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| 70251. |
1+563= |
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Answer» 1 + 563= 564basic addition |
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| 70252. |
Lo6 पाइ-नन 929]है कक. है 0 ण्य=655 guy M 2&4‘ 5 |
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Answer» LHS sec+tan - (sec^2 - tan ^2)/tan -sec + 1 take common sec + tan (1-sec + tan)/tan-sec+1 sec + tan 1/cos + sin/cos 1+sin/cos multiply numerator and denominator by 1-sin we get 1-sin^2/cos-cos sin take cos common from denominator and 1-sin^2 is cos^22 cos^2/cos(1-sin) cos/1-sin = RHS |
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| 70253. |
the square of 491 is |
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Answer» 491×491 241081hope it helps you The answer is 241, 081 491 x 491 = 241081 491*491=241081 is correct answer (500-9) ²=241081 is answer correct answer is 241081 241081 is answer plz like my answer The answer is 241081 241081......is correct answer the square of the number 491 is491×491=241081 the square of 491 is 491×491=241081 here is you answer my friend 491 X 491 = 241081 241081 is correct answer. |
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| 70254. |
)The height o an eaulaua tlanglethe formongle alivt efly and3T-1-732- |
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| 70255. |
Hint. Two numbers are co-prtmes if thetr HCF is 1Pind the greatest number which divides 615 and 963, leaving the remainder 6 in each case.ind remainders 9 and 5 |
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Answer» LCM THE 24582 46927OF LCM |
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| 70256. |
c) S 325-491 --d) 439,348-43,365Roud |
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Answer» c) 7834d) 440983 |
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| 70257. |
iy 218 ki oyioh bl ke v पा हुए न | e |
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| 70258. |
(ii) If α and β are the zeroes of the quadratic polynomialar+br + c, then α + β is equal to(a)a(l(d) of these |
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Answer» sum of zeroes i.e. alpha + beta = -b/a (c) option is correct |
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| 70259. |
26r + 138s-35 are 2 ± v3 find od T6xIf two zeroes ofthe polynomial razerocsIf the polynomial-r lár +25x + 10 is divided by another polynomial-2x +, the remainder comes out to be x +a, find k and a |
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| 70260. |
Q.1. Find the polynomial whose zeroes are V. ,-狂Q.2 In Fig. 1, Δ/ABC is similar to ΔDEF. If AB = 3DE,ar(AABC) 144 cm2, find the ar(ADEF). |
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Answer» Like my answer if you find it useful! |
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| 70261. |
! हे बस कि. पके/ I 77**7335—‘7 3.30 € +. हि .o 77 06९७१ 3 + ले शाह ९9 |
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| 70262. |
9. Write the appropriate polynomials in the boxes.Solution : - 20 x 5Quadratic polynomialBinomialx + 7Ex (3) MultiplySolution : ( -5)--PRIESAr+r+x+5,2r + 5x + 10,=-2Cubic polynomialTrinomial3+ +5xLinear polynomialMonomial= m - 3Here the degree |
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| 70263. |
4, 16, 7,44. P का 30वाँ पद हैं।(B)87(A) 77( -77(D) इनमें से कोई नहीं |
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| 70264. |
3 + \frac { 1 } { 3 + \frac { 1 } { 3 + \frac { 1 } { 3 - \frac { 1 } { 2 } } } } |
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| 70265. |
|| A BC /2 _१ = 26/ 5 = १०० A 8 = 2-4-2)27 2-r/A//t a + 77 77 7 |
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| 70266. |
(5) 42037(Set:4. 10, 7, 4, ........... A. P. का 30वाँ पद है :(B) 87(C) -77(D) इनमें से कोई नहीं(A) 77 |
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| 70267. |
14. Find the greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively15. If the HCE f 657 and 063 is aynrocsibl in th fm6063x- 15 find the value of |
