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72051.

3 marks the following integers on a number len105 0-2 m 2 -13

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72052.

Dyrepeu(e) Find the measure of the side of a squaredmeasure of the side of a square handkerchief of area 324 cm.22

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18 CM is the correct answer

81 cm is the side of handkerchief

hey the formula of area of square is A^2 so it will be underroot 324 which means the sides are 18 cm

18 cm. yes

18cm as 18×18 is 334

18 is the right answer

18cm as 18×18 is 324

18 is the correct ans.....

18 cm is the answer of the following

18 is correct answer

18 is the right answer

18cm is the correct answer

72053.

123×123

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15,129 is the right answer

Your correct answer is 15129

15129 is the right answer.

15129 is correct answer

15129 is the correct answer of the following question

15,129 is right answer of this question

15129 is the right answer to your question

72054.

12+123

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135 is the correct answer

135 is correct answer according to your question

72055.

1.Find the five irrational numbers bet

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check outmy solution

72056.

find 12th term of ap -3,-1/2,2

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a = -3

d = -1/2-(-3)

= 3-1/2

= 5/2

12th term = a + 11d

= -3 + 11(5/2)

= -3 + 55/2

= -6+55/2

= 49/2

Like my answer if you find it useful!

72057.

LongAnswer questions:1. Solve 1+ edx e 1

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72058.

3. Attempt the following:13 marks each)In a circle with radius 61 cm, two equal chords areat a distance of 11 cm from the centre. Find thelengths of the chords.(1)Solution:

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PLEASE LIKE IT, IF YOU FIND THE ANSWER HELPFUL.

72059.

3. Attempt the following13 marks eache ratio of two sides of a parallelogram is 7 : 4and its perimeter is 44 cm. Find the lengths of the(1) Thsides of the parallelogram.Solution:

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72060.

ha squared sheet, draw two triangles of equal areas sach that theiangles are congruent.thangles are not oongruentWhat can you say about their perimeters

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Here, ΔABC and ΔPQR have the same area and are congruent to each other also. Also, the perimeter of both the triangles will be the same.

(ii) Here, the two triangles have the same height and base. Thus, their areas are equal. However, these triangles are not congruent to each other. Also, the perimeter of both the triangles will not be the same.

72061.

47. Find the missing number of the series:9, 16, 30, ,114(Civil Excise Officer/Women CivilExcise Officer (NCA) - 2017)(a) 51 (b) 58 (c) 42 (d) 54

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Answer is 51. Pattern is 7*1 , 7*2, 7*3, ........

Answer is 51. Pattern is 7*1 , 7*2, 7*3, ........

58 is the correct ans 9*2-2=1616*2-2=3030*2-2=5858*2-2=114

the correct answer is 58...pattern is as follows9×2-2 =1616*2-2 =3030*2-2= 5858*2-2 =114

option B) 58 is the correct answer

9,16,30,58,114

114 is the right answer.

58 is the correct answerPattern is as follows9*2-2=1616*2-2=3030*2-2=58

72062.

8. If 5a = 3125, then the value of 5(a – 3) is :v (2) 25(b) 125(c) 625(d) 1625

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Answer:a)25

Explanation:given:5^a=31255^a=5^5Thus a=5

Now 5^(a-3)=5^(5-3)=5^2=25

the answer of the option is A) 25

72063.

3Classify as regional or heational 123

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72064.

If 50% of x = 3y and 25% of y = 10,then the value of x is(A) 100(B) 125(C) 240(D) 120

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Given,(50/100)x = 3yx/2 = 3yx = 6y............ (1)

(25/100)y = 10y/4 = 10y = 40.............(2)

Put value of y from eq(2) in eq(1), we get x = 6*40 = 240

Therefore, Value of x = 240(C) is correct option

thanks sir

72065.

7. Find five rational numbers betal

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72066.

7. Calculate the missing frequency from the following distributioni14. Ebeing given that the median of the distribution is 24.Class0-100-20 20-30 30-40 40-502518Frequency

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72067.

2) Observe the following13Solution : A={B={are common in set A and B.. The elementsAB=

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A = {3,13}B={1,9,11}the elements 1,9,11 are common in set A and BA⋂B = { 1, 9, 11 }is the best answer

.

72068.

