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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 73801. |
Every set is a subset of itself. i.e. ACA |
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Answer» This statement is true because all the elements of a set are present in itself. |
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| 73802. |
Example 4. Let A, B and C be three sets. IfA E B and B C, is it true that AC C ? If not, give anxample.(N.C.E.R.T.) |
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| 73803. |
Sonu scored 1sakbun examination 80% students passed. If 75 students appeared in the examination, findhow many passed and how many failed? |
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| 73804. |
| 1 + x, 0 SX S212. Let; (*) - 1 3 -x, 2<x<3. Find fof. |
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| 73805. |
y=atan(-tan(x) %2B sec(x)) |
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| 73806. |
In an examination, 94% of the students passed and 33 students failed. How many studentsappeared in the examination?Q64) |
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Answer» passed %=94%failed %=100-94=6%let x be total students6% of x =330.06x=33x=33/0.06=550total students =550 |
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| 73807. |
99 students appeared in an examination. 45 of thempassed. How many failed? |
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Answer» 99 students are in total. No of failed students = 99-45 = 54 |
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| 73808. |
9. In board examination 50,00,000 students appeared, only 33,47,610 were passed. Findthe number of students who failed in the examination. |
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Answer» Total number of students appeared = 50,00,000 Number of students passed= 33,47, 610 Then, Number of students failed in examination = 5000000 - 3347610= 16,52,390 |
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| 73809. |
Raghu,s age is 18 year less than two times his cousin,s Age full . what is Raghu age if his cousins age is X year |
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Answer» Raghu = 2×cousin - 18 now cousin = x so Raghu = 2x - 18 |
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| 73810. |
6. Draw a Venn diagram to show:A. A set and its subsetB. Two different or distinct sets but subsets of a universal set |
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| 73811. |
Write the elements of each setrepresented in the given Venn diagramAlso identify the universal set andsubsets.9.28573015 512235010 |
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Answer» P(12,9)Q(30,,1,15,5,23,50)R(1,15,5)U(7,57,10,30,15,5,23,1,28,12,9) |
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| 73812. |
A. Hencexample 21 Let U be universal set of all the students of Class XI of a coeducationalchool and A be the set of all girls in Class XI. Find A'.A1 2,4, 6, 8,10 |
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Answer» U is universal set of girls and boys A = { set of girls}So A' = U - A = { set of boys students} |
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| 73813. |
te wen diagram, the universal set, & = (students in dass 72 setstudents who passed Mathematics, and set N = (students whosed English It is given that (M) = 50, (NG) = 60 and (M N272 students failed in both subjects, find the total number ofudents who attend for the examination(3) 100(D) 120 |
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Answer» 50 passed in math60 in n English2failed in both subject50+60+2=110 b) is the correct answer |
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| 73814. |
squares and F, be the set of trapeziums in a plane.NCERT ExemplarlThen, F may be equal toF2UF FOF15. Suppose A, A2,..., Ago are thirty sets each having3 elements and B, B2, , Bn are n sets each having8 elements. Let A,- B,S and each30j-1elements of S belongs to exactly 10 of A,'s and exactly9 of B,'s. The value of n is equal to INCERT Exemplarl16.IfA={x : x is a multiple of 4}andB=(x:x is a |
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| 73815. |
byeliminationmethod3x-8,xty-10.Find S, for the Geothethe seFalYE the following equation |
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| 73816. |
sin AProve the following identity sesec Atan A-1sec ACOSAcot A-1 |
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Answer» sinx / secx + tanx -1 + cosx/ cosecx+ cot-1 =sinx / 1/ cosx + sinx/ cosx -1 +cosx/ 1/ sinx + cosx/ sinx-1 =sinx/(1+sinx-cosx)_/ cosx + cosx/(1+cosx - sinx)/ sinx = sinxcosx/ (1+sinx-cosx) + sinxcosx/(1+cosx-sinx) = sinxcosx(1/1+sinx-cosx) (1/ 1+ cosx-sinx) =sinxcosx(1+sinx-cosx)+(1+cosx-sinx)/ (1)- ( sinx - cosx)^2 = sinxcosx(1+ sinx-cosx+1+ cosx-sinx)/1-( sinx^2+cosx^2-2sinxcosx) = sinxcosx(1+1)/ 1- sinx^2- cosx^2+2sinxcosx / 2sinxcosx =1 |
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| 73817. |
If in partnership business the ratio of capitals of pratima and rabaya is 2:3 and the ratio of rabaya and jasmine is 4:5, find the ratio of capitals of pratima and jasmine. |
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Answer» it will be 8/15 |
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| 73818. |
A group of 210 students appeared in some test. The mean of 3rd of students is found to be60. The mean of the remaining students is found to be 78. The mean of the whole group willbe:(1) 74(2) 72(3) 80(4) 76 |
