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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 76201. |
y=(text*((t*(h*(e*(n*(f*(i*(d*n)))))))*Derivative(y, x)))*(sin(x) %2B cos(x))^2 |
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| 76202. |
sl 2A (x e 5)L e N |
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Answer» 100 - (x-5)(x-5) = 10*10 - (x-5)(x-5) = (10+x-5)(10-x+5) = (5+x)(15-x) |
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| 76203. |
8.Solve the inequation 8-2x 2 x-5; x e N. |
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| 76204. |
[NCERT Exemplar)Questiits areaon S. Side of a triangle are in the5. Side of a triangle are in the ratio of 12 17 25 and its perimeter is 540 |
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Answer» Ratio of the sides of the triangle = 12 : 17 : 25 Let the common ratio be x then sidesare 12x, 17x and 25x Perimeter of the triangle = 540cm 12x + 17x + 25x = 540 cm ⇒ 54x = 540cm ⇒ x = 10Sides of triangle are, 12 × 10 = 120cm 17x = 17 × 10 = 170cm 25x = 25 × 10 = 250cm Semi perimeter of triangle(s) = 540/2 = 270cm Using heron's formula,Area of the triangle = √s (s-a) (s-b) (s-c) = √270(270 - 120) (270 - 170) (270 - 250)cm2 = √270 × 150 × 100 × 20 cm² = 9000 cm² |
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| 76205. |
LUIS15SGNNe410 1525. Find the mode of the following data.Height (In cm) Above 30 Above 40 Above 50 Above 60 AbNo. of plants 34 30 27 / 191an Labove 70 Above 80 anoLOMC ANSWER TYRE QUESTI |
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Answer» 34+30+27+19+8+2=64+42+10=74+42=116/6 |
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| 76206. |
he coach of a cnckeland 3 more balls of the Samě kind 10geometricallycost of 2 kg of applés ähd ikg of grape2, the cost of4 kg of apples and 2 kg of grapes iSs on a day was foRs 300. Represent the sically and geometricallynf a Pair of Linear Equationsigolly represent a |
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| 76207. |
(ii) The cubes UIdigits, i.e., 1, 4, 5, 6 and(i) If 4' then x = 2.(v) Rational numbers are cl-rt Answer Type Questi8 32Divide :Divide : 8.32-valuateevaluate 6 - 1 |
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| 76208. |
Write down a pair of integer whose sum is -7 |
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Answer» Any pair of integers whose sum is -7 is (1, -8). PLEASE HIT THE LIKE BUTTON |
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| 76209. |
Example-13, Amotor boat whose speed is 18 km/h in still water. It takes I hour moreto go24 km upstream than to returm downstream to the same spot. Find the speed othe stream. |
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| 76210. |
x+7=9 linear equation solve check |
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Answer» x + 7 = 9subtract 7 on both sidesx + 7 - 7 = 9 - 7x = 2Verificationput x = 22 + 7 = 9so RHS = LHS |
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| 76211. |
what is Pythagoras theorem |
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Answer» Ans :- The Pythagorean theorem, also known as Pythagoras' theorem, is a fundamental relation in Euclidean geometry among the three sides of a right triangle. It states that the square of the hypotenuse is equal to the sum of the squares of the other two sides. |
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| 76212. |
erity the following7 (2 497 2 |
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Answer» LHS : 7/9*(2/7*4/-5) = 7/9(8/-35) = 8/-45 RHS : (7/9*2/7)*(4/-5) = 2/9*(4/-5) = 8/-45 Hence proved |
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| 76213. |
(2/7)^(-x)/(2/7)^(-3)=(2/7)^5 |
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| 76214. |
Fig. 12.21, two circular flower beds have beenn two sides of a square lawn PQRS m. If ther each circular flower bed is the or side 56 m. lf thethe diagonals of the square lawn, find the sum of the areas of thelawn and the flower beds. |
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| 76215. |
3.Find the solution sets of the followinginequations and represent them on thenumber line:a) 3 34x 8<25, x e N |
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| 76216. |
Express the following linear equations in the form ax + by+values ofa, b and c in each case:2.0 and indicate the9.35-(ifx_ y-10-0(İİİ).-2x + 3y-6(iv) x-3y(v) 2x5y (vi 3r+2-0(vii) y-2-0 .(vii) 5-2x |
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| 76217. |
2. Write a negative integer and a positive integer whose sum is -15. |
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Answer» the positive integer is 6 and the negative integer is -9 There are many possibilities:Negative integer = - 20Positive integer = 5 Negative integer = - 16Positive integer = 1 Negative integer = - 17Positive integer = 2 Negative integer = - 18Positive integer = 3 Negative integer = - 19Positive integer = 4 Negative integer = - 21Positive integer = 6 the positive integer is 6 and the negative integer is -9 answer is...-20 annd05 positive integer 6 and negative -9 positive integer 6 and negative -9 |
