Explore topic-wise InterviewSolutions in .

Total number of hours taken = Number of days * Hours per day= 6*(3/4)= 4.5 hours

PLEASE HIT THE LIKE BUTTON

the weight of other book will be total -weight of one book=3 1/4-1 2/513/4-7/565-28/2037/20kg

Let the number of pages in book = n

Then,3n/8 + 2/5(n - 3n/8) + 156 = nn - 3n/8 - 2n/5 + 3n/20 = 156

Take LCM40n - 15n - 16n + 6n = 156*4015 n = 6240n = 416

Total pages in book = 416

where is the answer

√225+31/225=1+p/15√256/225=15+p/1516/15=15+p/1516=15+pp=1

a) not visible

b) Ratio

We know 1 km = 1000 m

10 km = 10,000 m

So, 5 m : 10,000 m

= 1 : 2,000

LHS=cot²A(secA-1)/(1+sinA)={(cos²A/sin²A)(1/cosA-1)}/(1+sinA)=[{cos²A/(1-cos²A)}{(1-cosA)/cosA}]/(1+sinA)=[{cos²A/(1+cosA)(1-cosA)}×{(1-cosA)cosA}]/(1+sinA)={cosA/(1+cosA)}/(1+sinA)=cosA/(1+sinA)(1+cosA)RHS=sec²A(1-sinA)/(1+secA)=(1/cos²A)(1-sinA)/(1+1/cosA)={(1-sinA)/cos²A}/{(1+cosA)/cosA}={(1-sinA)/(1-sin²A)}/{(1+cosA)/cosA}={(1-sinA)/(1+sinA)(1-sinA)}/{(1+cosA)/cosA}={1/(1+sinA)}/{(1+cosA)/cosA}=cosA/(1+sinA)(1+cosA)∴, LHS=RHS (Proved)

Given:

p(x)=ax^2-3(a-1)x-11 is a zero of p(x)

thus p(1)=a(1)-3(a-1)(1) -1a-3a+3-1=0-2a+2=02a=2a=2/2a=1

uncle is the best answer

uncle is the correct answer

uncle is the correct answer

uncle is the correct answer.

uncle is the best answer

uncle is correct answer

uncle is the best answer

Uncle is best answer

uncle is correct answer.

(A) uncle right answer

the cost of 15 books is 1635so the cost of 1 book = 1635÷15 = Rs 109

Let the CP of each pen be Rs.x.

Then,

CP of 12 pens=Rs.12

SP of 12 pens=CP of 15 pnes=Rs.15

now,gain=SP-CP=Rs.(15-12)=Rs.3

gain%=gain/cp*100

=(3/12*100)%=25%

Hence,the gain=25%.

12℅ is the answer of the first one.

Given:The first term of the A.P. isa.The last term of the A.P. isl.

To prove: The sum of thenth term from the beginning and thenth term from the end is (a + l).

Let the common difference of the A.P. be 'd'.

We know that thenth term of an A.P. is given by

nthterm of the AP,Tn=a+ (n− 1)d ......(a)

Also, we know that thenth term from the end of an A.P. is given by

nthterm of the AP= [l- (n-1)d] ...... (b)

Adding equations (a) and (b), we get

a+ (n- 1)d+{l- (n- 1)d}​=a+ (n- 1)d+l- (n- 1)d= a+l

Therefore, it is proved that the sum of thenth term from the beginning and thenth term from the end is (a + l).

(c)1 is the correct answer of this problem

(C) 1

(√3 + √2)(√3 - √2) = 3 - 2 = 1

As given consumption of milk increase from Rs 120 to Rs 150

Then percentage increase in consumption= [(150 - 120)/120]×100= (30/120)*100= 25%

Therefore,Percentage increase in consumption is 25%

25% of consumption is increased

Suppose 100 items of 10 rs sold initially so initially 1000 Rs. now sale decreased by 5% so 95 and selling price increased by 10% so 11 so now total 95×11 = 1045 so percentage increase in profit = (1045-1000)*100/1000 = 45/10 = 4.5 %

15 book cost rs 3451 book cost rs 345/15=2350 book cost 1150

cost of 15 books = 345 rscost of 1 book= 345/15 = 23cost of 50 books = 23*50=1150 rs

cost of 35 metre cloth = 70105cost of 1 metre = 70105/35 =2003cost of 18 metres cloth = 2003*18 = 36054 rs

2) 15 books cost rs. 345cost of 1 book = 345/15 = 23 rs.therefore cost of 50 such books= 23 × 50= 1,150 rs.3) the cost of 35 meters of cloth is 701.05 rs.cost of 1 m cloth = 701.05/35= 20.03 rs.so the cost of 18 m of cloth= 20.03 × 18 = 360.54 rs.

1150 is the best answer

x=12 is the right answer

the right answer is 12

294÷7=4242×5=210

5m of cloth is of Rs 210

10)

plz send 11 qpestion also

hence the roots of quadratic equation are -> 3a/4b and (-2a/3a)

thanks a lot

PLEASE LIKE IT, IF YOU FIND THIS SOLUTION HELPFUL.

Area to be cemented= Area of bigger square - Area of smaller square= 40² - 35²= 1600 - 1225= 375m²

Cost = Area*Rate= 375*50= ₹ 18750

Please hit the like button if this helped you.

X= 16.64% is the correct answer

The cost of 8 kg of rice is Rupees 260

1

2

Please hit the like button if this helped you

in gram means 12500gm in kg means 12.5kg

weight of 12 books=1.5kgweight of one book=1.5/12weight of 100 books=(1.5×100)/12 =150/12 =12.5 kg ans

the weight of 100 books 12kg 500gm

weight of 12 books=1.5 kgweight of one book=1.5/12weight of 100 books=(1.5×1000)/12 =150/12 12.5 kg ans

the waight of 100 book is (125×100)=12kg500gm

weight of 12 books=1.5kgweight of one book=1.5/12weight of 100 books=(1.5×100)/12 =150/12 =12.5 kg

the weighy of the 100 book: 150/12kg

12 kg 500g is the correct answer

weight of 12 books is =1.5kgsuch 100 books weight is =12/1.5×100=12.5kg

150 kg because 1.5×10