Q.3 The area of a square and that of a rectangle are equal. Can thesehave different perimeters? Explain with an example

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thanks dear

72069.

Q. 6. Show that A (4, -1), B (6,,dC(7, -2) and D (5, -3) arevertices of a square.

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72070.

E Sample Papers (Unsolved)D-27In the figure, from a cuboidal solid metallic block, of dimensions 15 cm 10 cmhole of diameter 7 cm is drilled out. Find the surface area of the remaining block. (Use π× 5 cm, a cylindrical5 cm, a cylin7 cm5 cmeni15 cm

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72071.

1-30. The solution to the equation 364 is called the cube root of 64. The idea issimilar to the idea of a square root, except that the value must be cubed(multiplied by itself three times) to become 64. One way to write the cube roof 64 is using the notation 64. Use this information to evaluate each of thefollowing expressionsa. 64b. 125c.-S

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72072.

mean of the following frequency distribution is 26.Find the missing frequency f:15 20 25 3035 404ObservationFrequency8 18 f73

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72073.

The arithmetic mean of the following distribution is 25. Determine the value of Pclass0-10 10-3020-30 30-4040-50frequency 551815

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72074.

P y+3 QSquare: PQRSKite: NICE2. The sides of a parallelogram are in the ratio 2:3.If its perimeter is 20 cm, findthe lgof the sides.

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Sides will be in 2 cm , 6 cm 2 cm and 6 cm

72075.

\frac{1}{\log _{u}(b c)+1}+\frac{1}{\log _{b}(c a)+1}+\frac{1}{\log _{c}(a b)+1}=1

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72076.

22. An aircraft has 120 passenger seats. The number of seats occupied during 100 flights is givenbelow:| No. ofseats 100-104 104.108 108-112 112-116| 116-120Frequency 1520321815Determine the mean number of seats occupied over the flights

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hloo

72077.

b2+c2c2 +a2a2 + b2b+ec+aa+b11|=(a-b)(b-c) (c-a).1

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72078.

If the equation (1+ m2)x2+2mcx + c2-a2=0 has equal roots, then prove thatc2 = a2 (1 + m2). ),

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72079.

20. If (x + a) is a factor of the polynomial 2x² + 2ax + 5x + 10, find the valueof a.[CBSE 2009)

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x+a is a factor of 2x²+2ax+5x+10therefore f(-a)=0;substituting values,2(-a)²+2(a)(-a)+5(-a)+10=02a²-2a²-5a+10=0-5a+10=0therefore a=2

-5a = -10 a = 2

x+a=0x=-ap(-a)=0-5a+10=0-5a=-10a=10/5a=2

the value of a is 2 is the correct answer of the given question

72080.

X-b-C3. समीकरणX-C-a-+-bX-a-Cca* = 3 को हल करने पर ४ का मान प्राप्त होगा।(2009)

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x= a+b+c is the correct answer of the given question

72081.

ti n(A) 2, pA)then n(S)-E then n(S)-?(A) 10 (B)C)(D)dsyllabus.

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p(A)=n(A)/n(S)(1/5)=2/n(S)

n(S)=10

72082.

Profit and Loss135A dealer sold a camera for 1080 gaining tcot price. Find (1) the cost price of thecamera, and (l) the gain per cent earned by the dealer.tint. Let CP = x. Then, gain =ビ. Therefore, SP-(x +)-, sgain =8 Therefore. SP=(x+8)-8

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72083.

Number of ways in which 7 people can occupy six seats 3 seats on each side in a first class railwaycompartment if two specified persons are to be always included and occupy adjacent seats on thesame side, is (k). 5! then k has the value equal to(A) 2(B) 4(C) 8(D) none

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7 people 6 seats2 already specified so 5 people left and 4 seats left.5C2*4!*2!*4=8*5!K=8

72084.

If X = {a, b, c, d} and Y= {f, b, d, g} Find X-Y and XM.f the set= fl

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Given X = {a, b, c, d}Y = {f, b, d, g}

Then,X - Y = {a, c}XnY = {b, d}

72085.

2x2 +1a2 + b2= (x2 + 1)2(2x2 +1)2

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Apologies we are currently taking questions in English language only

72086.