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| 76218. |
any positive integer n, prove that r -n is divisible by 6.rboat whose speed in sti |
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Answer» n³ - n = n(n²-1) = n(n -1)(n + 1) is divided by 3 then possible reminder is 0, 1 and 2 [ ∵ if P = ab + r , then 0 ≤ r < a by Euclid lemma ] ∴ Let n = 3r , 3r +1 , 3r + 2 , where r is an integer Case 1 :- when n = 3r Then, n³ - n is divisible by 3 [∵n³ - n = n(n-1)(n+1) = 3r(3r-1)(3r+1) , clearly shown it is divisible by 3 ] Case2 :- when n = 3r + 1 e.g., n - 1 = 3r +1 - 1 = 3r Then, n³ - n = (3r + 1)(3r)(3r + 2) , it is divisible by 3 Case 3:- when n = 3r - 1 e.g., n + 1 = 3r - 1 + 1 = 3r Then, n³ - n = (3r -1)(3r -2)(3r) , it is divisible by 3 From above explanation we observed n³ - n is divisible by 3 , where n is any positive integers |
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| 76219. |
4. If both the zeros of the quadratic polynomial ax+ bx + c are equal and opposite insign, then find the value of b.nf thr following pair of linear equations |
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| 76220. |
linearSolve the following pair ofr and y:2(ax-by) + (a +4b) = 0 ;2(x +ay) + (b-4) = 0equations for |
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| 76221. |
represent -23/6 on a number line |
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| 76222. |
6) H-Bap' will not represent Pythagoras theorem statement () |
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Answer» false is the correct answer 😀😀 false iscorrectanswer the Pythagorus theorem isH2=p2+B2 |
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| 76223. |
Expand the following(Z+ 7)(Z-6) |
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Answer» z(z-6)+7(z-6)=z^2-6z+7z-42=z^2+z-42 |
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| 76224. |
Q1 For what value ofk, do the equations 3r-1 + S = 0 and 6-ky =-16 representcoincident lines? |
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| 76225. |
.If the equations x -2y 3 and 2x + by 6represent the same line, then the value ofb is |
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Answer» Equation in standard form : x - 2y - 3 = 0 ......(1) 2x + by - 6 = 0 .......(2) That will be case of coincident. 1/2 = -2/b so it gives b = -4 So, putting b = -4 (2) gives 2x - 4y -6 = 0divide by 2 gives x - 2y - 3 = 0 |
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| 76226. |
prove that tueanBAABC is an isosceles triangle in which AB-AC. Show that < B-< C.(Hint: Draw AP I BC) (Using RHS congruence rule) |
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| 76227. |
(1) MUN(1, 2, 3, 4, 5, 6) and M (1, 2, 4) thenwhich of the following represent set N? |
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Answer» M U N = 1,2,3,4,5,6M= 1,2,4then the Union of two sets carry every number of both sets so N= 3,5,6 |
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| 76228. |
4. AABC is an isosceles triangle in which AB-AC. Show that 4B-C.(Hint: Draw AP L BC) (Using RHS congruence rule) |
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| 76229. |
prove that the triangle ABC is isosceles.AABC is an isosceles triangle in which AB AC. Show that 4BHint: Draw AP LBC) (Using RHS congruence rule)2C4 |
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Answer» In triangles APB and APC,angle APB = angle APC = 90°AB = AC (given)AP = AP (common side)so, by RHS the triangles are congruent,.hence, angle B= angle C (c.p.c.t.) |
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| 76230. |
A rectangular field is 24 m long and I5 m wide. How many triangular flower beds each of base Iaalttude 4im can be lax in this field ?tiple Choice Questions (MCOs)es base. What is its |
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Answer» Area of the rectangular field = 24×15=360m.sqArea of one triangular flower bed =1/2×3×4=6m.sqno of flower beds = 360/6 = 60 flower beds thank |
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| 76231. |
x × (y×z) = (x×y) ×zx=7/3 , y=12/5 , z=4/9 |
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Answer» x*(y*z)=7/3*(12/5*4/9)=7/3*(4/5*4/3)=7*16/3*15=112/15and(x*y)*z=(7/3*12/5)*4/9=112/15hence verified |
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| 76232. |
Ifan-11, then find whether the pair of linear equations ax + by = c and Ix t mly = n has no solution,unique solution or infinitely many solutions.3. |
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| 76233. |