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Answer» Total students = 210 1/3 rd of 210 = 70 students Mean marks of 70 students = 60 Let the sum of marks of 70 students be x Mean = x/Number of students 60 = x/70 x = 70*60 ⇒ Sum of marks of 70 students= 4200 Remaining students = 210 - 70 = 140 students Mean of 140 students = 78 Sum of marks of 78 students = 140*78 = 10920 Total marks of 210 students = 4200 + 10920 = 15120 Mean of whole group = 15120/210 = 72 marks |
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| 73819. |
10 g and 89% is gold wn12. The cost of a Samsung Microwave Oven was18000 a year bacithless By gifiat % hasprice decreased ? |
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| 73820. |
(iii) A = (x : x + 5 = 5). It is null set or universal set. |
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Answer» It is an universal set because, the set has one item, that is 0. So it can not be a null set. Null set should not contain any component. Please hit the like button if this helped you hlo |
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| 73821. |
PRACTICE TESTS17. A man saved Rs 290 when two successive discounts of 10% and 5% were given on amicrowave oven. What was the marked price of the microwave oven?(1) Rs. 1,800(2) Rs. 2,500 (3) Rs. 2,200 (4) Rs.2,400 (5) Rs.2,000 |
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| 73822. |
आकृति 18.17 में 5 सेमी त्रिज्यातथा केन्द्र 0 वाले वृत्त में जीवाAB =6 सेमी लम्बी है।OM 1 AB 21 OM का मानज्ञात कीजिए। |
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Answer» Bhai image to sand kr phir ans dege |
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| 73823. |
a) 3 x (-1)c) (-21)×(-30)) (-1,5) × 0 × (-18) |
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Answer» a) 3*(-1)=-3b)630c)0 |
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| 73824. |
910Byselling a dress for 322, a shopkeeper gar s 15% At whatpricAn electrician sold two fans at 960 each. On one he gains20% and on the otherHow much does he gain or loss in the whóle transaction?eshould he sell it to gain 25%?he losses 20% |
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Answer» x = 322 * 100/115 = 280 Gain = 280 + 280*25/100 = 350 |
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| 73825. |
c - 178 %2B 522 - 410 |
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Answer» -178 - (-522) + (-410) = -178 + 522 - 410 = -588 + 522 = - 66 -178(-522)+(-410)=-178+522-410 =-588+522=-66 |
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| 73826. |
21. In the adjoining figure, △ABC is right-angled at Band ZA 30. If BC 6 cm, find (i) AB, (i) AC20. Let BC=x6 cmAB2 (ABC21. Let ABAC2 = (30。 |
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| 73827. |
EXERCISE 17.11. A paper is in the form of a rectangle DARK in which DA-30 cm30 mand KD = 21 cm. A semicircular portion with AR as diameter iscut-off. Find the area of the remaining part.21 om30 cm- |
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| 73828. |
(-21)*(-30) |
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Answer» 630 is the correct answer of the given question is + 630 is the answer to it 630 is the correct answer (-21)×(-30)=-21×-30=630 630 I think so...... 630 is the right answer 630 is correct answer Your correct answer is 630 360 is correct answer 630 is the answer to your question 630 is correct answer 630 is the right answer 630 is correct answer |
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| 73829. |
(-21)×(-30) |
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Answer» -21*-30 = 21*30 = 620 hi hello |
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| 73830. |
8. Perpendicular distance from the origin is 5 units and the angle made byperpendicular with the positive x-axis is 30°. |
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| 73831. |
6. Intersecting the y-axis at a distance of 2 units above the origin and making anangle of 30° with positive direction of the x-axis. |
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| 73832. |
3x-o-(-1)-12-2x-6-1x-12-2x-1-1x3Ă.30 24 -1x 30 and y 24.Putting the values of x and y in equation (i), we obtainDistance(30 x 24) km- 720 km.Hence, the length of the journey is 720 km.EXERCISE 3.10LEVEL-1I. Points A and B are 70 km. a part on a highway. A car starts from A and another carstarts from B simulataneously. If they travel in the same direction, they meet in 7hours, but if they travel towards each other, they meet in one hour. Find the speed ofCBSE 2002]the two cars. |
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Answer» A.____________.B Distance between A & B is 70km. ←A & ← B both travel in same direction. but their speed is not the same. So they both meet after 7 hours. let the speed of A be x and B be y. if they travel towards each other →← they meet in 1 hour. when they are moving in same direction ,the speed is x-y. when they are moving towards each other,the speed is x+y. Distance = 70km 7(x-y)=70 x-y=10---›(i) similarly 1(x+y)=70 x+y=70---›(ii) Solving (i) & (ii) x+y=70x -y=10_____2x=80. x=80/2=40 Km/ hr. substitute x in x+y=70 so,40+y=70;y=30 km/hr. The speed of Car A is 40km/hr. The speed of Car B is 30 km/hr. Hit like if you find it useful |
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| 73833. |