1. । विकल्प पर MV) चिहन ज(i) वह संख्या जो प्रत्येक ऋणात्मक पर्णाक से 4* तथा प्रत्येक धनात्मक पूर्णाक से छोटी ।होती है -(घ) इनमें से कोई नहीं(क) -1(ग)_0

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right answer 0 in this question

72087.

3 ’IJ ही 2 5 क प्रथम 22 पा का योग कहे

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a = 8d = 3 - 8 = -5Sum of n terms of an A. PSn = (n/2) [2a + (n - 1)d]

S₂₂ = (22/2) [2(8) + (22 - 1)(-5)]

S₂₂ = 11 [16 + 21(-5)]

S₂₂ = 11 [16 - 105]

S₂₂ = 11 × -89

S₂₂ = -979

72088.

J.A.C.,200910. (1) In how many ways can 10 seats in a bus be occupied by 4 passengers.(ii) In how many ways 6 prices can be distributed to 3 persons when each person is eligible for any of the prizes!

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what is this mystery I can not solve it sorry because I am in 10 class please give me a answer

1 is 50402nd is 360

n is the number of total seats on the bus.x is the number of those seats you want to occupy at one time.the formula for nPx is:nPx = n! / (n-x)!in your problem, n is equal to 10 and x is equal to 4the formula becomes:10P4 = 10! / (10-4)! which is equal to 10! / 6! which is equal to 10×9×8×7=5040

72089.

28.in. Let 5 kg of coffee be mixed with 2 kg of chicory.the selling price of 16 water bottles is equal to the cost price of 17 water bottles, find thugain per cent earned by the dealer.of 15 candles. Find the lose27.

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72090.

belowsE Ramus school has an extra land in the form givenA) Find the perimeter and area of teto fence this land with a long pieca dthis extra land2(8) The school managing commit2m Find the length of the wire needed o ns

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72091.

o write the synonyms ofo calmo heal -& idea-

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1)calm--tranquil2)heal---gate well3)idea--plan

calm- tranquilheal- gate wellidea-plan

1 calm=peace. 2 heal=top 3. idea=things

(1) clam- smooth,still(2) heal- repair, restore(3) Idea-thought,think

tranquilgate wellplan

1).calm=tranquil2).heal=get well3).idea=plan

1)calm=tranquil2)heal=gate well3)idea=plan

calm:-plesently freeheal:- to become soundidea:- plan or suggestions

calm= tranquilheal= gate wellidea =plan

calm= cool, composedheal= cureidea= plan

Calm - peace,StillHeal- Gate well ,topIdea -Plan,Thought

72092.

bcoespnaing to the longest side.10. The perimeter of an isosceles triangle is 42 cm and its base is (3/2) times each of the equalsides, Find thelength of each side of the triangle,area of the triangle and thetriangle.11. Find te a

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Let the side of the isosceles triangle be xGIVEN3/2 x +x +x=42cm3x/2 + 2x =42(3x+4x)/2=423x+4x=847x=84x=12cmside=12cm base=18cmThe height(altitude) of an isos. trangle divides it into two rt tranglesin a rt.trangle, base²+heigrt²=hypotenuse²thus, 9²+h²=12²h=√12²-9²=√144-81 =√63 =3√7cmarea =1/2 x base x hieght =1/2 x 18 x3√7 27√7cm²

72093.

\begin{array} { l } { \frac { f ( b ) - f ( a ) } { g ( b ) - g ( a ) } = \frac { f ^ { \prime } ( c ) } { g ^ { \prime } ( c ) } } \\ { \frac { f ( b ) - f ( a ) } { b - a } = \frac { f ^ { \prime } ( c ) } { g ^ { \prime } ( c ) } } \end{array}

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option (a) must be correct cauchy mean value theorem states that

72094.

(2) Add the polynomials3 2x2-9 and 5x3+2x + 9.

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ok

72095.

9!(ii)5!X3!

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9.5x3= 3..................5

1*2*3*4*5*6*7*8*9/1*2*3*4*5*1*2*3=6*7*8*9/2*3=504

72096.

(ii) x3-3x2 -9x- 5

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X³ - 3x² - 9x - 5

= x³ + x² - 4x² - 4x - 5x - 5

= x²( x + 1) - 4x ( x + 1) - 5(x + 1)

= (x + 1)(x² - 4x - 5)

= (x + 1)(x² -5x + x - 5)

= (x + 1)(x - 5) (x + 1)

hence, (x +1), (x -5) and (x +1) are the factors of given polynomial

72097.