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Answer» SOLUTION :Given numbers are 285 and 1249 and remainders are 9 and 7 respectively. Then new numbers after subtracting remainders are : 285 – 9 = 276 1249 – 7 = 1242.The required number is HCF of 276 and 1242.HCF by prime factorization method : Prime factorization of 276 = 2×2×3×23 = 2² × 3¹ × 23¹ Prime factorization of 1242 = 2×3×3×3×23 = 2¹ × 3³ × 23¹HCF of 276 and 1242 = 2¹ ×3¹×23¹= 6 × 23 = 138[HCF of two or more numbers = product of the smallest power of each common prime factor involved in the numbers.] HCF of 276 and 1242 is 138.Hence, the required greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively is 138. |
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| 70268. |
Find the greatest number which divides 285 and 1249leaving remainders 9 and 7 respectively.Ans. 13810. |
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| 70269. |
find the two zeroes of 2x4-7x3+19x2-14x+30 if two of its zeroes are √2 and -√2 |
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| 70270. |
75777/218 |
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Answer» 347.6009174312 ansure right |
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| 70271. |
563 218 732 491 929Q23. If all the digits ineach number are arrangedin increasing order, thenwhich number will be thehighest number after therearrangement?(a) 218(b) 732(c) 491(d) 563(e) of theseSUBSCRIBE |
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Answer» 356,128,237,149,299563 is the correct answer of the given question 356,128,237,149,299563 is the correct answer the highest number after rearrangement will be 563 563 is the right answer 563 is the right answer |
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| 70272. |
Divide , 218 ky400 |
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Answer» 25875/400= 64.6875thanks |
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| 70273. |
Qus. 4. If two zeroes of the polynomial - 6r3- 26x + 138x- 35 are 2tthe other zeroes |
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Answer» Like if you find it useful |
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| 70274. |
23. As shown in the figure, D divides the side BC of a AABC in theA (0, 3)ratio 1:2. Find the length of AD.ORThe area of a triangle is 5 square units. Two of its vertices are(2, 1) and (3, -2). The third vertex lies on y-x+3 0. Find the B Dthird vertex. |
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| 70275. |
If two zeroes of the polynomial*-ar'-26r+ 138r-35 are 2t 3, find other zeroes. |
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| 70276. |
D If two zeroes of the polynomial ar-6r-26138x-35 are 2t 3, find other zeroes. |
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Answer» Since 2+ √3 is a zero,x-(2+√3) is a factor of the polynomial. Since 2-√3 is a zero,x-(2-√3) is a factor of the polynomial. This means that (x-2-√3)(x-2+√3) are factors (x-2-√3)(x-2+√3) [ using identity ]= (x-2)² - (√3)² = x² -4x +4 - 3= x²- 4x+1 x²- 4x+1 is a factor of x⁴-6x³-26x²+138x-35 WE have to perform division algorithm ,divide x⁴-6x³-26x²+138x-35 with x²- 4x+1 we get the answer as :- x²- 2x - 35 Now split the middle terms !! x²- 7x + 5x - 35 x [ x - 7 ] + 5 [ x - 7 ] [ x+ 5 ] [ x - 7 ] The other zeroes are :- -5 and 7 Like my answer if you find it useful! |
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| 70277. |
2. It two zeroes of the polynomial x* + 30% - 1582 - 29x - 6 and 2 + (5). Find other zeroes |
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| 70278. |
If two zeroes of the polynomialf(x)-3x -15 +132 +25x-30 are1and-, then find other zeroes. |
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Answer» now quotient ko middile term split karo |
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| 70279. |
Three consecutive vertices of a parlvertex.41.arallelogram.Ifthe42. TheThe points (3,-4) and (-6,2) are the extremities of a diagonalcoordinates of the fourth vertex.third vertex is (-1,-3). Find the(1, 1), (2,-3) annf the mid-points of the sides of a triangle are ( |
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| 70280. |
The three vertices of a rectangle ABCD are A(2, 2), B(-3, 2) and C(-3, 5). Find the coordinates of D. Q13. The point ( 0, 5 ) lies a) On the x axis b) on the y axis c) in 2nd quadrant d) un 1st quadrant |
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Answer» D) is the correct answer (b) is the correct answer |