3. If am-11, then find whether the pair of linear equations ax + by = c and Ix + my = n has no solution,unique solution or infinitely many solutions. |
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| 76234. |
There are three non collinear points. How manylines can be drawn passing through the pointstaking two at a time? Show with the help of afigure. |
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Answer» 3 lines can be drawn ,and they are the sides of the triangle formed by those points |
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| 76235. |
z - 7 + 7 x y - x y z |
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| 76236. |
\left. \begin{array} { l } { x + y + z = 9 } \\ { 2 x + 5 y + 7 z = 52 } \\ { 2 x + y - z = 0 } \end{array} \right. |
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| 76237. |
Llbo questions of 1 mark each, two questions3 marks each and three questions of 4 maone of the alternatives in all such questionsUse of calculators is not permitedrg stSECTION AFGTI 1召67币牙で茽邪7 1 3茽可君!tion numbers 1 to 6 carry 1 mark each.af .ส. (HCF) (336, 59-6 ,at .ส. (LCIIf HCF (336, 54) 6, find LCM (336, 54Find the nature of roots of the quadrati |
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Answer» 2x^2-4x+3= 0D= (-4)^2-4*2*316-24-8as D is less than 0imaginery roots HCF × LCM = product of numbers 6× LCM = 336 ×54 LCM = (336×54)÷6 LCM = 3024 |
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| 76238. |
12 - x _ 7 %2B z ^ x = ( x ) d |
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| 76239. |
2. Represent 6,7, 8 on the number line. |
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| 76240. |
BE and CF are two equal altitudes of a triangle ABC. Using RHS congruencerule, prove that the triangle ABC is isosceles. |
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| 76241. |
Fill in the blanks -(a) Two distinct......in a plane cannot have more than one point in common.(b) Two distinct points in a plane determine a......line. |
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Answer» (b) segment line.......... b answers sigment line b- sigment line is the right answer |
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| 76242. |
20, द्िघात बहुपद »* + 3: + 2 का शून्यक होगा() (3, 2) () (-3, 2)(0) (3, -2) i) (-1, -2) |
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Answer» X= -1(-1)^2-3+2= 0x= (-2)(-2)^2+3(-2)+2= 4-6+2=0Option- Dplease like the solution 👍 ✔️ |
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| 76243. |
\left. \begin{array} { l } { \text { Solution of } | x + \frac { 1 } { x } | < 4 \text { is } } \\ { ( a ) ( 2 - \sqrt { 3 } , 2 + \sqrt { 3 } ) \cup ( - 2 - \sqrt { 3 } , - 2 + \sqrt { 3 } ) } \\ { ( b ) R - ( 2 - \sqrt { 3 } , 2 + \sqrt { 3 } ) } \\ { ( c ) R - ( - 2 - \sqrt { 3 } , - 2 + \sqrt { 3 } ) } \end{array} \right. |
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| 76244. |
14. Write a pair of integer whose difference gives:(a) aero |
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Answer» 6and(-6)is the pair of integer whose difference is zero -31+31 Or -12+12, etc -2+2 or -6 +6answer |
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| 76245. |
Prove that one and only one circle can bedrawn through three non collinear points. |
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| 76246. |
unique C10.5 There is one and only one circle passing through threenon-collinear points. |
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| 76247. |
( x - y ) ( x + y ) + ( y - z ) ( y + z ) + ( z - x ) ( z + x ) |
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| 76248. |
EXAMPLERepresent 8.47 on the real line. |
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| 76249. |
Represent each of the numbers √2, √3, √5 on the real line |
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Answer» 1.First, we draw a line OA of length 1 2.Now, we draw a perpendicular of length 1 on point A as AB 3.From, Pythagoras Theorem, OB =√2 4.Now, take an arc of length OB, and draw it on the number line which meets as E. So, at E, we can represent √2 as shown in the figure. Now, again draw a perpendicular at point B of length BC= 1 unit and join the points O and C. Again by pythagoras theorem we get OC = root 3. Then by compus taking radius =OC, draw an arc so that it cuts the number line at D. Then the distance OD will be the square root of 3. 5 = √(4+1)Here 4 and 1 both are perfect square number as √4 = 2 and √1 = 1So draw right triangle with side 2 and 1And according to Pythagoras theorem hypotenuse will √(2^2+1^2) = √5Then draw an arc of √5 on number line |
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| 76250. |
tpwlarksQuestions3. In the figure, lines AB and CD intersect eachother at point O. If<AOC : <COB = 5 : 4, then findall the angles.linor Pand RS intersect e |
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