2/3 %2B 3 %2B 4*(3/4) |
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| 73834. |
1a)26400(b) 26460(c) 24460(d) 26640The value of a machine depreciates at the rate of 10% per annum. It was purchased 3 yearsago forて60000, what is the present value of the machine?(a) ?53640 (b) 516809.(c) 43740(d)そ43470 |
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| 73835. |
15. Evaluate: (a)( 30 21) x 32 |
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Answer» Hit like if you find it useful |
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| 73836. |
If a varies inversely as b+2 and if a 8 when= 1.5, find a when b-5.2(a) 2(b) 54(d) 4 |
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Answer» let a = k/(b+2) now put a = 8 and b = 1.5 , to get the value of k => 8 = k/(1.5+2) => 8 = k/3.5 => k = 8*3.5 = 28 now the expression becomes a = 28/(b+2) so, when b = 5 a = 28/(b+2)=> a = 28/(5+2) = 28/7 = 4 option C |
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| 73837. |
Gas(ltr)30 XDistance (Km) 15 20 |
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Answer» If 30litres---15kmxlitres---20kmhencex=30*20/15=40litres |
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| 73838. |
The diameters of two circular plates are respectively 10 cm and 24 cm. What is thediameter of a plate which has area equal to the combined area of the two givenplates? |
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Answer» Area of 1 st Plate = (22/7)(D/2)² = (22/7) (10/2)² = (22/7)* 25 Area of 2nd plate = (22/7)*(24/2)²= (22/7)*144 Total area = (22/7)*(25+144) = (22/7)* 169 = (22/7)* 13² = (22/7)*(26/2)² Dia of new plate = 26 cm |
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| 73839. |
x का मान ज्ञात कीजिए ।\left(\frac{4}{3}\right)^{-4} \times\left(\frac{4}{3}\right)^{-5}=\left(\frac{4}{3}\right)^{-3 x} |
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| 73840. |
3 %2B 4*(3 %2B 3*(4/3)) |
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Answer» 3+4(3+4-3*3)=3+4(3+4-9) =3+4(7-9) =3+4(-2) =3-8=-5 -5 is right answer........... 3+4[3+4-3*3]=3+4[3+4-9]=3+4[7-9]=3+4[-2]=7-2=5 ans 3+4[3+4-3*3]=3+4[3+4-9]=3+4[7-9]=3+4[-2]=3+(-8) =-5 ans 3+4[3+4-3*3]=3+4[7-9]=3+4[-2]=3+[-8]=3-8= -5 ans |
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| 73841. |
į purchased fors purchased?348000 Its value depreciates at 10% per annum during the first yearA car isand at20% per annum during the second year what will be its value after 2 years? |
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Answer» please help me |
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| 73842. |
30, The value of a machine depreciates at the rate of 10% per annum. It was purchased 3 yearsago. If its present value is 291600, for how much was it purchased?EXAMPLE |
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| 73843. |
4. y varies inversely with x. Ify30 when x(2) X when y #18# 12, find(I)y when x#15 |
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| 73844. |
If equation 8x² – 3xy + sy' = 0 represents twomutually perpendicular lines, then 1 =a) 3b) 8c)-8d) -3 |
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| 73845. |
4,y varies inversely with x. Ify(1) y when x 1530 when x12, find(2) x when y18 |
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| 73846. |
14. Determine graphically, the vertices of the triangle formed by the lines y = x. 3y = 1+1 = x21-33 + 10 = 015 the |
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Answer» did not formed triangle |
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| 73847. |
2x + 3y-6, 4x-y + 4-0, without find the co-oldmanTwo vertices of a triangle are (4,-3)& (2, 5). If the orthocentre of the triangle is at (1,2), find the00a in the ratio K:1. Pind the two values ofk for whichcoordinates of the third vertex |
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| 73848. |
lfmatrix A =[ 1 2 3 ] , write AAT , where Ar is transpose of matrix A. |
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| 73849. |
The cost of a car purchased 2 years ago depreciates at the rate of 20% per year. If its present value in 315600; find:1. its value after 2 years.2. its value when it was purchased 2 years ago. |
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Answer» Let the original price of the car be Rs xDepreciation, R= 20% paTime period, n = 2 yearsValue of car after depreciation, A = Rs 2,08,000Recall the formula, A = P[1 – (r/100)]n208000 = x[1 – (20/100)]2= x[80/100]2= x[16/25]Therefore, x = (208000) × (25/16) = 325000Hence original price of the car is Rs 3,25,000. |
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| 73850. |
8. In the figure, two straight lines PQ and Rintersect each other at O. If POT = 75°, findtbvalues of a, b and c.ar2cn s1sne4b°Cl75bo |
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Answer» We have two straight lines PQ and RS.And,∠ POT = 75°So,∠ POR +∠ POT +∠ TOS = 180° (Linear pair angles)Now substitute the given values, we get4b + 75° + b = 180°5b = 75° = 180°5b = 180° - 75°5b = 105°b = 21°And,∠ POR = 4b = 4 (21)∠ POR = 84°And,∠ SOQ =∠ POR (vertically opposite angles)Substitute the values, we geta = 84°And,∠ QOR =∠ POS (vertically opposite angles)Substitute the values, we get2c = 75° + 21°2c = 96°c = 96/2c = 48°So,a = 84°b = 21°c = 48° |
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