11.(3x+5 को सरल कीजिए।3Nu

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2/3×3/5+5/22/5+5/2...

add this both and you will get the answer

72098.

Llys can 6votervote for any number of candidates not greater than the numbermany ways can a voter choose to vote.. In an election there are 5 candidates and 3 members are to be elected. 4 .canto be elected. In how

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Voter can vote for either one, two or three candidates.

No of ways he can vote for 1 is 5c1 =5No of ways he can vote for 2 is 5c2 =10No of ways he can vote for 3 is 5c3 =10Total =25

72099.

1. In an election there are b candidates and 3 members are to be electad. A voter cvote for any number of candidates not greater than the number to be elected. la homany ways can a voter choose to vote

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72100.

f.Explain the administration during the Delhi Sultanate.

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The Sultans of Delhi were no exception. They were not head of a religion but only head of their state. But their primary duty was the observance of the laws of Shariat or Islamic laws in matters of state.

Therefore, the policy of the rulers of the Delhi Sultanate was largely influenced by their religion viz., Islam. Due to this reason, with the exception of some of them, their policies were influenced by the Ulema and Islam was accepted as the religion of the state making the Delhi Sultanate a theocratic state in theory though it could not be possible in practice.

Most of the rulers of the Delhi Sultanate called themselves as the Naib (deputy) of the Khalifah and accepted Abbasid Khalifahs as their overlords. Ala-ud-din Mubarak Khalji alone was an exception to it whiles his son Qutb-ud- din Mubarak Khalji went a step further and himself assumed the title of Khalifah.

Muhammad Tughluq did not give the Khalifah any importance in the early period of his reign but ultimately had to yield and accepted the Khalifah as his overlord with a view to gain support of the Ulema. However, the rulers of the Delhi Sultanate accepted the Khalifah as their overlord only in name.

They called themselves as Naibs of the Khalifah on their coins but for all practical purposes they all behaved as independent rulers. They accepted the Khalifah as their overlord with a view to win over to their side Sunni subjects and the Ulema which wielded large religious influence among the Muslim populace.

The Central Government:

1. The Sultan:

The head of the state was the Sultan who enjoyed unlimited powers in every sphere of state activity. There was no law of succession during the period of the Sultanate. It was not necessary that the eldest son or the daughter of the Sultan should succeed the father. However, tradition developed from the close of the reign of Sultan Iltutmish that the throne belonged to the eldest son or the daughter of the Sultan.

Besides, the Sultan had also the right to nominate anyone as his successor to the throne. Thus, the principle of hereditary succession and nomination of successor by the Sultan came into vogue. Razia, Shihab-ud-din Khalji and Tughluq Shah were accepted rulers on the basis of one or other of these principles. However, the experiment of placing of a woman or minor on the throne failed.

Therefore, the practice developed that the right of heredity was to be accepted only in cases of competent successor. In case a competent successor was not available, the nobles got the right to choose the Sultan. Iltutmish, all brothers of Sultana Razia, Qutb-ud-din Mubarak Khalji and Firuz Tughluq were chosen Sultans with the consent of the nobility. Besides, the sword also decided the issue of succession. Ala-ud-din Khalji, Khizr Khan and Bahlul Lodi got the throne by force.

The Sultan, according to his strength, behaved as an all-powerful despot. The Sultan was the absolute master of the state and all legislative, executive and judicial powers were concentrated in his person. He was also the highest commander of the army.

All ministers, nobles and other officers of the state were appointed, promoted and dismissed by him. His order was the law in his state. But, these were his legal powers. Their effectiveness in practice depended on his military strength. The nobility also wielded influence particularly if the Sultan was weak.

The Ulema, being interpreter of Islamic laws, also influenced the policy of the Sultan. Only Ala-ud-din Khalji and Mubarak Khalji refused to accept the interference of the Ulema in matters of the state. Apart from maintenance of peace and order within the empire and its protection from foreign invasions, one important duty of the Sultan was to extend its territories.

2. Ministers and Other Officers:

Different ministers and other officials assisted the Sultan in administering the state.