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| 70281. |
If the perimeter of an equilateral triangle is 60m, find the areaof this triangle. |
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Answer» here perimeter is given ,u have to find area |
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| 70282. |
\left( 5 x ^ { 2 } - 9 + 6 x ^ { 4 } + 6 x + 7 x ^ { 3 } \right) \div \left( x ^ { 2 } - 1 \right) |
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| 70283. |
Find a number:(i) which when increased by 10% becomes 66.(ii) which when increased by 120% becomes 77.(iii) which when increased by 2.5% becomes 246. |
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Answer» 1.x + x(10/100)= 6611x/10 = 66x = 60 |
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| 70284. |
10. Find the greatest number which divide 2011 and 2623 leaving remaindersrespectivelyand3073 |
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| 70285. |
Find the largest number which divides 2011 and 2623 leaving remainders 9 and 5 respectively |
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| 70286. |
123-81/9=12-(13-12/3)=117/(7+6)=(-3)+(-6)/(-3)= |
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Answer» please like my answer if you find it useful |
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| 70287. |
OrEiged the largest number which divides 320 and 457 leaving remainders 5 and 7 respectively |
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Answer» Therefore the hcf of2718ab. bsbs1 bsbsbzvby VBB HhV jja a |
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| 70288. |
11037-63 |115&21M522218 |
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Answer» -137/462 is the correct answer of the given question |
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| 70289. |
-6/5 %2B 1/2 %2B 6/5 |
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Answer» =31/5-(43/10-3/2) =31/5-(43-15/10) =31/5-(-28/10) =31/5-(-14/5) =31/5+14/5=31+14/5=45/5=9answer 9 is the right answer. plz like my answer 9 is the correct answer of the given question Your correct answer is 9 9 is the correct answer |
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| 70290. |
3/6 %2B 5 %2B 6 |
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| 70291. |
( a 4 ( 3 x + 2 ) - 5 ( 6 x - 1 ) = 2 ( x - 8 ) - 6 ( 7 x - 4 ) |
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Answer» 4(3x+2) -5(6x-1) = 2(x-8) -6(7x-4)12x+8 -30x +5 = 2x -16 -42x +24-18x + 13 = -40x +8-18x +40x = 8-1322x = -5x = -5/22 |
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| 70292. |
7 6 30 2 32 1 414 51. If A-find A + B |
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| 70293. |
6 x ^ { 4 } - 5 x ^ { 3 } - 2 x ) \div ( 6 x + 1 ) |
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| 70294. |
If a polynomial x^{4}-6 x^{3}+8 x^{2}+6 x-9 has twozeroes as 3 and -1, then find the other zeroes. |
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| 70295. |
15. If (0,0) and (3, V3) are two vertices of anequilateral triangle, then find third vertex |
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| 70296. |
if (-4 3) and (4 3) are two vertices of an equilateral triangle find the coordinates of third vertex? |
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| 70297. |
(14) is the centroid of a triangle and two vertices are (4.-3) and (-9.7), then the third vertex is! |
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| 70298. |
If two vertices of an equilateral triangle are (0, 0)and (3, V3), find the third vertex of the triangle.26.3) |
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| 70299. |
51.) An equilateral triangle has two vertices at the points (3, 4) and (2, 3), find theceordinates of the third vertex. |
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| 70300. |
In AABC, 2C-32B, 2C-2(ZA+ZB), then the measure of B is:(A)40°(B) 60°(C) 90°= ² ( 2 (k+ 7) +-) 11 2 k = 14 +30(D) 120°luk+ |
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Answer» option d120° is correct answer let <B=x<C= 3x<C=2(<A+<B)3x=2<A+2x3x-2x=<Ax=<A<A+<B+<C=180x+x+3x=1805x= 180x= 180/5 = 36°<B= 36°=<A<c=3×36= 108°< option d is the correct answer |
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