let x = the multiplierthen4x = original number of boysand5x = original number of girls:4x/5x-100=6/7Cross multiply7(4x) = 6(5x-100)28x = 30x - 600600 = 30x - 28x600 = 2xx = 600/2x = 300 is the multiplierthen4(300) = 1200 boys

of these is the answer

c) 800is a correct answer

1200

no. of the boys is 1200

no. of boy is 1200 there for the answer is 1200

what is your question

2.Ans=Given that two numbers are in 7:8 ratioLet the numbers be 7x and 8xGiven that their sum = 45⇒ 7x+8x = 45⇒ 15x = 45⇒ x = 45/15⇒ x = 3∴ The numbers are7x = 7×3 = 21and8x = 8×3 = 24∴ The numbers are 21 and 24

Let the numbers be 7x ,8xBy the problem,7x+8x=4515x=45x=45/15x=3Therefore,the numbers are 7(3)=21,8(3)=24

Let the numbers are x and yThen,x^2 - y ^2 = 45.............(1)x^2 = 4y......(2)

Put value of x^2 in eq(1)

4y - y^2 = 45y^2 - 4y + 45 = 0y^2 - 9y + 5y + 45 = 0y(y - 9) + 5(y - 9) = 0(y - 9)(y +5) = 0y = 9, - 5

Put value of y = 9 in eq(2)x^2 = 4*9x^2 = 36x = 6

The numbers 6 and 9

Let the numbers are 5x and 6x

As per given condition

(5x - 7)/(6x - 7) = 4/5

25x - 35 = 24x - 28

25x - 24x = 35 - 28

x = 7

Therefore, Numbers are5x = 5*7 = 357x = 7*7 = 49

Halima got sweets = 6xZainab got sweets = 6x/3 = 2xAmina got sweets = 2x + 6Farouk got sweets = 2(x + 3)/2= x + 3

As per given condition6x + 2x + (2x + 6) + (x + 3) = 3111x = 31 - 911x = 22x = 22/11 = 2

Therefore Farouk got sweets= x + 3 = 2 + 3 = 5

(D) is correct option

sum of all observations=80.4*50=4020

new sum =4020-96+69=3993

present mean=3993/50=79.86

kunal have 9 sweets............

kunal has 9 sweet this

Kunal have 9 sweet s

KUNAL HAS 3 SWEETS=3ANJU GIVE 6 SWEETS=6total sweets= 9

9 is the correct answer of your question.

kunal has 3 sweets + Anju gives him 6 sweets more3+6=9sweetsso kunal have 9 sweets now.

total addition=50×38=1900now 45 and 55 are discardedso remaining addition=1900-45-55=1800so mean=1800/48=37.5

Volume of a cuboid is given by ‘Length*Breadth*Height’

Length*Breadth*Height = Volume of cuboid

10*8*height = 380

Height = 380/80 = 4.75m

METHOD=. BODMAS

1st devide 2nd multiple (must)now= 32/4+(3-11+42)-12*2=8+(3-11+42)-6=11-11+42-6=0+36=36 ans.

the correct answer is 36

8+3-11+42-2411-11+1818 is the right answer

18 is the correct answer of the given question

32÷4+3-11+42-12×2=8+3-11+42-24=18

Mean of 5 numbers = 20Sum of 5 numbers = 20×5 = 100

if one is excluded, mean of 4 numbers = 23Sum of 4 numbers = 23×4= 92

The number excluded= 100 - 92 = 8

but its answers a-4. b-92. c 100. D-8

Mean of 5 numbers = 20Sum of 5 numbers = 20×5 = 100

if one is excluded, mean of 4 numbers = 23Sum of 4 numbers = 23×4= 92

The number excluded= 100 - 92 = 8

thanks

73+86+78+75+x/5 = 80

x = 400 - 312

x = 88

which one is greater 89 or 89.25